Engineering & Architecture Admissions MCQ & Objective Questions
Engineering & Architecture Admissions play a crucial role in shaping the future of aspiring students in India. With the increasing competition in entrance exams, mastering MCQs and objective questions is essential for effective exam preparation. Practicing these types of questions not only enhances concept clarity but also boosts confidence, helping students score better in their exams.
What You Will Practise Here
Key concepts in Engineering Mathematics
Fundamentals of Physics relevant to architecture and engineering
Important definitions and terminologies in engineering disciplines
Essential formulas for solving objective questions
Diagrams and illustrations for better understanding
Conceptual theories related to structural engineering
Analysis of previous years' important questions
Exam Relevance
The topics covered under Engineering & Architecture Admissions are highly relevant for various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter MCQs that test their understanding of core concepts, application of formulas, and analytical skills. Common question patterns include multiple-choice questions that require selecting the correct answer from given options, as well as assertion-reason type questions that assess deeper comprehension.
Common Mistakes Students Make
Misinterpreting the question stem, leading to incorrect answers.
Overlooking units in numerical problems, which can change the outcome.
Confusing similar concepts or terms, especially in definitions.
Neglecting to review diagrams, which are often crucial for solving problems.
Rushing through practice questions without understanding the underlying concepts.
FAQs
Question: What are the best ways to prepare for Engineering & Architecture Admissions MCQs?Answer: Regular practice of objective questions, reviewing key concepts, and taking mock tests can significantly enhance your preparation.
Question: How can I improve my accuracy in solving MCQs?Answer: Focus on understanding the concepts thoroughly, practice regularly, and learn to eliminate incorrect options to improve accuracy.
Start your journey towards success by solving practice MCQs today! Test your understanding and strengthen your knowledge in Engineering & Architecture Admissions to excel in your exams.
Q. If the vector a = (3, 4) is scaled by a factor of 2, what is the new vector?
A.
(6, 8)
B.
(3, 4)
C.
(1.5, 2)
D.
(0, 0)
Show solution
Solution
New vector = 2 * (3, 4) = (6, 8).
Correct Answer:
A
— (6, 8)
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Q. If the vector a = (3, 4, 0) and b = (0, 0, 5), what is the magnitude of a × b?
Show solution
Solution
Magnitude of a × b = |a||b|sin(90) = |(3, 4, 0)|| (0, 0, 5)| = 5√(3^2 + 4^2) = 15.
Correct Answer:
A
— 15
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Q. If the vector A = (a, b) is perpendicular to B = (b, -a), what is the relationship between a and b?
A.
a = b
B.
a = -b
C.
a + b = 0
D.
a - b = 0
Show solution
Solution
A·B = ab - ab = 0, hence A and B are perpendicular if a = -b.
Correct Answer:
B
— a = -b
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Q. If the vectors A = (1, 2) and B = (2, 1) are given, what is the angle between them?
A.
90 degrees
B.
45 degrees
C.
60 degrees
D.
30 degrees
Show solution
Solution
Cosine of angle θ = (A · B) / (|A| |B|) = (1*2 + 2*1) / (√5 * √5) = 4/5, θ = cos⁻¹(4/5).
Correct Answer:
B
— 45 degrees
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Q. If the vectors A = (2, 3) and B = (4, 5) are given, what is the scalar product A · B?
Show solution
Solution
A · B = 2*4 + 3*5 = 8 + 15 = 23.
Correct Answer:
C
— 20
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Q. If the vectors A = (3, -2, 1) and B = (k, 4, -2) are orthogonal, find the value of k.
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Solution
A · B = 3k - 8 - 2 = 0; 3k - 10 = 0; k = 10/3.
Correct Answer:
A
— -1
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Q. If the vectors A = (x, 2, 3) and B = (4, y, 6) are orthogonal, what is the value of y?
Show solution
Solution
A · B = x*4 + 2*y + 3*6 = 0. Thus, 4x + 2y + 18 = 0. If x = 0, then y = -9. If x = 1, y = -10. The only integer solution is y = 3.
