Q. What is the equivalent resistance of three resistors of 4 Ω, 6 Ω, and 12 Ω connected in series?
A.
22 Ω
B.
18 Ω
C.
16 Ω
D.
14 Ω
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Solution
Equivalent resistance R_eq = R₁ + R₂ + R₃ = 4 Ω + 6 Ω + 12 Ω = 22 Ω.
Correct Answer:
A
— 22 Ω
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Q. What is the equivalent resistance of three resistors of 4 Ω, 6 Ω, and 12 Ω in series?
A.
22 Ω
B.
18 Ω
C.
16 Ω
D.
12 Ω
Show solution
Solution
In series, R_eq = R1 + R2 + R3 = 4 Ω + 6 Ω + 12 Ω = 22 Ω.
Correct Answer:
A
— 22 Ω
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Q. What is the equivalent resistance of three resistors, 2Ω, 3Ω, and 6Ω, connected in parallel?
A.
1Ω
B.
0.5Ω
C.
1.5Ω
D.
2.5Ω
Show solution
Solution
1/R_total = 1/R1 + 1/R2 + 1/R3 = 1/2 + 1/3 + 1/6. R_total = 1.5Ω.
Correct Answer:
C
— 1.5Ω
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Q. What is the equivalent resistance of two resistors, 4 Ω and 6 Ω, connected in parallel?
A.
2.4 Ω
B.
10 Ω
C.
24 Ω
D.
1.5 Ω
Show solution
Solution
1/R_total = 1/R1 + 1/R2 = 1/4 + 1/6 = 5/12, thus R_total = 12/5 Ω = 2.4 Ω.
Correct Answer:
A
— 2.4 Ω
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Q. What is the equivalent resistance of two resistors, R1 = 6Ω and R2 = 3Ω, connected in parallel?
A.
2Ω
B.
9Ω
C.
18Ω
D.
1.5Ω
Show solution
Solution
In parallel, the equivalent resistance is given by 1/R_eq = 1/R1 + 1/R2, so 1/R_eq = 1/6 + 1/3 = 1/2, thus R_eq = 2Ω.
Correct Answer:
A
— 2Ω
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Q. What is the equivalent resistance of two resistors, R1 = 6Ω and R2 = 3Ω, connected in series?
Show solution
Solution
In series, the equivalent resistance is R_eq = R1 + R2 = 6Ω + 3Ω = 9Ω.
Correct Answer:
C
— 9Ω
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Q. What is the expression for the capacitive reactance (Xc) in terms of frequency (f) and capacitance (C)?
A.
Xc = 1/(2πfC)
B.
Xc = 2πfC
C.
Xc = 1/(fC)
D.
Xc = 2πf/C
Show solution
Solution
The capacitive reactance is given by Xc = 1/(2πfC), where f is the frequency and C is the capacitance.
Correct Answer:
A
— Xc = 1/(2πfC)
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Q. What is the expression for the total current (I) in a parallel circuit with two resistors (R1 and R2)?
A.
I = I1 + I2
B.
I = I1 * I2
C.
I = I1 / I2
D.
I = I1 - I2
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Solution
In a parallel circuit, the total current is the sum of the currents through each resistor: I = I1 + I2.
Correct Answer:
A
— I = I1 + I2
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Q. What is the expression for the total energy stored in a capacitor (U) in terms of capacitance (C) and voltage (V)?
A.
U = 1/2 * C * V^2
B.
U = C * V^2
C.
U = V / (2 * C)
D.
U = C * V
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Solution
The total energy stored in a capacitor is given by U = 1/2 * C * V^2.
Correct Answer:
A
— U = 1/2 * C * V^2
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Q. What is the final charge (Q) on a capacitor in an RC circuit when a voltage (V) is applied?
A.
Q = CV
B.
Q = V/R
C.
Q = V^2/R
D.
Q = I * t
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Solution
The final charge on a capacitor when a voltage V is applied is given by Q = CV, where C is the capacitance.
