JEE Main Preparation Resources for Competitive Exams

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JEE Main MCQ & Objective Questions

The JEE Main exam is a crucial step for students aspiring to enter prestigious engineering colleges in India. It tests not only knowledge but also the ability to apply concepts effectively. Practicing MCQs and objective questions is essential for scoring better, as it helps in familiarizing students with the exam pattern and enhances their problem-solving skills. Engaging with practice questions allows students to identify important questions and strengthen their exam preparation.

What You Will Practise Here

Fundamental concepts of Physics, Chemistry, and Mathematics
Key formulas and their applications in problem-solving
Important definitions and theories relevant to JEE Main
Diagrams and graphical representations for better understanding
Numerical problems and their step-by-step solutions
Previous years' JEE Main questions for real exam experience
Time management strategies while solving MCQs

Exam Relevance

The topics covered in JEE Main are not only significant for the JEE exam but also appear in various CBSE and State Board examinations. Many concepts are shared with the NEET syllabus, making them relevant across multiple competitive exams. Common question patterns include conceptual applications, numerical problems, and theoretical questions that assess a student's understanding of core subjects.

Common Mistakes Students Make

Misinterpreting the question stem, leading to incorrect answers
Neglecting units in numerical problems, which can change the outcome
Overlooking negative marking and not managing time effectively
Relying too heavily on rote memorization instead of understanding concepts
Failing to review and analyze mistakes from practice tests

FAQs

Question: How can I improve my speed in solving JEE Main MCQ questions?
Answer: Regular practice with timed quizzes and focusing on shortcuts can significantly enhance your speed.

Question: Are the JEE Main objective questions similar to previous years' papers?
Answer: Yes, many questions are based on previous years' patterns, so practicing them can be beneficial.

Question: What is the best way to approach JEE Main practice questions?
Answer: Start with understanding the concepts, then attempt practice questions, and finally review your answers to learn from mistakes.

Now is the time to take charge of your preparation! Dive into solving JEE Main MCQs and practice questions to test your understanding and boost your confidence for the exam.

Chemistry Syllabus (JEE Main) Mathematics Syllabus (JEE Main) Physics Syllabus (JEE Main)

Q. In a generator, what is the role of the rotating coil in a magnetic field?

A. To create a magnetic field
B. To induce current
C. To store energy
D. To measure voltage

Solution

In a generator, the rotating coil in a magnetic field induces current through electromagnetic induction, converting mechanical energy into electrical energy.

Correct Answer: B — To induce current

Q. In a geometric series, if the first term is 4 and the common ratio is 3, what is the 4th term?

A. 108
B. 81
C. 64
D. 48

Solution

The nth term of a geometric series is given by a_n = ar^(n-1). Thus, a_4 = 4 * 3^(4-1) = 4 * 27 = 108.

Correct Answer: A — 108

Q. In a gravitational field, the potential energy of an object is maximum at which point?

A. At the surface of the Earth
B. At infinity
C. At the center of the Earth
D. At the highest point in the field

Solution

The gravitational potential energy is considered maximum at infinity, where it is defined to be zero.

Correct Answer: B — At infinity

Q. In a group of 100 people, 60 like cricket, 30 like football, and 10 like both. What is the probability that a person likes football given that they like cricket?

A. 1/6
B. 1/3
C. 1/2
D. 1/4

Solution

P(Football|Cricket) = P(Football and Cricket) / P(Cricket) = 10/60 = 1/6.

Correct Answer: A — 1/6

Q. In a group of 100 people, 60 like football, 30 like basketball, and 10 like both. What is the probability that a person likes football given that they like basketball?

A. 0.5
B. 0.3
C. 0.6
D. 0.7

Solution

Using conditional probability, P(Football | Basketball) = P(Football and Basketball) / P(Basketball) = 10/30 = 1/3.

Correct Answer: C — 0.6

Q. In a group of 50 people, 20 are smokers and 30 are non-smokers. If a person is selected at random, what is the probability that the person is a non-smoker given that they are not a smoker?

A. 1
B. 0
C. 1/2
D. 1/3

Solution

If the person is not a smoker, they must be a non-smoker. Therefore, the probability is 1.

