Physics Syllabus (JEE Main)
Q. What is the value of 4^0?
-
A.
0
-
B.
1
-
C.
4
-
D.
undefined
Solution
Any non-zero number raised to the power of 0 is 1.
Correct Answer: B — 1
Learn More →
Q. What is the value of 5^2 * 5^3?
-
A.
5^5
-
B.
5^6
-
C.
5^7
-
D.
5^8
Solution
Using the property of exponents, 5^2 * 5^3 = 5^(2+3) = 5^5.
Correct Answer: A — 5^5
Learn More →
Q. What is the value of 7^0?
-
A.
0
-
B.
1
-
C.
7
-
D.
undefined
Solution
Any non-zero number raised to the power of 0 is 1.
Correct Answer: B — 1
Learn More →
Q. What is the value of 9^(1/2)?
Solution
9^(1/2) = √9 = 3.
Correct Answer: C — 3
Learn More →
Q. What is the value of acceleration due to gravity at the surface of the Earth?
-
A.
9.8 m/s²
-
B.
10 m/s²
-
C.
9.81 m/s²
-
D.
9.6 m/s²
Solution
The standard value of acceleration due to gravity at the surface of the Earth is approximately 9.8 m/s².
Correct Answer: A — 9.8 m/s²
Learn More →
Q. What is the value of gravitational acceleration (g) at the surface of the Earth?
-
A.
9.8 m/s²
-
B.
10 m/s²
-
C.
9.81 m/s²
-
D.
8.9 m/s²
Solution
The standard value of gravitational acceleration at the Earth's surface is approximately 9.81 m/s².
Correct Answer: C — 9.81 m/s²
Learn More →
Q. What is the value of gravitational acceleration at the height equal to the radius of the Earth?
-
A.
g/2
-
B.
g/4
-
C.
g/3
-
D.
g/8
Solution
At height R, g' = g / (2^2) = g / 4.
Correct Answer: B — g/4
Learn More →
Q. What is the value of gravitational acceleration at the surface of the Earth?
-
A.
9.8 m/s^2
-
B.
10 m/s^2
-
C.
9.81 m/s^2
-
D.
8.9 m/s^2
Solution
The standard value of gravitational acceleration at the surface of the Earth is approximately 9.81 m/s^2.
Correct Answer: C — 9.81 m/s^2
Learn More →
Q. What is the value of gravitational acceleration on the surface of the Earth?
-
A.
9.8 m/s²
-
B.
10 m/s²
-
C.
9.81 m/s²
-
D.
9.6 m/s²
Solution
The standard value of gravitational acceleration on the surface of the Earth is approximately 9.8 m/s².
Correct Answer: A — 9.8 m/s²
Learn More →
Q. What is the value of log_3(27)?
Solution
Since 27 = 3^3, log_3(27) = 3.
Correct Answer: B — 3
Learn More →
Q. What is the value of Planck's constant in Joule seconds?
-
A.
6.626 x 10^-34
-
B.
3.14 x 10^-34
-
C.
1.602 x 10^-19
-
D.
9.11 x 10^-31
Solution
Planck's constant is approximately 6.626 x 10^-34 Joule seconds.
Correct Answer: A — 6.626 x 10^-34
Learn More →
Q. What is the value of R (universal gas constant) in L·atm/(K·mol)?
-
A.
0.0821
-
B.
8.314
-
C.
62.36
-
D.
1.987
Solution
The value of R in L·atm/(K·mol) is 0.0821.
Correct Answer: A — 0.0821
Learn More →
Q. What is the value of R in the ideal gas law in L·atm/(K·mol)?
-
A.
0.0821
-
B.
8.314
-
C.
0.0831
-
D.
8.31
Solution
The value of the ideal gas constant R in L·atm/(K·mol) is 0.0821.
Correct Answer: A — 0.0821
Learn More →
Q. What is the value of R in the Ideal Gas Law in terms of L·kPa/(K·mol)?
-
A.
0.0821
-
B.
8.314
-
C.
0.08314
-
D.
8.31
Solution
The value of R in L·kPa/(K·mol) is 8.314.
Correct Answer: A — 0.0821
Learn More →
Q. What is the value of the gravitational constant G?
-
A.
6.67 x 10^-11 N(m/kg)^2
-
B.
9.81 m/s^2
-
C.
3.00 x 10^8 m/s
-
D.
1.60 x 10^-19 C
Solution
The gravitational constant G is approximately 6.67 x 10^-11 N(m/kg)^2.
Correct Answer: A — 6.67 x 10^-11 N(m/kg)^2
Learn More →
Q. What is the value of the universal gas constant R in J/(mol·K)?
-
A.
8.314
-
B.
0.0821
-
C.
1.987
-
D.
22.414
Solution
The universal gas constant R is 8.314 J/(mol·K).
Correct Answer: A — 8.314
Learn More →
Q. What is the viscosity of water at 20°C?
-
A.
0.001 Pa·s
-
B.
0.01 Pa·s
-
C.
0.1 Pa·s
-
D.
