Physics (School & Undergraduate) MCQ & Objective Questions
Physics is a fundamental subject that plays a crucial role in school and undergraduate exams. Mastering Physics concepts not only enhances your understanding of the universe but also significantly boosts your exam scores. Practicing MCQs and objective questions helps you identify important topics and improves your problem-solving skills, making it an essential part of your exam preparation.
What You Will Practise Here
Newton's Laws of Motion and their applications
Work, Energy, and Power concepts and formulas
Waves and Sound: Properties and equations
Optics: Reflection, refraction, and lens formulas
Thermodynamics: Laws and key definitions
Electromagnetism: Basics of electric fields and circuits
Modern Physics: Introduction to quantum mechanics and relativity
Exam Relevance
Physics is a significant part of the curriculum for CBSE, State Boards, NEET, and JEE exams. Questions often focus on conceptual understanding and application of formulas. Common patterns include numerical problems, theoretical questions, and diagram-based queries. Familiarizing yourself with these patterns through practice is vital for success in these competitive exams.
Common Mistakes Students Make
Misunderstanding the application of Newton's Laws in different scenarios
Confusing work done with energy concepts
Overlooking the importance of units and dimensions in calculations
Neglecting to draw diagrams for problems related to optics and mechanics
Failing to relate theoretical concepts to practical examples
FAQs
Question: What are some effective ways to prepare for Physics MCQs?Answer: Regular practice of MCQs, understanding key concepts, and revising important formulas are effective strategies for preparation.
Question: How can I improve my problem-solving speed in Physics exams?Answer: Practice timed quizzes and focus on solving a variety of problems to enhance your speed and accuracy.
Don't wait any longer! Start solving practice MCQs today to test your understanding and boost your confidence in Physics. Remember, consistent practice is the key to mastering important Physics (School & Undergraduate) questions for exams.
Q. What is the formula for calculating the force exerted by an object?
A.
F = ma
B.
F = mv
C.
F = m/g
D.
F = p/v
Show solution
Solution
The force exerted by an object is calculated using Newton's second law, F = ma, where F is force, m is mass, and a is acceleration.
Correct Answer:
A
— F = ma
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Q. What is the formula for calculating the gravitational force between two masses?
A.
F = ma
B.
F = G(m1*m2)/r^2
C.
F = mv^2/r
D.
F = qE
Show solution
Solution
The gravitational force between two masses is given by Newton's law of universal gravitation: F = G(m1*m2)/r^2, where G is the gravitational constant.
Correct Answer:
B
— F = G(m1*m2)/r^2
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Q. What is the formula for calculating the heat transfer by conduction?
A.
Q = mcΔT
B.
Q = kA(T1-T2)/d
C.
Q = mL
D.
Q = hA(Ts - Tf)
Show solution
Solution
The formula for heat transfer by conduction is Q = kA(T1-T2)/d, where k is the thermal conductivity, A is the area, and d is the thickness.
Correct Answer:
B
— Q = kA(T1-T2)/d
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Q. What is the formula for centripetal force?
A.
F = mv^2/r
B.
F = ma
C.
F = G(m1*m2)/r^2
D.
F = qE
Show solution
Solution
The formula for centripetal force is F = mv^2/r, where m is mass, v is velocity, and r is the radius of the circular path.
Correct Answer:
A
— F = mv^2/r
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Q. What is the formula for the charge (Q) on a capacitor at time t during charging in an RC circuit?
A.
Q = C*V(1 - e^(-t/RC))
B.
Q = C*V*e^(-t/RC)
C.
Q = C*V*t
D.
Q = C*V*t^2
Show solution
Solution
The charge on a capacitor during charging in an RC circuit is given by Q = C*V(1 - e^(-t/RC)).
Correct Answer:
A
— Q = C*V(1 - e^(-t/RC))
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Q. What is the formula for the diffraction angle in a single-slit diffraction pattern?
A.
a sin(θ) = nλ
B.
a sin(θ) = (n + 0.5)λ
C.
a tan(θ) = nλ
D.
a cos(θ) = nλ
Show solution
Solution
The formula for the diffraction angle in a single-slit diffraction pattern is a sin(θ) = nλ.
Correct Answer:
A
— a sin(θ) = nλ
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Q. What is the formula for the electric field (E) between two parallel plates separated by a distance (d) with a potential difference (V)?
A.
E = V/d
B.
E = d/V
C.
E = V*d
D.
E = d^2/V
Show solution
Solution
The electric field between two parallel plates is given by E = V/d.
