Engineering & Architecture Admissions - Exam Prep Guide

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Engineering & Architecture Admissions

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Engineering & Architecture Admissions MCQ & Objective Questions

Engineering & Architecture Admissions play a crucial role in shaping the future of aspiring students in India. With the increasing competition in entrance exams, mastering MCQs and objective questions is essential for effective exam preparation. Practicing these types of questions not only enhances concept clarity but also boosts confidence, helping students score better in their exams.

What You Will Practise Here

Key concepts in Engineering Mathematics
Fundamentals of Physics relevant to architecture and engineering
Important definitions and terminologies in engineering disciplines
Essential formulas for solving objective questions
Diagrams and illustrations for better understanding
Conceptual theories related to structural engineering
Analysis of previous years' important questions

Exam Relevance

The topics covered under Engineering & Architecture Admissions are highly relevant for various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter MCQs that test their understanding of core concepts, application of formulas, and analytical skills. Common question patterns include multiple-choice questions that require selecting the correct answer from given options, as well as assertion-reason type questions that assess deeper comprehension.

Common Mistakes Students Make

Misinterpreting the question stem, leading to incorrect answers.
Overlooking units in numerical problems, which can change the outcome.
Confusing similar concepts or terms, especially in definitions.
Neglecting to review diagrams, which are often crucial for solving problems.
Rushing through practice questions without understanding the underlying concepts.

FAQs

Question: What are the best ways to prepare for Engineering & Architecture Admissions MCQs?
Answer: Regular practice of objective questions, reviewing key concepts, and taking mock tests can significantly enhance your preparation.

Question: How can I improve my accuracy in solving MCQs?
Answer: Focus on understanding the concepts thoroughly, practice regularly, and learn to eliminate incorrect options to improve accuracy.

Start your journey towards success by solving practice MCQs today! Test your understanding and strengthen your knowledge in Engineering & Architecture Admissions to excel in your exams.

JEE Main

Q. In a reaction, if the rate constant doubles when the temperature increases by 10°C, what is the activation energy (Ea) approximately?

A. 20 kJ/mol
B. 40 kJ/mol
C. 60 kJ/mol
D. 80 kJ/mol

Solution

Using the Arrhenius equation, Ea can be estimated to be around 40 kJ/mol.

Correct Answer: B — 40 kJ/mol

Q. In a redox reaction, which species is reduced?

A. Oxidizing agent
B. Reducing agent
C. Product
D. Reactant

Solution

The oxidizing agent is the species that gains electrons and is reduced.

Correct Answer: A — Oxidizing agent

Q. In a refrigerator, the work done on the system is used to:

A. Increase the internal energy
B. Decrease the internal energy
C. Transfer heat from cold to hot
D. Transfer heat from hot to cold

Solution

In a refrigerator, work is done on the system to transfer heat from a colder body to a hotter body, which is against the natural flow of heat.

Correct Answer: C — Transfer heat from cold to hot

Q. In a region of space where the electric field is uniform, what is the electric flux through a surface area A oriented perpendicular to the field?

A. EA
B. 0
C. E/A
D. A/E

Solution

The electric flux Φ through a surface area A in a uniform electric field E is given by Φ = EA when the surface is perpendicular to the field.

Correct Answer: A — EA

Q. In a region where the electric field is uniform, how does the electric flux through a surface depend on the angle between the field and the normal to the surface?

A. It is maximum when the angle is 0°
B. It is maximum when the angle is 90°
C. It is independent of the angle
D. It is zero when the angle is 0°

Solution

The electric flux is maximum when the angle between the electric field and the normal to the surface is 0°, as Φ = E·A·cos(θ).

Correct Answer: A — It is maximum when the angle is 0°

Q. In a region where the electric field is uniform, what is the shape of the Gaussian surface that would yield the simplest calculation of electric flux?

A. Sphere
B. Cube
C. Cylinder
D. Plane

Solution

A plane is the simplest Gaussian surface for uniform electric fields, as it allows for straightforward calculation of flux.

Correct Answer: D — Plane

Q. In a reversible process, the change in entropy of the universe is:

A. Positive
B. Negative
C. Zero
D. Undefined

Solution

In a reversible process, the change in entropy of the universe is zero, as the system and surroundings are in equilibrium.

Correct Answer: C — Zero

Q. In a reversible process, the change in Gibbs free energy (ΔG) is:

A. Always positive
B. Always negative
C. Zero at equilibrium
D. None of the above

Solution

In a reversible process, the change in Gibbs free energy (ΔG) is zero at equilibrium.

Correct Answer: C — Zero at equilibrium

Q. In a reversible process, the change in Gibbs free energy is equal to:

A. Zero
B. Enthalpy
C. Entropy
D. Temperature

Solution

In a reversible process at equilibrium, the change in Gibbs free energy is zero.

Correct Answer: A — Zero

Q. In a rotating system, if the angular momentum is doubled while the moment of inertia remains constant, what happens to the angular velocity?

A. It doubles
B. It halves
C. It remains the same
D. It quadruples

Solution

Since L = Iω, if L is doubled and I remains constant, then ω must also double.

Correct Answer: A — It doubles

Q. In a seesaw, if one child exerts a force of 30 N at a distance of 1.5 m from the pivot, what is the torque produced by this child?

A. 15 Nm
B. 30 Nm
C. 45 Nm
D. 60 Nm

Solution

Torque (τ) = F × r = 30 N × 1.5 m = 45 Nm.

Correct Answer: C — 45 Nm

Q. In a seesaw, if one child exerts a force of 30 N at a distance of 2 m from the pivot, what is the torque exerted by that child?

A. 15 Nm
B. 30 Nm
C. 60 Nm
D. 0 Nm

Solution

Torque (τ) = F × r = 30 N × 2 m = 60 Nm.

