JEE Main MCQ & Objective Questions
The JEE Main exam is a crucial step for students aspiring to enter prestigious engineering colleges in India. It tests not only knowledge but also the ability to apply concepts effectively. Practicing MCQs and objective questions is essential for scoring better, as it helps in familiarizing students with the exam pattern and enhances their problem-solving skills. Engaging with practice questions allows students to identify important questions and strengthen their exam preparation.
What You Will Practise Here
Fundamental concepts of Physics, Chemistry, and Mathematics
Key formulas and their applications in problem-solving
Important definitions and theories relevant to JEE Main
Diagrams and graphical representations for better understanding
Numerical problems and their step-by-step solutions
Previous years' JEE Main questions for real exam experience
Time management strategies while solving MCQs
Exam Relevance
The topics covered in JEE Main are not only significant for the JEE exam but also appear in various CBSE and State Board examinations. Many concepts are shared with the NEET syllabus, making them relevant across multiple competitive exams. Common question patterns include conceptual applications, numerical problems, and theoretical questions that assess a student's understanding of core subjects.
Common Mistakes Students Make
Misinterpreting the question stem, leading to incorrect answers
Neglecting units in numerical problems, which can change the outcome
Overlooking negative marking and not managing time effectively
Relying too heavily on rote memorization instead of understanding concepts
Failing to review and analyze mistakes from practice tests
FAQs
Question: How can I improve my speed in solving JEE Main MCQ questions?Answer: Regular practice with timed quizzes and focusing on shortcuts can significantly enhance your speed.
Question: Are the JEE Main objective questions similar to previous years' papers?Answer: Yes, many questions are based on previous years' patterns, so practicing them can be beneficial.
Question: What is the best way to approach JEE Main practice questions?Answer: Start with understanding the concepts, then attempt practice questions, and finally review your answers to learn from mistakes.
Now is the time to take charge of your preparation! Dive into solving JEE Main MCQs and practice questions to test your understanding and boost your confidence for the exam.
Q. In a lottery, there are 100 tickets, and 10 of them are winning tickets. If one ticket is drawn at random, what is the probability that it is a winning ticket?
A.
1/10
B.
1/5
C.
1/20
D.
1/50
Show solution
Solution
The probability of drawing a winning ticket = Number of winning tickets / Total tickets = 10/100 = 1/10.
Correct Answer:
A
— 1/10
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Q. In a lottery, there are 100 tickets, and 10 of them are winning tickets. What is the probability of selecting a winning ticket?
A.
1/10
B.
1/5
C.
1/20
D.
1/50
Show solution
Solution
The probability of selecting a winning ticket is the number of winning tickets divided by the total number of tickets, which is 10/100 = 1/10.
Correct Answer:
A
— 1/10
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Q. In a magnetic field, the force on a charged particle is maximum when the particle's velocity is:
A.
Parallel to the field
B.
Perpendicular to the field
C.
At an angle of 45 degrees
D.
At an angle of 90 degrees
Show solution
Solution
The magnetic force on a charged particle is given by F = qvB sin(θ), which is maximum when θ = 90 degrees (perpendicular).
Correct Answer:
B
— Perpendicular to the field
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Q. In a magnetic field, the force on a charged particle is zero when it moves:
A.
Perpendicular to the field
B.
Parallel to the field
C.
At an angle of 30 degrees
D.
At an angle of 90 degrees
Show solution
Solution
The magnetic force on a charged particle is zero when it moves parallel to the magnetic field, as the angle θ = 0° results in sin(θ) = 0.
Correct Answer:
B
— Parallel to the field
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Q. In a material with a resistivity of 2 x 10^-8 Ω·m, what is the resistance of a 10 m long wire with a cross-sectional area of 1 mm²?
A.
0.02 Ω
B.
0.2 Ω
C.
2 Ω
D.
20 Ω
Show solution
Solution
Resistance R = ρ(L/A) = 2 x 10^-8 * (10 / (1 x 10^-6)) = 0.2 Ω.
Correct Answer:
B
— 0.2 Ω
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Q. In a material with a resistivity of 2 x 10^-8 Ω·m, what is the resistance of a 3 m long wire with a cross-sectional area of 1 mm²?
A.
0.006 Ω
B.
0.018 Ω
C.
0.024 Ω
D.
0.036 Ω
Show solution
Solution
Resistance R = ρ(L/A) = 2 x 10^-8 * (3 / (1 x 10^-6)) = 0.024 Ω.
