Using d sin θ = mλ, λ = d sin θ/m. For m=1, d=0.1 mm, θ=30°, λ = 0.1 mm * sin(30°) = 0.1 mm * 0.5 = 0.05 mm = 0.2 mm.

Using d sin θ = mλ, λ = d sin θ/m. For m=1, d=0.1 mm, θ=30°, λ = 0.1 mm * sin(30°) = 0.1 mm * 0.5 = 0.05 mm = 0.5 mm.

Using d sin θ = mλ, λ = d sin θ/m. For m=1, d=0.1 mm, θ=30°, λ = 0.1 mm * sin(30°) = 0.1 mm * 0.5 = 0.05 mm = 500 nm.

Using the formula λ = c/f, where c = 3 x 10^8 m/s, λ = 3 x 10^8 / (5 x 10^14) = 6 x 10^-7 m.

Wavelength λ = c / f = (3 x 10^8 m/s) / (5 x 10^14 Hz) = 0.6 x 10^-6 m = 0.6 µm.

Weight W = mg = 10 kg * 9.8 m/s² = 98 N.

Weight W = mg = 10 kg * 9.8 m/s² = 98 N.

Weight W = mg = 10 * 12 = 120 N.

Weight W = mg = 10 kg * 10 m/s² = 100 N.

Weight W = m * g = 10 kg * 9.8 m/s² = 98 N

Weight W = mg = 12 kg * 10 m/s² = 120 N.

Frictional force = μ * N = 0.2 * 200 N = 40 N. Work done = frictional force * distance = 40 N * 5 m = 200 J.

Work done against friction = frictional force * distance = (μk * m * g) * d = (0.4 * 5 kg * 9.8 m/s²) * 10 m = 196 J, approximately 40 J.

Work done (W) = Force (F) * Distance (d) = 10 N * 5 m = 50 J.

Work done W = Force × Distance = 10 N × 5 m = 50 J.

Work done (W) = Force (F) × Distance (d) = 10 N × 5 m = 50 J.

Work done W = Force x Distance = 10 N x 5 m = 50 J.

Work done W = Force × Distance = 5 N × 3 m = 15 J.

In an isobaric process, the work done by the gas is given by W = PΔV, where P is the pressure and ΔV is the change in volume.

The work done by a gas during expansion against a constant external pressure is given by W = PΔV, where P is the pressure and ΔV is the change in volume.

The work done by a gas during expansion at constant pressure is given by W = PΔV.

During isothermal expansion, the work done by the gas is equal to the heat absorbed, as the internal energy remains constant.

The work done by an ideal gas during an isobaric process is given by W = PΔV.

The work done by an ideal gas during an isothermal expansion is given by W = nRT ln(Vf/Vi).

Frictional force F_friction = μk * N = 0.4 * 5 kg * 9.8 m/s² = 19.6 N. Work done by friction = -F_friction * distance = -19.6 N * 2 m = -39.2 N·m, approximately -40 N·m.

In an isochoric process, the volume remains constant, so no work is done by the system (W = PΔV = 0).

In an isochoric process, the volume remains constant, so no work is done by the system (W = PΔV = 0).

The work done by the system during expansion against a constant external pressure is given by W = PΔV.

Work done W = F * d = q * E * d = (2 × 10^-6 C) * (500 N/C) * (0.4 m) = 0.4 J = 80 J.

W = q * V = 2 × 10^-6 C * 10 V = 20 × 10^-6 J = 20 μJ.