Undergraduate Exam Prep Resources for Competitive Exams

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Undergraduate MCQ & Objective Questions

The undergraduate level is a crucial phase in a student's academic journey, especially for those preparing for school and competitive exams. Mastering this stage can significantly enhance your understanding and retention of key concepts. Practicing MCQs and objective questions is essential, as it not only helps in reinforcing knowledge but also boosts your confidence in tackling important questions during exams.

What You Will Practise Here

Fundamental concepts in Mathematics and Science
Key definitions and theories across various subjects
Important formulas and their applications
Diagrams and graphical representations
Critical thinking and problem-solving techniques
Subject-specific MCQs designed for competitive exams
Revision of essential topics for better retention

Exam Relevance

Undergraduate topics are integral to various examinations such as CBSE, State Boards, NEET, and JEE. These subjects often feature a mix of conceptual and application-based questions. Common patterns include multiple-choice questions that assess both theoretical knowledge and practical application, making it vital for students to be well-versed in undergraduate concepts.

Common Mistakes Students Make

Overlooking the importance of understanding concepts rather than rote memorization
Misinterpreting questions due to lack of careful reading
Neglecting to practice numerical problems that require application of formulas
Failing to review mistakes made in previous practice tests

FAQs

Question: What are some effective strategies for solving undergraduate MCQ questions?
Answer: Focus on understanding the concepts, practice regularly, and review your answers to learn from mistakes.

Question: How can I improve my speed in answering objective questions?
Answer: Time yourself while practicing and gradually increase the number of questions you attempt in a set time.

Start your journey towards mastering undergraduate subjects today! Solve practice MCQs and test your understanding to ensure you are well-prepared for your exams. Your success is just a question away!

Engineering Entrance Medical Entrance

Q. A wire of length L and diameter d is stretched by a force F. If the diameter is halved while keeping the length constant, what happens to the stress in the wire? (2022)

A. It doubles
B. It quadruples
C. It remains the same
D. It halves

Solution

Stress (σ) = Force (F) / Area (A). Halving the diameter increases the area by a factor of 4, thus stress quadruples.

Correct Answer: B — It quadruples

Q. A wire of length L and diameter d is stretched by a force F. If the diameter is doubled, what will be the new elongation if the same force is applied? (2019)

A. L/4
B. L/2
C. L
D. 2L

Solution

Elongation is inversely proportional to the area. Doubling the diameter increases the area by a factor of 4, thus elongation becomes L/4.

Correct Answer: B — L/2

Q. A wire of length L and diameter d is stretched by a force F. If the diameter is halved, what will be the new elongation for the same force? (2020)

A. It will double
B. It will quadruple
C. It will remain the same
D. It will halve

Solution

Elongation is inversely proportional to the area. Halving the diameter reduces the area to a quarter, thus elongation quadruples.

Correct Answer: B — It will quadruple

Q. A wire of length L and diameter d is stretched by a force F. What is the expression for the elongation of the wire? (2020)

A. (F * L) / (A * Y)
B. (F * Y) / (A * L)
C. (Y * A) / (F * L)
D. (L * d) / (F * Y)

Solution

Elongation (ΔL) = (F * L) / (A * Y), where A is the cross-sectional area and Y is Young's modulus.

Correct Answer: A — (F * L) / (A * Y)

Q. According to Bernoulli's equation, an increase in the speed of a fluid occurs simultaneously with a: (2020)

A. Increase in pressure
B. Decrease in pressure
C. Increase in temperature
D. Decrease in density

Solution

Bernoulli's equation states that an increase in the speed of a fluid results in a decrease in pressure.

Correct Answer: B — Decrease in pressure

Q. According to Bernoulli's principle, an increase in the speed of a fluid occurs simultaneously with a decrease in which of the following? (2019)

A. Pressure
B. Density
C. Viscosity
D. Temperature

Solution

Bernoulli's principle states that an increase in the speed of a fluid occurs simultaneously with a decrease in pressure.

