The function is a downward-opening parabola. The maximum occurs at x = -b/(2a) = -8/(2*-2) = 2. f(2) = -2(2^2) + 8(2) - 3 = 8.

The function is a downward-opening parabola. The maximum occurs at x = -b/(2a) = 8/(2*2) = 2. f(2) = -2(2^2) + 8(2) - 5 = 9.

The vertex occurs at x = 2. f(2) = -2^2 + 4(2) + 1 = 9, which is the maximum value.

The vertex occurs at x = 3. f(3) = -3^2 + 6(3) - 8 = 6.

First, arrange the numbers: 10, 11, 12, 13, 14, 15. Since there are 6 numbers (even), the median is the average of the 3rd and 4th numbers: (12 + 13) / 2 = 12.5.

First, arrange the numbers: 10, 11, 12, 13, 14, 15. Since there are 6 numbers (even), the median is the average of the 3rd and 4th numbers: (12 + 13) / 2 = 12.5.

First, arrange the numbers: 10, 11, 12, 13, 14, 15. The median is the average of the 3rd and 4th numbers: (12 + 13) / 2 = 12.5.

Arranging the numbers: 1, 3, 3, 6, 7, 8, 9. Median = 6 (middle value).

Arranging the numbers: 1, 3, 3, 6, 7, 8, 9. Median = 6 (middle value).

Arrange the numbers: 10, 20, 30, 40, 50, 60, 70, 80. The median is the average of the 4th and 5th values: (40 + 50) / 2 = 45.

Arranging the numbers: 1, 2, 3, 4. Median = (2 + 3) / 2 = 2.5.

Arrange the numbers: 2, 3, 6, 8, 9. The median is the middle number, which is 6.

Arrange the numbers: 10, 12, 15, 18, 20, 25. Since there are 6 numbers, the median is the average of the 3rd and 4th values: (15 + 18) / 2 = 16.5.

Midpoint = ((1+3)/2, (2+4)/2) = (2, 3).

Midpoint M = ((x1 + x2)/2, (y1 + y2)/2) = ((2 + 4)/2, (3 + 7)/2) = (3, 5).

Midpoint = ((2+4)/2, (3+7)/2) = (3, 5).

The minimum occurs at x = -b/(2a) = 16/(2*4) = 2. f(2) = 4(2^2) - 16(2) + 15 = 1.

The vertex gives the minimum at x = 2. f(2) = 4(2^2) - 16(2) + 20 = 4.

The vertex is at x = 8/(2*4) = 1. The minimum value is f(1) = 4(1)^2 - 8(1) + 3 = -1.

The minimum occurs at x = -b/(2a) = -6/(2*1) = -3. f(-3) = (-3)^2 + 6(-3) + 10 = 1.

The vertex form gives the minimum at x = 2. f(2) = 2.

The vertex form gives the minimum at x = 2. f(2) = 2^2 - 4*2 + 7 = 3.

The vertex form gives the minimum at x = 2. f(2) = 2^2 - 4*2 + 7 = 3.

The minimum occurs at x = 2. f(2) = 2(2^2) - 8(2) + 10 = 6.

The vertex occurs at x = -b/(2a) = 12/6 = 2. f(2) = 3(2^2) - 12(2) + 7 = 1.

The minimum occurs at x = -b/(2a) = 12/(2*3) = 2. f(2) = 3(2^2) - 12(2) + 9 = 3.

The vertex of the parabola occurs at x = 2. f(2) = 2^2 - 4(2) + 5 = 1, which is the minimum value.

f'(x) = 4x^3 - 16x. Setting f'(x) = 0 gives x = 0, ±2. f(2) = 0, which is the minimum value.

The series consists of every second letter in the alphabet: A, C, E, G, I.

Each number is multiplied by 2. 48 * 2 = 96.