Engineering Entrance MCQ & Objective Questions
Preparing for Engineering Entrance exams is crucial for aspiring engineers in India. Mastering MCQs and objective questions not only enhances your understanding of key concepts but also boosts your confidence during exams. Regular practice with these questions helps identify important topics and improves your overall exam preparation.
What You Will Practise Here
Fundamental concepts of Physics and Mathematics
Key formulas and their applications in problem-solving
Important definitions and theorems relevant to engineering
Diagrams and graphical representations for better understanding
Conceptual questions that challenge your critical thinking
Previous years' question papers and their analysis
Time management strategies while solving MCQs
Exam Relevance
The Engineering Entrance syllabus is integral to various examinations like CBSE, State Boards, NEET, and JEE. Questions often focus on core subjects such as Physics, Chemistry, and Mathematics, with formats varying from direct MCQs to application-based problems. Understanding the common question patterns can significantly enhance your performance and help you tackle the exams with ease.
Common Mistakes Students Make
Overlooking the importance of units and dimensions in calculations
Misinterpreting questions due to lack of careful reading
Neglecting to review basic concepts before attempting advanced problems
Rushing through practice questions without thorough understanding
FAQs
Question: What are the best ways to prepare for Engineering Entrance MCQs?Answer: Focus on understanding concepts, practice regularly with objective questions, and review previous years' papers.
Question: How can I improve my speed in solving MCQs?Answer: Regular practice, time-bound mock tests, and familiarizing yourself with common question types can help improve your speed.
Start your journey towards success by solving Engineering Entrance MCQ questions today! Test your understanding and build a strong foundation for your exams.
Q. Calculate the term independent of x in the expansion of (x^2 - 3x + 2)^4.
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Solution
The term independent of x occurs when the powers of x cancel out. The term is C(4,2) * (2)^2 * (-3)^2 = 6 * 4 * 9 = 216.
Correct Answer:
B
— 12
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Q. Calculate the value of (1 + 3)^5 using the binomial theorem.
A.
81
B.
243
C.
125
D.
256
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Solution
(1 + 3)^5 = 4^5 = 1024.
Correct Answer:
B
— 243
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Q. Calculate the value of 100 - (25 × 3). (2015)
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Solution
25 × 3 = 75, then 100 - 75 = 25.
Correct Answer:
B
— 75
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Q. Calculate the value of 12 × 3 - 4 × 2. (2023) 2023
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Solution
12 × 3 = 36 and 4 × 2 = 8, so 36 - 8 = 28.
Correct Answer:
A
— 28
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Q. Calculate the value of 12 × 3 - 4. (2021)
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Solution
12 × 3 = 36, then 36 - 4 = 32.
Correct Answer:
B
— 28
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Q. Calculate the value of 12 × 5 - 8. (2021)
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Solution
12 × 5 = 60, then 60 - 8 = 52.
Correct Answer:
C
— 56
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Q. Calculate the value of 12 × 8 - 10. (2021)
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Solution
12 × 8 = 96, then 96 - 10 = 86.
Correct Answer:
B
— 82
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Q. Calculate the value of 12 × 8 - 24. (2021)
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Solution
12 × 8 = 96, then 96 - 24 = 72.
Correct Answer:
A
— 72
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Q. Calculate the value of 12 × 8 - 4 × 6. (2021)
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Solution
12 × 8 = 96 and 4 × 6 = 24, so 96 - 24 = 72.
Correct Answer:
B
— 60
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Q. Calculate the value of 25% of 200. (2015)
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Solution
25% of 200 = (25/100) × 200 = 50.
Correct Answer:
A
— 50
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Q. Calculate the value of 5! (5 factorial). (2020)
A.
120
B.
100
C.
60
D.
24
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Solution
5! = 5 × 4 × 3 × 2 × 1 = 120.
Correct Answer:
A
— 120
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Q. Calculate the value of 5! - 4!. (2019)
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Solution
5! = 120 and 4! = 24, so 120 - 24 = 96.
Correct Answer:
D
— 96
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Q. Calculate the value of 6^2 - 4^2. (2023) 2023
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Solution
6^2 = 36 and 4^2 = 16, so 36 - 16 = 20.
Correct Answer:
A
— 20
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Q. Calculate the value of 8 + 2 × 5. (2015)
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Solution
According to BODMAS, 2 × 5 = 10, then 8 + 10 = 18.
Correct Answer:
D
— 16
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Q. Calculate the value of 8 × (2 + 3). (2015)
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Solution
2 + 3 = 5, then 8 × 5 = 40.
Correct Answer:
A
— 40
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Q. Calculate the value of 8^2 - 4^2. (2021)
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Solution
8^2 = 64 and 4^2 = 16, so 64 - 16 = 48.
Correct Answer:
A
— 48
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Q. Calculate the weight of a 10 kg object on the surface of Mars, where the acceleration due to gravity is 3.7 m/s².
A.
37 N
B.
74 N
C.
10 N
D.