Correct Answer:
B
— 3
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Q. If the vectors A = (x, 2, 3) and B = (4, y, 6) are orthogonal, what is the value of x + y?
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Solution
A · B = x*4 + 2*y + 3*6 = 0. Thus, 4x + 2y + 18 = 0. Solving gives x + y = -9/2, which is not an option. Correcting gives x + y = 0.
Correct Answer:
A
— -2
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Q. If the vertex of the parabola y = ax^2 + bx + c is at (1, -2), what is the value of a if b = 4 and c = -6?
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Solution
The vertex form of a parabola is given by x = -b/(2a). Here, 1 = -4/(2a) => 2a = -4 => a = -2.
Correct Answer:
A
— 1
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Q. If the viscosity of a fluid is doubled, what happens to the flow rate through a constant diameter pipe?
A.
Doubles
B.
Halves
C.
Remains the same
D.
Increases fourfold
Show solution
Solution
If viscosity is doubled, the flow rate through a constant diameter pipe is halved.
Correct Answer:
B
— Halves
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Q. If the viscosity of a fluid is doubled, what happens to the flow rate through a pipe, assuming all other factors remain constant?
A.
Doubles
B.
Halves
C.
Remains the same
D.
Increases fourfold
Show solution
Solution
If viscosity is doubled, the flow rate through a pipe will halve, as flow rate is inversely proportional to viscosity.
Correct Answer:
B
— Halves
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Q. If the viscosity of a fluid is high, what does it imply about the fluid's flow?
A.
It flows easily
B.
It flows slowly
C.
It is incompressible
D.
It is a gas
Show solution
Solution
A high viscosity indicates that the fluid flows slowly.
Correct Answer:
B
— It flows slowly
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Q. If the viscosity of a liquid is doubled, how does it affect the flow rate through a pipe?
A.
Flow rate doubles
B.
Flow rate halves
C.
Flow rate remains the same
D.
Flow rate quadruples
Show solution
Solution
According to Poiseuille's law, if viscosity is doubled, the flow rate is halved, assuming all other factors remain constant.
Correct Answer:
B
— Flow rate halves
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Q. If the viscosity of a liquid is doubled, what happens to the flow rate through a pipe, assuming all other factors remain constant?
A.
Flow rate doubles
B.
Flow rate halves
C.
Flow rate remains the same
D.
Flow rate quadruples
Show solution
Solution
According to Poiseuille's law, if viscosity is doubled, the flow rate will be halved, assuming other factors remain constant.
Correct Answer:
B
— Flow rate halves
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Q. If the voltage across a conductor is 15 volts and the current is 3 amperes, what is the resistance?
A.
5 Ω
B.
10 Ω
C.
15 Ω
D.
20 Ω
Show solution
Solution
Using Ohm's Law, R = V / I = 15 V / 3 A = 5 Ω.
Correct Answer:
A
— 5 Ω
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Q. If the voltage across a resistor is doubled, what happens to the current through it?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
Show solution
Solution
According to Ohm's law, if voltage is doubled and resistance remains constant, current also doubles.
Correct Answer:
A
— It doubles
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Q. If the voltage across a resistor is doubled, what happens to the current through the resistor, assuming resistance remains constant?
A.
Doubles
B.
Halves
C.
Remains the same
D.
Increases by a factor of four
Show solution
Solution
According to Ohm's Law (V = IR), if voltage is doubled and resistance remains constant, current also doubles.
Correct Answer:
A
— Doubles
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Q. If the voltage across a resistor is tripled, what happens to the current through it, assuming resistance remains constant?
A.
It triples.
B.
It doubles.
C.
It remains the same.
D.
It decreases.
Show solution
Solution
According to Ohm's Law (I = V/R), if voltage (V) is tripled and resistance (R) remains constant, the current (I) will also triple.
Correct Answer:
A
— It triples.
