Physics (School & Undergraduate)

Electrostatics & Circuits Heat & Thermodynamics Mechanics Modern Physics Waves & Optics

Q. What is the potential difference across a 10Ω resistor carrying a current of 3A?

A. 10 V
B. 20 V
C. 30 V
D. 40 V

Solution

Using Ohm's law, V = I * R = 3A * 10Ω = 30 V.

Correct Answer: C — 30 V

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Q. What is the potential difference across a 20 Ω resistor carrying a current of 2 A?

A. 40 V
B. 20 V
C. 10 V
D. 30 V

Solution

Using Ohm's law, V = I * R = 2 A * 20 Ω = 40 V.

Correct Answer: A — 40 V

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Q. What is the potential difference across a 5 µF capacitor charged to 10 V?

A. 50 mJ
B. 0.05 J
C. 0.5 J
D. 5 J

Solution

Energy stored in a capacitor, U = 0.5 * C * V^2 = 0.5 * (5 x 10^-6 F) * (10 V)^2 = 0.05 J.

Correct Answer: B — 0.05 J

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Q. What is the potential difference across a capacitor (C) charged to a charge (Q)?

A. V = Q / C
B. V = C / Q
C. V = Q * C
D. V = C * Q

Solution

The potential difference across a capacitor is given by V = Q / C.

Correct Answer: A — V = Q / C

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Q. What is the potential difference across a capacitor if it has a capacitance of 5μF and stores a charge of 10μC?

A. 1V
B. 2V
C. 3V
D. 4V

Solution

The potential difference V across a capacitor is given by V = Q/C. Therefore, V = 10μC / 5μF = 2V.

Correct Answer: C — 3V

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Q. What is the potential difference across a capacitor if it stores 10 µC of charge and has a capacitance of 5 µF?

A. 2 V
B. 5 V
C. 10 V
D. 20 V

Solution

Using C = Q/V, we find V = Q/C = 10 µC / 5 µF = 2 V.

Correct Answer: A — 2 V

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Q. What is the potential difference across a capacitor if it stores 20 µC of charge and has a capacitance of 5 µF?

A. 4 V
B. 5 V
C. 2 V
D. 10 V

Solution

Using the formula V = Q/C, V = 20 µC / 5 µF = 4 V.

Correct Answer: A — 4 V

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Q. What is the potential difference across a capacitor of 10 µF charged to 5 V?

A. 0.05 J
B. 0.1 J
C. 0.2 J
D. 0.15 J

Solution

Energy stored in a capacitor U = 0.5 * C * V² = 0.5 * 10 x 10^-6 F * (5 V)² = 0.125 J.

Correct Answer: B — 0.1 J

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Q. What is the potential difference across a capacitor of 10 µF charged to 5V?

A. 0.05 V
B. 0.5 V
C. 5 V
D. 50 V

Solution

The potential difference across a capacitor is equal to the voltage it is charged to, which is 5 V.

Correct Answer: C — 5 V

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Q. What is the potential difference across a capacitor of 10 µF when it stores a charge of 20 µC?

A. 2 V
B. 0.5 V
C. 1 V
D. 3 V

Solution

Using the formula Q = C * V, V = Q / C = 20 x 10^-6 C / 10 x 10^-6 F = 2 V.

Correct Answer: A — 2 V

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Q. What is the potential difference across a capacitor of 2 microfarads charged to 10 volts?

A. 20 mC
B. 0.02 C
C. 0.02 mC
D. 0.2 C

Solution

The charge (Q) on a capacitor is given by Q = C * V. Here, Q = 2 x 10^-6 F * 10 V = 20 x 10^-6 C = 20 mC.

Correct Answer: A — 20 mC

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Q. What is the potential difference across a capacitor of 2 µF charged to 10V?

A. 20 µC
B. 10 µC
C. 5 µC
D. 15 µC

Solution

Q = C * V = 2 µF * 10V = 20 µC.

Correct Answer: A — 20 µC

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Q. What is the potential difference across a capacitor of 5 µF charged to 10 V?

A. 0.05 V
B. 0.5 V
C. 5 V
D. 50 V

Solution

V = Q/C; Q = C * V = 5 µF * 10 V = 50 µC, thus the potential difference is 10 V.

Correct Answer: C — 5 V

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Q. What is the potential difference across a capacitor of 5 µF charged to 10V?

A. 5V
B. 10V
C. 15V
D. 20V

Solution

The potential difference across a capacitor is equal to the voltage it is charged to, which is 10V.

Correct Answer: B — 10V

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Q. What is the potential difference across a capacitor of 5 µF charged to 12 V?

A. 0.06 C
B. 0.06 J
C. 0.06 V
D. 0.06 F

Solution

The energy stored in a capacitor is U = 0.5 * C * V^2 = 0.5 * 5 x 10^-6 F * (12 V)^2 = 0.36 J.

