Engineering & Architecture Admissions MCQ & Objective Questions
Engineering & Architecture Admissions play a crucial role in shaping the future of aspiring students in India. With the increasing competition in entrance exams, mastering MCQs and objective questions is essential for effective exam preparation. Practicing these types of questions not only enhances concept clarity but also boosts confidence, helping students score better in their exams.
What You Will Practise Here
Key concepts in Engineering Mathematics
Fundamentals of Physics relevant to architecture and engineering
Important definitions and terminologies in engineering disciplines
Essential formulas for solving objective questions
Diagrams and illustrations for better understanding
Conceptual theories related to structural engineering
Analysis of previous years' important questions
Exam Relevance
The topics covered under Engineering & Architecture Admissions are highly relevant for various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter MCQs that test their understanding of core concepts, application of formulas, and analytical skills. Common question patterns include multiple-choice questions that require selecting the correct answer from given options, as well as assertion-reason type questions that assess deeper comprehension.
Common Mistakes Students Make
Misinterpreting the question stem, leading to incorrect answers.
Overlooking units in numerical problems, which can change the outcome.
Confusing similar concepts or terms, especially in definitions.
Neglecting to review diagrams, which are often crucial for solving problems.
Rushing through practice questions without understanding the underlying concepts.
FAQs
Question: What are the best ways to prepare for Engineering & Architecture Admissions MCQs?Answer: Regular practice of objective questions, reviewing key concepts, and taking mock tests can significantly enhance your preparation.
Question: How can I improve my accuracy in solving MCQs?Answer: Focus on understanding the concepts thoroughly, practice regularly, and learn to eliminate incorrect options to improve accuracy.
Start your journey towards success by solving practice MCQs today! Test your understanding and strengthen your knowledge in Engineering & Architecture Admissions to excel in your exams.
Q. In a circuit with a 24V battery and three resistors in parallel (4Ω, 6Ω, and 12Ω), what is the total current supplied by the battery?
Show solution
Solution
1/R_eq = 1/4 + 1/6 + 1/12 = 1. Therefore, R_eq = 2Ω. Total current I = V/R_eq = 24V/2Ω = 12A.
Correct Answer:
C
— 4A
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Q. In a circuit with a 24V battery and three resistors in series (R1 = 2Ω, R2 = 3Ω, R3 = 5Ω), what is the voltage drop across R2?
A.
6V
B.
8V
C.
12V
D.
10V
Show solution
Solution
Total resistance R_total = R1 + R2 + R3 = 2Ω + 3Ω + 5Ω = 10Ω. Current I = V/R_total = 24V / 10Ω = 2.4A. Voltage drop across R2 = I * R2 = 2.4A * 3Ω = 7.2V.
Correct Answer:
B
— 8V
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Q. In a circuit with a 24V battery and three resistors of 2 ohms, 4 ohms, and 6 ohms in series, what is the total current flowing through the circuit?
A.
2 A
B.
3 A
C.
4 A
D.
1 A
Show solution
Solution
Total resistance R = 2 + 4 + 6 = 12 ohms. Using Ohm's law, I = V/R = 24V / 12 ohms = 2 A.
Correct Answer:
B
— 3 A
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Q. In a circuit with a 24V battery and three resistors of 4Ω, 4Ω, and 8Ω in series, what is the voltage drop across the 8Ω resistor?
A.
8V
B.
12V
C.
16V
D.
24V
Show solution
Solution
Total resistance R = 4Ω + 4Ω + 8Ω = 16Ω. Current I = V/R = 24V/16Ω = 1.5A. Voltage drop across 8Ω = I * R = 1.5A * 8Ω = 12V.
Correct Answer:
B
— 12V
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Q. In a circuit with a 24V battery and two 12 ohm resistors in series, what is the current flowing through the circuit?
A.
1 A
B.
2 A
C.
3 A
D.
4 A
Show solution
Solution
Total resistance R_total = 12 + 12 = 24 ohms. Current I = V/R_total = 24V / 24Ω = 1 A.
Correct Answer:
B
— 2 A
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Q. In a circuit with a 24V battery and two 12Ω resistors in parallel, what is the total current supplied by the battery?
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Solution
Total resistance R = 1/(1/12 + 1/12) = 6Ω; Total current I = V/R = 24V / 6Ω = 4A.
Correct Answer:
D
— 4A
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Q. In a circuit with a 24V battery and two 12Ω resistors in series, what is the current flowing through the circuit?