Correct Answer:
A
— E = V/d
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Q. What is the formula for the electric field (E) due to a point charge (Q) at a distance (r)?
A.
E = k * Q / r^2
B.
E = Q / (4 * π * ε * r^2)
C.
E = Q / r^2
D.
E = k * Q * r^2
Show solution
Solution
The electric field due to a point charge is given by E = k * Q / r^2, where k is Coulomb's constant.
Correct Answer:
A
— E = k * Q / r^2
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Q. What is the formula for the energy stored in a capacitor?
A.
U = 1/2 C V^2
B.
U = C V
C.
U = C V^2
D.
U = 1/2 Q V
Show solution
Solution
The energy (U) stored in a capacitor is given by U = 1/2 C V^2.
Correct Answer:
A
— U = 1/2 C V^2
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Q. What is the formula for the induced electromotive force (emf) in a coil when the magnetic flux changes?
A.
emf = -dΦ/dt
B.
emf = F/q
C.
emf = W/t
D.
emf = mv^2/r
Show solution
Solution
The induced emf in a coil is given by Faraday's law of electromagnetic induction, which states that emf = -dΦ/dt, where Φ is the magnetic flux.
Correct Answer:
A
— emf = -dΦ/dt
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Q. What is the formula for the observed frequency (f') in the Doppler effect when the source is moving towards a stationary observer?
A.
f' = f (v / (v - vs))
B.
f' = f (v + vs) / v
C.
f' = f (v - vs) / v
D.
f' = f (v / (v + vs))
Show solution
Solution
The formula for the observed frequency when the source is moving towards the observer is f' = f (v / (v - vs)).
Correct Answer:
A
— f' = f (v / (v - vs))
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Q. What is the formula for the period of a simple harmonic oscillator?
A.
T = 2π√(m/k)
B.
T = 2π√(k/m)
C.
T = 2π(m/k)
D.
T = 2π(k/m)
Show solution
Solution
The period T of a simple harmonic oscillator is given by T = 2π√(m/k), where m is the mass and k is the spring constant.
Correct Answer:
B
— T = 2π√(k/m)
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Q. What is the formula for the total capacitance (C_total) of capacitors in series?
A.
1/C_total = 1/C1 + 1/C2
B.
C_total = C1 + C2
C.
C_total = C1 * C2
D.
C_total = C1 - C2
Show solution
Solution
For capacitors in series, the total capacitance is given by 1/C_total = 1/C1 + 1/C2.
Correct Answer:
A
— 1/C_total = 1/C1 + 1/C2
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Q. What is the frequency of a sound wave if its wavelength is 2 meters and the speed of sound is 340 m/s?
A.
170 Hz
B.
340 Hz
C.
680 Hz
D.
850 Hz
Show solution
Solution
Frequency (f) = Speed (v) / Wavelength (λ) = 340 m/s / 2 m = 170 Hz.
Correct Answer:
B
— 340 Hz
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Q. What is the gravitational force between two 10 kg masses separated by 2 m?
A.
25 N
B.
50 N
C.
100 N
D.
200 N
Show solution
Solution
Using Newton's law of gravitation, F = G(m1*m2)/r² = (6.674×10⁻¹¹)(10 kg)(10 kg)/(2 m)² = 50 N.
Correct Answer:
B
— 50 N
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Q. What is the gravitational force between two 10 kg masses separated by 2 meters?
A.
0.25 N
B.
5 N
C.
10 N
D.
20 N
Show solution
Solution
Using Newton's law of gravitation, F = G(m1*m2)/r² = (6.674×10⁻¹¹)(10 kg * 10 kg) / (2 m)² = 0.25 N.
Correct Answer:
A
— 0.25 N
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Q. What is the gravitational force between two 10 kg masses separated by a distance of 2 meters?
A.
25 N
B.
50 N
C.
100 N
D.
20 N
Show solution
Solution
Using Newton's law of universal gravitation, F = G(m1*m2)/r², where G = 6.674 × 10⁻¹¹ N(m/kg)², F = (6.674 × 10⁻¹¹)(10)(10)/(2²) = 50 N.
Correct Answer:
B
— 50 N
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Q. What is the gravitational force between two 5 kg masses separated by a distance of 2 m?
A.
6.25 N
B.
12.5 N
C.
9.8 N
D.
0.5 N
Show solution
Solution
Using Newton's law of universal gravitation, F = G(m1*m2)/r², where G = 6.674×10⁻¹¹ N(m/kg)².
Correct Answer:
A
— 6.25 N
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Q. What is the gravitational force between two masses?
A.
