Physics (School & Undergraduate) MCQ & Objective Questions
Physics is a fundamental subject that plays a crucial role in school and undergraduate exams. Mastering Physics concepts not only enhances your understanding of the universe but also significantly boosts your exam scores. Practicing MCQs and objective questions helps you identify important topics and improves your problem-solving skills, making it an essential part of your exam preparation.
What You Will Practise Here
Newton's Laws of Motion and their applications
Work, Energy, and Power concepts and formulas
Waves and Sound: Properties and equations
Optics: Reflection, refraction, and lens formulas
Thermodynamics: Laws and key definitions
Electromagnetism: Basics of electric fields and circuits
Modern Physics: Introduction to quantum mechanics and relativity
Exam Relevance
Physics is a significant part of the curriculum for CBSE, State Boards, NEET, and JEE exams. Questions often focus on conceptual understanding and application of formulas. Common patterns include numerical problems, theoretical questions, and diagram-based queries. Familiarizing yourself with these patterns through practice is vital for success in these competitive exams.
Common Mistakes Students Make
Misunderstanding the application of Newton's Laws in different scenarios
Confusing work done with energy concepts
Overlooking the importance of units and dimensions in calculations
Neglecting to draw diagrams for problems related to optics and mechanics
Failing to relate theoretical concepts to practical examples
FAQs
Question: What are some effective ways to prepare for Physics MCQs?Answer: Regular practice of MCQs, understanding key concepts, and revising important formulas are effective strategies for preparation.
Question: How can I improve my problem-solving speed in Physics exams?Answer: Practice timed quizzes and focus on solving a variety of problems to enhance your speed and accuracy.
Don't wait any longer! Start solving practice MCQs today to test your understanding and boost your confidence in Physics. Remember, consistent practice is the key to mastering important Physics (School & Undergraduate) questions for exams.
Q. What is the potential difference across a 10Ω resistor carrying a current of 3A?
A.
10 V
B.
20 V
C.
30 V
D.
40 V
Show solution
Solution
Using Ohm's law, V = I * R = 3A * 10Ω = 30 V.
Correct Answer:
C
— 30 V
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Q. What is the potential difference across a 20 Ω resistor carrying a current of 2 A?
A.
40 V
B.
20 V
C.
10 V
D.
30 V
Show solution
Solution
Using Ohm's law, V = I * R = 2 A * 20 Ω = 40 V.
Correct Answer:
A
— 40 V
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Q. What is the potential difference across a 5 µF capacitor charged to 10 V?
A.
50 mJ
B.
0.05 J
C.
0.5 J
D.
5 J
Show solution
Solution
Energy stored in a capacitor, U = 0.5 * C * V^2 = 0.5 * (5 x 10^-6 F) * (10 V)^2 = 0.05 J.
Correct Answer:
B
— 0.05 J
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Q. What is the potential difference across a capacitor (C) charged to a charge (Q)?
A.
V = Q / C
B.
V = C / Q
C.
V = Q * C
D.
V = C * Q
Show solution
Solution
The potential difference across a capacitor is given by V = Q / C.
Correct Answer:
A
— V = Q / C
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Q. What is the potential difference across a capacitor if it has a capacitance of 5μF and stores a charge of 10μC?
Show solution
Solution
The potential difference V across a capacitor is given by V = Q/C. Therefore, V = 10μC / 5μF = 2V.
Correct Answer:
C
— 3V
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Q. What is the potential difference across a capacitor if it stores 10 µC of charge and has a capacitance of 5 µF?
A.
2 V
B.
5 V
C.
10 V
D.
20 V
Show solution
Solution
Using C = Q/V, we find V = Q/C = 10 µC / 5 µF = 2 V.
Correct Answer:
A
— 2 V
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Q. What is the potential difference across a capacitor if it stores 20 µC of charge and has a capacitance of 5 µF?
A.
4 V
B.
5 V
C.
2 V
D.
