Vth = Vsource * (Rload / (Rseries + Rload)) = 10V * (4Ω / (2Ω + 4Ω)) = 10V * (4/6) = 7.5V.

The Thevenin equivalent voltage is the open-circuit voltage across the terminals, which is equal to the battery voltage, 20V.

The voltage across the 5Ω resistor is half of the total voltage due to the voltage divider rule: V_th = 10V * (5Ω / (5Ω + 10Ω)) = 10V * (1/3) = 3.33V.

Vth = Vsource * (Rload / (Rseries + Rload)); assuming Rload = 10Ω, Vth = 15V * (10Ω / (5Ω + 10Ω)) = 10V.

The Thevenin equivalent voltage is equal to the open-circuit voltage, which is 15V.

The Thevenin equivalent voltage is the open-circuit voltage across the load resistor when it is removed from the circuit.

The Thevenin equivalent voltage is the voltage across the load resistor, which can be found using voltage division: V_load = V_source * (R_load / (R_series + R_load)) = 12 V * (2 / (4 + 2)) = 8 V.

The Thevenin equivalent voltage is the same as the source voltage, which is 12 V.

The Thevenin equivalent voltage is the open-circuit voltage, which is the source voltage, 12V.

The Thevenin equivalent voltage is the open-circuit voltage across terminals A and B, which is equal to the source voltage, 12V.

The voltage across the 10Ω resistor is V = (10V * 10Ω) / (5Ω + 10Ω) = 6.67V.

Using voltage division, Vth = 20V * (5Ω / (10Ω + 5Ω)) = 20V * (5/15) = 6.67V, rounded to 15V.

The Thevenin equivalent voltage is the open-circuit voltage across the load, which is the same as the source voltage in this case, 10V.

The Thevenin voltage is the voltage across the load resistor. Using voltage division, V_load = 12V * (2Ω / (4Ω + 2Ω)) = 12V * (1/3) = 4V.

Using voltage division: Vth = 20V * (10Ω / (5Ω + 10Ω)) = 20V * (10/15) = 13.33V.

The Thevenin equivalent voltage is equal to the open-circuit voltage, which is 15 V.

The Thevenin equivalent voltage is defined as the open-circuit voltage measured across the terminals of the circuit.

The Thevenin equivalent voltage is the open-circuit voltage, which is 10 V in this case.

Thevenin equivalent voltage is the open-circuit voltage, which is 10V across the 5Ω resistor.

The time constant for a second-order system can be approximated as 1/(damping ratio * natural frequency), which is 1/(0.5 * 2) = 1.

The time constant T of a first-order system is the coefficient of s in the denominator. Here, T = 1/2 = 2.

The time constant T is given by the coefficient of s in the denominator, which is 2. Therefore, T = 5/2 = 0.4.

The time constant (T) is the coefficient of s in the denominator, which is 1/2, thus T = 2 seconds.

The formula for total capacitance in series is 1/C_total = 1/C1 + 1/C2. Thus, 1/C_total = 1/4 + 1/6 = 5/12, so C_total = 12/5 = 2.4μF.

Total resistance R = 4Ω + 6Ω + 12Ω = 22Ω. Using Ohm's Law, I = V / R = 12V / 22Ω ≈ 0.545 A.

Total resistance R = 8Ω + 4Ω = 12Ω. Using Ohm's Law, I = V / R = 24V / 12Ω = 2 A.

In a series circuit, total impedance Z = R + jX, so Z = 4 + j3, which has a magnitude of 7 ohms.

In a series circuit, total impedance Z = R + jX = 4Ω + j3Ω, which gives a magnitude of √(4² + 3²) = 5Ω.

Power can be calculated using P = V * I. Thus, P = 12V * 2A = 24W.

Power P = V^2 / R = 24V^2 / 6Ω = 96W.