JEE Main MCQ & Objective Questions
The JEE Main exam is a crucial step for students aspiring to enter prestigious engineering colleges in India. It tests not only knowledge but also the ability to apply concepts effectively. Practicing MCQs and objective questions is essential for scoring better, as it helps in familiarizing students with the exam pattern and enhances their problem-solving skills. Engaging with practice questions allows students to identify important questions and strengthen their exam preparation.
What You Will Practise Here
Fundamental concepts of Physics, Chemistry, and Mathematics
Key formulas and their applications in problem-solving
Important definitions and theories relevant to JEE Main
Diagrams and graphical representations for better understanding
Numerical problems and their step-by-step solutions
Previous years' JEE Main questions for real exam experience
Time management strategies while solving MCQs
Exam Relevance
The topics covered in JEE Main are not only significant for the JEE exam but also appear in various CBSE and State Board examinations. Many concepts are shared with the NEET syllabus, making them relevant across multiple competitive exams. Common question patterns include conceptual applications, numerical problems, and theoretical questions that assess a student's understanding of core subjects.
Common Mistakes Students Make
Misinterpreting the question stem, leading to incorrect answers
Neglecting units in numerical problems, which can change the outcome
Overlooking negative marking and not managing time effectively
Relying too heavily on rote memorization instead of understanding concepts
Failing to review and analyze mistakes from practice tests
FAQs
Question: How can I improve my speed in solving JEE Main MCQ questions?Answer: Regular practice with timed quizzes and focusing on shortcuts can significantly enhance your speed.
Question: Are the JEE Main objective questions similar to previous years' papers?Answer: Yes, many questions are based on previous years' patterns, so practicing them can be beneficial.
Question: What is the best way to approach JEE Main practice questions?Answer: Start with understanding the concepts, then attempt practice questions, and finally review your answers to learn from mistakes.
Now is the time to take charge of your preparation! Dive into solving JEE Main MCQs and practice questions to test your understanding and boost your confidence for the exam.
Q. In a circuit with a 24V battery and three resistors in parallel (4Ω, 6Ω, and 12Ω), what is the total current supplied by the battery?
Show solution
Solution
1/R_eq = 1/4 + 1/6 + 1/12 = 1. Therefore, R_eq = 2Ω. Total current I = V/R_eq = 24V/2Ω = 12A.
Correct Answer:
C
— 4A
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Q. In a circuit with a 24V battery and three resistors in series (R1 = 2Ω, R2 = 3Ω, R3 = 5Ω), what is the voltage drop across R2?
A.
6V
B.
8V
C.
12V
D.
10V
Show solution
Solution
Total resistance R_total = R1 + R2 + R3 = 2Ω + 3Ω + 5Ω = 10Ω. Current I = V/R_total = 24V / 10Ω = 2.4A. Voltage drop across R2 = I * R2 = 2.4A * 3Ω = 7.2V.
Correct Answer:
B
— 8V
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Q. In a circuit with a 24V battery and three resistors of 2 ohms, 4 ohms, and 6 ohms in series, what is the total current flowing through the circuit?
A.
2 A
B.
3 A
C.
4 A
D.
1 A
Show solution
Solution
Total resistance R = 2 + 4 + 6 = 12 ohms. Using Ohm's law, I = V/R = 24V / 12 ohms = 2 A.
Correct Answer:
B
— 3 A
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Q. In a circuit with a 24V battery and three resistors of 4Ω, 4Ω, and 8Ω in series, what is the voltage drop across the 8Ω resistor?
A.
8V
B.
12V
C.
16V
D.
24V
Show solution
Solution
Total resistance R = 4Ω + 4Ω + 8Ω = 16Ω. Current I = V/R = 24V/16Ω = 1.5A. Voltage drop across 8Ω = I * R = 1.5A * 8Ω = 12V.
Correct Answer:
B
— 12V
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Q. In a circuit with a 24V battery and two 12 ohm resistors in series, what is the current flowing through the circuit?
A.
1 A
B.
2 A
C.
3 A
D.
4 A
Show solution
Solution
Total resistance R_total = 12 + 12 = 24 ohms. Current I = V/R_total = 24V / 24Ω = 1 A.
Correct Answer:
B
— 2 A
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Q. In a circuit with a 24V battery and two 12Ω resistors in parallel, what is the total current supplied by the battery?
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Solution
Total resistance R = 1/(1/12 + 1/12) = 6Ω; Total current I = V/R = 24V / 6Ω = 4A.
Correct Answer:
D
— 4A
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Q. In a circuit with a 24V battery and two 12Ω resistors in series, what is the current flowing through the circuit?