Correct Answer: A — 1

Q. In a group of 50 people, 30 like tea, 20 like coffee, and 10 like both. What is the probability that a randomly selected person likes either tea or coffee?

A. 0.4
B. 0.6
C. 0.5
D. 0.7

Solution

Using the principle of inclusion-exclusion, the number of people who like either tea or coffee is 30 + 20 - 10 = 40. The probability is 40/50 = 0.8.

Correct Answer: B — 0.6

Q. In a harmonic oscillator, the total mechanical energy is constant. What is the form of this energy?

A. Kinetic energy only
B. Potential energy only
C. Sum of kinetic and potential energy
D. None of the above

Solution

In a harmonic oscillator, the total mechanical energy is the sum of kinetic and potential energy, which remains constant over time.

Correct Answer: C — Sum of kinetic and potential energy

Q. In a heat engine, if the input heat is 800 J and the work output is 300 J, what is the efficiency?

A. 37.5%
B. 50%
C. 62.5%
D. 75%

Solution

Efficiency = (Work output / Heat input) × 100 = (300 J / 800 J) × 100 = 37.5%.

Correct Answer: C — 62.5%

Q. In a heat engine, if the work done is 200 J and the heat absorbed is 500 J, what is the efficiency?

A. 40%
B. 50%
C. 60%
D. 80%

Solution

Efficiency = (Work done / Heat absorbed) * 100 = (200 J / 500 J) * 100 = 40%.

Correct Answer: B — 50%

Q. In a heat engine, if the work output is 200 J and the heat input is 600 J, what is the efficiency?

A. 33.33%
B. 50%
C. 66.67%
D. 75%

Solution

Efficiency = (Work output / Heat input) × 100 = (200 J / 600 J) × 100 = 33.33%.

Correct Answer: C — 66.67%

Q. In a heat engine, the work done is equal to:

A. Heat absorbed from the hot reservoir
B. Heat rejected to the cold reservoir
C. Heat absorbed minus heat rejected
D. Heat absorbed plus heat rejected

Solution

The work done by a heat engine is equal to the heat absorbed from the hot reservoir minus the heat rejected to the cold reservoir.

Correct Answer: C — Heat absorbed minus heat rejected

Q. In a hydraulic lift, if the input power is 2000 W and the output power is 1800 W, what is the efficiency of the lift?

A. 90%
B. 80%
C. 70%
D. 75%

Solution

Efficiency is calculated as (Output Power / Input Power) * 100%. Here, efficiency = (1800 W / 2000 W) * 100% = 90%.

Correct Answer: B — 80%

Q. In a hydraulic lift, if the input power is 500 W and the efficiency is 80%, what is the output power?

A. 400 W
B. 500 W
C. 600 W
D. 700 W

Solution

Output power can be calculated using the formula: Output Power = Efficiency * Input Power. Here, Output Power = 0.8 * 500 W = 400 W.

Correct Answer: A — 400 W

Q. In a hydrogen atom, the energy levels are quantized. What is the formula for the energy of the nth level?

A. E_n = -13.6/n^2 eV
B. E_n = -13.6n^2 eV
C. E_n = -13.6/n eV
D. E_n = -13.6n eV

Solution

The energy levels of a hydrogen atom are given by E_n = -13.6/n^2 eV, where n is the principal quantum number.

Correct Answer: A — E_n = -13.6/n^2 eV

Q. In a hydrogen atom, what is the energy of the electron in the ground state?

A. -13.6 eV
B. -3.4 eV
C. -1.51 eV
D. 0 eV

Solution

The energy of the electron in the ground state of a hydrogen atom is -13.6 eV.

Correct Answer: A — -13.6 eV

Q. In a hydrogen atom, what is the energy of the electron in the n=2 state?

A. -3.4 eV
B. -13.6 eV
C. -1.51 eV
D. -0.85 eV

Solution

The energy of an electron in a hydrogen atom in the n=2 state is given by E_n = -13.6/n^2 = -13.6/4 = -3.4 eV.

Correct Answer: A — -3.4 eV

Q. In a hydrogen atom, what is the wavelength of the emitted photon when an electron transitions from n=3 to n=2?

A. 656 nm
B. 486 nm
C. 434 nm
D. 410 nm

Solution

Using the Rydberg formula, the wavelength for the transition from n=3 to n=2 is approximately 486 nm.

