Major Competitive Exams

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Major Competitive Exams

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Major Competitive Exams MCQ & Objective Questions

Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.

What You Will Practise Here

Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams

Exam Relevance

The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.

Common Mistakes Students Make

Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam

FAQs

Question: How can I improve my performance in Major Competitive Exams?
Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.

Question: What types of questions should I focus on for these exams?
Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.

Question: Are there specific strategies for tackling objective questions?
Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.

Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!

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Q. A biconvex lens has a radius of curvature of 30 cm on both sides. What is its focal length?

A. 10 cm
B. 15 cm
C. 20 cm
D. 30 cm

Solution

Using the lens maker's formula, the focal length is calculated to be 20 cm.

Correct Answer: C — 20 cm

Q. A biconvex lens has a radius of curvature of 30 cm on both sides. What is the focal length of the lens if the refractive index is 1.5?

A. 10 cm
B. 15 cm
C. 20 cm
D. 25 cm

Solution

Using the lens maker's formula, f = R/(n-1) = 30/(1.5-1) = 30/0.5 = 60 cm.

Correct Answer: B — 15 cm

Q. A biconvex lens has radii of curvature 20 cm and 30 cm. What is the focal length of the lens?

A. 10 cm
B. 15 cm
C. 25 cm
D. 50 cm

Solution

Using the lens maker's formula, the focal length is calculated to be 15 cm.

Correct Answer: B — 15 cm

Q. A bicycle costs $120 after a 20% discount. What was the original price?

A. $140
B. $150
C. $160
D. $180

Solution

Let the original price be x. Then, x - 0.2x = $120, which means 0.8x = $120. Therefore, x = $150.

Correct Answer: C — $160

Q. A bicycle costs $120. If it depreciates by 15% each year, what will be its value after one year?

A. $102
B. $100
C. $110
D. $90

Solution

15% of $120 is $18. Value after one year = $120 - $18 = $102.

Correct Answer: A — $102

Q. A bicycle is bought for $300 and sold for $270. What is the loss percentage?

A. 10%
B. 15%
C. 20%
D. 25%

Solution

Loss = Cost Price - Selling Price = 300 - 270 = 30. Loss Percentage = (Loss/Cost Price) * 100 = (30/300) * 100 = 10%.

Correct Answer: B — 15%

Q. A bicycle is marked at $300. If a discount of 15% is applied, what is the selling price?

A. $255
B. $270
C. $280
D. $290

Solution

Selling Price = Marked Price - (Discount % * Marked Price) = 300 - (0.15 * 300) = 300 - 45 = $255.

Correct Answer: A — $255

Q. A bicycle is marked at $300. If it is sold for $240 after a discount, what is the discount percentage?

A. 20%
B. 25%
C. 30%
D. 15%

Solution

Discount = 300 - 240 = $60. Discount Percentage = (60/300) * 100 = 20%.

Correct Answer: B — 25%

Q. A bicycle is marked at $300. If it is sold for $240 after two successive discounts of 10% and 20%, what is the total discount percentage?

A. 20%
B. 25%
C. 30%
D. 35%

Solution

First discount = 300 * 10/100 = 30. New price = 300 - 30 = 270. Second discount = 270 * 20/100 = 54. Final price = 270 - 54 = 216. Total discount = 300 - 216 = 84. Percentage = (84/300) * 100 = 28%.

Correct Answer: C — 30%

Q. A bicycle is sold for $120 after a discount of 20%. What was the original price?

A. $150
B. $140
C. $160
D. $130

Solution

Let the original price be x. After a 20% discount, Selling Price = x - 0.2x = 0.8x. 0.8x = 120, x = 120/0.8 = 150.

Correct Answer: A — $150

Q. A bicycle is sold for $120 after allowing a discount of 20%. What was the marked price?

A. $140
B. $150
C. $160
D. $180

Solution

Let the marked price be x. Selling Price = Marked Price - Discount = x - 0.2x = 0.8x. 0.8x = 120, so x = 120/0.8 = 150.

Correct Answer: A — $140

Q. A bicycle is sold for $180 after allowing a discount of 10%. What was the marked price?

A. $200
B. $220
C. $250
D. $180

Solution

Let the marked price be x. Selling Price = Marked Price - Discount = x - 0.1x = 0.9x. So, 0.9x = 180. Therefore, x = 180/0.9 = $200.

Correct Answer: A — $200

Q. A bicycle is sold for $300 after a discount of 25%. What was the marked price?

A. $350
B. $375
C. $400
D. $450

Solution

Let the marked price be x. Selling Price = x - 25% of x = 0.75x. Thus, 0.75x = 300, so x = 400.

Correct Answer: B — $375

Q. A bicycle is sold for $300 at a profit of 25%. What was the cost price of the bicycle?

A. $240
B. $250
C. $260
D. $270

Solution

Let the cost price be x. Selling Price = Cost Price + Profit = x + 0.25x = 1.25x. So, 1.25x = 300. Therefore, x = 300/1.25 = 240.