Correct Answer:
C
— 0.024 Ω
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Q. In a material, if the strain energy density is given by U, what is the expression for the total strain energy stored in a volume V of the material?
A.
U * V
B.
U / V
C.
U + V
D.
U - V
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Solution
The total strain energy stored in a volume V is given by the product of strain energy density U and volume V, i.e., Total Energy = U * V.
Correct Answer:
A
— U * V
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Q. In a material, if the strain is 0.01 and the Young's modulus is 200 GPa, what is the stress in the material?
A.
2 MPa
B.
20 MPa
C.
200 MPa
D.
2000 MPa
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Solution
Stress = Young's modulus * strain = 200 GPa * 0.01 = 2 GPa = 2000 MPa.
Correct Answer:
C
— 200 MPa
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Q. In a Michelson interferometer, what happens to the interference pattern if one of the mirrors is moved away from the beam splitter?
A.
Fringes move closer
B.
Fringes move apart
C.
Fringes disappear
D.
No change in pattern
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Solution
Moving one mirror changes the path length of one beam, causing the fringes to move apart or closer depending on the direction of movement.
Correct Answer:
B
— Fringes move apart
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Q. In a Michelson interferometer, what happens to the interference pattern if one of the mirrors is moved?
A.
The pattern disappears
B.
The pattern shifts
C.
The pattern becomes brighter
D.
The pattern becomes dimmer
Show solution
Solution
Moving one of the mirrors changes the path length of one beam, causing a shift in the interference pattern.
Correct Answer:
B
— The pattern shifts
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Q. In a Michelson interferometer, what happens to the interference pattern if one of the mirrors is moved slightly?
A.
The pattern remains unchanged
B.
The pattern shifts
C.
The pattern disappears
D.
The pattern becomes brighter
Show solution
Solution
Moving one of the mirrors changes the path length for one of the beams, causing a shift in the interference pattern.
Correct Answer:
B
— The pattern shifts
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Q. In a Michelson interferometer, what happens when one of the mirrors is moved slightly?
A.
No change in interference pattern
B.
Fringes shift
C.
Fringes disappear
D.
Fringes become brighter
Show solution
Solution
Moving one of the mirrors changes the path length, causing a shift in the interference pattern (fringes).
Correct Answer:
B
— Fringes shift
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Q. In a mixture of gases, how does the RMS speed depend on the individual gas components?
A.
It depends only on the lightest gas
B.
It is the weighted average of the RMS speeds of the components
C.
It is the sum of the RMS speeds of the components
D.
It is independent of the gas components
Show solution
Solution
The RMS speed of a mixture of gases is the weighted average of the RMS speeds of the individual components, taking into account their molar masses.
Correct Answer:
B
— It is the weighted average of the RMS speeds of the components
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Q. In a mixture of gases, how is the RMS speed of the mixture calculated?
A.
Using the average molar mass of the mixture
B.
Using the molar mass of the heaviest gas
C.
Using the molar mass of the lightest gas
D.
It cannot be calculated
Show solution
Solution
The RMS speed of a mixture of gases is calculated using the average molar mass of the mixture in the formula v_rms = sqrt((3RT)/M_avg).
Correct Answer:
A
— Using the average molar mass of the mixture
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Q. In a moving coil galvanometer, what is the role of the spring?
A.
To provide a magnetic field
B.
To measure current
C.
To return the coil to its original position
D.
To increase sensitivity
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Solution
The spring in a moving coil galvanometer provides a restoring torque that returns the coil to its original position when the current is removed.
Correct Answer:
C
— To return the coil to its original position
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Q. In a Newton's rings experiment, if the radius of the ring increases, what can be inferred about the wavelength of light used?
A.
Wavelength is increasing
B.
Wavelength is decreasing
C.
Wavelength remains constant
D.
Wavelength cannot be determined
Show solution
Solution
The radius of the rings is directly proportional to the wavelength of light used. If the radius increases, the wavelength must also be increasing.
Correct Answer:
A
— Wavelength is increasing
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Q. In a normal distribution, approximately what percentage of data lies within one standard deviation of the mean?
A.
50%
B.
68%
C.
75%
D.
95%
Show solution
Solution
In a normal distribution, approximately 68% of the data lies within one standard deviation of the mean.
Correct Answer:
B
— 68%
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Q. In a normal distribution, what percentage of data lies within one standard deviation of the mean?