F = G(m1m2)/r^2
B.
F = G(m1 + m2)/r^2
C.
F = G(m1 - m2)/r^2
D.
F = G(m1m2)r^2
Show solution
Solution
The gravitational force between two masses is given by Newton's law of gravitation: F = G(m1m2)/r^2.
Correct Answer:
A
— F = G(m1m2)/r^2
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Q. What is the gravitational force between two particles of masses m1 and m2 separated by a distance r?
A.
G * (m1 * m2) / r^2
B.
G * (m1 + m2) / r^2
C.
G * (m1 - m2) / r^2
D.
G * (m1 * m2) * r^2
Show solution
Solution
The gravitational force between two masses is given by Newton's law of gravitation, F = G * (m1 * m2) / r^2.
Correct Answer:
A
— G * (m1 * m2) / r^2
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Q. What is the gravitational potential energy of a 1 kg mass at a height of 10 m?
A.
10 J
B.
20 J
C.
30 J
D.
40 J
Show solution
Solution
Using the formula PE = m * g * h, where g = 10 m/s^2, PE = 1 kg * 10 m/s^2 * 10 m = 100 J.
Correct Answer:
A
— 10 J
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Q. What is the gravitational potential energy of an object at height h?
A.
PE = mgh
B.
PE = 1/2 mv^2
C.
PE = Fd
D.
PE = mv
Show solution
Solution
The gravitational potential energy of an object at height h is given by PE = mgh, where m is mass, g is the acceleration due to gravity, and h is height.
Correct Answer:
A
— PE = mgh
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Q. What is the heat required to raise the temperature of 3 kg of aluminum from 25°C to 75°C? (Specific heat of aluminum = 900 J/kg°C)
A.
135000 J
B.
90000 J
C.
180000 J
D.
45000 J
Show solution
Solution
Using Q = mcΔT, Q = 3 kg * 900 J/kg°C * (75°C - 25°C) = 3 * 900 * 50 = 135000 J.
Correct Answer:
A
— 135000 J
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Q. What is the kinetic energy of a 2 kg object moving at a speed of 3 m/s?
A.
9 J
B.
6 J
C.
12 J
D.
3 J
Show solution
Solution
Kinetic energy KE = 0.5mv² = 0.5 × 2 kg × (3 m/s)² = 9 J.
Correct Answer:
A
— 9 J
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Q. What is the kinetic energy of a 3 kg object moving at a speed of 5 m/s?
A.
37.5 J
B.
15 J
C.
7.5 J
D.
25 J
Show solution
Solution
Kinetic energy KE = 0.5mv² = 0.5 × 3 kg × (5 m/s)² = 37.5 J.
Correct Answer:
A
— 37.5 J
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Q. What is the kinetic energy of a 4 kg object moving at 3 m/s?
A.
6 J
B.
12 J
C.
18 J
D.
24 J
Show solution
Solution
Kinetic energy KE = 0.5 * m * v² = 0.5 * 4 kg * (3 m/s)² = 18 J.
Correct Answer:
B
— 12 J
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Q. What is the kinetic energy of a 4 kg object moving at a speed of 2 m/s?
A.
8 J
B.
4 J
C.
16 J
D.
2 J
Show solution
Solution
Kinetic energy is calculated as KE = 0.5 × m × v², so KE = 0.5 × 4 kg × (2 m/s)² = 8 J.
Correct Answer:
A
— 8 J
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Q. What is the kinetic energy of a 5 kg object moving at a speed of 4 m/s?
A.
10 J
B.
20 J
C.
40 J
D.
80 J
Show solution
Solution
Kinetic Energy = 0.5 × m × v² = 0.5 × 5 kg × (4 m/s)² = 40 J.
Correct Answer:
B
— 20 J
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Q. What is the kinetic energy of a rotating rigid body?
A.
KE = 1/2 Iω^2
B.
KE = Iω
C.
KE = 1/2 mv^2
D.
KE = mvω
Show solution
Solution
The kinetic energy of a rotating rigid body is given by KE = 1/2 Iω^2, where I is the moment of inertia and ω is the angular velocity.
Correct Answer:
A
— KE = 1/2 Iω^2
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Q. What is the kinetic energy of an object with a mass of 2 kg moving at a speed of 3 m/s?
A.
9 J
B.
6 J
C.
3 J
D.
0 J
Show solution
Solution
Kinetic energy is calculated as KE = 0.5 * m * v². Here, KE = 0.5 * 2 kg * (3 m/s)² = 9 J.
Correct Answer:
A
— 9 J
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