Show solution
Solution
Total resistance R_total = 12Ω + 12Ω = 24Ω. Current I = V/R_total = 24V / 24Ω = 1A.
Correct Answer:
B
— 2A
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Q. In a circuit with a 24V battery and two resistors in series (4Ω and 8Ω), what is the voltage across the 8Ω resistor?
A.
8V
B.
12V
C.
16V
D.
20V
Show solution
Solution
Voltage across 8Ω resistor = (R2 / (R1 + R2)) * Vtotal = (8 / (4 + 8)) * 24 = 16V.
Correct Answer:
B
— 12V
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Q. In a circuit with a 24V battery and two resistors in series (6Ω and 3Ω), what is the voltage across the 3Ω resistor?
A.
8V
B.
12V
C.
16V
D.
4V
Show solution
Solution
Total resistance = 6Ω + 3Ω = 9Ω. Current I = V / R = 24V / 9Ω = 2.67A. Voltage across 3Ω = I * R = 2.67A * 3Ω = 8V.
Correct Answer:
A
— 8V
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Q. In a circuit with a 24V battery and two resistors in series (R1 = 6Ω, R2 = 12Ω), what is the voltage drop across R2?
A.
12V
B.
18V
C.
6V
D.
8V
Show solution
Solution
Voltage drop across R2 = V_R2 = (R2 / (R1 + R2)) * V_total = (12Ω / (6Ω + 12Ω)) * 24V = 12V.
Correct Answer:
A
— 12V
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Q. In a circuit with a 24V battery and two resistors in series (R1 = 8Ω, R2 = 16Ω), what is the current flowing through the circuit?
Show solution
Solution
Total resistance R_total = R1 + R2 = 8Ω + 16Ω = 24Ω. The current is I = V/R_total = 24V / 24Ω = 1A.
Correct Answer:
B
— 2A
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Q. In a circuit with a 24V battery and two resistors in series (R1 = 8Ω, R2 = 16Ω), what is the voltage across R2?
A.
16V
B.
8V
C.
12V
D.
4V
Show solution
Solution
Using voltage division, V_R2 = V_total * (R2 / (R1 + R2)) = 24V * (16Ω / (8Ω + 16Ω)) = 16V.
Correct Answer:
A
— 16V
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Q. In a circuit with a 24V battery and two resistors of 4Ω and 8Ω in series, what is the voltage across the 8Ω resistor?
A.
8V
B.
12V
C.
16V
D.
20V
Show solution
Solution
Voltage across R2 = (R2 / (R1 + R2)) * V = (8 / (4 + 8)) * 24 = 16V.
Correct Answer:
B
— 12V
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Q. In a circuit with a 24V battery and two resistors of 6Ω and 12Ω in series, what is the voltage across the 12Ω resistor?
A.
8V
B.
12V
C.
16V
D.
6V
Show solution
Solution
Voltage across R2 = (R2/(R1+R2)) * V = (12/(6+12)) * 24 = 12V.
Correct Answer:
B
— 12V
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Q. In a circuit with a 24V battery and two resistors of 8 ohms and 16 ohms in series, what is the current flowing through the circuit?
A.
1 A
B.
2 A
C.
3 A
D.
4 A
Show solution
Solution
Total resistance R = 8 + 16 = 24 ohms. Current I = V/R = 24V / 24Ω = 1 A.
Correct Answer:
B
— 2 A
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Q. In a circuit with a 24V battery and two resistors of 8 ohms and 16 ohms in series, what is the total current in the circuit?
A.
1 A
B.
2 A
C.
3 A
D.
4 A
Show solution
Solution
Total resistance R_total = 8 + 16 = 24 ohms. Current I = V/R_total = 24V / 24Ω = 1 A.
Correct Answer:
B
— 2 A
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Q. In a circuit with a 24V battery and two resistors of 8 ohms and 4 ohms in series, what is the current flowing through the circuit?
A.
1 A
B.
2 A
C.
3 A
D.
4 A
Show solution
Solution
Total resistance R_total = 8 + 4 = 12 ohms. Current I = V/R_total = 24V / 12Ω = 2 A.
Correct Answer:
B
— 2 A
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Q. In a circuit with a 24V battery and two resistors of 8Ω and 16Ω in series, what is the voltage across the 16Ω resistor?
A.
8V
B.
12V
C.
16V
D.
24V
Show solution
Solution
Voltage across R2 = (R2/(R1+R2)) * V = (16/(8+16)) * 24 = 16V.