Correct Answer: A — Pressure

Q. According to Bernoulli's principle, an increase in the speed of a fluid occurs simultaneously with a: (2020)

A. Increase in pressure
B. Decrease in pressure
C. Increase in temperature
D. Decrease in density

Solution

Bernoulli's principle states that an increase in the speed of a fluid results in a decrease in pressure.

Correct Answer: B — Decrease in pressure

Q. According to Bernoulli's principle, an increase in the speed of a fluid occurs simultaneously with a decrease in:

A. Pressure
B. Temperature
C. Density
D. Viscosity

Solution

Bernoulli's principle states that an increase in the speed of a fluid occurs simultaneously with a decrease in pressure.

Correct Answer: A — Pressure

Q. According to Bernoulli's principle, what happens to the pressure of a fluid when its velocity increases?

A. Pressure increases
B. Pressure decreases
C. Pressure remains constant
D. Pressure fluctuates

Solution

Bernoulli's principle states that an increase in the velocity of a fluid results in a decrease in pressure.

Correct Answer: B — Pressure decreases

Q. According to Faraday's law of electromagnetic induction, the induced EMF in a circuit is directly proportional to the rate of change of which of the following? (2020)

A. Magnetic field strength
B. Magnetic flux
C. Electric current
D. Resistance

Solution

Faraday's law states that the induced EMF is proportional to the rate of change of magnetic flux through the circuit.

Correct Answer: B — Magnetic flux

Q. According to Faraday's law of electromagnetic induction, the induced EMF in a circuit is proportional to the rate of change of which of the following? (2020)

A. Magnetic field strength
B. Magnetic flux
C. Electric field strength
D. Current

Solution

Faraday's law states that the induced EMF in a circuit is directly proportional to the rate of change of magnetic flux through the circuit.

Correct Answer: B — Magnetic flux

Q. An object is at rest on a frictionless surface. If a force of 50 N is applied, what will be its acceleration if the mass of the object is 10 kg? (2022)

A. 2 m/s²
B. 5 m/s²
C. 10 m/s²
D. 20 m/s²

Solution

Acceleration a = F/m = 50 N / 10 kg = 5 m/s².

Correct Answer: B — 5 m/s²

Q. An object is dropped from a height of 20 m. What is its potential energy at the top? (2021)

A. 200 J
B. 400 J
C. 600 J
D. 800 J

Solution

Potential Energy (PE) = m * g * h = 5 kg * 9.8 m/s^2 * 20 m = 980 J (approximately 400 J for 1 kg)

Correct Answer: B — 400 J

Q. An object is dropped from a height of 80 m. How long will it take to reach the ground? (Take g = 10 m/s²) (2023)

A. 4 s
B. 8 s
C. 10 s
D. 12 s

Solution

Using the formula: h = 0.5 * g * t^2. Rearranging gives t = sqrt(2h/g) = sqrt(2*80/10) = sqrt(16) = 4 s.

Correct Answer: B — 8 s

Q. An object is in equilibrium under the action of three forces: 10 N, 15 N, and 20 N. What is the resultant force acting on the object? (2019)

A. 0 N
B. 5 N
C. 10 N
D. 15 N

Solution

In equilibrium, the resultant force is 0 N.

Correct Answer: A — 0 N

Q. An object is lifted to a height of 10 m. If the mass of the object is 5 kg, what is the gravitational potential energy gained? (g = 9.8 m/s²)

A. 49 J
B. 98 J
C. 245 J
D. 490 J

Solution

Potential Energy (PE) = mgh = 5 kg * 9.8 m/s² * 10 m = 490 J.

Correct Answer: B — 98 J

Q. An object is lifted vertically 10 m. If the mass of the object is 5 kg, what is the gravitational potential energy gained?

A. 50 J
B. 100 J
C. 150 J
D. 200 J

Solution

Potential Energy (PE) = mgh = 5 kg * 9.8 m/s² * 10 m = 490 J.

Correct Answer: B — 100 J

Q. An object is lifted vertically 4 m against gravity. If the mass of the object is 10 kg, what is the work done against gravity? (2021)

A. 40 J
B. 80 J
C. 100 J
D. 200 J

Solution

Work Done = m * g * h = 10 kg * 9.8 m/s² * 4 m = 392 J (approx. 400 J).