1 Pa·s
Solution
The viscosity of water at 20°C is approximately 0.001 Pa·s.
Correct Answer: A — 0.001 Pa·s
Learn More →
Q. What is the voltage across a 10 ohm resistor carrying a current of 0.5 A?
-
A.
5 V
-
B.
10 V
-
C.
15 V
-
D.
20 V
Solution
Using Ohm's law, V = I * R = 0.5 A * 10 Ω = 5 V.
Correct Answer: A — 5 V
Learn More →
Q. What is the voltage drop across a 3 ohm resistor carrying a current of 2 A?
-
A.
3 V
-
B.
6 V
-
C.
9 V
-
D.
12 V
Solution
Using Ohm's law, V = I * R = 2 A * 3 ohms = 6 V.
Correct Answer: B — 6 V
Learn More →
Q. What is the voltage drop across a 5 ohm resistor carrying a current of 2 A?
-
A.
5 V
-
B.
10 V
-
C.
15 V
-
D.
20 V
Solution
Using Ohm's law, V = I * R = 2 A * 5 ohms = 10 V.
Correct Answer: B — 10 V
Learn More →
Q. What is the voltage drop across a 5 ohm resistor carrying a current of 3 A?
-
A.
15 V
-
B.
10 V
-
C.
5 V
-
D.
20 V
Solution
Using Ohm's law, V = I * R = 3 A * 5Ω = 15 V.
Correct Answer: A — 15 V
Learn More →
Q. What is the voltage drop across a 5Ω resistor carrying a current of 3A?
-
A.
5V
-
B.
10V
-
C.
15V
-
D.
20V
Solution
Using Ohm's law, V = I * R = 3A * 5Ω = 15V.
Correct Answer: C — 15V
Learn More →
Q. What is the volume of 1 liter in cubic meters?
-
A.
0.001
-
B.
0.01
-
C.
1
-
D.
1000
Solution
1 liter is equal to 0.001 cubic meters.
Correct Answer: A — 0.001
Learn More →
Q. What is the volume of a cube with a side length of 2 meters?
-
A.
4 m³
-
B.
6 m³
-
C.
8 m³
-
D.
10 m³
Solution
Volume = side³ = 2³ = 8 m³.
Correct Answer: C — 8 m³
Learn More →
Q. What is the volume of a cube with a side length of 3 cm?
-
A.
9 cm³
-
B.
18 cm³
-
C.
27 cm³
-
D.
36 cm³
Solution
The volume of a cube is given by side³, so 3 cm³ = 27 cm³.
Correct Answer: C — 27 cm³
Learn More →
Q. What is the wavelength of a photon with a frequency of 5 x 10^14 Hz?
-
A.
6 x 10^-7 m
-
B.
3 x 10^-7 m
-
C.
1 x 10^-6 m
-
D.
4 x 10^-7 m
Solution
Using the formula λ = c/f, where c = 3 x 10^8 m/s, λ = 3 x 10^8 / (5 x 10^14) = 6 x 10^-7 m.
Correct Answer: A — 6 x 10^-7 m
Learn More →
Q. What is the wavelength of a photon with a frequency of 6 x 10^14 Hz?
-
A.
5 x 10^-7 m
-
B.
3 x 10^-7 m
-
C.
6 x 10^-7 m
-
D.
1 x 10^-6 m
Solution
Wavelength λ = c/f = (3 x 10^8 m/s) / (6 x 10^14 Hz) = 5 x 10^-7 m.
Correct Answer: A — 5 x 10^-7 m
Learn More →
Q. What is the wavelength of an electron accelerated through a potential difference of 100 V? (mass of electron = 9.11 x 10^-31 kg)
-
A.
1.22 x 10^-10 m
-
B.
1.23 x 10^-9 m
-
C.
1.24 x 10^-11 m
-
D.
1.25 x 10^-12 m
Solution
The wavelength λ = h/p = h/sqrt(2meV) = (6.63 x 10^-34)/sqrt(2 * 9.11 x 10^-31 * 100) = 1.22 x 10^-10 m.
Correct Answer: A — 1.22 x 10^-10 m
Learn More →
Q. What is the wavelength of light emitted when an electron transitions from n=3 to n=2 in a hydrogen atom?
-
A.
410 nm
-
B.
656 nm
-
C.
486 nm
-
D.
434 nm
Solution
Using the Rydberg formula, the wavelength for the transition from n=3 to n=2 is approximately 434 nm.
Correct Answer: D — 434 nm
Learn More →
Q. What is the wavelength of light if its frequency is 5 x 10^14 Hz?
-
A.
6 x 10^-7 m
-
B.
3 x 10^8 m
-
C.
5 x 10^-7 m
-
D.
1 x 10^-6 m
Solution
Using the formula λ = c/f, where c = 3 x 10^8 m/s, λ = 3 x 10^8 / (5 x 10^14) = 6 x 10^-7 m.
Correct Answer: C — 5 x 10^-7 m
Learn More →
Showing 4471 to 4500 of 5000 (167 Pages)