Show solution
Solution
Total resistance R_total = 12Ω + 12Ω = 24Ω. Current I = V/R_total = 24V / 24Ω = 1A.
Correct Answer:
B
— 2A
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Q. In a circuit with a 24V battery and two resistors in series (4Ω and 8Ω), what is the voltage across the 8Ω resistor?
A.
8V
B.
12V
C.
16V
D.
20V
Show solution
Solution
Voltage across 8Ω resistor = (R2 / (R1 + R2)) * Vtotal = (8 / (4 + 8)) * 24 = 16V.
Correct Answer:
B
— 12V
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Q. In a circuit with a 24V battery and two resistors in series (6Ω and 3Ω), what is the voltage across the 3Ω resistor?
A.
8V
B.
12V
C.
16V
D.
4V
Show solution
Solution
Total resistance = 6Ω + 3Ω = 9Ω. Current I = V / R = 24V / 9Ω = 2.67A. Voltage across 3Ω = I * R = 2.67A * 3Ω = 8V.
Correct Answer:
A
— 8V
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Q. In a circuit with a 24V battery and two resistors in series (R1 = 6Ω, R2 = 12Ω), what is the voltage drop across R2?
A.
12V
B.
18V
C.
6V
D.
8V
Show solution
Solution
Voltage drop across R2 = V_R2 = (R2 / (R1 + R2)) * V_total = (12Ω / (6Ω + 12Ω)) * 24V = 12V.
Correct Answer:
A
— 12V
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Q. In a circuit with a 24V battery and two resistors in series (R1 = 8Ω, R2 = 16Ω), what is the current flowing through the circuit?
Show solution
Solution
Total resistance R_total = R1 + R2 = 8Ω + 16Ω = 24Ω. The current is I = V/R_total = 24V / 24Ω = 1A.
Correct Answer:
B
— 2A
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Q. In a circuit with a 24V battery and two resistors in series (R1 = 8Ω, R2 = 16Ω), what is the voltage across R2?
A.
16V
B.
8V
C.
12V
D.
4V
Show solution
Solution
Using voltage division, V_R2 = V_total * (R2 / (R1 + R2)) = 24V * (16Ω / (8Ω + 16Ω)) = 16V.
Correct Answer:
A
— 16V
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Q. In a circuit with a 24V battery and two resistors of 4Ω and 8Ω in series, what is the voltage across the 8Ω resistor?
A.
8V
B.
12V
C.
16V
D.
20V
Show solution
Solution
Voltage across R2 = (R2 / (R1 + R2)) * V = (8 / (4 + 8)) * 24 = 16V.
Correct Answer:
B
— 12V
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Q. In a circuit with a 24V battery and two resistors of 6Ω and 12Ω in series, what is the voltage across the 12Ω resistor?
A.
8V
B.
12V
C.
16V
D.
6V
Show solution
Solution
Voltage across R2 = (R2/(R1+R2)) * V = (12/(6+12)) * 24 = 12V.
Correct Answer:
B
— 12V
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Q. In a circuit with a 24V battery and two resistors of 8 ohms and 16 ohms in series, what is the total current in the circuit?
A.
1 A
B.
2 A
C.
3 A
D.
4 A
Show solution
Solution
Total resistance R_total = 8 + 16 = 24 ohms. Current I = V/R_total = 24V / 24Ω = 1 A.
Correct Answer:
B
— 2 A
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Q. In a circuit with a 24V battery and two resistors of 8 ohms and 16 ohms in series, what is the current flowing through the circuit?
A.
1 A
B.
2 A
C.
3 A
D.
4 A
Show solution
Solution
Total resistance R = 8 + 16 = 24 ohms. Current I = V/R = 24V / 24Ω = 1 A.
Correct Answer:
B
— 2 A
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Q. In a circuit with a 24V battery and two resistors of 8 ohms and 4 ohms in series, what is the current flowing through the circuit?
A.
1 A
B.
2 A
C.
3 A
D.
4 A
Show solution
Solution
Total resistance R_total = 8 + 4 = 12 ohms. Current I = V/R_total = 24V / 12Ω = 2 A.
Correct Answer:
B
— 2 A
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Q. In a circuit with a 24V battery and two resistors of 8Ω and 16Ω in series, what is the voltage across the 16Ω resistor?
A.
8V
B.
12V
C.
16V
D.
24V
Show solution
Solution
Voltage across R2 = (R2/(R1+R2)) * V = (16/(8+16)) * 24 = 16V.
Correct Answer:
B
— 12V
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Q. In a circuit with a 24V battery and two resistors of 8Ω and 4Ω in series, what is the current flowing through the circuit?