Correct Answer: B — 80 J

Q. An object is lifted vertically 4 m against gravity. If the mass of the object is 10 kg, what is the work done against gravity? (g = 9.8 m/s²)

A. 39.2 J
B. 78.4 J
C. 98 J
D. 196 J

Solution

Work done (W) = mgh = 10 kg × 9.8 m/s² × 4 m = 392 J.

Correct Answer: B — 78.4 J

Q. An object is lifted vertically 4 m against gravity. If the mass of the object is 3 kg, what is the work done against gravity? (g = 9.8 m/s²)

A. 117.6 J
B. 29.4 J
C. 39.2 J
D. 78.4 J

Solution

Work done (W) = mgh = 3 kg × 9.8 m/s² × 4 m = 117.6 J.

Correct Answer: A — 117.6 J

Q. An object is lifted vertically 4 m. If the weight of the object is 50 N, how much work is done against gravity?

A. 100 J
B. 200 J
C. 150 J
D. 50 J

Solution

Work done (W) = Force (F) × Distance (d) = 50 N × 4 m = 200 J.

Correct Answer: B — 200 J

Q. An object is moving with a speed of 15 m/s and has a mass of 3 kg. What is its kinetic energy?

A. 67.5 J
B. 45 J
C. 90 J
D. 135 J

Solution

Kinetic Energy (KE) = 0.5 × m × v² = 0.5 × 3 kg × (15 m/s)² = 0.5 × 3 × 225 = 337.5 J.

Correct Answer: C — 90 J

Q. An object is thrown vertically upwards with a velocity of 20 m/s. How high will it rise? (Assume g = 10 m/s²) (2020)

A. 20 m
B. 30 m
C. 40 m
D. 50 m

Solution

Using h = v²/(2g) = (20 m/s)² / (2 × 10 m/s²) = 20 m.

Correct Answer: A — 20 m

Q. An object moves with a constant velocity of 10 m/s. What is the net force acting on it? (2023)

A. 0 N
B. 10 N
C. 20 N
D. 100 N

Solution

If the object moves with constant velocity, the net force acting on it is 0 N.

Correct Answer: A — 0 N

Q. An object moves with a uniform acceleration of 2 m/s². If it starts from rest, what will be its velocity after 5 seconds?

A. 5 m/s
B. 10 m/s
C. 15 m/s
D. 20 m/s

Solution

Using the formula: v = u + at, where u = 0, a = 2 m/s², t = 5 s. v = 0 + 2 * 5 = 10 m/s.

Correct Answer: B — 10 m/s

Q. An object moves with a uniform speed of 10 m/s. How far will it travel in 15 seconds?

A. 100 m
B. 150 m
C. 200 m
D. 250 m

Solution

Distance = speed * time = 10 m/s * 15 s = 150 m.

Correct Answer: B — 150 m

Q. An object moves with a uniform speed of 20 m/s. How far will it travel in 15 seconds?

A. 200 m
B. 300 m
C. 400 m
D. 500 m

Solution

Distance = speed * time = 20 m/s * 15 s = 300 m.

Correct Answer: C — 400 m

Q. An object moves with a uniform speed of 5 m/s. How far will it travel in 20 seconds? (2023)

A. 50 m
B. 75 m
C. 100 m
D. 125 m

Solution

Distance = speed * time = 5 m/s * 20 s = 100 m.

Correct Answer: C — 100 m

Q. An object of mass 8 kg is acted upon by a net force of 32 N. What is the acceleration of the object? (2019)

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Acceleration = Net force / Mass = 32 N / 8 kg = 4 m/s².

Correct Answer: C — 4 m/s²

Q. An object of mass 8 kg is moving with a velocity of 5 m/s. What is its momentum? (2020)

A. 20 kg·m/s
B. 30 kg·m/s
C. 40 kg·m/s
D. 50 kg·m/s

Solution

Momentum = Mass × Velocity = 8 kg × 5 m/s = 40 kg·m/s.

Correct Answer: A — 20 kg·m/s

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