Correct Answer: B — 486 nm

Q. In a hydrogen atom, which transition emits the photon with the highest energy?

A. n=2 to n=1
B. n=3 to n=2
C. n=4 to n=3
D. n=5 to n=4

Solution

The energy of the emitted photon is highest for the transition from n=2 to n=1, as it involves the largest energy difference.

Correct Answer: A — n=2 to n=1

Q. In a hydrogen atom, which transition would emit the highest energy photon?

A. n=2 to n=1
B. n=3 to n=2
C. n=4 to n=3
D. n=5 to n=4

Solution

The energy of the photon emitted is highest for the transition from n=2 to n=1, as it involves the largest energy difference.

Correct Answer: A — n=2 to n=1

Q. In a hydrogen atom, which transition would emit the photon with the highest energy?

A. n=2 to n=1
B. n=3 to n=2
C. n=4 to n=3
D. n=5 to n=4

Solution

The energy of the emitted photon is highest for the transition from n=2 to n=1, as it involves the largest energy difference.

Correct Answer: A — n=2 to n=1

Q. In a lab experiment, the density of a liquid is measured as 1.2 g/cm³ with an uncertainty of ±0.05 g/cm³. What is the relative error?

A. 4.17%
B. 3.33%
C. 5.00%
D. 2.50%

Solution

Relative error = (Uncertainty / Measured value) * 100 = (0.05 / 1.2) * 100 = 4.17%.

Correct Answer: A — 4.17%

Q. In a lab experiment, the speed of sound is measured as 340 m/s with an uncertainty of ±5 m/s. What is the percentage uncertainty in this measurement?

A. 1.47%
B. 1.5%
C. 2%
D. 0.5%

Solution

Percentage uncertainty = (absolute uncertainty / measured value) * 100 = (5 / 340) * 100 ≈ 1.47%.

Correct Answer: B — 1.5%

Q. In a lab experiment, the speed of sound is measured as 340 m/s with an uncertainty of ±2 m/s. What is the total uncertainty if the speed is used in a calculation involving division by 2?

A. ±1 m/s
B. ±2 m/s
C. ±0.5 m/s
D. ±0.25 m/s

Solution

Total uncertainty = (2 m/s) / 2 = ±1 m/s.

Correct Answer: A — ±1 m/s

Q. In a liquid drop, the shape is spherical due to which property?

A. Viscosity
B. Surface tension
C. Density
D. Pressure

Solution

The spherical shape of a liquid drop minimizes the surface area, which is a result of surface tension acting to reduce the energy of the surface.

Correct Answer: B — Surface tension

Q. In a lottery, 10 tickets are sold. If you buy 1 ticket, what is the probability of winning?

A. 1/10
B. 1/5
C. 1/2
D. 1/20

Solution

There is 1 winning ticket out of 10. Probability = 1/10.

Correct Answer: A — 1/10

Q. In a lottery, there are 10 tickets, and 3 of them are winning tickets. If one ticket is drawn at random, what is the probability that it is a winning ticket?

A. 1/10
B. 1/3
C. 3/10
D. 7/10

Solution

The probability of drawing a winning ticket is 3/10.

Correct Answer: C — 3/10

Q. In a lottery, there are 10 tickets, and 3 of them are winning tickets. What is the probability of selecting a winning ticket?

A. 1/10
B. 3/10
C. 1/3
D. 1/5

Solution

The probability of selecting a winning ticket is the number of winning tickets divided by the total number of tickets, which is 3/10.

Correct Answer: B — 3/10

Q. In a lottery, there are 10 tickets, of which 2 are winning tickets. What is the probability of selecting a winning ticket?

A. 1/5
B. 1/10
C. 1/2
D. 2/10

Solution

The probability of selecting a winning ticket is the number of winning tickets divided by the total number of tickets, which is 2/10 = 1/5.

Correct Answer: B — 1/10

Q. In a lottery, there are 10 tickets, of which 3 are winning tickets. What is the probability of selecting a winning ticket?

A. 1/10
B. 1/3
C. 3/10
D. 7/10

Solution

The probability of selecting a winning ticket is the number of winning tickets divided by the total number of tickets, which is 3/10.

Correct Answer: C — 3/10

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