Q. What is the value of 4^0?
A.
0
B.
1
C.
4
D.
undefined
Show solution
Solution
Any non-zero number raised to the power of 0 is 1.
Correct Answer:
B
— 1
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Q. What is the value of 5^2 * 5^3?
A.
5^5
B.
5^6
C.
5^7
D.
5^8
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Solution
Using the property of exponents, 5^2 * 5^3 = 5^(2+3) = 5^5.
Correct Answer:
A
— 5^5
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Q. What is the value of 7^0?
A.
0
B.
1
C.
7
D.
undefined
Show solution
Solution
Any non-zero number raised to the power of 0 is 1.
Correct Answer:
B
— 1
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Q. What is the value of 9^(1/2)?
Show solution
Solution
9^(1/2) = √9 = 3.
Correct Answer:
C
— 3
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Q. What is the value of acceleration due to gravity at the surface of the Earth?
A.
9.8 m/s²
B.
10 m/s²
C.
9.81 m/s²
D.
9.6 m/s²
Show solution
Solution
The standard value of acceleration due to gravity at the surface of the Earth is approximately 9.8 m/s².
Correct Answer:
A
— 9.8 m/s²
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Q. What is the value of gravitational acceleration (g) at the surface of the Earth?
A.
9.8 m/s²
B.
10 m/s²
C.
9.81 m/s²
D.
8.9 m/s²
Show solution
Solution
The standard value of gravitational acceleration at the Earth's surface is approximately 9.81 m/s².
Correct Answer:
C
— 9.81 m/s²
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Q. What is the value of gravitational acceleration at the height equal to the radius of the Earth?
A.
g/2
B.
g/4
C.
g/3
D.
g/8
Show solution
Solution
At height R, g' = g / (2^2) = g / 4.
Correct Answer:
B
— g/4
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Q. What is the value of gravitational acceleration at the surface of the Earth?
A.
9.8 m/s^2
B.
10 m/s^2
C.
9.81 m/s^2
D.
8.9 m/s^2
Show solution
Solution
The standard value of gravitational acceleration at the surface of the Earth is approximately 9.81 m/s^2.
Correct Answer:
C
— 9.81 m/s^2
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Q. What is the value of gravitational acceleration on the surface of the Earth?
A.
9.8 m/s²
B.
10 m/s²
C.
9.81 m/s²
D.
9.6 m/s²
Show solution
Solution
The standard value of gravitational acceleration on the surface of the Earth is approximately 9.8 m/s².
Correct Answer:
A
— 9.8 m/s²
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Q. What is the value of log_3(27)?
Show solution
Solution
Since 27 = 3^3, log_3(27) = 3.
Correct Answer:
B
— 3
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Q. What is the value of Planck's constant in Joule seconds?
A.
6.626 x 10^-34
B.
3.14 x 10^-34
C.
1.602 x 10^-19
D.
9.11 x 10^-31
Show solution
Solution
Planck's constant is approximately 6.626 x 10^-34 Joule seconds.
Correct Answer:
A
— 6.626 x 10^-34
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Q. What is the value of R (universal gas constant) in L·atm/(K·mol)?
A.
0.0821
B.
8.314
C.
62.36
D.
1.987
Show solution
Solution
The value of R in L·atm/(K·mol) is 0.0821.
Correct Answer:
A
— 0.0821
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Q. What is the value of R in the ideal gas law in L·atm/(K·mol)?
A.
0.0821
B.
8.314
C.
0.0831
D.
8.31
Show solution
Solution
The value of the ideal gas constant R in L·atm/(K·mol) is 0.0821.
Correct Answer:
A
— 0.0821
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Q. What is the value of R in the Ideal Gas Law in terms of L·kPa/(K·mol)?
A.
0.0821
B.
8.314
C.
0.08314
D.
8.31
Show solution
Solution
The value of R in L·kPa/(K·mol) is 8.314.
