Q. For the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g), what happens to the equilibrium if the volume of the container is decreased? (2022)
A.
Equilibrium shifts to the left
B.
Equilibrium shifts to the right
C.
No effect on equilibrium
D.
Equilibrium constant changes
Solution
Decreasing the volume increases the pressure, and according to Le Chatelier's principle, the equilibrium will shift towards the side with fewer moles of gas, which is the right side (2 moles of SO3).
Correct Answer:
B
— Equilibrium shifts to the right
Q. For the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g), what happens to the equilibrium position if SO3 is removed from the system? (2023)
A.
The equilibrium shifts to the left
B.
The equilibrium shifts to the right
C.
The equilibrium remains unchanged
D.
The reaction stops
Solution
Removing SO3 will decrease its concentration, causing the system to shift to the right to produce more SO3 in order to re-establish equilibrium, according to Le Chatelier's principle.
Correct Answer:
B
— The equilibrium shifts to the right
Q. For the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g), what is the effect of decreasing the volume? (2021)
A.
The equilibrium shifts to the left.
B.
The equilibrium shifts to the right.
C.
The equilibrium remains unchanged.
D.
The reaction stops.
Solution
Decreasing the volume increases the pressure, and according to Le Chatelier's principle, the equilibrium will shift towards the side with fewer moles of gas, which is the right side in this case.
Correct Answer:
B
— The equilibrium shifts to the right.
Q. For the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g), what will happen if the volume of the container is increased? (2020) 2020
A.
Equilibrium shifts to the right
B.
Equilibrium shifts to the left
C.
No change in equilibrium
D.
Reaction stops
Solution
Increasing the volume decreases the pressure, and according to Le Chatelier's principle, the equilibrium will shift to the side with more moles of gas, which is the left side in this case.
Correct Answer:
B
— Equilibrium shifts to the left
Q. For the reaction A(g) ⇌ B(g), if the concentration of B is increased, what will happen to the concentration of A at equilibrium?
A.
Increase
B.
Decrease
C.
Remain the same
D.
Cannot be determined
Solution
According to Le Chatelier's principle, increasing the concentration of a product will shift the equilibrium to the left, decreasing the concentration of A.
Q. For the reaction CO(g) + 2H2(g) ⇌ CH3OH(g), what will happen if the pressure is increased?
A.
Equilibrium shifts to the left
B.
Equilibrium shifts to the right
C.
No change in equilibrium
D.
Equilibrium constant increases
Solution
Increasing pressure favors the side with fewer moles of gas. In this case, the right side has 1 mole of CH3OH compared to 3 moles on the left, so the equilibrium shifts to the right.
Correct Answer:
B
— Equilibrium shifts to the right
Q. For the reaction N2(g) + 3H2(g) ⇌ 2NH3(g), if the concentration of NH3 is increased, what will happen to the equilibrium?
A.
Shift to the right
B.
Shift to the left
C.
No change
D.
Increase the rate of reaction
Solution
According to Le Chatelier's principle, increasing the concentration of a product (NH3) will shift the equilibrium to the left to counteract the change.
Q. For the reaction N2(g) + 3H2(g) ⇌ 2NH3(g), what happens if the volume of the container is decreased?
A.
Equilibrium shifts to the left
B.
Equilibrium shifts to the right
C.
No change in equilibrium
D.
Equilibrium constant changes
Solution
Decreasing the volume increases the pressure, and according to Le Chatelier's principle, the equilibrium will shift towards the side with fewer moles of gas, which is the right side in this case.
Correct Answer:
B
— Equilibrium shifts to the right
Q. For the reaction N2(g) + 3H2(g) ⇌ 2NH3(g), what happens to the equilibrium if the volume of the container is decreased? (2020)
A.
Equilibrium shifts to the right
B.
Equilibrium shifts to the left
C.
No change in equilibrium
D.
Equilibrium shifts to the side with more moles
Solution
Decreasing the volume increases the pressure, and according to Le Chatelier's principle, the equilibrium will shift to the side with fewer moles of gas, which is the right side in this case.
Correct Answer:
A
— Equilibrium shifts to the right
Q. For the reaction N2(g) + 3H2(g) ⇌ 2NH3(g), what happens to the equilibrium position if the pressure is increased?
A.
Shifts to the left
B.
Shifts to the right
C.
No change
D.
Depends on temperature
Solution
Increasing the pressure shifts the equilibrium towards the side with fewer moles of gas. In this case, the right side has 2 moles of NH3 compared to 4 moles of reactants.
Q. For the reaction N2(g) + 3H2(g) ⇌ 2NH3(g), what happens to the equilibrium position if the volume of the container is decreased?
A.
Equilibrium shifts to the left
B.
Equilibrium shifts to the right
C.
No change in equilibrium
D.
Equilibrium shifts in both directions
Solution
According to Le Chatelier's principle, decreasing the volume increases the pressure, and the equilibrium will shift towards the side with fewer moles of gas, which is the right side (2 moles of NH3).
Correct Answer:
B
— Equilibrium shifts to the right
Q. For the reaction: 2A(g) + B(g) ⇌ 3C(g), if the volume of the container is decreased, what will be the effect on the equilibrium? (2022)
A.
Shift to the left
B.
Shift to the right
C.
No change
D.
Increase in temperature
Solution
Decreasing the volume increases the pressure, and the equilibrium will shift towards the side with fewer moles of gas. Here, it shifts to the right, producing more C.
Q. For the reaction: 2A(g) + B(g) ⇌ 3C(g), what is the correct expression for the equilibrium constant Kc? (2021)
A.
[C]^3 / ([A]^2[B])
B.
[A]^2[B] / [C]^3
C.
[C]^3 / [A]^2
D.
[B] / [C]^3
Solution
The equilibrium constant Kc is given by the expression Kc = [C]^3 / ([A]^2[B]), where the concentrations are raised to the power of their coefficients.
Q. For the reaction: 2SO2(g) + O2(g) ⇌ 2SO3(g), what happens to the equilibrium position if the volume of the container is decreased? (2020)
A.
Shifts to the left
B.
Shifts to the right
C.
No change
D.
Depends on temperature
Solution
Decreasing the volume increases the pressure, and according to Le Chatelier's principle, the equilibrium will shift towards the side with fewer moles of gas, which is the right side in this case.
Q. For the reaction: 2SO2(g) + O2(g) ⇌ 2SO3(g), what will happen if the volume of the container is increased? (2020)
A.
Equilibrium shifts to the right
B.
Equilibrium shifts to the left
C.
No change in equilibrium
D.
Equilibrium shifts to the center
Solution
Increasing the volume decreases the pressure, and according to Le Chatelier's principle, the equilibrium will shift to the side with more moles of gas, which is the left side in this case.
Correct Answer:
B
— Equilibrium shifts to the left