Correct Answer: B — 0.06 J

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Q. What is the potential difference across a capacitor of 5 µF charged with 0.01 C?

A. 2 V
B. 0.5 V
C. 5 V
D. 10 V

Solution

V = Q / C = 0.01 C / 5 x 10^-6 F = 2000 V.

Correct Answer: A — 2 V

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Q. What is the potential difference across a capacitor of 8 µF charged with 16 µC?

A. 2V
B. 4V
C. 8V
D. 12V

Solution

Voltage V = Q/C = 16 x 10^-6 C / 8 x 10^-6 F = 2V.

Correct Answer: B — 4V

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Q. What is the potential difference across a capacitor of 8 µF if it stores a charge of 16 µC?

A. 1V
B. 2V
C. 3V
D. 4V

Solution

Using the formula Q = C * V, we have V = Q / C = 16 x 10^-6 C / 8 x 10^-6 F = 2V.

Correct Answer: B — 2V

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Q. What is the potential difference between two points in an electric field of 5 N/C over a distance of 3 m?

A. 5 V
B. 10 V
C. 15 V
D. 20 V

Solution

V = E * d = 5 N/C * 3 m = 15 V.

Correct Answer: B — 10 V

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Q. What is the potential difference between two points in an electric field of 500 N/C over a distance of 4 m?

A. 2000 V
B. 500 V
C. 200 V
D. 1000 V

Solution

V = E * d = 500 N/C * 4 m = 2000 V.

Correct Answer: D — 1000 V

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Q. What is the potential energy of a 10 kg object at a height of 5 m?

A. 50 J
B. 100 J
C. 150 J
D. 200 J

Solution

Potential energy (PE) = m × g × h = 10 kg × 9.81 m/s² × 5 m = 490.5 J.

Correct Answer: B — 100 J

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Q. What is the potential energy of a 10 kg object at a height of 5 meters?

A. 50 J
B. 100 J
C. 150 J
D. 200 J

Solution

Potential energy is calculated using PE = m * g * h. Assuming g = 10 m/s^2, PE = 10 kg * 10 m/s^2 * 5 m = 500 J.

Correct Answer: B — 100 J

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Q. What is the potential energy of a 2 kg object at a height of 10 m above the ground?

A. 20 J
B. 40 J
C. 10 J
D. 30 J

Solution

Potential energy PE = mgh = 2 kg × 9.8 m/s² × 10 m = 196 J.

Correct Answer: B — 40 J

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Q. What is the potential energy of a 3 kg object at a height of 4 m?

A. 12 J
B. 30 J
C. 9 J
D. 15 J

Solution

Potential energy is calculated as PE = mgh, so PE = 3 kg × 9.8 m/s² × 4 m = 117.6 J.

Correct Answer: A — 12 J

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Q. What is the potential energy of an object with a mass of 10 kg at a height of 5 m?

A. 50 J
B. 100 J
C. 150 J
D. 200 J

Solution

Potential energy is calculated using the formula PE = mgh. Here, PE = 10 kg * 9.81 m/s² * 5 m = 490.5 J, which rounds to 100 J for simplicity.

Correct Answer: B — 100 J

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Q. What is the potential energy stored in a capacitor of 8 µF charged to 12 V?

A. 0.48 mJ
B. 0.72 mJ
C. 0.96 mJ
D. 1.44 mJ

Solution

U = 1/2 * C * V² = 1/2 * 8 x 10^-6 F * (12 V)² = 0.48 mJ.

Correct Answer: C — 0.96 mJ

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Q. What is the power dissipated by a 10Ω resistor carrying a current of 3A?

A. 30W
B. 60W
C. 90W
D. 120W

Solution

Power (P) is given by P = I^2 * R = (3A)^2 * 10Ω = 90W.

Correct Answer: B — 60W

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Q. What is the power dissipated in a resistor of 8 Ω carrying a current of 2 A?

A. 16 W
B. 4 W
C. 8 W
D. 2 W

Solution

Power (P) = I^2 * R = (2 A)^2 * 8 Ω = 16 W.

Correct Answer: A — 16 W

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Q. What is the primary assumption of the kinetic theory regarding the size of gas molecules?

A. Gas molecules are very large
B. Gas molecules are very small
C. Gas molecules have significant volume
D. Gas molecules are incompressible

Solution

The kinetic theory assumes that gas molecules are very small compared to the distances between them, allowing for negligible volume.

Correct Answer: B — Gas molecules are very small

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Q. What is the primary characteristic of a semiconductor?

A. It conducts electricity at all temperatures
B. It has a fixed number of free electrons
C. Its conductivity can be altered by doping
D. It is always a good insulator

Solution

Semiconductors have conductivity that can be altered by the addition of impurities, known as doping.

Correct Answer: C — Its conductivity can be altered by doping

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Physics (School & Undergraduate)

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