JEE Main Preparation Resources for Competitive Exams

My Learning Cart

JEE Main

Download Q&A

JEE Main MCQ & Objective Questions

The JEE Main exam is a crucial step for students aspiring to enter prestigious engineering colleges in India. It tests not only knowledge but also the ability to apply concepts effectively. Practicing MCQs and objective questions is essential for scoring better, as it helps in familiarizing students with the exam pattern and enhances their problem-solving skills. Engaging with practice questions allows students to identify important questions and strengthen their exam preparation.

What You Will Practise Here

Fundamental concepts of Physics, Chemistry, and Mathematics
Key formulas and their applications in problem-solving
Important definitions and theories relevant to JEE Main
Diagrams and graphical representations for better understanding
Numerical problems and their step-by-step solutions
Previous years' JEE Main questions for real exam experience
Time management strategies while solving MCQs

Exam Relevance

The topics covered in JEE Main are not only significant for the JEE exam but also appear in various CBSE and State Board examinations. Many concepts are shared with the NEET syllabus, making them relevant across multiple competitive exams. Common question patterns include conceptual applications, numerical problems, and theoretical questions that assess a student's understanding of core subjects.

Common Mistakes Students Make

Misinterpreting the question stem, leading to incorrect answers
Neglecting units in numerical problems, which can change the outcome
Overlooking negative marking and not managing time effectively
Relying too heavily on rote memorization instead of understanding concepts
Failing to review and analyze mistakes from practice tests

FAQs

Question: How can I improve my speed in solving JEE Main MCQ questions?
Answer: Regular practice with timed quizzes and focusing on shortcuts can significantly enhance your speed.

Question: Are the JEE Main objective questions similar to previous years' papers?
Answer: Yes, many questions are based on previous years' patterns, so practicing them can be beneficial.

Question: What is the best way to approach JEE Main practice questions?
Answer: Start with understanding the concepts, then attempt practice questions, and finally review your answers to learn from mistakes.

Now is the time to take charge of your preparation! Dive into solving JEE Main MCQs and practice questions to test your understanding and boost your confidence for the exam.

Chemistry Syllabus (JEE Main) Mathematics Syllabus (JEE Main) Physics Syllabus (JEE Main)

Q. If ΔG is negative for a reaction, what can be inferred about the reaction?

A. The reaction is at equilibrium.
B. The reaction is spontaneous.
C. The reaction is non-spontaneous.
D. The reaction requires energy input.

Solution

A negative ΔG indicates that the reaction is spontaneous.

Correct Answer: B — The reaction is spontaneous.

Q. If ΔG is negative for a reaction, what can be inferred?

A. The reaction is non-spontaneous.
B. The reaction is at equilibrium.
C. The reaction is spontaneous.
D. The reaction requires energy input.

Solution

A negative ΔG indicates that the reaction is spontaneous under the given conditions.

Correct Answer: C — The reaction is spontaneous.

Q. If ΔG is negative, what does it indicate about the reaction?

A. Reaction is at equilibrium
B. Reaction is spontaneous
C. Reaction is non-spontaneous
D. Reaction requires energy input

Solution

A negative ΔG indicates that the reaction is spontaneous.

Correct Answer: B — Reaction is spontaneous

Q. If ΔG is positive, what can be inferred about the reaction?

A. The reaction is spontaneous.
B. The reaction is at equilibrium.
C. The reaction is non-spontaneous.
D. The reaction will proceed in reverse.

Solution

If ΔG is positive, the reaction is non-spontaneous under the given conditions.

Correct Answer: C — The reaction is non-spontaneous.

Q. If ΔH = 100 kJ and ΔS = 0.2 kJ/K, what is ΔG at 298 K?

A. 100 kJ
B. 96 kJ
C. 104 kJ
D. 90 kJ

Solution

ΔG = ΔH - TΔS = 100 kJ - 298 K * 0.2 kJ/K = 100 kJ - 59.6 kJ = 40.4 kJ.

Correct Answer: B — 96 kJ

Q. If ΔH is negative and ΔS is positive, what can be said about ΔG?

A. ΔG is always positive.
B. ΔG is always negative.
C. ΔG can be positive or negative depending on temperature.
D. ΔG is zero.

Solution

If ΔH is negative and ΔS is positive, ΔG will always be negative, indicating that the reaction is spontaneous at all temperatures.

Correct Answer: B — ΔG is always negative.

Q. In a bag containing 3 red, 2 blue, and 5 green balls, what is the probability of drawing a blue ball?

A. 1/5
B. 1/4
C. 1/10
D. 1/2

Solution

Total balls = 3 + 2 + 5 = 10. Probability of drawing a blue ball = Number of blue balls / Total balls = 2/10 = 1/5.

