The number of arrangements in a circle is (n-1)! = (6-1)! = 5! = 120.

The number of ways to divide 6 people into 2 groups of 3 is (6! / (3!3!)) / 2 = 20.

The number of arrangements around a circular table is (n-1)! = 5! = 120.

The number of arrangements of 6 people at a round table is (6-1)! = 5! = 120.

The number of arrangements of 6 people in a row is 6! = 720.

The number of ways to select 6 from 10 is C(10, 6) = 210.

Treat the 3 specific books as one unit. So, we have 5 units to arrange: 5! * 3! = 360.

Treat the 3 specific books as one unit. So, we have 6 units to arrange: 6! = 720. The 3 books can be arranged in 3! = 6 ways. Total = 720 * 6 = 4320.

The number of arrangements is 8! = 40320.

The number of ways to choose 3 from 5 is C(5,3) = 10.

The number of ways to form a committee of 3 from 7 is given by 7C3 = 35.

The number of ways to form a committee of 4 from 10 is given by 10C4 = 210.

The number of ways to form a committee of 4 from 8 is 8C4 = 70.

The word 'LEVEL' has 5 letters with 'E' repeated twice. The arrangements are 5! / 2! = 60 / 2 = 30.

The number of arrangements = 4! = 24.

The word 'BANANA' has 6 letters with 'A' repeating 3 times and 'N' repeating 2 times. The arrangements are 6!/(3!2!) = 60.

The number of ways to choose 3 fruits from 5 is given by 5C3 = 10.

The number of ways to form a committee of 3 from 10 is given by 10C3 = 120.

The number of ways to choose 2 from 5 is given by 5C2 = 10.

The number of ways to choose 2 fruits from 5 is given by 5C2 = 10.

The number of ways to select 2 students from 8 is given by 8C2 = 28.

Q = m * L = 1000 g * 2260 J/g = 2260000 J.

Heat required = mass × specific heat × change in temperature = 250 g × 4.2 J/g°C × (75°C - 25°C) = 5250 J.

Q = mcΔT = 500 g * 4.2 J/g°C * (75 - 25)°C = 10000 J.

Work = Force * Distance = 10 N * 5 m = 50 J.

Work done = Force × Distance = 15 N × 3 m = 45 J

Work = Force * Distance = 30 N * 4 m = 120 J.

To round 0.0001234 to two significant figures, we look at the first two non-zero digits (1 and 2) and round up, resulting in 0.00013.

To round 0.05060 to three significant figures, we keep the first three significant digits (5, 0, and 6), resulting in 0.0506.

In indirect speech, 'will' changes to 'would'.