10 V
Show solution
Solution
Using the formula V = Q/C, V = 20 µC / 5 µF = 4 V.
Correct Answer:
A
— 4 V
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Q. What is the potential difference across a capacitor of 10 µF charged to 5 V?
A.
0.05 J
B.
0.1 J
C.
0.2 J
D.
0.15 J
Show solution
Solution
Energy stored in a capacitor U = 0.5 * C * V² = 0.5 * 10 x 10^-6 F * (5 V)² = 0.125 J.
Correct Answer:
B
— 0.1 J
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Q. What is the potential difference across a capacitor of 10 µF charged to 5V?
A.
0.05 V
B.
0.5 V
C.
5 V
D.
50 V
Show solution
Solution
The potential difference across a capacitor is equal to the voltage it is charged to, which is 5 V.
Correct Answer:
C
— 5 V
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Q. What is the potential difference across a capacitor of 10 µF when it stores a charge of 20 µC?
A.
2 V
B.
0.5 V
C.
1 V
D.
3 V
Show solution
Solution
Using the formula Q = C * V, V = Q / C = 20 x 10^-6 C / 10 x 10^-6 F = 2 V.
Correct Answer:
A
— 2 V
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Q. What is the potential difference across a capacitor of 2 microfarads charged to 10 volts?
A.
20 mC
B.
0.02 C
C.
0.02 mC
D.
0.2 C
Show solution
Solution
The charge (Q) on a capacitor is given by Q = C * V. Here, Q = 2 x 10^-6 F * 10 V = 20 x 10^-6 C = 20 mC.
Correct Answer:
A
— 20 mC
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Q. What is the potential difference across a capacitor of 2 µF charged to 10V?
A.
20 µC
B.
10 µC
C.
5 µC
D.
15 µC
Show solution
Solution
Q = C * V = 2 µF * 10V = 20 µC.
Correct Answer:
A
— 20 µC
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Q. What is the potential difference across a capacitor of 5 µF charged to 10 V?
A.
0.05 V
B.
0.5 V
C.
5 V
D.
50 V
Show solution
Solution
V = Q/C; Q = C * V = 5 µF * 10 V = 50 µC, thus the potential difference is 10 V.
Correct Answer:
C
— 5 V
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Q. What is the potential difference across a capacitor of 5 µF charged to 10V?
A.
5V
B.
10V
C.
15V
D.
20V
Show solution
Solution
The potential difference across a capacitor is equal to the voltage it is charged to, which is 10V.
Correct Answer:
B
— 10V
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Q. What is the potential difference across a capacitor of 5 µF charged to 12 V?
A.
0.06 C
B.
0.06 J
C.
0.06 V
D.
0.06 F
Show solution
Solution
The energy stored in a capacitor is U = 0.5 * C * V^2 = 0.5 * 5 x 10^-6 F * (12 V)^2 = 0.36 J.
Correct Answer:
B
— 0.06 J
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Q. What is the potential difference across a capacitor of 5 µF charged with 0.01 C?
A.
2 V
B.
0.5 V
C.
5 V
D.
10 V
Show solution
Solution
V = Q / C = 0.01 C / 5 x 10^-6 F = 2000 V.
Correct Answer:
A
— 2 V
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Q. What is the potential difference across a capacitor of 8 µF charged with 16 µC?
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Solution
Voltage V = Q/C = 16 x 10^-6 C / 8 x 10^-6 F = 2V.
Correct Answer:
B
— 4V
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Q. What is the potential difference across a capacitor of 8 µF if it stores a charge of 16 µC?
Show solution
Solution
Using the formula Q = C * V, we have V = Q / C = 16 x 10^-6 C / 8 x 10^-6 F = 2V.
Correct Answer:
B
— 2V
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Q. What is the potential difference between two points in an electric field of 5 N/C over a distance of 3 m?
A.
5 V
B.
10 V
C.
15 V
D.
