Engineering & Architecture Admissions - Exam Prep Guide

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Engineering & Architecture Admissions

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Engineering & Architecture Admissions MCQ & Objective Questions

Engineering & Architecture Admissions play a crucial role in shaping the future of aspiring students in India. With the increasing competition in entrance exams, mastering MCQs and objective questions is essential for effective exam preparation. Practicing these types of questions not only enhances concept clarity but also boosts confidence, helping students score better in their exams.

What You Will Practise Here

Key concepts in Engineering Mathematics
Fundamentals of Physics relevant to architecture and engineering
Important definitions and terminologies in engineering disciplines
Essential formulas for solving objective questions
Diagrams and illustrations for better understanding
Conceptual theories related to structural engineering
Analysis of previous years' important questions

Exam Relevance

The topics covered under Engineering & Architecture Admissions are highly relevant for various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter MCQs that test their understanding of core concepts, application of formulas, and analytical skills. Common question patterns include multiple-choice questions that require selecting the correct answer from given options, as well as assertion-reason type questions that assess deeper comprehension.

Common Mistakes Students Make

Misinterpreting the question stem, leading to incorrect answers.
Overlooking units in numerical problems, which can change the outcome.
Confusing similar concepts or terms, especially in definitions.
Neglecting to review diagrams, which are often crucial for solving problems.
Rushing through practice questions without understanding the underlying concepts.

FAQs

Question: What are the best ways to prepare for Engineering & Architecture Admissions MCQs?
Answer: Regular practice of objective questions, reviewing key concepts, and taking mock tests can significantly enhance your preparation.

Question: How can I improve my accuracy in solving MCQs?
Answer: Focus on understanding the concepts thoroughly, practice regularly, and learn to eliminate incorrect options to improve accuracy.

Start your journey towards success by solving practice MCQs today! Test your understanding and strengthen your knowledge in Engineering & Architecture Admissions to excel in your exams.

JEE Main

Q. In a circuit with three resistors in series (2 ohms, 3 ohms, and 5 ohms), what is the total resistance?

A. 10 ohms
B. 5 ohms
C. 3 ohms
D. 2 ohms

Solution

For resistors in series, R_total = R1 + R2 + R3 = 2 + 3 + 5 = 10 ohms.

Correct Answer: A — 10 ohms

Q. In a circuit with three resistors R1, R2, and R3 connected in series, if R1 = 2Ω, R2 = 3Ω, and R3 = 5Ω, what is the total resistance?

A. 5Ω
B. 10Ω
C. 8Ω
D. 3Ω

Solution

Total resistance in series is R_total = R1 + R2 + R3 = 2Ω + 3Ω + 5Ω = 10Ω.

Correct Answer: B — 10Ω

Q. In a circuit with two inputs A and B, if A = 0 and B = 0, what is the output of an OR gate?

A. 0
B. 1
C. 2
D. 3

Solution

An OR gate outputs 1 if at least one input is 1. Since both inputs are 0, the output is 0.

Correct Answer: A — 0

Q. In a circuit with two loops, if the current in the first loop is 2 A and in the second loop is 3 A, what is the total current entering a junction where these loops meet?

A. 1 A
B. 5 A
C. 6 A
D. 2 A

Solution

According to Kirchhoff's current law, the total current entering a junction equals the total current leaving it. Therefore, total current = 2 A + 3 A = 5 A.

Correct Answer: B — 5 A

Q. In a circuit with two loops, if the current in the first loop is 5 A and the second loop is 3 A, what is the current through a shared resistor of 2 ohms?

A. 1 A
B. 2 A
C. 3 A
D. 5 A

Solution

The current through the shared resistor is the difference of the currents in the loops, so 5 A - 3 A = 2 A.

Correct Answer: A — 1 A

Q. In a circuit with two resistors in parallel, if one resistor is 4 ohms and the other is 6 ohms, what is the equivalent resistance?

A. 2.4 ohms
B. 10 ohms
C. 24 ohms
D. 3.6 ohms

Solution

Using the formula for resistors in parallel, 1/R_eq = 1/4 + 1/6, we find R_eq = 2.4 ohms.

Correct Answer: A — 2.4 ohms

Q. In a circuit with two resistors in parallel, if one resistor is 4Ω and the other is 12Ω, what is the total current flowing through the circuit when connected to a 24V battery?

