Since L is between M and N, and O is opposite L, N must be to the right of O.

The arrangement is O, L, M, N. N is sitting to the right of M.

Since L is to the right of M, and N is opposite L, M must be to the left of N.

If L is to the right of M, then O must be to the left of M, as N is opposite L.

Since L is not next to M, it is possible for P to be next to L, making this statement true in some arrangements.

N is between O and P, so N is next to P. L and M being opposite does not affect this arrangement.

M is between N and O, so O is next to M, making M the answer.

With M opposite N and O to the right of M, P must be to the left of N, completing the arrangement.

The arrangement can be visualized as M-N-P-O-Q-R-S. Therefore, P is sitting opposite N.

With M to the right of N, we can visualize the arrangement. O's position opposite M helps us determine that Q is to the left of N.

Since R is opposite P and P is next to Q, Q is sitting next to R.

Since P is to the right of Q and R is to the left of Q, Q must be in the middle.

If Product B's sales in Q3 were 327 units, a 10% increase would result in approximately 360 units.

The expected growth rate from Q3 (320 units) to Q4 (400 units) is 25%.

Sales in Q2 were 200 + (25% of 200) = 200 + 50 = 250 units.

Product D's sales increased from 200 units in Q1 to 300 units in Q2, which is a 50% increase.

The sales in Q2 were 390 units, which is a 30% increase from Q1.

The sales increased to 390 units in Q2, which is a 30% increase from Q1.

Since R is between S and T, and U is opposite S, T must be next to U.

Since R is to the left of S, R is also to the right of S, making R the one sitting to the right of S.

The arrangement is T, S, R. Thus, S is in the middle.

The intersection of sets A and B includes only the elements that are present in both sets, which are {b, c}.

The number of elements in the union of sets A and B is given by |A ∪ B| = |A| + |B| - |A ∩ B| = 10 + 15 - 5 = 20.

The number of elements in the union of sets A and B is given by |A ∪ B| = |A| + |B| - |A ∩ B| = 10 + 15 - 5 = 20.

The number of elements in the union of sets A and B is given by |A ∪ B| = |A| + |B| - |A ∩ B| = 15 + 10 - 5 = 20.

The number of elements in the union of sets A and B is given by |A ∪ B| = |A| + |B| - |A ∩ B| = 15 + 10 - 5 = 20.

Hybrid sets can include elements that are exclusive to either of the original sets, making them versatile in composition.

By definition, a hybrid set formed from set A and set B must include all elements from set A.

Both 12 and 9 are multiples of 3 and less than 15, but 12 is the first option listed.

The integer 10 is not divisible by 3, hence it is not a member of set C.