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JEE Main MCQ & Objective Questions

The JEE Main exam is a crucial step for students aspiring to enter prestigious engineering colleges in India. It tests not only knowledge but also the ability to apply concepts effectively. Practicing MCQs and objective questions is essential for scoring better, as it helps in familiarizing students with the exam pattern and enhances their problem-solving skills. Engaging with practice questions allows students to identify important questions and strengthen their exam preparation.

What You Will Practise Here

Fundamental concepts of Physics, Chemistry, and Mathematics
Key formulas and their applications in problem-solving
Important definitions and theories relevant to JEE Main
Diagrams and graphical representations for better understanding
Numerical problems and their step-by-step solutions
Previous years' JEE Main questions for real exam experience
Time management strategies while solving MCQs

Exam Relevance

The topics covered in JEE Main are not only significant for the JEE exam but also appear in various CBSE and State Board examinations. Many concepts are shared with the NEET syllabus, making them relevant across multiple competitive exams. Common question patterns include conceptual applications, numerical problems, and theoretical questions that assess a student's understanding of core subjects.

Common Mistakes Students Make

Misinterpreting the question stem, leading to incorrect answers
Neglecting units in numerical problems, which can change the outcome
Overlooking negative marking and not managing time effectively
Relying too heavily on rote memorization instead of understanding concepts
Failing to review and analyze mistakes from practice tests

FAQs

Question: How can I improve my speed in solving JEE Main MCQ questions?
Answer: Regular practice with timed quizzes and focusing on shortcuts can significantly enhance your speed.

Question: Are the JEE Main objective questions similar to previous years' papers?
Answer: Yes, many questions are based on previous years' patterns, so practicing them can be beneficial.

Question: What is the best way to approach JEE Main practice questions?
Answer: Start with understanding the concepts, then attempt practice questions, and finally review your answers to learn from mistakes.

Now is the time to take charge of your preparation! Dive into solving JEE Main MCQs and practice questions to test your understanding and boost your confidence for the exam.

Chemistry Syllabus (JEE Main) Mathematics Syllabus (JEE Main) Physics Syllabus (JEE Main)

Q. A car moves in a circular path of radius 50 m with a constant speed of 20 m/s. What is the centripetal acceleration?

A. 4 m/s²
B. 8 m/s²
C. 10 m/s²
D. 16 m/s²

Solution

Centripetal acceleration (a_c) = v²/r = (20²)/50 = 8 m/s².

Correct Answer: C — 10 m/s²

Q. A car moving with a speed of 30 m/s applies brakes and comes to a stop in 5 seconds. What is the deceleration of the car?

A. 3 m/s²
B. 4 m/s²
C. 5 m/s²
D. 6 m/s²

Solution

Deceleration = (final velocity - initial velocity) / time = (0 - 30) / 5 = -6 m/s².

Correct Answer: A — 3 m/s²

Q. A car of mass 1000 kg accelerates at 2 m/s². What is the net force acting on the car?

A. 2000 N
B. 500 N
C. 1000 N
D. 1500 N

Solution

Using F = ma, the net force is F = 1000 kg * 2 m/s² = 2000 N.

Correct Answer: A — 2000 N

Q. A car of mass 1000 kg accelerates from rest to a speed of 20 m/s in 10 seconds. What is the net force acting on the car? (2000)

A. 100 N
B. 200 N
C. 300 N
D. 400 N

Solution

Acceleration a = (final speed - initial speed) / time = (20 m/s - 0) / 10 s = 2 m/s². Net force F = ma = 1000 kg * 2 m/s² = 2000 N.

Correct Answer: B — 200 N

Q. A car of mass 1000 kg accelerates from rest to a speed of 20 m/s. What is the work done by the engine? (2000)

A. 20000 J
B. 40000 J
C. 50000 J
D. 80000 J

Solution

Kinetic Energy = 0.5 × mass × velocity^2 = 0.5 × 1000 kg × (20 m/s)^2 = 200000 J.

Correct Answer: B — 40000 J

Q. A car of mass 1000 kg accelerates from rest to a speed of 20 m/s. What is the work done on the car?

A. 20000 J
B. 40000 J
C. 80000 J
D. 100000 J

Solution

Kinetic energy = 0.5 × m × v^2 = 0.5 × 1000 kg × (20 m/s)^2 = 200000 J.