A.
50%
B.
68%
C.
75%
D.
95%
Show solution
Solution
In a normal distribution, approximately 68% of the data lies within one standard deviation of the mean.
Correct Answer:
B
— 68%
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Q. In a normal distribution, what percentage of data lies within one standard deviation from the mean?
A.
68%
B.
95%
C.
99%
D.
50%
Show solution
Solution
In a normal distribution, approximately 68% of the data lies within one standard deviation from the mean.
Correct Answer:
A
— 68%
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Q. In a nuclear reaction, what is conserved?
A.
Mass only
B.
Charge only
C.
Mass and charge
D.
Energy only
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Solution
In nuclear reactions, both mass and charge are conserved, according to the law of conservation of mass-energy and charge.
Correct Answer:
C
— Mass and charge
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Q. In a nuclear reaction, what is the term for the energy released when a nucleus is formed from its constituent nucleons?
A.
Binding energy
B.
Kinetic energy
C.
Potential energy
D.
Thermal energy
Show solution
Solution
The energy released when a nucleus is formed from its constituent nucleons is called binding energy.
Correct Answer:
A
— Binding energy
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Q. In a nuclear reaction, what is the term for the energy released?
A.
Kinetic energy
B.
Potential energy
C.
Binding energy
D.
Nuclear energy
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Solution
The energy released in a nuclear reaction is referred to as nuclear energy, which is a result of changes in the binding energy of the nucleus.
Correct Answer:
D
— Nuclear energy
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Q. In a nuclear reaction, what is the term for the mass difference between the reactants and products?
A.
Mass defect
B.
Binding energy
C.
Nuclear fusion
D.
Nuclear fission
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Solution
The mass defect is the difference in mass between the reactants and products in a nuclear reaction, which is related to the binding energy.
Correct Answer:
A
— Mass defect
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Q. In a p-n junction diode, what happens when it is forward biased?
A.
Depletion region widens
B.
Current flows easily
C.
No current flows
D.
Reverse breakdown occurs
Show solution
Solution
When a p-n junction diode is forward biased, the depletion region narrows, allowing current to flow easily through the junction.
Correct Answer:
B
— Current flows easily
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Q. In a p-n junction diode, what happens when it is reverse-biased?
A.
Current flows freely
B.
Depletion region widens
C.
Holes move towards the n-side
D.
Electrons move towards the p-side
Show solution
Solution
When a p-n junction diode is reverse-biased, the depletion region widens, preventing current flow.
Correct Answer:
B
— Depletion region widens
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Q. In a p-n junction, what is formed at the junction region?
A.
Electric field
B.
Magnetic field
C.
Thermal field
D.
Gravitational field
Show solution
Solution
An electric field is formed at the p-n junction due to the diffusion of charge carriers.
Correct Answer:
A
— Electric field
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Q. In a p-n junction, what is the region called where no charge carriers are present?
A.
Depletion region
B.
Conduction band
C.
Valence band
D.
Neutral zone
Show solution
Solution
The depletion region is the area around the p-n junction where charge carriers are depleted, creating an electric field.
Correct Answer:
A
— Depletion region
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Q. In a p-n junction, what is the region called where no charge carriers exist?
A.
Depletion region
B.
Conduction band
C.
Valence band
D.
Neutral zone
Show solution
Solution
The depletion region is the area around the p-n junction where charge carriers have recombined, leaving behind immobile ions.
Correct Answer:
A
— Depletion region
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Q. In a parallel circuit with three resistors of 2Ω, 3Ω, and 6Ω, what is the equivalent resistance?
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Solution
The equivalent resistance for resistors in parallel is given by 1/R_eq = 1/R1 + 1/R2 + 1/R3. Thus, 1/R_eq = 1/2 + 1/3 + 1/6 = 1. Therefore, R_eq = 1Ω.
Correct Answer:
B
— 2Ω
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Q. In a parallel circuit with three resistors of 6 ohms, 12 ohms, and 18 ohms, what is the equivalent resistance?
A.
3 ohms
B.
4 ohms
C.
2 ohms
D.
1 ohm
Show solution
Solution
Using the formula for resistors in parallel, 1/R_eq = 1/R1 + 1/R2 + 1/R3, we find R_eq = 1 / (1/6 + 1/12 + 1/18) = 3 ohms.
Correct Answer:
A
— 3 ohms
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