Arithmetic Aptitude is a crucial component of many school and competitive exams in India. Mastering this subject not only enhances your mathematical skills but also boosts your confidence in tackling objective questions. Regular practice with MCQs and practice questions helps you identify important questions and improves your exam preparation, ensuring you score better in your assessments.
What You Will Practise Here
Basic arithmetic operations: addition, subtraction, multiplication, and division
Fractions and decimals: conversion and operations
Percentage calculations: increase, decrease, and comparisons
Ratio and proportion: understanding and application
Averages: calculating and interpreting data
Simple and compound interest: formulas and problem-solving
Time, speed, and distance: concepts and related problems
Exam Relevance
Arithmetic Aptitude is a significant topic in various examinations, including CBSE, State Boards, NEET, and JEE. Students can expect questions that test their understanding of basic concepts, calculations, and problem-solving abilities. Common question patterns include direct application of formulas, word problems, and data interpretation, making it essential to practice thoroughly.
Common Mistakes Students Make
Misunderstanding the question requirements, leading to incorrect answers.
Overlooking the order of operations in complex calculations.
Confusing percentages with fractions, resulting in calculation errors.
Neglecting to convert units properly in time, speed, and distance problems.
Failing to apply the correct formula for interest calculations.
FAQs
Question: What are some effective strategies for solving Arithmetic Aptitude MCQs? Answer: Practice regularly, understand the underlying concepts, and familiarize yourself with different question types to enhance your speed and accuracy.
Question: How can I improve my speed in solving Arithmetic Aptitude questions? Answer: Time yourself while practicing and focus on shortcuts and tricks that can simplify calculations.
Start your journey towards mastering Arithmetic Aptitude today! Solve practice MCQs and test your understanding to ensure you are well-prepared for your exams. Your success is just a question away!
Q. A mixture of two types of tea contains 40% of tea A and 60% of tea B. If 20 liters of tea B is added, what will be the new percentage of tea A if the total mixture becomes 100 liters?
A.
30%
B.
35%
C.
40%
D.
45%
Solution
Initial volume of tea A = 0.4 * 80 = 32 liters. Total volume after adding tea B = 100 liters. New percentage of tea A = (32/100) * 100 = 32%.
Q. A mixture of two types of tea costs $5 per kg and $7 per kg. If 10 kg of the first type is mixed with 5 kg of the second type, what is the cost per kg of the mixture?
A.
$5.50
B.
$6.00
C.
$6.50
D.
$7.00
Solution
Total cost = (10 * 5) + (5 * 7) = 50 + 35 = $85. Total weight = 10 + 5 = 15 kg. Cost per kg = 85/15 = $5.67.
Q. A mother is 4 times as old as her daughter. After 8 years, the mother will be twice as old as her daughter. What is the present age of the daughter?
A.
4
B.
8
C.
12
D.
16
Solution
Let the daughter's age be x. Then the mother's age is 4x. In 8 years, 4x + 8 = 2(x + 8). Solving gives x = 8.
Q. A number is increased by 20% and then decreased by 20%. What is the net change in the number?
A.
0%
B.
4%
C.
5%
D.
10%
Solution
Let the original number be 100. After a 20% increase, it becomes 120. After a 20% decrease, it becomes 120 - 24 = 96. The net change is (96 - 100)/100 * 100% = -4%.
Q. A number is increased by 20% and then decreased by 20%. What is the net change?
A.
0%
B.
4%
C.
5%
D.
10%
Solution
Let the number be 100. After a 20% increase, it becomes 120. After a 20% decrease, it becomes 120 - 24 = 96. The net change is (96 - 100)/100 * 100% = -4%.
Q. A person has a total of $5000 in two accounts. If the first account earns 4% interest and the second earns 6%, how much is in the first account if the total interest earned in one year is $240?
A.
$2000
B.
$3000
C.
$2500
D.
$1500
Solution
Let the amount in the first account be x. Then, amount in the second account = 5000 - x. Interest from first account = 0.04x, from second = 0.06(5000 - x). Total interest = 0.04x + 0.06(5000 - x) = 240. Solving gives x = $2500.