A. 2A
B. 3A
C. 4A
D. 6A

Solution

First, find the equivalent resistance: 1/R_eq = 1/4 + 1/12 = 1/3. R_eq = 3Ω. Then, I = V/R = 24V / 3Ω = 8A.

Correct Answer: D — 6A

Q. In a circuit with two resistors in parallel, if one resistor is 6Ω and the other is 3Ω, what is the total current flowing through the circuit when connected to a 12V battery?

A. 2A
B. 4A
C. 6A
D. 8A

Solution

First, find the equivalent resistance: 1/R_eq = 1/6 + 1/3 = 1/2, R_eq = 2Ω. Then, I = V/R = 12V/2Ω = 6A.

Correct Answer: B — 4A

Q. In a circuit with two resistors in parallel, if one resistor is 6Ω and the other is 3Ω, what is the total current flowing if the voltage across the parallel combination is 12V?

A. 2A
B. 4A
C. 6A
D. 8A

Solution

Total current I = V / Req; Req = 1/(1/6 + 1/3) = 2Ω; I = 12V / 2Ω = 6A.

Correct Answer: B — 4A

Q. In a circuit with two resistors in parallel, if one resistor is 6Ω and the other is 3Ω, what is the total current if a voltage of 12V is applied across the combination?

A. 2A
B. 4A
C. 6A
D. 8A

Solution

Total resistance in parallel: 1/Rtotal = 1/6 + 1/3 = 1/2. Rtotal = 2Ω. Total current I = V/R = 12V/2Ω = 6A.

Correct Answer: B — 4A

Q. In a circuit with two resistors in parallel, if one resistor is 6Ω and the other is 3Ω, what is the total current flowing if the voltage across the circuit is 12V?

A. 2A
B. 4A
C. 6A
D. 8A

Solution

Total resistance in parallel: 1/Rtotal = 1/6 + 1/3 = 1/2. Rtotal = 2Ω. Total current I = V/R = 12V/2Ω = 6A.

Correct Answer: B — 4A

Q. In a circuit with two resistors in series, if R1 = 4Ω and R2 = 6Ω, what is the total resistance?

A. 2Ω
B. 4Ω
C. 6Ω
D. 10Ω

Solution

The total resistance in series is R_total = R1 + R2 = 4Ω + 6Ω = 10Ω.

Correct Answer: D — 10Ω

Q. In a circuit with two resistors in series, if the total resistance is 12 ohms and one resistor is 4 ohms, what is the value of the other resistor?

A. 8 ohms
B. 4 ohms
C. 12 ohms
D. 16 ohms

Solution

Using the formula for resistors in series, R_total = R1 + R2, we have 12 = 4 + R2, thus R2 = 12 - 4 = 8 ohms.

Correct Answer: A — 8 ohms

Q. In a circuit with two resistors in series, if the total voltage across the circuit is 12V and the resistors have values of 4Ω and 6Ω, what is the voltage across the 4Ω resistor?

A. 4V
B. 6V
C. 8V
D. 12V

Solution

Using the voltage divider rule, V1 = (R1 / (R1 + R2)) * Vtotal = (4 / (4 + 6)) * 12 = 4.8V.

Correct Answer: B — 6V

Q. In a circuit with two resistors in series, if the total voltage across the circuit is 12V and the resistors are 4Ω and 6Ω, what is the voltage across the 4Ω resistor?

A. 4V
B. 6V
C. 8V
D. 12V

Solution

Using the voltage divider rule, V1 = (R1 / (R1 + R2)) * Vtotal = (4 / (4 + 6)) * 12 = 4.8V.

Correct Answer: A — 4V

Q. In a circuit, a capacitor is charged and then discharged through a resistor. What is the time constant of the circuit?

A. RC
B. C/R
C. R/C
D. 1/RC

Solution

The time constant (τ) of an RC circuit is given by τ = R * C.

Correct Answer: A — RC

Q. In a circuit, if a capacitor is fully charged, what is the voltage across it?

A. Zero
B. Equal to the source voltage
C. Half of the source voltage
D. Double the source voltage

Solution

When a capacitor is fully charged, the voltage across it is equal to the voltage of the source it was connected to.

Correct Answer: B — Equal to the source voltage

Q. In a circuit, if the voltage across a resistor is 12V and the current through it is 3A, what is the resistance?

A. 4 ohms
B. 3 ohms
C. 2 ohms
D. 1 ohm

Solution

Using Ohm's law, R = V/I = 12V / 3A = 4 ohms.