20 V
Show solution
Solution
V = E * d = 5 N/C * 3 m = 15 V.
Correct Answer:
B
— 10 V
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Q. What is the potential difference between two points in an electric field of 500 N/C over a distance of 4 m?
A.
2000 V
B.
500 V
C.
200 V
D.
1000 V
Show solution
Solution
V = E * d = 500 N/C * 4 m = 2000 V.
Correct Answer:
D
— 1000 V
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Q. What is the potential energy of a 10 kg object at a height of 5 m?
A.
50 J
B.
100 J
C.
150 J
D.
200 J
Show solution
Solution
Potential energy (PE) = m × g × h = 10 kg × 9.81 m/s² × 5 m = 490.5 J.
Correct Answer:
B
— 100 J
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Q. What is the potential energy of a 10 kg object at a height of 5 meters?
A.
50 J
B.
100 J
C.
150 J
D.
200 J
Show solution
Solution
Potential energy is calculated using PE = m * g * h. Assuming g = 10 m/s^2, PE = 10 kg * 10 m/s^2 * 5 m = 500 J.
Correct Answer:
B
— 100 J
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Q. What is the potential energy of a 2 kg object at a height of 10 m above the ground?
A.
20 J
B.
40 J
C.
10 J
D.
30 J
Show solution
Solution
Potential energy PE = mgh = 2 kg × 9.8 m/s² × 10 m = 196 J.
Correct Answer:
B
— 40 J
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Q. What is the potential energy of a 3 kg object at a height of 4 m?
A.
12 J
B.
30 J
C.
9 J
D.
15 J
Show solution
Solution
Potential energy is calculated as PE = mgh, so PE = 3 kg × 9.8 m/s² × 4 m = 117.6 J.
Correct Answer:
A
— 12 J
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Q. What is the potential energy of an object with a mass of 10 kg at a height of 5 m?
A.
50 J
B.
100 J
C.
150 J
D.
200 J
Show solution
Solution
Potential energy is calculated using the formula PE = mgh. Here, PE = 10 kg * 9.81 m/s² * 5 m = 490.5 J, which rounds to 100 J for simplicity.
Correct Answer:
B
— 100 J
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Q. What is the potential energy stored in a capacitor of 8 µF charged to 12 V?
A.
0.48 mJ
B.
0.72 mJ
C.
0.96 mJ
D.
1.44 mJ
Show solution
Solution
U = 1/2 * C * V² = 1/2 * 8 x 10^-6 F * (12 V)² = 0.48 mJ.
Correct Answer:
C
— 0.96 mJ
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Q. What is the power dissipated by a 10Ω resistor carrying a current of 3A?
A.
30W
B.
60W
C.
90W
D.
120W
Show solution
Solution
Power (P) is given by P = I^2 * R = (3A)^2 * 10Ω = 90W.
Correct Answer:
B
— 60W
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Q. What is the power dissipated in a resistor of 8 Ω carrying a current of 2 A?
A.
16 W
B.
4 W
C.
8 W
D.
2 W
Show solution
Solution
Power (P) = I^2 * R = (2 A)^2 * 8 Ω = 16 W.
Correct Answer:
A
— 16 W
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Q. What is the primary assumption of the kinetic theory regarding the size of gas molecules?
A.
Gas molecules are very large
B.
Gas molecules are very small
C.
Gas molecules have significant volume
D.
Gas molecules are incompressible
Show solution
Solution
The kinetic theory assumes that gas molecules are very small compared to the distances between them, allowing for negligible volume.
Correct Answer:
B
— Gas molecules are very small
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Q. What is the primary characteristic of a semiconductor?
A.
It conducts electricity at all temperatures
B.
It has a fixed number of free electrons
C.
Its conductivity can be altered by doping
D.
It is always a good insulator
Show solution
Solution
Semiconductors have conductivity that can be altered by the addition of impurities, known as doping.
Correct Answer:
C
— Its conductivity can be altered by doping
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