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Q. A car moves in a circular path of radius 50 m with a constant speed of 20 m/s. What is the centripetal acceleration?

A. 4 m/s²
B. 8 m/s²
C. 10 m/s²
D. 16 m/s²

Solution

Centripetal acceleration (a_c) = v²/r = (20²)/50 = 8 m/s².

Correct Answer: C — 10 m/s²

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Q. A car moving with a speed of 30 m/s applies brakes and comes to a stop in 5 seconds. What is the deceleration of the car?

A. 3 m/s²
B. 4 m/s²
C. 5 m/s²
D. 6 m/s²

Solution

Deceleration = (final velocity - initial velocity) / time = (0 - 30) / 5 = -6 m/s².

Correct Answer: A — 3 m/s²

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Q. A car of mass 1000 kg accelerates at 2 m/s². What is the net force acting on the car?

A. 2000 N
B. 500 N
C. 1000 N
D. 1500 N

Solution

Using F = ma, the net force is F = 1000 kg * 2 m/s² = 2000 N.

Correct Answer: A — 2000 N

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Q. A car of mass 1000 kg accelerates from rest to a speed of 20 m/s in 10 seconds. What is the net force acting on the car? (2000)

A. 100 N
B. 200 N
C. 300 N
D. 400 N

Solution

Acceleration a = (final speed - initial speed) / time = (20 m/s - 0) / 10 s = 2 m/s². Net force F = ma = 1000 kg * 2 m/s² = 2000 N.

Correct Answer: B — 200 N

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Q. A car of mass 1000 kg accelerates from rest to a speed of 20 m/s. What is the work done by the engine? (2000)

A. 20000 J
B. 40000 J
C. 50000 J
D. 80000 J

Solution

Kinetic Energy = 0.5 × mass × velocity^2 = 0.5 × 1000 kg × (20 m/s)^2 = 200000 J.

Correct Answer: B — 40000 J

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Q. A car of mass 1000 kg accelerates from rest to a speed of 20 m/s. What is the work done on the car?

A. 20000 J
B. 40000 J
C. 80000 J
D. 100000 J

Solution

Kinetic energy = 0.5 × m × v^2 = 0.5 × 1000 kg × (20 m/s)^2 = 200000 J.

Correct Answer: B — 40000 J

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Q. A car of mass 1000 kg is moving at a speed of 15 m/s. What is the kinetic energy of the car?

A. 11250 J
B. 22500 J
C. 33750 J
D. 45000 J

Solution

Kinetic energy KE = (1/2)mv² = (1/2)(1000 kg)(15 m/s)² = 11250 J.

Correct Answer: B — 22500 J

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Q. A car of mass 1000 kg is moving at a speed of 20 m/s. What is its kinetic energy?

A. 200 J
B. 400 J
C. 200,000 J
D. 400,000 J

Solution

Kinetic energy is given by KE = 0.5mv². Here, KE = 0.5 * 1000 * (20)² = 200,000 J.

Correct Answer: C — 200,000 J

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Q. A car of mass 1000 kg is moving at a speed of 20 m/s. What is its total mechanical energy assuming no friction?

A. 200,000 J
B. 400,000 J
C. 300,000 J
D. 100,000 J

Solution

Total Mechanical Energy = Kinetic Energy + Potential Energy. KE = 1/2 * m * v^2 = 1/2 * 1000 * (20^2) = 200,000 J (assuming PE = 0)

Correct Answer: B — 400,000 J

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Q. A car of mass 1000 kg is moving with a speed of 20 m/s. What is its kinetic energy?

A. 200,000 J
B. 400,000 J
C. 800,000 J
D. 1,000,000 J

Solution

Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 1000 kg × (20 m/s)² = 200,000 J.

Correct Answer: B — 400,000 J

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Q. A car of mass 1000 kg is moving with a velocity of 15 m/s. What is the kinetic energy of the car?

A. 11250 J
B. 15000 J
C. 22500 J
D. 30000 J

Solution

Kinetic energy KE = (1/2)mv² = (1/2)(1000 kg)(15 m/s)² = 11250 J.

Correct Answer: A — 11250 J

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Q. A car of mass 1000 kg is moving with a velocity of 20 m/s. If the brakes are applied and the car comes to a stop in 5 seconds, what is the average force applied by the brakes?

A. 2000 N
B. 4000 N
C. 5000 N
D. 6000 N

Solution

The change in momentum is 1000 kg * 20 m/s = 20000 kg·m/s. The average force is F = Δp/Δt = 20000 kg·m/s / 5 s = 4000 N.

Correct Answer: B — 4000 N

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Q. A car of mass 1000 kg is moving with a velocity of 20 m/s. What is the momentum of the car?

A. 2000 kg·m/s
B. 10000 kg·m/s
C. 5000 kg·m/s
D. 40000 kg·m/s

Solution

Momentum p = mv = 1000 kg * 20 m/s = 20000 kg·m/s.

Correct Answer: B — 10000 kg·m/s

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Q. A car of mass 1000 kg is moving with a velocity of 20 m/s. What is the net force required to bring it to rest in 5 seconds?

A. 4000 N
B. 2000 N
C. 1000 N
D. 500 N

Solution

First, find the deceleration: a = (final velocity - initial velocity) / time = (0 - 20 m/s) / 5 s = -4 m/s². Then, F = ma = 1000 kg * 4 m/s² = 4000 N.