Correct Answer: B — 1/4

Q. In a bag of 10 balls, 4 are red and 6 are blue. What is the probability of picking a red ball?

A. 2/5
B. 4/10
C. 3/5
D. 1/2

Solution

Probability = Number of red balls / Total balls = 4/10 = 2/5.

Correct Answer: B — 4/10

Q. In a balanced Wheatstone bridge, if R1 = 10Ω, R2 = 15Ω, and R3 = 5Ω, what is the value of R4?

A. 7.5Ω
B. 10Ω
C. 15Ω
D. 20Ω

Solution

Using the balance condition R1/R2 = R3/R4, we find R4 = (R2 * R3) / R1 = (15 * 5) / 10 = 7.5Ω.

Correct Answer: A — 7.5Ω

Q. In a balanced Wheatstone bridge, if R1 = 10Ω, R2 = 5Ω, and R3 = 15Ω, what is the value of R4?

A. 7.5Ω
B. 10Ω
C. 12.5Ω
D. 20Ω

Solution

Using the balance condition R1/R2 = R3/R4, we find R4 = (R2 * R3) / R1 = (5 * 15) / 10 = 7.5Ω.

Correct Answer: C — 12.5Ω

Q. In a balanced Wheatstone bridge, the potential difference across the galvanometer is:

A. Equal to the supply voltage.
B. Zero.
C. Equal to the resistance of the galvanometer.
D. Equal to the potential difference across R1.

Solution

In a balanced Wheatstone bridge, the potential difference across the galvanometer is zero.

Correct Answer: B — Zero.

Q. In a balanced Wheatstone bridge, what is the potential difference across the galvanometer?

A. Equal to the supply voltage
B. Zero
C. Equal to the resistance
D. Depends on the resistances

Solution

In a balanced Wheatstone bridge, the potential difference across the galvanometer is zero.

Correct Answer: B — Zero

Q. In a balanced Wheatstone bridge, what is the relationship between the resistances R1, R2, R3, and R4?

A. R1/R2 = R3/R4
B. R1 + R2 = R3 + R4
C. R1 * R4 = R2 * R3
D. R1 - R2 = R3 - R4

Solution

In a balanced Wheatstone bridge, the ratio of the resistances in one arm equals the ratio in the other arm, hence R1/R2 = R3/R4.

Correct Answer: A — R1/R2 = R3/R4

Q. In a binary solution of A and B, if component A has a higher vapor pressure than component B, what can be inferred about the solution?

A. It will show positive deviation from Raoult's Law.
B. It will show negative deviation from Raoult's Law.
C. It will have a lower boiling point than pure A.
D. It will have a higher boiling point than pure B.

Solution

If component A has a higher vapor pressure than component B, the solution will show positive deviation from Raoult's Law.

Correct Answer: A — It will show positive deviation from Raoult's Law.

Q. In a binary solution of A and B, if the mole fraction of A is 0.6, what is the mole fraction of B?

A. 0.4
B. 0.6
C. 1.0
D. 0.2

Solution

The mole fraction of B can be calculated as 1 - mole fraction of A = 1 - 0.6 = 0.4.

Correct Answer: A — 0.4

Q. In a binary solution of A and B, if the vapor pressure of A is 80 mmHg and that of B is 40 mmHg, what is the total vapor pressure when both are present?

A. 40 mmHg
B. 80 mmHg
C. 120 mmHg
D. 100 mmHg

Solution

The total vapor pressure is the sum of the partial pressures: P_total = P_A + P_B = 80 mmHg + 40 mmHg = 120 mmHg.

Correct Answer: D — 100 mmHg

Q. In a binary solution of A and B, if the vapor pressure of A is 80 mmHg and that of B is 40 mmHg, what is the total vapor pressure of the solution if the mole fraction of A is 0.75?

A. 60 mmHg
B. 70 mmHg
C. 80 mmHg
D. 90 mmHg

Solution

Total vapor pressure = P_A + P_B = (0.75 * 80) + (0.25 * 40) = 60 + 10 = 70 mmHg.

Correct Answer: D — 90 mmHg

Q. In a binary solution of A and B, if the vapor pressure of pure A is 150 mmHg and pure B is 50 mmHg, what is the total vapor pressure when the mole fraction of A is 0.4?

A. 90 mmHg
B. 120 mmHg
C. 150 mmHg
D. 100 mmHg

Solution

Total vapor pressure = (X_A * P_A^0) + (X_B * P_B^0) = (0.4 * 150) + (0.6 * 50) = 60 + 30 = 90 mmHg.

Correct Answer: B — 120 mmHg

Q. In a binary solution of A and B, if the vapor pressure of pure A is 80 mmHg and pure B is 40 mmHg, what is the vapor pressure of the solution if the mole fraction of A is 0.6?

