The JEE Main exam is a crucial step for students aspiring to enter prestigious engineering colleges in India. It tests not only knowledge but also the ability to apply concepts effectively. Practicing MCQs and objective questions is essential for scoring better, as it helps in familiarizing students with the exam pattern and enhances their problem-solving skills. Engaging with practice questions allows students to identify important questions and strengthen their exam preparation.
What You Will Practise Here
Fundamental concepts of Physics, Chemistry, and Mathematics
Key formulas and their applications in problem-solving
Important definitions and theories relevant to JEE Main
Diagrams and graphical representations for better understanding
Numerical problems and their step-by-step solutions
Previous years' JEE Main questions for real exam experience
Time management strategies while solving MCQs
Exam Relevance
The topics covered in JEE Main are not only significant for the JEE exam but also appear in various CBSE and State Board examinations. Many concepts are shared with the NEET syllabus, making them relevant across multiple competitive exams. Common question patterns include conceptual applications, numerical problems, and theoretical questions that assess a student's understanding of core subjects.
Common Mistakes Students Make
Misinterpreting the question stem, leading to incorrect answers
Neglecting units in numerical problems, which can change the outcome
Overlooking negative marking and not managing time effectively
Relying too heavily on rote memorization instead of understanding concepts
Failing to review and analyze mistakes from practice tests
FAQs
Question: How can I improve my speed in solving JEE Main MCQ questions? Answer: Regular practice with timed quizzes and focusing on shortcuts can significantly enhance your speed.
Question: Are the JEE Main objective questions similar to previous years' papers? Answer: Yes, many questions are based on previous years' patterns, so practicing them can be beneficial.
Question: What is the best way to approach JEE Main practice questions? Answer: Start with understanding the concepts, then attempt practice questions, and finally review your answers to learn from mistakes.
Now is the time to take charge of your preparation! Dive into solving JEE Main MCQs and practice questions to test your understanding and boost your confidence for the exam.
Q. Two particles A and B of masses m1 and m2 are moving in a circular path with angular velocities ω1 and ω2 respectively. What is the total angular momentum of the system?
A.
m1ω1 + m2ω2
B.
m1ω1 - m2ω2
C.
m1ω1m2ω2
D.
m1ω1 + m2ω2/2
Solution
Total angular momentum L = m1ω1 + m2ω2 for particles moving in the same direction.
Q. Two particles A and B of masses m1 and m2 are moving in a straight line with velocities v1 and v2 respectively. If they collide elastically, which of the following statements is true regarding their angular momentum about the center of mass?
A.
It is conserved
B.
It is not conserved
C.
Depends on the masses
D.
Depends on the velocities
Solution
Angular momentum about the center of mass is conserved in an elastic collision.
Q. Two particles A and B of masses m1 and m2 are moving in opposite directions with velocities v1 and v2 respectively. What is the total angular momentum of the system about a point O located at the midpoint between A and B?
A.
(m1v1 + m2v2)r
B.
(m1v1 - m2v2)r
C.
0
D.
(m1v1 + m2v2)/2
Solution
Since they are moving in opposite directions, the total angular momentum about point O is zero.
Q. Two particles A and B of masses m1 and m2 are moving in opposite directions with velocities v1 and v2 respectively. What is the total angular momentum of the system about the origin if they are at a distance r from the origin?
A.
m1v1r + m2v2r
B.
m1v1r - m2v2r
C.
m1v1r + m2(-v2)r
D.
0
Solution
Total angular momentum L = m1v1r - m2v2r, but since they are in opposite directions, it simplifies to m1v1r + m2v2r.
Q. Two particles A and B of masses m1 and m2 are moving in opposite directions with velocities v1 and v2 respectively. What is the total angular momentum of the system about the origin?
A.
m1v1 + m2v2
B.
m1v1 - m2v2
C.
m1v1 + m2(-v2)
D.
m1v1 + m2v2
Solution
Total angular momentum L = m1v1 + m2(-v2) = m1v1 - m2v2.
Q. Two particles A and B of masses m1 and m2 are moving in opposite directions with velocities v1 and v2 respectively. What is the total angular momentum of the system about a point O located at the center of mass?
A.
(m1v1 + m2v2)
B.
(m1v1 - m2v2)
C.
m1v1 + m2v2
D.
0
Solution
Total angular momentum is the sum of individual angular momenta, which is m1v1 + m2v2.
Q. Two particles A and B of masses m1 and m2 are moving with velocities v1 and v2 respectively. If they collide elastically, which of the following statements is true regarding their angular momentum about the center of mass?
A.
It is conserved
B.
It is not conserved
C.
Depends on the masses
D.
Depends on the velocities
Solution
Angular momentum is conserved in an elastic collision about the center of mass.
Q. Two particles of masses m1 and m2 are moving in a circular path of radius r with angular velocities ω1 and ω2 respectively. What is the total angular momentum of the system?
Q. Two particles of masses m1 and m2 are moving in a circular path with radii r1 and r2 respectively. If they have the same angular velocity, what is the ratio of their angular momenta?
A.
m1r1/m2r2
B.
m1/m2
C.
r1/r2
D.
m1r2/m2r1
Solution
Angular momentum L = mvr, thus L1/L2 = (m1r1)/(m2r2) when ω is constant.
Q. Two particles of masses m1 and m2 are moving in a straight line with velocities v1 and v2 respectively. If they collide elastically, what is the expression for the change in angular momentum about the center of mass?
A.
m1v1 + m2v2
B.
m1v1 - m2v2
C.
0
D.
m1v1 + m2v2 - (m1v1' + m2v2')
Solution
In an elastic collision, the total angular momentum about the center of mass is conserved.
Q. Using Biot-Savart Law, what is the magnetic field at the center of a circular loop of radius R carrying current I?
A.
μ₀I/(2R)
B.
μ₀I/(4R)
C.
μ₀I/(πR)
D.
μ₀I/(2πR)
Solution
The magnetic field at the center of a circular loop of radius R carrying current I is given by B = μ₀I/(2R) and for a complete loop, it simplifies to B = μ₀I/(2πR).
Q. Using Kirchhoff's Current Law, if three currents enter a junction as 2A, 3A, and I, what is the value of I if the total current leaving the junction is 5A?
A.
0A
B.
1A
C.
2A
D.
3A
Solution
According to KCL, I = total entering - total leaving = (2A + 3A) - 5A = 0A.
Q. Using Kirchhoff's Current Law, if three currents enter a junction as 3A, 2A, and I, what is the value of I if the total current leaving the junction is 5A?
A.
4A
B.
5A
C.
2A
D.
3A
Solution
According to KCL, I = Total entering - Total leaving = (3A + 2A) - 5A = 0A.
Q. Using Kirchhoff's Voltage Law, if a loop in a circuit has a 12V battery and two resistors of 4Ω and 6Ω, what is the voltage drop across the 4Ω resistor?
Q. Using Kirchhoff's voltage law, if a loop in a circuit has a 9V battery and two resistors (2Ω and 3Ω) with voltage drops of 4V and 5V respectively, is the loop correctly analyzed?
A.
Yes
B.
No
C.
Only if the battery is 12V
D.
Only if the resistors are in series
Solution
According to Kirchhoff's voltage law, the sum of the voltage drops must equal the source voltage. Here, 4V + 5V = 9V, which is correct.
