Coulombs Law and Electric Field - Exam Prep Insights

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Coulombs Law and Electric Field - Capacitance and Dielectrics

Q. What is the potential energy stored in a capacitor of 8 µF charged to 12 V?

A. 0.48 mJ
B. 0.72 mJ
C. 0.96 mJ
D. 1.44 mJ

Solution

U = 1/2 * C * V² = 1/2 * 8 x 10^-6 F * (12 V)² = 0.48 mJ.

Correct Answer: C — 0.96 mJ

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Q. What is the total capacitance of two capacitors of 4 µF and 6 µF in series?

A. 2.4 µF
B. 10 µF
C. 1.5 µF
D. 3.6 µF

Solution

1/C_eq = 1/C1 + 1/C2 = 1/4 + 1/6 = 5/12, thus C_eq = 12/5 = 2.4 µF.

Correct Answer: A — 2.4 µF

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Q. What is the total energy stored in a 10 µF capacitor charged to 20 V?

A. 2 J
B. 0.02 J
C. 0.2 J
D. 0.5 J

Solution

U = 0.5 * C * V^2 = 0.5 * (10 x 10^-6 F) * (20 V)^2 = 0.02 J.

Correct Answer: C — 0.2 J

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Q. What is the voltage across a 10 Ω resistor carrying a current of 2 A?

A. 5 V
B. 10 V
C. 20 V
D. 15 V

Solution

Using Ohm's law, V = I * R = 2 A * 10 Ω = 20 V.

Correct Answer: B — 10 V

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Q. What is the voltage across a 5 Ω resistor carrying a current of 3 A?

A. 15 V
B. 10 V
C. 5 V
D. 20 V

Solution

Using Ohm's law, V = I * R = 3 A * 5 Ω = 15 V.

Correct Answer: A — 15 V

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