A. 64 mmHg
B. 72 mmHg
C. 80 mmHg
D. 56 mmHg

Solution

Using Raoult's Law, the vapor pressure of the solution = (0.6 * 80 mmHg) + (0.4 * 40 mmHg) = 64 mmHg.

Correct Answer: B — 72 mmHg

Q. In a binary solution of A and B, if the vapor pressure of pure A is 80 mmHg and pure B is 40 mmHg, what is the total vapor pressure when the mole fraction of A is 0.5?

A. 60 mmHg
B. 70 mmHg
C. 80 mmHg
D. 50 mmHg

Solution

Total vapor pressure = P_A + P_B = (0.5 * 80) + (0.5 * 40) = 40 + 20 = 60 mmHg.

Correct Answer: B — 70 mmHg

Q. In a binary solution of A and B, if the vapor pressure of pure A is 80 mmHg and pure B is 40 mmHg, what is the vapor pressure of component A if the mole fraction of A is 0.6?

A. 48 mmHg
B. 64 mmHg
C. 80 mmHg
D. 32 mmHg

Solution

Using Raoult's Law, the vapor pressure of A in the solution is 0.6 * 80 mmHg = 48 mmHg.

Correct Answer: B — 64 mmHg

Q. In a binary solution of A and B, if the vapor pressure of pure A is 80 mmHg and that of pure B is 40 mmHg, what is the total vapor pressure when the mole fraction of A is 0.6?

A. 64 mmHg
B. 72 mmHg
C. 80 mmHg
D. 88 mmHg

Solution

Using Raoult's Law, the total vapor pressure = (0.6 * 80 mmHg) + (0.4 * 40 mmHg) = 48 mmHg + 16 mmHg = 64 mmHg.

Correct Answer: B — 72 mmHg

Q. In a binary solution of A and B, if the vapor pressure of pure A is 80 mmHg and that of pure B is 40 mmHg, what is the vapor pressure of the solution if the mole fraction of A is 0.6?

A. 64 mmHg
B. 72 mmHg
C. 80 mmHg
D. 56 mmHg

Solution

Using Raoult's Law, the vapor pressure of the solution = (0.6 * 80 mmHg) + (0.4 * 40 mmHg) = 64 mmHg.

Correct Answer: B — 72 mmHg

Q. In a box of 10 balls, 4 are red and 6 are blue. What is the probability of picking a red ball?

A. 0.4
B. 0.5
C. 0.6
D. 0.7

Solution

Probability = Number of red balls / Total balls = 4/10 = 0.4.

Correct Answer: A — 0.4

Q. In a box of 100 balls, 30 are red, 50 are blue, and 20 are green. What is the probability of picking a red ball?

A. 0.3
B. 0.5
C. 0.2
D. 0.1

Solution

Probability = Number of red balls / Total balls = 30/100 = 0.3.

Correct Answer: A — 0.3

Q. In a box, there are 5 white and 3 black balls. If a ball is drawn and it is black, what is the probability that the next ball drawn is white?

A. 0.625
B. 0.5
C. 0.375
D. 0.25

Solution

After drawing a black ball, there are 5 white and 2 black balls left. The probability of drawing a white ball next is 5/(5+2) = 5/7 ≈ 0.625.

Correct Answer: A — 0.625

Q. In a capacitor, if the plate area is increased while keeping the separation constant, what happens to the capacitance?

A. It increases
B. It decreases
C. It remains the same
D. It becomes zero

Solution

Capacitance is directly proportional to the plate area A. Increasing A increases capacitance.

Correct Answer: A — It increases

Q. In a capacitor, what does the dielectric constant represent?

A. The ability to store charge
B. The ability to resist electric field
C. The ability to increase capacitance
D. The ability to conduct electricity

Solution

The dielectric constant represents the ability of a material to increase the capacitance of a capacitor compared to a vacuum.

Correct Answer: C — The ability to increase capacitance

Q. In a capacitor, what is the relationship between charge (Q), capacitance (C), and voltage (V)?

A. Q = C + V
B. Q = C * V
C. Q = V / C
D. Q = C - V

Solution

The relationship is given by Q = C * V, where Q is the charge, C is the capacitance, and V is the voltage.

Correct Answer: B — Q = C * V

Q. In a capillary tube, how does the viscosity of a fluid affect the height to which it rises?

A. Higher viscosity leads to higher rise
B. Higher viscosity leads to lower rise
C. Viscosity has no effect
D. It depends on the tube diameter

Solution

Higher viscosity results in a lower height of rise in a capillary tube due to greater resistance to flow.

Correct Answer: B — Higher viscosity leads to lower rise

Showing 4411 to 4440 of 10700 (357 Pages)

School

College

Degree

Competitve

Skills

Soulshift Feedback ×

On a scale of 0–10, how likely are you to recommend The Soulshift Academy?

Not likely Very likely