Show solution
Solution
Total resistance R_total = 8Ω + 4Ω = 12Ω. Current I = V/R_total = 24V / 12Ω = 2A.
Correct Answer:
B
— 3A
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Q. In a circuit with a 24V battery and two resistors of 8Ω and 4Ω in series, what is the voltage across the 4Ω resistor?
A.
6V
B.
8V
C.
12V
D.
16V
Show solution
Solution
Using the voltage divider rule, V_R2 = (R2 / (R1 + R2)) * Vtotal = (4 / (8 + 4)) * 24 = 8V.
Correct Answer:
C
— 12V
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Q. In a circuit with a 5V battery and two resistors in parallel (5Ω and 10Ω), what is the current through the 10Ω resistor?
A.
0.5A
B.
1A
C.
1.5A
D.
2A
Show solution
Solution
Using Ohm's Law, I = V/R = 5V / 10Ω = 0.5A.
Correct Answer:
B
— 1A
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Q. In a circuit with a 6Ω and a 3Ω resistor in parallel, what is the equivalent resistance?
A.
2Ω
B.
4Ω
C.
1.5Ω
D.
9Ω
Show solution
Solution
Using the formula for parallel resistors, 1/R_eq = 1/6 + 1/3 = 1/2, R_eq = 2Ω.
Correct Answer:
A
— 2Ω
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Q. In a circuit with a 9 V battery and a 3 ohm resistor, what is the current flowing through the circuit?
A.
3 A
B.
2 A
C.
1 A
D.
4 A
Show solution
Solution
Using Ohm's law, I = V / R = 9 V / 3 ohms = 3 A.
Correct Answer:
B
— 2 A
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Q. In a circuit with a 9V battery and three resistors (3Ω, 3Ω, and 3Ω) in series, what is the voltage across each resistor?
Show solution
Solution
In a series circuit, the voltage is divided equally among the resistors. Therefore, V across each 3Ω resistor = 9V / 3 = 3V.
Correct Answer:
A
— 3V
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Q. In a circuit with a 9V battery and three resistors in series (2Ω, 3Ω, and 5Ω), what is the total resistance?
A.
5Ω
B.
8Ω
C.
10Ω
D.
15Ω
Show solution
Solution
Total resistance R = R1 + R2 + R3 = 2Ω + 3Ω + 5Ω = 10Ω.
Correct Answer:
C
— 10Ω
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Q. In a circuit with a 9V battery and three resistors of 3Ω, 3Ω, and 6Ω in parallel, what is the total current supplied by the battery?
Show solution
Solution
1/R_eq = 1/3 + 1/3 + 1/6 = 1. Therefore, R_eq = 1Ω. Total current I = V/R_eq = 9V/1Ω = 9A.
Correct Answer:
C
— 3A
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Q. In a circuit with a 9V battery and two resistors (R1 = 3Ω, R2 = 6Ω) in series, what is the current flowing through the circuit?
A.
1A
B.
2A
C.
3A
D.
0.5A
Show solution
Solution
Total resistance R_total = R1 + R2 = 3Ω + 6Ω = 9Ω. Current I = V/R = 9V/9Ω = 1A.
Correct Answer:
B
— 2A
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Q. In a circuit with a 9V battery and two resistors in series (R1 = 3Ω, R2 = 6Ω), what is the voltage across R2?
Show solution
Solution
Using voltage division, V_R2 = (R2 / (R1 + R2)) * V_total = (6Ω / (3Ω + 6Ω)) * 9V = 6V.
Correct Answer:
A
— 6V
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Q. In a circuit with a 9V battery and two resistors of 3 ohms and 6 ohms in parallel, what is the equivalent resistance?
A.
2 ohms
B.
3 ohms
C.
4 ohms
D.
1.5 ohms
Show solution
Solution
1/R_eq = 1/R1 + 1/R2 = 1/3 + 1/6 = 1/2, R_eq = 2 ohms.
Correct Answer:
A
— 2 ohms
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Q. In a circuit with a 9V battery and two resistors of 3 ohms and 6 ohms in series, what is the voltage drop across the 6 ohm resistor?
A.
6V
B.
3V
C.
9V
D.
4.5V
Show solution
Solution
The total resistance is 9 ohms. The current is I = V/R = 9V / 9 ohms = 1 A. The voltage drop across the 6 ohm resistor is V = I * R = 1 A * 6 ohms = 6V.
Correct Answer:
A
— 6V
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