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JEE Main MCQ & Objective Questions

The JEE Main exam is a crucial step for students aspiring to enter prestigious engineering colleges in India. It tests not only knowledge but also the ability to apply concepts effectively. Practicing MCQs and objective questions is essential for scoring better, as it helps in familiarizing students with the exam pattern and enhances their problem-solving skills. Engaging with practice questions allows students to identify important questions and strengthen their exam preparation.

What You Will Practise Here

Fundamental concepts of Physics, Chemistry, and Mathematics
Key formulas and their applications in problem-solving
Important definitions and theories relevant to JEE Main
Diagrams and graphical representations for better understanding
Numerical problems and their step-by-step solutions
Previous years' JEE Main questions for real exam experience
Time management strategies while solving MCQs

Exam Relevance

The topics covered in JEE Main are not only significant for the JEE exam but also appear in various CBSE and State Board examinations. Many concepts are shared with the NEET syllabus, making them relevant across multiple competitive exams. Common question patterns include conceptual applications, numerical problems, and theoretical questions that assess a student's understanding of core subjects.

Common Mistakes Students Make

Misinterpreting the question stem, leading to incorrect answers
Neglecting units in numerical problems, which can change the outcome
Overlooking negative marking and not managing time effectively
Relying too heavily on rote memorization instead of understanding concepts
Failing to review and analyze mistakes from practice tests

FAQs

Question: How can I improve my speed in solving JEE Main MCQ questions?
Answer: Regular practice with timed quizzes and focusing on shortcuts can significantly enhance your speed.

Question: Are the JEE Main objective questions similar to previous years' papers?
Answer: Yes, many questions are based on previous years' patterns, so practicing them can be beneficial.

Question: What is the best way to approach JEE Main practice questions?
Answer: Start with understanding the concepts, then attempt practice questions, and finally review your answers to learn from mistakes.

Now is the time to take charge of your preparation! Dive into solving JEE Main MCQs and practice questions to test your understanding and boost your confidence for the exam.

Chemistry Syllabus (JEE Main) Mathematics Syllabus (JEE Main) Physics Syllabus (JEE Main)

Q. In a solenoid carrying current, the magnetic field inside the solenoid is:

A. Zero
B. Uniform and directed along the axis
C. Non-uniform and directed radially
D. Variable and depends on the distance from the center

Solution

Inside a long solenoid, the magnetic field is uniform and directed along the axis of the solenoid.

Correct Answer: B — Uniform and directed along the axis

Q. In a solenoid carrying current, what is the direction of the magnetic field inside the solenoid according to Ampere's Law?

A. From south to north
B. From north to south
C. Perpendicular to the axis
D. Radially outward

Solution

The magnetic field inside a solenoid is directed from the north pole to the south pole of the solenoid.

Correct Answer: B — From north to south

Q. In a solenoid carrying current, what is the direction of the magnetic field inside the solenoid?

A. Perpendicular to the axis of the solenoid
B. Along the axis of the solenoid
C. Radially outward from the solenoid
D. Zero inside the solenoid

Solution

The magnetic field inside a solenoid is uniform and directed along the axis of the solenoid.

Correct Answer: B — Along the axis of the solenoid

Q. In a solenoid carrying current, what is the magnetic field inside the solenoid?

A. Zero
B. μ₀nI
C. μ₀I
D. μ₀I/(2n)

Solution

The magnetic field inside a solenoid carrying current is given by B = μ₀nI, where n is the number of turns per unit length.

Correct Answer: B — μ₀nI

Q. In a solenoid, if the number of turns per unit length is doubled, what happens to the magnetic field inside the solenoid?

A. It doubles
B. It remains the same
C. It halves
D. It quadruples

Solution

The magnetic field inside a solenoid is directly proportional to the number of turns per unit length, so it doubles.

Correct Answer: A — It doubles

Q. In a solenoid, what factor does NOT affect the strength of the magnetic field inside it?

A. Number of turns per unit length
B. Current through the solenoid
C. Length of the solenoid
D. Permeability of the core material

Solution

The length of the solenoid does not affect the strength of the magnetic field inside it; it is determined by the number of turns per unit length, the current, and the permeability of the core material.