Correct Answer:
A
— 0.0821
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Q. What is the value of the gravitational constant G?
A.
6.67 x 10^-11 N(m/kg)^2
B.
9.81 m/s^2
C.
3.00 x 10^8 m/s
D.
1.60 x 10^-19 C
Show solution
Solution
The gravitational constant G is approximately 6.67 x 10^-11 N(m/kg)^2.
Correct Answer:
A
— 6.67 x 10^-11 N(m/kg)^2
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Q. What is the value of the universal gas constant R in J/(mol·K)?
A.
8.314
B.
0.0821
C.
1.987
D.
22.414
Show solution
Solution
The universal gas constant R is 8.314 J/(mol·K).
Correct Answer:
A
— 8.314
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Q. What is the viscosity of water at 20°C?
A.
0.001 Pa·s
B.
0.01 Pa·s
C.
0.1 Pa·s
D.
1 Pa·s
Show solution
Solution
The viscosity of water at 20°C is approximately 0.001 Pa·s.
Correct Answer:
A
— 0.001 Pa·s
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Q. What is the voltage across a 10 ohm resistor carrying a current of 0.5 A?
A.
5 V
B.
10 V
C.
15 V
D.
20 V
Show solution
Solution
Using Ohm's law, V = I * R = 0.5 A * 10 Ω = 5 V.
Correct Answer:
A
— 5 V
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Q. What is the voltage drop across a 3 ohm resistor carrying a current of 2 A?
A.
3 V
B.
6 V
C.
9 V
D.
12 V
Show solution
Solution
Using Ohm's law, V = I * R = 2 A * 3 ohms = 6 V.
Correct Answer:
B
— 6 V
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Q. What is the voltage drop across a 5 ohm resistor carrying a current of 2 A?
A.
5 V
B.
10 V
C.
15 V
D.
20 V
Show solution
Solution
Using Ohm's law, V = I * R = 2 A * 5 ohms = 10 V.
Correct Answer:
B
— 10 V
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Q. What is the voltage drop across a 5 ohm resistor carrying a current of 3 A?
A.
15 V
B.
10 V
C.
5 V
D.
20 V
Show solution
Solution
Using Ohm's law, V = I * R = 3 A * 5Ω = 15 V.
Correct Answer:
A
— 15 V
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Q. What is the voltage drop across a 5Ω resistor carrying a current of 3A?
A.
5V
B.
10V
C.
15V
D.
20V
Show solution
Solution
Using Ohm's law, V = I * R = 3A * 5Ω = 15V.
Correct Answer:
C
— 15V
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Q. What is the volume of 1 liter in cubic meters?
A.
0.001
B.
0.01
C.
1
D.
1000
Show solution
Solution
1 liter is equal to 0.001 cubic meters.
Correct Answer:
A
— 0.001
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Q. What is the volume of a cube with a side length of 2 meters?
A.
4 m³
B.
6 m³
C.
8 m³
D.
10 m³
Show solution
Solution
Volume = side³ = 2³ = 8 m³.
Correct Answer:
C
— 8 m³
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Q. What is the volume of a cube with a side length of 3 cm?
A.
9 cm³
B.
18 cm³
C.
27 cm³
D.
36 cm³
Show solution
Solution
The volume of a cube is given by side³, so 3 cm³ = 27 cm³.
Correct Answer:
C
— 27 cm³
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Q. What is the wavelength of a photon with a frequency of 5 x 10^14 Hz?
A.
6 x 10^-7 m
B.
3 x 10^-7 m
C.
1 x 10^-6 m
D.
4 x 10^-7 m
Show solution
Solution
Using the formula λ = c/f, where c = 3 x 10^8 m/s, λ = 3 x 10^8 / (5 x 10^14) = 6 x 10^-7 m.
Correct Answer:
A
— 6 x 10^-7 m
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Q. What is the wavelength of a photon with a frequency of 6 x 10^14 Hz?