Correct Answer: A — 4 ohms

Q. In a circuit, if the voltage across a resistor is doubled, what happens to the current through it?

A. Doubles
B. Halves
C. Remains the same
D. Quadruples

Solution

According to Ohm's law, if voltage is doubled and resistance remains constant, current also doubles.

Correct Answer: A — Doubles

Q. In a circuit, if the voltage is halved and the resistance remains constant, what happens to the current?

A. It doubles
B. It halves
C. It remains the same
D. It quadruples

Solution

According to Ohm's law, if voltage is halved while resistance remains constant, current also halves.

Correct Answer: B — It halves

Q. In a circuit, if the voltage is increased from 5V to 15V while the resistance remains constant at 5 ohms, what is the change in current?

A. Increases by 1 A
B. Increases by 2 A
C. Increases by 3 A
D. Increases by 4 A

Solution

Initial current I1 = 5V / 5Ω = 1 A; Final current I2 = 15V / 5Ω = 3 A; Change in current = I2 - I1 = 3 A - 1 A = 2 A.

Correct Answer: C — Increases by 3 A

Q. In a circuit, if the voltage is increased while keeping the resistance constant, what happens to the current?

A. It decreases
B. It increases
C. It remains constant
D. It becomes zero

Solution

According to Ohm's Law, if voltage increases and resistance remains constant, the current will increase.

Correct Answer: B — It increases

Q. In a circuit, if the voltage is increased while the resistance remains constant, what happens to the current?

A. It decreases
B. It increases
C. It remains the same
D. It becomes zero

Solution

According to Ohm's Law, if the voltage (V) increases and resistance (R) remains constant, the current (I) increases.

Correct Answer: B — It increases

Q. In a circuit, two capacitors of capacitance 2μF and 3μF are connected in parallel. What is the total capacitance?

A. 5μF
B. 6μF
C. 1.2μF
D. 0.6μF

Solution

The total capacitance C_total in parallel is the sum of individual capacitances: C_total = C1 + C2 = 2μF + 3μF = 5μF.

Correct Answer: A — 5μF

Q. In a circuit, two capacitors of capacitance 3μF and 6μF are connected in parallel. What is the total capacitance?

A. 9μF
B. 2μF
C. 18μF
D. 1μF

Solution

In parallel, the total capacitance is the sum: C_total = C1 + C2 = 3μF + 6μF = 9μF.

Correct Answer: A — 9μF

Q. In a circuit, two capacitors of capacitance 4μF and 6μF are connected in parallel. What is the total capacitance?

A. 10μF
B. 24μF
C. 2.4μF
D. 0.4μF

Solution

For capacitors in parallel, the total capacitance is the sum of the individual capacitances: C_total = C1 + C2 = 4μF + 6μF = 10μF.

Correct Answer: A — 10μF

Q. In a circular loop of radius R carrying a current I, what is the magnetic field at the center of the loop?

A. μ₀I/(2R)
B. μ₀I/(4R)
C. μ₀I/(2πR)
D. μ₀I/(4πR)

Solution

The magnetic field B at the center of a circular loop of radius R carrying current I is given by B = μ₀I/(2R).

Correct Answer: A — μ₀I/(2R)

Q. In a circular loop of radius R carrying a current I, what is the magnetic field at the center of the loop according to the Biot-Savart Law?

A. B = (μ₀I)/(2R)
B. B = (μ₀I)/(4R)
C. B = (μ₀I)/(R)
D. B = (μ₀I)/(πR)

Solution

The magnetic field at the center of a circular loop of radius R carrying current I is given by B = (μ₀I)/(2R).

Correct Answer: A — B = (μ₀I)/(2R)

Q. In a circular path of radius r around a long straight wire carrying current I, what is the line integral of the magnetic field?

A. 0
B. μ₀I
C. μ₀I/2
D. μ₀I/4

Solution

The line integral of B around the path is equal to μ₀I by Ampere's Law.

Correct Answer: B — μ₀I

Q. In a class of 30 students, 18 are boys and 12 are girls. If a student is selected at random, what is the probability that the student is a girl?

A. 2/5
B. 1/3
C. 1/2
D. 3/5

Solution

The probability of selecting a girl is the number of girls divided by the total number of students, which is 12/30 = 2/5.

Correct Answer: A — 2/5

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