Correct Answer: C — Length of the solenoid

Q. In a solenoid, what happens to the magnetic field strength if the number of turns is doubled while keeping the current constant?

A. It doubles
B. It halves
C. It remains the same
D. It quadruples

Solution

The magnetic field strength inside a solenoid is directly proportional to the number of turns per unit length, so doubling the turns doubles the magnetic field strength.

Correct Answer: A — It doubles

Q. In a solenoid, what is the effect of increasing the number of turns per unit length on the magnetic field strength?

A. Increases
B. Decreases
C. Remains the same
D. Becomes zero

Solution

Increasing the number of turns per unit length in a solenoid increases the magnetic field strength.

Correct Answer: A — Increases

Q. In a solenoid, what is the expression for the magnetic field inside it when it carries a current I?

A. B = μ₀nI
B. B = μ₀I/2πr
C. B = μ₀I/4πr²
D. B = μ₀I/n

Solution

Inside a long solenoid, the magnetic field is given by B = μ₀nI, where n is the number of turns per unit length.

Correct Answer: A — B = μ₀nI

Q. In a solution of 0.1 M NH4Cl, what is the pH if the Kb of NH3 is 1.8 x 10^-5?

A. 4.75
B. 5.75
C. 6.75
D. 7.75

Solution

Using the formula for weak bases, pH = 14 - pKb = 14 - (14 - 4.75) = 5.75.

Correct Answer: B — 5.75

Q. In a solution of 1 mol of solute in 9 mol of solvent, what is the mole fraction of the solute?

A. 0.1
B. 0.2
C. 0.5
D. 0.9

Solution

Mole fraction of solute = moles of solute / (moles of solute + moles of solvent) = 1 / (1 + 9) = 0.1.

Correct Answer: A — 0.1

Q. In a solution of 1 mole of solute B in 3 moles of solvent A, what is the mole fraction of solvent A?

A. 0.25
B. 0.75
C. 0.33
D. 0.67

Solution

Mole fraction of A = moles of A / (moles of A + moles of B) = 3 / (3 + 1) = 0.75.

Correct Answer: B — 0.75

Q. In a solution of a non-volatile solute, how does the addition of solute affect the boiling point of the solvent?

A. It decreases the boiling point
B. It has no effect on the boiling point
C. It increases the boiling point
D. It depends on the nature of the solute

Solution

The addition of a non-volatile solute raises the boiling point of the solvent, a phenomenon known as boiling point elevation.

Correct Answer: C — It increases the boiling point

Q. In a solution of a non-volatile solute, how does the vapor pressure compare to that of the pure solvent?

A. Higher than the pure solvent
B. Lower than the pure solvent
C. Equal to the pure solvent
D. Depends on the temperature

Solution

The presence of a non-volatile solute lowers the vapor pressure of the solvent compared to that of the pure solvent.

Correct Answer: B — Lower than the pure solvent

Q. In a solution of two volatile components A and B, if the mole fraction of A is 0.6, what is the vapor pressure of the solution if the vapor pressure of pure A is 100 mmHg and that of pure B is 50 mmHg?

A. 80 mmHg
B. 90 mmHg
C. 70 mmHg
D. 60 mmHg

Solution

Using Raoult's Law, the vapor pressure of the solution is P_total = (0.6 * 100) + (0.4 * 50) = 60 + 20 = 80 mmHg.

Correct Answer: B — 90 mmHg

Q. In a solution of volatile components A and B, if the vapor pressure of A is 80 mmHg and that of B is 20 mmHg, what is the total vapor pressure?

A. 100 mmHg
B. 80 mmHg
C. 60 mmHg
D. 20 mmHg

Solution

The total vapor pressure of a solution is the sum of the partial vapor pressures of its components: 80 mmHg + 20 mmHg = 100 mmHg.

Correct Answer: A — 100 mmHg

Q. In a spontaneous process, the change in Gibbs free energy (ΔG) is:

A. Positive
B. Negative
C. Zero
D. Undefined

Solution

For a spontaneous process, the change in Gibbs free energy (ΔG) is negative.

