The JEE Main exam is a crucial step for students aspiring to enter prestigious engineering colleges in India. It tests not only knowledge but also the ability to apply concepts effectively. Practicing MCQs and objective questions is essential for scoring better, as it helps in familiarizing students with the exam pattern and enhances their problem-solving skills. Engaging with practice questions allows students to identify important questions and strengthen their exam preparation.
What You Will Practise Here
Fundamental concepts of Physics, Chemistry, and Mathematics
Key formulas and their applications in problem-solving
Important definitions and theories relevant to JEE Main
Diagrams and graphical representations for better understanding
Numerical problems and their step-by-step solutions
Previous years' JEE Main questions for real exam experience
Time management strategies while solving MCQs
Exam Relevance
The topics covered in JEE Main are not only significant for the JEE exam but also appear in various CBSE and State Board examinations. Many concepts are shared with the NEET syllabus, making them relevant across multiple competitive exams. Common question patterns include conceptual applications, numerical problems, and theoretical questions that assess a student's understanding of core subjects.
Common Mistakes Students Make
Misinterpreting the question stem, leading to incorrect answers
Neglecting units in numerical problems, which can change the outcome
Overlooking negative marking and not managing time effectively
Relying too heavily on rote memorization instead of understanding concepts
Failing to review and analyze mistakes from practice tests
FAQs
Question: How can I improve my speed in solving JEE Main MCQ questions? Answer: Regular practice with timed quizzes and focusing on shortcuts can significantly enhance your speed.
Question: Are the JEE Main objective questions similar to previous years' papers? Answer: Yes, many questions are based on previous years' patterns, so practicing them can be beneficial.
Question: What is the best way to approach JEE Main practice questions? Answer: Start with understanding the concepts, then attempt practice questions, and finally review your answers to learn from mistakes.
Now is the time to take charge of your preparation! Dive into solving JEE Main MCQs and practice questions to test your understanding and boost your confidence for the exam.
Q. In a total internal reflection scenario, if the angle of incidence is 45° and the refractive index of the medium is 1.5, what is the angle of refraction?
A.
45°
B.
30°
C.
60°
D.
Total internal reflection occurs
Solution
Since the angle of incidence (45°) is less than the critical angle (approximately 41.8° for glass to air), total internal reflection does not occur, and the angle of refraction cannot be calculated.
Correct Answer:
D
— Total internal reflection occurs
Q. In a transformer, if the primary coil has 100 turns and the secondary coil has 200 turns, what is the relationship between primary and secondary voltages?
A.
Vp/Vs = 1/2
B.
Vp/Vs = 2
C.
Vp/Vs = 1
D.
Vp/Vs = 2/1
Solution
The voltage ratio in a transformer is given by Vp/Vs = Np/Ns, so Vp/Vs = 100/200 = 1/2, hence Vs = 2Vp.
Q. In a transformer, if the primary coil has 100 turns and the secondary coil has 200 turns, what is the relationship between the primary and secondary voltages?
A.
V_primary = V_secondary
B.
V_primary < V_secondary
C.
V_primary > V_secondary
D.
V_primary = 2 * V_secondary
Solution
In a transformer, the voltage ratio is directly proportional to the turns ratio. Therefore, if the secondary coil has more turns, the secondary voltage will be greater than the primary voltage.
Q. In a transformer, if the primary coil has 100 turns and the secondary coil has 50 turns, what is the relationship between the primary and secondary voltages?
A.
V1/V2 = 2
B.
V1/V2 = 0.5
C.
V1/V2 = 1
D.
V1/V2 = 4
Solution
The voltage ratio in a transformer is equal to the turns ratio: V1/V2 = N1/N2. Here, V1/V2 = 100/50 = 2.
Q. In a transformer, if the primary coil has 100 turns and the secondary coil has 50 turns, what is the relationship between the primary voltage (Vp) and the secondary voltage (Vs)?
A.
Vp = Vs
B.
Vp = 2Vs
C.
Vs = 2Vp
D.
Vp = 0.5Vs
Solution
The voltage ratio in a transformer is given by the turns ratio: Vp/Vs = Np/Ns. Here, Vp = 2Vs.
Q. In a transformer, if the primary coil has 200 turns and the secondary coil has 50 turns, what is the relationship between the primary and secondary voltages?
A.
Vp/Vs = 4
B.
Vp/Vs = 0.25
C.
Vp/Vs = 2
D.
Vp/Vs = 1
Solution
The voltage ratio in a transformer is inversely proportional to the turns ratio: Vp/Vs = Np/Ns = 200/50 = 4.
Q. In a uniform electric field, the potential difference between two points is given by which of the following?
A.
E × d
B.
E/d
C.
d/E
D.
E + d
Solution
In a uniform electric field, the potential difference (V) between two points separated by a distance (d) is given by V = E × d, where E is the electric field strength.