Q. What is the formula for calculating the force exerted by an object?
A.
F = ma
B.
F = mv
C.
F = m/g
D.
F = p/v
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Solution
The force exerted by an object is calculated using Newton's second law, F = ma, where F is force, m is mass, and a is acceleration.
Correct Answer:
A
— F = ma
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Q. What is the formula for calculating the gravitational force between two masses?
A.
F = ma
B.
F = G(m1*m2)/r^2
C.
F = mv^2/r
D.
F = qE
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Solution
The gravitational force between two masses is given by Newton's law of universal gravitation: F = G(m1*m2)/r^2, where G is the gravitational constant.
Correct Answer:
B
— F = G(m1*m2)/r^2
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Q. What is the formula for calculating the heat transfer by conduction?
A.
Q = mcΔT
B.
Q = kA(T1-T2)/d
C.
Q = mL
D.
Q = hA(Ts - Tf)
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Solution
The formula for heat transfer by conduction is Q = kA(T1-T2)/d, where k is the thermal conductivity, A is the area, and d is the thickness.
Correct Answer:
B
— Q = kA(T1-T2)/d
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Q. What is the formula for centripetal force?
A.
F = mv^2/r
B.
F = ma
C.
F = G(m1*m2)/r^2
D.
F = qE
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Solution
The formula for centripetal force is F = mv^2/r, where m is mass, v is velocity, and r is the radius of the circular path.
Correct Answer:
A
— F = mv^2/r
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Q. What is the formula for the charge (Q) on a capacitor at time t during charging in an RC circuit?
A.
Q = C*V(1 - e^(-t/RC))
B.
Q = C*V*e^(-t/RC)
C.
Q = C*V*t
D.
Q = C*V*t^2
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Solution
The charge on a capacitor during charging in an RC circuit is given by Q = C*V(1 - e^(-t/RC)).
Correct Answer:
A
— Q = C*V(1 - e^(-t/RC))
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Q. What is the formula for the diffraction angle in a single-slit diffraction pattern?
A.
a sin(θ) = nλ
B.
a sin(θ) = (n + 0.5)λ
C.
a tan(θ) = nλ
D.
a cos(θ) = nλ
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Solution
The formula for the diffraction angle in a single-slit diffraction pattern is a sin(θ) = nλ.
Correct Answer:
A
— a sin(θ) = nλ
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Q. What is the formula for the electric field (E) between two parallel plates separated by a distance (d) with a potential difference (V)?
A.
E = V/d
B.
E = d/V
C.
E = V*d
D.
E = d^2/V
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Solution
The electric field between two parallel plates is given by E = V/d.
Correct Answer:
A
— E = V/d
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Q. What is the formula for the electric field (E) due to a point charge (Q) at a distance (r)?
A.
E = k * Q / r^2
B.
E = Q / (4 * π * ε * r^2)
C.
E = Q / r^2
D.
E = k * Q * r^2
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Solution
The electric field due to a point charge is given by E = k * Q / r^2, where k is Coulomb's constant.
Correct Answer:
A
— E = k * Q / r^2
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Q. What is the formula for the energy stored in a capacitor?
A.
U = 1/2 C V^2
B.
U = C V
C.
U = C V^2
D.
U = 1/2 Q V
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Solution
The energy (U) stored in a capacitor is given by U = 1/2 C V^2.
Correct Answer:
A
— U = 1/2 C V^2
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Q. What is the formula for the induced electromotive force (emf) in a coil when the magnetic flux changes?
A.
emf = -dΦ/dt
B.
emf = F/q
C.
emf = W/t
D.
emf = mv^2/r
Show solution
Solution
The induced emf in a coil is given by Faraday's law of electromagnetic induction, which states that emf = -dΦ/dt, where Φ is the magnetic flux.
Correct Answer:
A
— emf = -dΦ/dt
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Q. What is the formula for the observed frequency (f') in the Doppler effect when the source is moving towards a stationary observer?
A.
f' = f (v / (v - vs))
B.
f' = f (v + vs) / v
C.
f' = f (v - vs) / v
D.
f' = f (v / (v + vs))
Show solution
Solution
The formula for the observed frequency when the source is moving towards the observer is f' = f (v / (v - vs)).
Correct Answer:
A
— f' = f (v / (v - vs))
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Q. What is the formula for the period of a simple harmonic oscillator?
A.
T = 2π√(m/k)
B.
T = 2π√(k/m)
C.
T = 2π(m/k)
D.
T = 2π(k/m)
Show solution
Solution
The period T of a simple harmonic oscillator is given by T = 2π√(m/k), where m is the mass and k is the spring constant.
Correct Answer:
B
— T = 2π√(k/m)
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Q. What is the formula for the total capacitance (C_total) of capacitors in series?
A.
1/C_total = 1/C1 + 1/C2
B.
C_total = C1 + C2
C.
C_total = C1 * C2
D.
C_total = C1 - C2
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Solution
For capacitors in series, the total capacitance is given by 1/C_total = 1/C1 + 1/C2.
Correct Answer:
A
— 1/C_total = 1/C1 + 1/C2
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Q. What is the frequency of a sound wave if its wavelength is 2 meters and the speed of sound is 340 m/s?
A.
170 Hz
B.
340 Hz
C.
680 Hz
D.
850 Hz
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Solution
Frequency (f) = Speed (v) / Wavelength (λ) = 340 m/s / 2 m = 170 Hz.
Correct Answer:
B
— 340 Hz
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Q. What is the gravitational force between two 10 kg masses separated by 2 m?
A.
25 N
B.
50 N
C.
100 N
D.
200 N
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Solution
Using Newton's law of gravitation, F = G(m1*m2)/r² = (6.674×10⁻¹¹)(10 kg)(10 kg)/(2 m)² = 50 N.