Correct Answer: B — Negative

Q. In a standing wave, the points of maximum displacement are called:

A. Nodes
B. Antinodes
C. Crests
D. Troughs

Solution

In a standing wave, the points of maximum displacement are called antinodes, while nodes are points of zero displacement.

Correct Answer: B — Antinodes

Q. In a standing wave, what is the distance between two consecutive nodes?

A. λ/2
B. λ
C. 2λ
D. 3λ

Solution

The distance between two consecutive nodes in a standing wave is λ/2.

Correct Answer: A — λ/2

Q. In a standing wave, what is the point called where there is no displacement?

A. Node
B. Antinode
C. Crest
D. Trough

Solution

A node is a point in a standing wave where the displacement is always zero.

Correct Answer: A — Node

Q. In a standing wave, what is the position of the nodes?

A. Points of maximum amplitude
B. Points of minimum amplitude
C. Points of zero displacement
D. Points of maximum energy

Solution

Nodes in a standing wave are points where there is no displacement, meaning they are points of minimum amplitude.

Correct Answer: C — Points of zero displacement

Q. In a standing wave, what is the relationship between the nodes and antinodes?

A. Nodes are points of maximum amplitude
B. Antinodes are points of zero amplitude
C. Nodes are points of zero amplitude
D. Antinodes are points of minimum amplitude

Solution

In a standing wave, nodes are points of zero amplitude, while antinodes are points of maximum amplitude.

Correct Answer: C — Nodes are points of zero amplitude

Q. In a static equilibrium problem, if the sum of clockwise moments equals the sum of counterclockwise moments, what can be concluded?

A. The object is in equilibrium
B. The object is accelerating
C. The object is in motion
D. The object is unstable

Solution

If the sum of clockwise moments equals the sum of counterclockwise moments, the object is in equilibrium.

Correct Answer: A — The object is in equilibrium

Q. In a survey, 60% of people like tea, 30% like coffee, and 10% like both. What is the probability that a person likes coffee given that they like tea?

A. 0.5
B. 0.3
C. 0.2
D. 0.1

Solution

P(Coffee|Tea) = P(Coffee and Tea) / P(Tea) = 0.1 / 0.6 = 0.166.

Correct Answer: A — 0.5

Q. In a survey, 60% of people like tea, and 40% like coffee. If a person is chosen at random, what is the probability that they like coffee given that they do not like tea?

A. 0.4
B. 0.6
C. 0.5
D. 1

Solution

If a person does not like tea, they must like coffee. Therefore, the probability is 1.

Correct Answer: A — 0.4

Q. In a survey, 60% of people prefer tea over coffee. If 10 people are surveyed, what is the expected number of people who prefer tea?

A. 4
B. 6
C. 8
D. 10

Solution

Expected number = 60% of 10 = 0.6 * 10 = 6.

Correct Answer: B — 6

Q. In a survey, 60% of people prefer tea over coffee. If 50 people are surveyed, how many prefer tea?

A. 30
B. 25
C. 35
D. 40

Solution

Number preferring tea = 60% of 50 = 0.6 * 50 = 30.

Correct Answer: D — 40

Q. In a survey, 70% of people like chocolate. If 10 people are surveyed, what is the expected number of people who like chocolate?

A. 5
B. 7
C. 8
D. 6

Solution

Expected number = 10 * 0.7 = 7.

Correct Answer: B — 7

Q. In a survey, 70% of people like chocolate. If 200 people are surveyed, how many like chocolate?

A. 140
B. 150
C. 160
D. 170

Solution

Number of people who like chocolate = 70% of 200 = 0.7 * 200 = 140.

Correct Answer: A — 140

Q. In a survey, 70% of people like chocolate. If 200 people were surveyed, how many like chocolate?

A. 140
B. 150
C. 160
D. 170

Solution

Number of people who like chocolate = 70% of 200 = 0.7 * 200 = 140.

Correct Answer: A — 140

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