Correct Answer:
B
— 12V
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Q. In a circuit with a 24V battery and two resistors of 8Ω and 4Ω in series, what is the current flowing through the circuit?
Show solution
Solution
Total resistance R_total = 8Ω + 4Ω = 12Ω. Current I = V/R_total = 24V / 12Ω = 2A.
Correct Answer:
B
— 3A
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Q. In a circuit with a 24V battery and two resistors of 8Ω and 4Ω in series, what is the voltage across the 4Ω resistor?
A.
6V
B.
8V
C.
12V
D.
16V
Show solution
Solution
Using the voltage divider rule, V_R2 = (R2 / (R1 + R2)) * Vtotal = (4 / (8 + 4)) * 24 = 8V.
Correct Answer:
C
— 12V
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Q. In a circuit with a 5V battery and two resistors in parallel (5Ω and 10Ω), what is the current through the 10Ω resistor?
A.
0.5A
B.
1A
C.
1.5A
D.
2A
Show solution
Solution
Using Ohm's Law, I = V/R = 5V / 10Ω = 0.5A.
Correct Answer:
B
— 1A
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Q. In a circuit with a 6Ω and a 3Ω resistor in parallel, what is the equivalent resistance?
A.
2Ω
B.
4Ω
C.
1.5Ω
D.
9Ω
Show solution
Solution
Using the formula for parallel resistors, 1/R_eq = 1/6 + 1/3 = 1/2, R_eq = 2Ω.
Correct Answer:
A
— 2Ω
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Q. In a circuit with a 9 V battery and a 3 ohm resistor, what is the current flowing through the circuit?
A.
3 A
B.
2 A
C.
1 A
D.
4 A
Show solution
Solution
Using Ohm's law, I = V / R = 9 V / 3 ohms = 3 A.
Correct Answer:
B
— 2 A
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Q. In a circuit with a 9V battery and three resistors (3Ω, 3Ω, and 3Ω) in series, what is the voltage across each resistor?
Show solution
Solution
In a series circuit, the voltage is divided equally among the resistors. Therefore, V across each 3Ω resistor = 9V / 3 = 3V.
Correct Answer:
A
— 3V
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Q. In a circuit with a 9V battery and three resistors in series (2Ω, 3Ω, and 5Ω), what is the total resistance?
A.
5Ω
B.
8Ω
C.
10Ω
D.
15Ω
Show solution
Solution
Total resistance R = R1 + R2 + R3 = 2Ω + 3Ω + 5Ω = 10Ω.
Correct Answer:
C
— 10Ω
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Q. In a circuit with a 9V battery and three resistors of 3Ω, 3Ω, and 6Ω in parallel, what is the total current supplied by the battery?
Show solution
Solution
1/R_eq = 1/3 + 1/3 + 1/6 = 1. Therefore, R_eq = 1Ω. Total current I = V/R_eq = 9V/1Ω = 9A.
Correct Answer:
C
— 3A
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Q. In a circuit with a 9V battery and two resistors (R1 = 3Ω, R2 = 6Ω) in series, what is the current flowing through the circuit?
A.
1A
B.
2A
C.
3A
D.
0.5A
Show solution
Solution
Total resistance R_total = R1 + R2 = 3Ω + 6Ω = 9Ω. Current I = V/R = 9V/9Ω = 1A.
Correct Answer:
B
— 2A
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Q. In a circuit with a 9V battery and two resistors in series (R1 = 3Ω, R2 = 6Ω), what is the voltage across R2?
Show solution
Solution
Using voltage division, V_R2 = (R2 / (R1 + R2)) * V_total = (6Ω / (3Ω + 6Ω)) * 9V = 6V.
Correct Answer:
A
— 6V
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Q. In a circuit with a 9V battery and two resistors of 3 ohms and 6 ohms in parallel, what is the equivalent resistance?
A.
2 ohms
B.
3 ohms
C.
4 ohms
D.
1.5 ohms
Show solution
Solution
1/R_eq = 1/R1 + 1/R2 = 1/3 + 1/6 = 1/2, R_eq = 2 ohms.
Correct Answer:
A
— 2 ohms
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Q. In a circuit with a 9V battery and two resistors of 3 ohms and 6 ohms in series, what is the voltage drop across the 6 ohm resistor?
A.
6V
B.
3V
C.
9V
D.
4.5V
Show solution
Solution
The total resistance is 9 ohms. The current is I = V/R = 9V / 9 ohms = 1 A. The voltage drop across the 6 ohm resistor is V = I * R = 1 A * 6 ohms = 6V.
Correct Answer:
A
— 6V
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