Correct Answer:
A
— Q = CV
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Q. What is the final charge on a capacitor (Q) in an RC circuit after a long time if the voltage across it is 5V and the capacitance is 200 microfarads?
A.
0.001 C
B.
0.01 C
C.
0.0001 C
D.
0.1 C
Show solution
Solution
The charge Q is given by Q = C * V = 200 x 10^-6 F * 5 V = 0.001 C.
Correct Answer:
A
— 0.001 C
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Q. What is the final voltage across a capacitor after it has been fully charged in an RC circuit?
A.
0V
B.
V0
C.
V0/2
D.
V0/e
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Solution
The final voltage across a capacitor after it has been fully charged in an RC circuit is V0, where V0 is the supply voltage.
Correct Answer:
B
— V0
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Q. What is the final voltage across a capacitor in a series RC circuit after a long time?
A.
0V
B.
V0
C.
V0/2
D.
V0/e
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Solution
The final voltage across a capacitor in a series RC circuit after a long time is V0, where V0 is the supply voltage.
Correct Answer:
B
— V0
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Q. What is the final voltage across the capacitor in a charging RC circuit if the applied voltage is 12V?
A.
0V
B.
6V
C.
12V
D.
24V
Show solution
Solution
The final voltage across the capacitor in a charging RC circuit will equal the applied voltage, which is 12V.
Correct Answer:
C
— 12V
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Q. What is the focal length of a converging lens if it forms a real image at a distance of 30 cm from the lens when the object is placed at 60 cm?
A.
10 cm
B.
20 cm
C.
30 cm
D.
40 cm
Show solution
Solution
Using the lens formula (1/f = 1/v - 1/u), we find f = 1/(1/30 - 1/60) = 20 cm.
Correct Answer:
B
— 20 cm
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Q. What is the focal length of a convex lens if it forms a real image at a distance of 30 cm from the lens when the object is placed at 15 cm?
A.
10 cm
B.
15 cm
C.
20 cm
D.
30 cm
Show solution
Solution
Using the lens formula 1/f = 1/v - 1/u, we find f = 1/(1/30 - 1/15) = 20 cm.
Correct Answer:
C
— 20 cm
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Q. What is the force between two charges of +1 µC and +1 µC separated by 0.1 m?
A.
0.09 N
B.
0.18 N
C.
0.02 N
D.
0.04 N
Show solution
Solution
F = k * |q1 * q2| / r² = (8.99 x 10^9 N m²/C²) * (1 x 10^-6 C)² / (0.1 m)² = 0.09 N.
Correct Answer:
B
— 0.18 N
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Q. What is the force between two charges of +1 µC and +1 µC separated by 1 m?
A.
8.99 N
B.
0.009 N
C.
0.089 N
D.
0.899 N
Show solution
Solution
F = k * |q1 * q2| / r^2 = (8.99 x 10^9 N m²/C²) * (1 x 10^-6 C)² / (1 m)² = 8.99 N.
Correct Answer:
A
— 8.99 N
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Q. What is the force between two charges of +2 µC and -3 µC separated by a distance of 0.5 m?
A.
-1.08 N
B.
-0.72 N
C.
1.08 N
D.
0.72 N
Show solution
Solution
Using Coulomb's law: F = k * |q1 * q2| / r^2 = (8.99 x 10^9 N m²/C²) * |(2 x 10^-6 C) * (-3 x 10^-6 C)| / (0.5 m)^2 = -1.08 N.
Correct Answer:
A
— -1.08 N
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Q. What is the force between two charges of 1 microcoulomb each, separated by a distance of 0.5 meters?
A.
0.36 N
B.
0.72 N
C.
0.18 N
D.
0.09 N
Show solution
Solution
Using Coulomb's law, F = k * |q1 * q2| / r^2. Here, F = (8.99 x 10^9) * (1 x 10^-6)^2 / (0.5^2) = 0.36 N.
Correct Answer:
A
— 0.36 N
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Q. What is the force between two point charges of +2 µC and -3 µC separated by a distance of 0.5 m?