A.
5 x 10^-7 m
B.
3 x 10^-7 m
C.
6 x 10^-7 m
D.
1 x 10^-6 m
Show solution
Solution
Wavelength λ = c/f = (3 x 10^8 m/s) / (6 x 10^14 Hz) = 5 x 10^-7 m.
Correct Answer:
A
— 5 x 10^-7 m
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Q. What is the wavelength of an electron accelerated through a potential difference of 100 V? (mass of electron = 9.11 x 10^-31 kg)
A.
1.22 x 10^-10 m
B.
1.23 x 10^-9 m
C.
1.24 x 10^-11 m
D.
1.25 x 10^-12 m
Show solution
Solution
The wavelength λ = h/p = h/sqrt(2meV) = (6.63 x 10^-34)/sqrt(2 * 9.11 x 10^-31 * 100) = 1.22 x 10^-10 m.
Correct Answer:
A
— 1.22 x 10^-10 m
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Q. What is the wavelength of light emitted when an electron transitions from n=3 to n=2 in a hydrogen atom?
A.
410 nm
B.
656 nm
C.
486 nm
D.
434 nm
Show solution
Solution
Using the Rydberg formula, the wavelength for the transition from n=3 to n=2 is approximately 434 nm.
Correct Answer:
D
— 434 nm
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Q. What is the wavelength of light if its frequency is 5 x 10^14 Hz?
A.
6 x 10^-7 m
B.
3 x 10^8 m
C.
5 x 10^-7 m
D.
1 x 10^-6 m
Show solution
Solution
Using the formula λ = c/f, where c = 3 x 10^8 m/s, λ = 3 x 10^8 / (5 x 10^14) = 6 x 10^-7 m.
Correct Answer:
C
— 5 x 10^-7 m
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Physics Syllabus (JEE Main) MCQ & Objective Questions
The Physics Syllabus for JEE Main is crucial for students aiming to excel in their exams. Understanding this syllabus not only helps in grasping fundamental concepts but also enhances problem-solving skills through practice. Engaging with MCQs and objective questions is essential for effective exam preparation, as it allows students to identify important questions and strengthen their knowledge base.
What You Will Practise Here
Mechanics: Laws of Motion, Work, Energy, and Power
Thermodynamics: Laws of Thermodynamics, Heat Transfer
Waves and Oscillations: Simple Harmonic Motion, Wave Properties
Electromagnetism: Electric Fields, Magnetic Fields, and Circuits
Optics: Reflection, Refraction, and Optical Instruments
Modern Physics: Quantum Theory, Atomic Models, and Nuclear Physics
Fluid Mechanics: Properties of Fluids, Bernoulli's Principle
Exam Relevance
The Physics Syllabus (JEE Main) is integral to various examinations, including CBSE, State Boards, and competitive exams like NEET and JEE. Questions often focus on conceptual understanding and application of theories. Common patterns include numerical problems, conceptual MCQs, and assertion-reason type questions, which test both knowledge and analytical skills.
Common Mistakes Students Make
Misinterpreting the question stem, leading to incorrect answers.
Neglecting units and dimensions in calculations.
Overlooking the significance of diagrams in understanding concepts.
Confusing similar concepts, such as velocity and acceleration.
Failing to apply formulas correctly in different contexts.
FAQs
Question: What are the key topics in the Physics Syllabus for JEE Main?Answer: Key topics include Mechanics, Thermodynamics, Waves, Electromagnetism, Optics, Modern Physics, and Fluid Mechanics.
Question: How can I improve my performance in Physics MCQs?Answer: Regular practice of MCQs, understanding concepts deeply, and revising important formulas can significantly enhance your performance.
Start solving practice MCQs today to test your understanding of the Physics Syllabus (JEE Main). This will not only boost your confidence but also prepare you effectively for your upcoming exams. Remember, consistent practice is the key to success!