Correct Answer: A — 4000 N

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Q. A car travels 100 m in 4 seconds. What is its average speed?

A. 20 m/s
B. 25 m/s
C. 30 m/s
D. 35 m/s

Solution

Average speed = total distance / total time = 100 m / 4 s = 25 m/s.

Correct Answer: B — 25 m/s

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Q. A car travels 100 m in 5 seconds. What is its average speed?

A. 20 m/s
B. 25 m/s
C. 15 m/s
D. 30 m/s

Solution

Average speed = total distance / total time = 100 m / 5 s = 20 m/s.

Correct Answer: B — 25 m/s

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Q. A car travels 100 m north and then 100 m east. What is the magnitude of the displacement from the starting point? (2000)

A. 100 m
B. 141.42 m
C. 200 m
D. 50 m

Solution

Displacement = √(100^2 + 100^2) = √20000 = 141.42 m.

Correct Answer: B — 141.42 m

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Q. A car travels around a circular track of radius 50 m at a speed of 15 m/s. What is the centripetal force acting on the car if its mass is 1000 kg?

A. 450 N
B. 225 N
C. 150 N
D. 75 N

Solution

Centripetal force (F_c) = mv²/r = 1000 kg * (15 m/s)² / 50 m = 4500 N.

Correct Answer: A — 450 N

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Q. A car travels at 90 km/h and a truck at 60 km/h in opposite directions. What is the relative speed of the car with respect to the truck?

A. 30 km/h
B. 60 km/h
C. 150 km/h
D. 90 km/h

Solution

Relative speed = Speed of car + Speed of truck = 90 km/h + 60 km/h = 150 km/h.

Correct Answer: C — 150 km/h

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Q. A car travels at a speed of 80 km/h and a bike travels at 60 km/h. If they start from the same point and travel in the same direction, how far apart will they be after 1 hour?

A. 20 km
B. 10 km
C. 30 km
D. 40 km

Solution

Relative speed = 80 - 60 = 20 km/h. Distance apart after 1 hour = 20 km.

Correct Answer: A — 20 km

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Q. A car travels at a speed of 80 km/h and a truck travels at 60 km/h in the same direction. How far apart will they be after 2 hours if they start together?

A. 20 km
B. 40 km
C. 60 km
D. 80 km

Solution

Relative speed = 80 - 60 = 20 km/h. Distance = speed * time = 20 * 2 = 40 km.

Correct Answer: B — 40 km

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Q. A car's speed is measured as 60 km/h with a possible error of 2 km/h. What is the minimum speed?

A. 58 km/h
B. 60 km/h
C. 62 km/h
D. 55 km/h

Solution

Minimum speed = Measured speed - Error = 60 - 2 = 58 km/h.

Correct Answer: A — 58 km/h

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Q. A car's speed is measured as 60 km/h with a relative error of 5%. What is the absolute error?

A. 3 km/h
B. 2 km/h
C. 4 km/h
D. 5 km/h

Solution

Absolute error = Relative error * Measured value = 0.05 * 60 = 3 km/h.

Correct Answer: A — 3 km/h

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Q. A card is drawn from a standard deck of 52 cards. What is the probability that it is a heart given that it is a red card?

A. 1/2
B. 1/4
C. 1/3
D. 1/13

Solution

There are 26 red cards (hearts and diamonds). The probability of drawing a heart given that it is red is 13/26 = 1/2.

Correct Answer: A — 1/2

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Q. A card is drawn from a standard deck of 52 cards. What is the probability that the card drawn is a queen?

A. 1/13
B. 1/52
C. 1/26
D. 3/52

Solution

There are 4 queens in a deck of 52 cards. Probability = 4/52 = 1/13.

Correct Answer: A — 1/13

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Q. A card is drawn from a standard deck of 52 cards. What is the probability that the card is a heart given that it is a red card?

A. 1/2
B. 1/4
C. 1/3
D. 2/3

Solution

There are 26 red cards (hearts and diamonds). The probability of drawing a heart given that the card is red is 13/26 = 1/2.

Correct Answer: A — 1/2

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Q. A card is drawn from a standard deck of 52 cards. What is the probability that the card drawn is a heart?

A. 1/4
B. 1/13
C. 1/52
D. 3/13

Solution

There are 13 hearts in a deck of 52 cards. The probability of drawing a heart is 13/52 = 1/4.

Correct Answer: A — 1/4

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Q. A changing magnetic field induces a current in a closed loop. What is this phenomenon called?

A. Electromagnetic induction
B. Magnetic resonance
C. Electrolysis
D. Magnetism

Solution

This phenomenon is known as electromagnetic induction, where a changing magnetic field induces an electromotive force (EMF) in a conductor.

Correct Answer: A — Electromagnetic induction

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Q. A changing magnetic field induces an electric field. This phenomenon is known as?

A. Electromagnetic induction
B. Electrostatics
C. Magnetostatics
D. Electrodynamics

Solution

The phenomenon of a changing magnetic field inducing an electric field is known as electromagnetic induction.

Correct Answer: A — Electromagnetic induction

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Q. A charge of +10μC is placed at the origin. What is the electric potential at a point 2m away from the charge?

A. 4500 V
B. 2250 V
C. 5000 V
D. 1000 V

Solution

V = k * q / r = (9 × 10^9) * (10 × 10^-6) / 2 = 4500 V.

Correct Answer: B — 2250 V

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Engineering & Architecture Admissions

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