100 N
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Solution
Weight = mass * gravity = 10 kg * 3.7 m/s² = 37 N
Correct Answer:
A
— 37 N
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Q. Calculate the weight of a 10 kg object on the surface of the Earth (g = 9.8 m/s²).
A.
98 N
B.
10 N
C.
9.8 N
D.
100 N
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Solution
Weight W = m * g = 10 kg * 9.8 m/s² = 98 N.
Correct Answer:
A
— 98 N
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Q. Determine the angle between the lines y = 2x + 3 and y = -1/2x + 1.
A.
90 degrees
B.
60 degrees
C.
45 degrees
D.
30 degrees
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Solution
The slopes are m1 = 2 and m2 = -1/2. The angle θ = tan^(-1) |(m1 - m2)/(1 + m1*m2)| = tan^(-1)(5/4) which is approximately 60 degrees.
Correct Answer:
B
— 60 degrees
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Q. Determine the coefficient of x^4 in the expansion of (2x - 3)^6.
A.
540
B.
720
C.
810
D.
960
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Solution
The coefficient of x^4 is given by 6C4 * (2)^4 * (-3)^2 = 15 * 16 * 9 = 2160.
Correct Answer:
B
— 720
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Q. Determine the coordinates of the centroid of the triangle with vertices A(0, 0, 0), B(6, 0, 0), and C(0, 8, 0). (2023)
A.
(2, 2, 0)
B.
(2, 3, 0)
C.
(3, 2, 0)
D.
(0, 0, 0)
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Solution
Centroid = ((0+6+0)/3, (0+0+8)/3, (0+0+0)/3) = (2, 2.67, 0).
Correct Answer:
A
— (2, 2, 0)
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Q. Determine the coordinates of the centroid of the triangle with vertices A(0, 0, 0), B(0, 4, 0), and C(3, 0, 0). (2021)
A.
(1, 1.33, 0)
B.
(1, 2, 0)
C.
(0, 1.33, 0)
D.
(0, 2, 0)
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Solution
Centroid = ((0+0+3)/3, (0+4+0)/3, (0+0+0)/3) = (1, 1.33, 0).
Correct Answer:
B
— (1, 2, 0)
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Q. Determine the coordinates of the centroid of the triangle with vertices A(0, 0, 0), B(4, 0, 0), C(0, 3, 0). (2023)
A.
(1, 1, 0)
B.
(2, 1, 0)
C.
(4/3, 1, 0)
D.
(0, 1, 0)
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Solution
Centroid G = ((0+4+0)/3, (0+0+3)/3, (0+0+0)/3) = (4/3, 1, 0).
Correct Answer:
B
— (2, 1, 0)
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Q. Determine the coordinates of the centroid of the triangle with vertices A(1, 2, 3), B(4, 5, 6), and C(7, 8, 9). (2021)
A.
(4, 5, 6)
B.
(3, 4, 5)
C.
(5, 6, 7)
D.
(6, 7, 8)
Show solution
Solution
Centroid G = ((1+4+7)/3, (2+5+8)/3, (3+6+9)/3) = (4, 5, 6).
Correct Answer:
B
— (3, 4, 5)
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Q. Determine the coordinates of the foot of the perpendicular from the point (1, 2, 3) to the plane x + 2y + 3z = 14. (2023)
A.
(2, 3, 4)
B.
(1, 2, 4)
C.
(2, 1, 3)
D.
(3, 2, 1)
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Solution
Using the formula for the foot of the perpendicular, we find the coordinates to be (1, 2, 4).
Correct Answer:
B
— (1, 2, 4)
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Q. Determine the critical points of f(x) = 3x^4 - 8x^3 + 6. (2021)
A.
(0, 6)
B.
(1, 1)
C.
(2, 0)
D.
(3, -1)
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Solution
f'(x) = 12x^3 - 24x^2. Setting f'(x) = 0 gives x = 0, 2. Check f(1) = 1.
Correct Answer:
B
— (1, 1)
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Q. Determine the critical points of f(x) = e^x - 2x. (2021)
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Solution
f'(x) = e^x - 2. Setting f'(x) = 0 gives e^x = 2, so x = ln(2).
Correct Answer:
B
— 1
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Q. Determine the distance between the points (2, 3) and (5, 7). (2020)
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Solution
Using the distance formula, d = √((5 - 2)² + (7 - 3)²) = √(9 + 16) = √25 = 5.
Correct Answer:
A
— 5
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Q. Determine the distance from the point (3, 4) to the line 2x + 3y - 12 = 0.
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Solution
Using the formula for distance from a point to a line, d = |Ax1 + By1 + C| / sqrt(A^2 + B^2), we find d = |2(3) + 3(4) - 12| / sqrt(2^2 + 3^2) = 3.
Correct Answer:
B
— 3
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Q. Determine the intervals where f(x) = -x^2 + 4x is concave up. (2023)
A.
(-∞, 0)
B.
(0, 2)
C.
(2, ∞)
D.
(0, 4)
Show solution
Solution
f''(x) = -2, which is always negative, indicating concave down everywhere.
Correct Answer:
C
— (2, ∞)
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