Correct Answer: C — 60 Nm

Q. In a seesaw, if one child exerts a torque of 30 N·m on one side, what torque must the other child exert to balance it?

A. 15 N·m
B. 30 N·m
C. 45 N·m
D. 60 N·m

Solution

To balance the seesaw, the other child must exert an equal torque of 30 N·m.

Correct Answer: B — 30 N·m

Q. In a semiconductor, what is the term for the energy required to move an electron from the valence band to the conduction band?

A. Ionization energy
B. Band gap energy
C. Thermal energy
D. Activation energy

Solution

The energy required to move an electron from the valence band to the conduction band is known as the band gap energy.

Correct Answer: B — Band gap energy

Q. In a sequence defined by a_n = 2^n, what is the 5th term?

A. 16
B. 8
C. 32
D. 4

Solution

a_5 = 2^5 = 32.

Correct Answer: A — 16

Q. In a sequence defined by a_n = 2^n, what is the value of a_5?

A. 32
B. 16
C. 64
D. 8

Solution

a_5 = 2^5 = 32.

Correct Answer: A — 32

Q. In a series circuit with a 12V battery and three resistors of 2Ω, 3Ω, and 5Ω, what is the current flowing through the circuit?

A. 1A
B. 2A
C. 3A
D. 4A

Solution

Total resistance R = 2Ω + 3Ω + 5Ω = 10Ω. Current I = V / R = 12V / 10Ω = 1.2A.

Correct Answer: B — 2A

Q. In a series circuit with a 12V battery and two resistors of 3Ω and 6Ω, what is the current flowing through the circuit?

A. 1A
B. 2A
C. 3A
D. 4A

Solution

Total resistance R = R1 + R2 = 3Ω + 6Ω = 9Ω. Current I = V/R = 12V/9Ω = 4/3A.

Correct Answer: B — 2A

Q. In a series circuit with a 12V battery and two resistors of 4Ω and 8Ω, what is the current flowing through the circuit?

A. 1A
B. 2A
C. 3A
D. 4A

Solution

Total resistance R = R1 + R2 = 4Ω + 8Ω = 12Ω; I = V / R = 12V / 12Ω = 1A.

Correct Answer: B — 2A

Q. In a series circuit, if one resistor fails (opens), what happens to the current in the circuit?

A. It increases
B. It decreases
C. It becomes zero
D. It remains the same

Solution

In a series circuit, if one resistor fails, the circuit is broken and the current becomes zero.

Correct Answer: C — It becomes zero

Q. In a series circuit, if one resistor fails open, what happens to the current in the circuit?

A. It increases
B. It decreases
C. It becomes zero
D. It remains the same

Solution

In a series circuit, if one resistor fails open, the current becomes zero because the circuit is broken.

Correct Answer: C — It becomes zero

Q. In a series circuit, if one resistor has a resistance of 5 Ω and another has 10 Ω, what is the total resistance?

A. 5 Ω
B. 10 Ω
C. 15 Ω
D. 20 Ω

Solution

In a series circuit, total resistance R_total = R1 + R2 = 5 Ω + 10 Ω = 15 Ω.

Correct Answer: C — 15 Ω

Q. In a series circuit, if one resistor has a resistivity of 5 Ω·m and another has 10 Ω·m, what is the total resistance?

A. 5 Ω
B. 10 Ω
C. 15 Ω
D. 20 Ω

Solution

In series, total resistance R_total = R1 + R2 = 5 + 10 = 15 Ω.

Correct Answer: C — 15 Ω

Q. In a series circuit, if one resistor is removed, what happens to the total resistance?

A. It increases.
B. It decreases.
C. It remains the same.
D. It becomes zero.

Solution

In a series circuit, removing a resistor decreases the total resistance because the total resistance is the sum of all resistances.

Correct Answer: B — It decreases.

Q. In a series RLC circuit, at resonance, what is the relationship between inductive reactance and capacitive reactance?

A. X_L > X_C
B. X_L < X_C
C. X_L = X_C
D. X_L + X_C = 0

Solution

At resonance in a series RLC circuit, the inductive reactance (X_L) equals the capacitive reactance (X_C), hence X_L = X_C.

Correct Answer: C — X_L = X_C

Q. In a series RLC circuit, if the resistance is increased, what happens to the bandwidth?

A. Increases
B. Decreases
C. Remains the same
D. Becomes zero

Solution

In a series RLC circuit, increasing the resistance decreases the bandwidth because the quality factor (Q) is inversely proportional to resistance.

Correct Answer: B — Decreases

Q. In a series RLC circuit, if the resistance is increased, what happens to the bandwidth of the resonance peak?

A. Increases
B. Decreases
C. Remains the same
D. Becomes zero

Solution

Increasing the resistance in a series RLC circuit decreases the bandwidth of the resonance peak.

Correct Answer: B — Decreases

Q. In a series RLC circuit, if the resistance is increased, what happens to the bandwidth of the resonance?

A. Increases
B. Decreases
C. Remains the same
D. Becomes zero

Solution

Increasing the resistance in a series RLC circuit decreases the bandwidth of the resonance because the quality factor (Q) is inversely proportional to resistance.

Correct Answer: B — Decreases

Q. In a series RLC circuit, what happens to the current at resonance?

A. Maximum
B. Minimum
C. Zero
D. Constant

Solution

At resonance, the current is maximum in a series RLC circuit.

Correct Answer: A — Maximum

Q. In a series RLC circuit, what happens to the current when the frequency is increased beyond the resonant frequency?

A. Increases
B. Decreases
C. Remains constant
D. Becomes zero

Solution

Beyond the resonant frequency, the circuit becomes more inductive, causing the current to decrease.

Correct Answer: B — Decreases

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