Correct Answer: A — $240

Q. A bicycle's price is decreased by 15% and the new price is $85. What was the original price?

A. $100
B. $90
C. $80
D. $70

Solution

Let the original price be x. Then, x - (15% of x) = 85. This means 0.85x = 85, so x = 85 / 0.85 = $100.

Correct Answer: A — $100

Q. A bicycle's price is increased by 15% to $230. What was the original price?

A. $200
B. $210
C. $220
D. $190

Solution

Let the original price be x. Then, x + 0.15x = 230 => 1.15x = 230 => x = 230 / 1.15 = $200.

Correct Answer: A — $200

Q. A bill is passed in the Lok Sabha with a majority of 300 votes. If the total number of votes cast is 500, what percentage of votes did the bill receive? (2019)

A. 50%
B. 60%
C. 70%
D. 80%

Solution

Percentage of votes = (300/500) * 100 = 60%.

Correct Answer: C — 70%

Q. A bill is passed in the Lok Sabha with a majority of 300 votes. If the total votes cast were 500, what is the percentage of votes in favor of the bill?

A. 50%
B. 60%
C. 70%
D. 80%

Solution

Percentage of votes in favor = (300/500) * 100 = 60%.

Correct Answer: C — 70%

Q. A bill is passed in the Lok Sabha with a majority of 55%. If there are 545 members, how many members voted in favor of the bill?

A. 300
B. 275
C. 250
D. 200

Solution

Members voting in favor = 55% of 545 = 0.55 * 545 = 299.75, rounded to 300.

Correct Answer: B — 275

Q. A bill is passed in the Lok Sabha with a majority of 60%. If 400 members voted, how many members voted against the bill?

A. 160
B. 140
C. 100
D. 120

Solution

Members voting for the bill = 60% of 400 = 240. Members voting against = 400 - 240 = 160.

Correct Answer: A — 160

Q. A bill is passed in the Lok Sabha with a majority of 60%. If there are 545 members in the Lok Sabha, how many members voted in favor of the bill?

A. 327
B. 330
C. 300
D. 350

Solution

Members voting in favor = 60% of 545 = 0.6 * 545 = 327.

Correct Answer: A — 327

Q. A bill is passed in the Lok Sabha with a majority of 60%. If there are 545 members, how many members voted in favor of the bill?

A. 327
B. 330
C. 300
D. 350

Solution

60% of 545 = 0.6 * 545 = 327 members voted in favor.

Correct Answer: A — 327

Q. A bill requires a simple majority to pass in the Lok Sabha. If there are 545 members, how many votes are needed for a simple majority? (2021)

A. 272
B. 273
C. 274
D. 275

Solution

A simple majority is more than half, so (545/2) + 1 = 273 votes are needed.

Correct Answer: B — 273

Q. A biotech company has a growth rate of 15% per year. If the initial investment is $10,000, what will be the value after 3 years?

A. $12,000
B. $13,500
C. $14,000
D. $15,000

Solution

Future Value = 10000 * (1 + 0.15)^3 = 10000 * 1.520875 = $15,208.75.

Correct Answer: B — $13,500

Q. A bird is to a nest as a bee is to a _____.

A. hive
B. flower
C. honey
D. pollen

Solution

Birds build nests for shelter, while bees create hives for their colonies.

Correct Answer: A — hive

Q. A bird is to flying as a fish is to _____.

A. swimming
B. jumping
C. running
D. crawling

Solution

Birds fly, and fish swim; both are actions characteristic of the respective animals.

Correct Answer: A — swimming

Q. A block is at rest on a horizontal surface. If the applied force is gradually increased and reaches the maximum static frictional force, what will happen next?

A. The block will remain at rest
B. The block will start moving
C. The block will accelerate
D. The block will slide back

Solution

Once the applied force exceeds the maximum static frictional force, the block will start moving.

Correct Answer: B — The block will start moving

Q. A block is sliding down a frictionless incline of angle 30 degrees. If the incline has a coefficient of static friction of 0.5, what is the maximum angle at which the block can remain at rest?

A. 30 degrees
B. 45 degrees
C. 60 degrees
D. 90 degrees

Solution

The maximum angle for static friction is given by tan(θ) = μs. Here, θ = tan⁻¹(0.5) which is approximately 26.57 degrees, so the block can remain at rest at angles less than this.

Correct Answer: B — 45 degrees

Q. A block is sliding down a frictionless incline of angle θ. If the incline has a coefficient of static friction μs, what is the maximum angle θ for which the block will not slide?

A. tan⁻¹(μs)
B. sin⁻¹(μs)
C. cos⁻¹(μs)
D. μs

Solution

The block will not slide if the component of gravitational force down the incline is less than or equal to the maximum static friction force, leading to θ = tan⁻¹(μs).

Correct Answer: A — tan⁻¹(μs)

Q. A block is sliding down a frictionless incline. If the incline is now covered with a material that has a coefficient of kinetic friction of 0.3, how does this affect the acceleration of the block?

A. Increases acceleration
B. Decreases acceleration
C. No effect on acceleration
D. Acceleration becomes zero

Solution

The presence of kinetic friction opposes the motion, thus decreasing the acceleration of the block compared to a frictionless incline.

Correct Answer: B — Decreases acceleration

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