Correct Answer:
B
— 50 N
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Q. What is the gravitational force between two 10 kg masses separated by 2 meters?
A.
0.25 N
B.
5 N
C.
10 N
D.
20 N
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Solution
Using Newton's law of gravitation, F = G(m1*m2)/r² = (6.674×10⁻¹¹)(10 kg * 10 kg) / (2 m)² = 0.25 N.
Correct Answer:
A
— 0.25 N
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Q. What is the gravitational force between two 10 kg masses separated by a distance of 2 meters?
A.
25 N
B.
50 N
C.
100 N
D.
20 N
Show solution
Solution
Using Newton's law of universal gravitation, F = G(m1*m2)/r², where G = 6.674 × 10⁻¹¹ N(m/kg)², F = (6.674 × 10⁻¹¹)(10)(10)/(2²) = 50 N.
Correct Answer:
B
— 50 N
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Q. What is the gravitational force between two 5 kg masses separated by a distance of 2 m?
A.
6.25 N
B.
12.5 N
C.
9.8 N
D.
0.5 N
Show solution
Solution
Using Newton's law of universal gravitation, F = G(m1*m2)/r², where G = 6.674×10⁻¹¹ N(m/kg)².
Correct Answer:
A
— 6.25 N
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Q. What is the gravitational force between two masses?
A.
F = G(m1m2)/r^2
B.
F = G(m1 + m2)/r^2
C.
F = G(m1 - m2)/r^2
D.
F = G(m1m2)r^2
Show solution
Solution
The gravitational force between two masses is given by Newton's law of gravitation: F = G(m1m2)/r^2.
Correct Answer:
A
— F = G(m1m2)/r^2
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Q. What is the gravitational force between two particles of masses m1 and m2 separated by a distance r?
A.
G * (m1 * m2) / r^2
B.
G * (m1 + m2) / r^2
C.
G * (m1 - m2) / r^2
D.
G * (m1 * m2) * r^2
Show solution
Solution
The gravitational force between two masses is given by Newton's law of gravitation, F = G * (m1 * m2) / r^2.
Correct Answer:
A
— G * (m1 * m2) / r^2
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Q. What is the gravitational potential energy of a 1 kg mass at a height of 10 m?
A.
10 J
B.
20 J
C.
30 J
D.
40 J
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Solution
Using the formula PE = m * g * h, where g = 10 m/s^2, PE = 1 kg * 10 m/s^2 * 10 m = 100 J.
Correct Answer:
A
— 10 J
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Q. What is the gravitational potential energy of an object at height h?
A.
PE = mgh
B.
PE = 1/2 mv^2
C.
PE = Fd
D.
PE = mv
Show solution
Solution
The gravitational potential energy of an object at height h is given by PE = mgh, where m is mass, g is the acceleration due to gravity, and h is height.
Correct Answer:
A
— PE = mgh
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Q. What is the heat required to raise the temperature of 3 kg of aluminum from 25°C to 75°C? (Specific heat of aluminum = 900 J/kg°C)
A.
135000 J
B.
90000 J
C.
180000 J
D.
45000 J
Show solution
Solution
Using Q = mcΔT, Q = 3 kg * 900 J/kg°C * (75°C - 25°C) = 3 * 900 * 50 = 135000 J.
Correct Answer:
A
— 135000 J
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Q. What is the kinetic energy of a 2 kg object moving at a speed of 3 m/s?
A.
9 J
B.
6 J
C.
12 J
D.
3 J
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Solution
Kinetic energy KE = 0.5mv² = 0.5 × 2 kg × (3 m/s)² = 9 J.
Correct Answer:
A
— 9 J
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Q. What is the kinetic energy of a 3 kg object moving at a speed of 5 m/s?
A.
37.5 J
B.
15 J
C.
7.5 J
D.
25 J
Show solution
Solution
Kinetic energy KE = 0.5mv² = 0.5 × 3 kg × (5 m/s)² = 37.5 J.
Correct Answer:
A
— 37.5 J
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Q. What is the kinetic energy of a 4 kg object moving at 3 m/s?
A.
6 J
B.
12 J
C.
18 J
D.
24 J
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Solution
Kinetic energy KE = 0.5 * m * v² = 0.5 * 4 kg * (3 m/s)² = 18 J.
Correct Answer:
B
— 12 J
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Q. What is the kinetic energy of a 4 kg object moving at a speed of 2 m/s?
A.
8 J
B.
4 J
C.
16 J
D.
2 J
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Solution
Kinetic energy is calculated as KE = 0.5 × m × v², so KE = 0.5 × 4 kg × (2 m/s)² = 8 J.
Correct Answer:
A
— 8 J
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Q. What is the kinetic energy of a 5 kg object moving at a speed of 4 m/s?
A.
10 J
B.
20 J
C.
40 J
D.
80 J
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Solution
Kinetic Energy = 0.5 × m × v² = 0.5 × 5 kg × (4 m/s)² = 40 J.
Correct Answer:
B
— 20 J
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Q. What is the kinetic energy of a rotating rigid body?
A.
KE = 1/2 Iω^2
B.
KE = Iω
C.
KE = 1/2 mv^2
D.
KE = mvω
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Solution
The kinetic energy of a rotating rigid body is given by KE = 1/2 Iω^2, where I is the moment of inertia and ω is the angular velocity.
Correct Answer:
A
— KE = 1/2 Iω^2
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Q. What is the kinetic energy of an object with a mass of 2 kg moving at a speed of 3 m/s?
A.
9 J
B.
6 J
C.
3 J
D.
0 J
Show solution
Solution
Kinetic energy is calculated as KE = 0.5 * m * v². Here, KE = 0.5 * 2 kg * (3 m/s)² = 9 J.
Correct Answer:
A
— 9 J
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