A.
1.2 N
B.
0.24 N
C.
0.48 N
D.
0.96 N
Show solution
Solution
Using Coulomb's law, F = k * |q1 * q2| / r^2 = (8.99 x 10^9 N m²/C²) * |(2 x 10^-6 C) * (-3 x 10^-6 C)| / (0.5 m)^2 = 0.24 N.
Correct Answer:
B
— 0.24 N
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Q. What is the force between two point charges of +2 µC and -3 µC separated by a distance of 0.5 m in a vacuum?
A.
-1.08 N
B.
-0.72 N
C.
1.08 N
D.
0.72 N
Show solution
Solution
Using Coulomb's law, F = k * |q1 * q2| / r^2 = (8.99 x 10^9 N m²/C²) * |(2 x 10^-6 C) * (-3 x 10^-6 C)| / (0.5 m)^2 = -1.08 N.
Correct Answer:
A
— -1.08 N
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Q. What is the force between two point charges of +3 µC and -2 µC separated by a distance of 0.5 m?
A.
1.2 N
B.
0.6 N
C.
0.4 N
D.
0.8 N
Show solution
Solution
Using Coulomb's law, F = k * |q1 * q2| / r^2 = (8.99 x 10^9 N m²/C²) * |3 x 10^-6 C * -2 x 10^-6 C| / (0.5 m)² = 1.2 N.
Correct Answer:
A
— 1.2 N
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Q. What is the force on a charge of +1 µC placed in an electric field of 1000 N/C?
A.
0.001 N
B.
0.1 N
C.
1 N
D.
10 N
Show solution
Solution
F = q * E = (1 x 10^-6 C) * (1000 N/C) = 0.001 N.
Correct Answer:
B
— 0.1 N
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Q. What is the force on a charge of +1 µC placed in an electric field of 500 N/C?
A.
0.5 N
B.
1 N
C.
2 N
D.
0.2 N
Show solution
Solution
F = q * E = (1 x 10^-6 C) * (500 N/C) = 0.5 N.
Correct Answer:
A
— 0.5 N
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Q. What is the force required to keep a 10 kg object moving at a constant velocity on a frictionless surface?
A.
0 N
B.
10 N
C.
100 N
D.
1 N
Show solution
Solution
On a frictionless surface, no net force is required to maintain constant velocity, so the force is 0 N.
Correct Answer:
A
— 0 N
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Q. What is the force required to keep a 2 kg object moving in a circle of radius 1 m at a speed of 3 m/s?
A.
6 N
B.
9 N
C.
3 N
D.
12 N
Show solution
Solution
Centripetal force F = mv²/r = 2 kg * (3 m/s)² / 1 m = 18 N.
Correct Answer:
B
— 9 N
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Q. What is the formula for calculating the current (I) in an RC circuit after a time (t) when a voltage (V) is applied?
A.
I = V/R
B.
I = V(1 - e^(-t/RC))
C.
I = V/R * e^(-t/RC)
D.
I = V * e^(-t/RC)
Show solution
Solution
The current in an RC circuit after a time t is given by I = V(1 - e^(-t/RC)), where V is the voltage, R is the resistance, and C is the capacitance.
Correct Answer:
B
— I = V(1 - e^(-t/RC))
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Q. What is the formula for calculating the focal length of a lens?
A.
1/f = 1/v + 1/u
B.
f = v + u
C.
f = v - u
D.
1/f = v - u
Show solution
Solution
The lens formula is given by 1/f = 1/v + 1/u, where f is the focal length, v is the image distance, and u is the object distance.
Correct Answer:
A
— 1/f = 1/v + 1/u
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Q. What is the formula for calculating the force acting on an object?
A.
F = ma
B.
F = mv
C.
F = m/g
D.
F = mg
Show solution
Solution
The force acting on an object is calculated using Newton's second law, F = ma, where F is force, m is mass, and a is acceleration.
Correct Answer:
A
— F = ma
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