Using the formula v² = u² + 2as, where v = 0, u = 20 m/s, and a = -g = -10 m/s², we get 0 = (20)² + 2(-10)s, solving gives s = 20 m.

Using the formula: height = (initial velocity^2) / (2 * g), where g = 9.8 m/s². Height = (15^2) / (2 * 9.8) = 11.25 m.

Using the formula h = v² / (2g), h = (15 m/s)² / (2 × 9.8 m/s²) = 11.5 m.

Using the formula h = v²/(2g), we have h = (20 m/s)² / (2 * 10 m/s²) = 20 m.

Using the formula v² = u² + 2as, where v = 0, u = 20 m/s, and a = -g = -10 m/s². 0 = (20)² + 2(-10)h, solving gives h = 20 m.

Using the formula h = v²/(2g), we have h = (20 m/s)² / (2 * 10 m/s²) = 20 m.

Using the equation v² = u² + 2as, where v = 0, u = 30 m/s, and a = -9.8 m/s² (acceleration due to gravity), we have 0 = (30)² + 2*(-9.8)*s. Solving gives s = 45.92 m, approximately 45 m.

Using conservation of energy, initial kinetic energy = potential energy at maximum height. 0.5mv² = mgh. Solving gives h = v²/(2g) = (30)²/(2 * 9.8) = 45.9 m.

At the highest point, the tension can be zero if the centripetal force is provided entirely by the weight.

At the highest point, the centripetal force is provided by the weight, so T + mg = mv²/r, T = 0.

At the highest point, T + mg = mv²/r. 2 N + 3 N = mv²/1. v² = 5, v = √5 ≈ 2.24 m/s.

Using conservation of energy, mgh = (1/2)mv^2 + (1/2)(2/5)mv^2. Solving gives the moment of inertia I = (2/5)m(10^2).

The potential energy at the top of the ramp is given by PE = mgh.

Using conservation of energy, potential energy mgh converts to kinetic energy (1/2 mv^2). Thus, v = √(2gh).

Using conservation of energy, the final velocity v at the bottom is given by v = √(2gh).

The relationship is given by v = Rω, where v is the linear speed, R is the radius, and ω is the angular speed.

The relationship between linear speed and angular speed for rolling without slipping is ω = v/R.

The moment of inertia of a solid sphere is (2/5)MR^2. If the radius is doubled, the moment of inertia increases by a factor of 4.

The moment of inertia for a solid sphere is (2/5)MR^2. If the radius is doubled, the moment of inertia increases by a factor of 4.

For rolling without slipping, the relationship is v = ωR, where v is linear velocity, ω is angular velocity, and R is the radius.

Interest = Principal * Rate * Time = $1,000 * 0.05 * 3 = $150.

Sarah read the most books with a total of 25.

Activity C took the least time with 4 hours.

Expected successful throws = 75% of 20 = 0.75 * 20 = 15.

Expected successful throws = 75% of 20 = 0.75 * 20 = 15.

Expected successful shots = 75% of 20 = 0.75 * 20 = 15.

Expected successful shots = 75% of 40 = 0.75 * 40 = 30 shots.

Using Snell's law, sin(θ2) = sin(60)/1.5, we find θ2 = 30 degrees.

Using Snell's law, n1 * sin(θ1) = n2 * sin(θ2). Here, n1 = 1 (air), θ1 = 45 degrees, n2 = 1.5 (prism). Solving gives θ2 ≈ 30 degrees.

Critical angle θc = sin⁻¹(n2/n1) = sin⁻¹(1.33/2.42) ≈ 36.9°.