Correct Answer: B — 40000 J

Q. A car of mass 1000 kg is moving at a speed of 15 m/s. What is the kinetic energy of the car?

A. 11250 J
B. 22500 J
C. 33750 J
D. 45000 J

Solution

Kinetic energy KE = (1/2)mv² = (1/2)(1000 kg)(15 m/s)² = 11250 J.

Correct Answer: B — 22500 J

Q. A car of mass 1000 kg is moving at a speed of 20 m/s. What is its kinetic energy?

A. 200 J
B. 400 J
C. 200,000 J
D. 400,000 J

Solution

Kinetic energy is given by KE = 0.5mv². Here, KE = 0.5 * 1000 * (20)² = 200,000 J.

Correct Answer: C — 200,000 J

Q. A car of mass 1000 kg is moving at a speed of 20 m/s. What is its total mechanical energy assuming no friction?

A. 200,000 J
B. 400,000 J
C. 300,000 J
D. 100,000 J

Solution

Total Mechanical Energy = Kinetic Energy + Potential Energy. KE = 1/2 * m * v^2 = 1/2 * 1000 * (20^2) = 200,000 J (assuming PE = 0)

Correct Answer: B — 400,000 J

Q. A car of mass 1000 kg is moving with a speed of 20 m/s. What is its kinetic energy?

A. 200,000 J
B. 400,000 J
C. 800,000 J
D. 1,000,000 J

Solution

Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 1000 kg × (20 m/s)² = 200,000 J.

Correct Answer: B — 400,000 J

Q. A car of mass 1000 kg is moving with a velocity of 15 m/s. What is the kinetic energy of the car?

A. 11250 J
B. 15000 J
C. 22500 J
D. 30000 J

Solution

Kinetic energy KE = (1/2)mv² = (1/2)(1000 kg)(15 m/s)² = 11250 J.

Correct Answer: A — 11250 J

Q. A car of mass 1000 kg is moving with a velocity of 20 m/s. If the brakes are applied and the car comes to a stop in 5 seconds, what is the average force applied by the brakes?

A. 2000 N
B. 4000 N
C. 5000 N
D. 6000 N

Solution

The change in momentum is 1000 kg * 20 m/s = 20000 kg·m/s. The average force is F = Δp/Δt = 20000 kg·m/s / 5 s = 4000 N.

Correct Answer: B — 4000 N

Q. A car of mass 1000 kg is moving with a velocity of 20 m/s. What is the momentum of the car?

A. 2000 kg·m/s
B. 10000 kg·m/s
C. 5000 kg·m/s
D. 40000 kg·m/s

Solution

Momentum p = mv = 1000 kg * 20 m/s = 20000 kg·m/s.

Correct Answer: B — 10000 kg·m/s

Q. A car of mass 1000 kg is moving with a velocity of 20 m/s. What is the net force required to bring it to rest in 5 seconds?

A. 4000 N
B. 2000 N
C. 1000 N
D. 500 N

Solution

First, find the deceleration: a = (final velocity - initial velocity) / time = (0 - 20 m/s) / 5 s = -4 m/s². Then, F = ma = 1000 kg * 4 m/s² = 4000 N.

Correct Answer: A — 4000 N

Q. A car travels 100 m in 4 seconds. What is its average speed?

A. 20 m/s
B. 25 m/s
C. 30 m/s
D. 35 m/s

Solution

Average speed = total distance / total time = 100 m / 4 s = 25 m/s.

Correct Answer: B — 25 m/s

Q. A car travels 100 m in 5 seconds. What is its average speed?

A. 20 m/s
B. 25 m/s
C. 15 m/s
D. 30 m/s

Solution

Average speed = total distance / total time = 100 m / 5 s = 20 m/s.

Correct Answer: B — 25 m/s

Q. A car travels 100 m north and then 100 m east. What is the magnitude of the displacement from the starting point? (2000)

A. 100 m
B. 141.42 m
C. 200 m
D. 50 m

Solution

Displacement = √(100^2 + 100^2) = √20000 = 141.42 m.

Correct Answer: B — 141.42 m

Q. A car travels around a circular track of radius 50 m at a speed of 15 m/s. What is the centripetal force acting on the car if its mass is 1000 kg?

A. 450 N
B. 225 N
C. 150 N
D. 75 N

Solution

Centripetal force (F_c) = mv²/r = 1000 kg * (15 m/s)² / 50 m = 4500 N.

Correct Answer: A — 450 N

Q. A car travels at 90 km/h and a truck at 60 km/h in opposite directions. What is the relative speed of the car with respect to the truck?

A. 30 km/h
B. 60 km/h
C. 150 km/h
D. 90 km/h

Solution

Relative speed = Speed of car + Speed of truck = 90 km/h + 60 km/h = 150 km/h.

Correct Answer: C — 150 km/h

Q. A car travels at a speed of 80 km/h and a bike travels at 60 km/h. If they start from the same point and travel in the same direction, how far apart will they be after 1 hour?

A. 20 km
B. 10 km
C. 30 km
D. 40 km

Solution

Relative speed = 80 - 60 = 20 km/h. Distance apart after 1 hour = 20 km.

Correct Answer: A — 20 km

Q. A car travels at a speed of 80 km/h and a truck travels at 60 km/h in the same direction. How far apart will they be after 2 hours if they start together?

A. 20 km
B. 40 km
C. 60 km
D. 80 km

Solution

Relative speed = 80 - 60 = 20 km/h. Distance = speed * time = 20 * 2 = 40 km.

Correct Answer: B — 40 km

Q. A car's speed is measured as 60 km/h with a possible error of 2 km/h. What is the minimum speed?

A. 58 km/h
B. 60 km/h
C. 62 km/h
D. 55 km/h

Solution

Minimum speed = Measured speed - Error = 60 - 2 = 58 km/h.

Correct Answer: A — 58 km/h

Q. A car's speed is measured as 60 km/h with a relative error of 5%. What is the absolute error?

A. 3 km/h
B. 2 km/h
C. 4 km/h
D. 5 km/h

Solution

Absolute error = Relative error * Measured value = 0.05 * 60 = 3 km/h.

Correct Answer: A — 3 km/h

Q. A card is drawn from a standard deck of 52 cards. What is the probability that it is a heart given that it is a red card?

A. 1/2
B. 1/4
C. 1/3
D. 1/13

Solution

There are 26 red cards (hearts and diamonds). The probability of drawing a heart given that it is red is 13/26 = 1/2.

Correct Answer: A — 1/2

Q. A card is drawn from a standard deck of 52 cards. What is the probability that the card drawn is a queen?

A. 1/13
B. 1/52
C. 1/26
D. 3/52

Solution

There are 4 queens in a deck of 52 cards. Probability = 4/52 = 1/13.

Correct Answer: A — 1/13

Q. A card is drawn from a standard deck of 52 cards. What is the probability that the card is a heart given that it is a red card?

A. 1/2
B. 1/4
C. 1/3
D. 2/3

Solution

There are 26 red cards (hearts and diamonds). The probability of drawing a heart given that the card is red is 13/26 = 1/2.

Correct Answer: A — 1/2

Q. A card is drawn from a standard deck of 52 cards. What is the probability that the card drawn is a heart?

A. 1/4
B. 1/13
C. 1/52
D. 3/13

Solution

There are 13 hearts in a deck of 52 cards. The probability of drawing a heart is 13/52 = 1/4.

Correct Answer: A — 1/4

Q. A changing magnetic field induces a current in a closed loop. What is this phenomenon called?

A. Electromagnetic induction
B. Magnetic resonance
C. Electrolysis
D. Magnetism

Solution

This phenomenon is known as electromagnetic induction, where a changing magnetic field induces an electromotive force (EMF) in a conductor.

Correct Answer: A — Electromagnetic induction

Q. A changing magnetic field induces an electric field. This phenomenon is known as?

A. Electromagnetic induction
B. Electrostatics
C. Magnetostatics
D. Electrodynamics

Solution

The phenomenon of a changing magnetic field inducing an electric field is known as electromagnetic induction.

Correct Answer: A — Electromagnetic induction

Q. A charge of +10μC is placed at the origin. What is the electric potential at a point 2m away from the charge?

A. 4500 V
B. 2250 V
C. 5000 V
D. 1000 V

Solution

V = k * q / r = (9 × 10^9) * (10 × 10^-6) / 2 = 4500 V.

Correct Answer: B — 2250 V

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