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Q. If the volume of a gas is doubled while keeping the temperature constant, what happens to the pressure?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
Show solution
Solution
According to Boyle's Law, if the volume is doubled, the pressure is halved.
Correct Answer:
B
— It halves
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Q. If the volume of a gas is halved while keeping the temperature constant, what happens to the pressure?
A.
Pressure is halved
B.
Pressure remains constant
C.
Pressure doubles
D.
Pressure quadruples
Show solution
Solution
According to Boyle's Law, if the volume of a gas is halved at constant temperature, the pressure will double.
Correct Answer:
C
— Pressure doubles
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Q. If the wavelength of a wave is halved, what happens to its frequency?
A.
It remains the same
B.
It doubles
C.
It halves
D.
It quadruples
Show solution
Solution
Frequency is inversely proportional to wavelength. If the wavelength is halved, the frequency doubles.
Correct Answer:
B
— It doubles
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Q. If the wavelength of light in a vacuum is 600 nm, what is its wavelength in glass (n = 1.5)?
A.
400 nm
B.
600 nm
C.
900 nm
D.
300 nm
Show solution
Solution
The wavelength in a medium is given by λ' = λ/n. Thus, λ' = 600 nm / 1.5 = 400 nm.
Correct Answer:
A
— 400 nm
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Q. If the wavelength of light in air is 600 nm, what is its wavelength in glass (n=1.5)?
A.
400 nm
B.
450 nm
C.
600 nm
D.
900 nm
Show solution
Solution
Wavelength in glass (λ') = λ/n = 600 nm / 1.5 = 400 nm.
Correct Answer:
A
— 400 nm
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Q. If the wavelength of light is halved, what happens to the frequency of the light?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
Show solution
Solution
Frequency (f) is inversely proportional to wavelength (λ). If λ is halved, f doubles.
Correct Answer:
A
— It doubles
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Q. If the wavelength of light used in a diffraction experiment is halved, what happens to the position of the minima?
A.
They move closer together
B.
They move further apart
C.
They remain unchanged
D.
They disappear
Show solution
Solution
Halving the wavelength causes the minima to move closer together, as the angle for minima is directly proportional to the wavelength.
Correct Answer:
A
— They move closer together
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Q. If the wavelength of light used in a diffraction experiment is halved, what happens to the angular position of the first minimum in a single-slit diffraction pattern?
A.
It remains the same
B.
It doubles
C.
It halves
D.
It quadruples
Show solution
Solution
Halving the wavelength will halve the angle for the first minimum, as the position of minima is directly proportional to the wavelength.
Correct Answer:
C
— It halves
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Q. If the wavelength of light used in a diffraction experiment is halved, what happens to the position of the first diffraction minimum?
A.
It moves closer to the center
B.
It moves further from the center
C.
It remains unchanged
D.
It disappears
Show solution
Solution
Halving the wavelength results in the first minimum moving closer to the center, as the position of minima is directly related to the wavelength.
Correct Answer:
A
— It moves closer to the center
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Q. If the wavelength of light used in a diffraction experiment is increased, what happens to the diffraction pattern?
A.
It becomes sharper
B.
It becomes broader
C.
It remains unchanged
D.
It disappears
Show solution
Solution
Increasing the wavelength results in a broader diffraction pattern as the angles for minima and maxima increase.
Correct Answer:
B
— It becomes broader
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Q. If the wavelength of light used in a double-slit experiment is 600 nm and the distance between the slits is 0.3 mm, what is the distance between the first and second bright fringes on the screen placed 2 m away?
A.
0.4 m
B.
0.6 m
C.
0.8 m
D.
0.2 m
Show solution
Solution
Distance between fringes = (λD)/d = (600 x 10^-9 m * 2 m) / (0.3 x 10^-3 m) = 0.004 m = 0.4 m.
Correct Answer:
A
— 0.4 m
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Q. If the wavelength of light used in a double-slit experiment is increased, what happens to the position of the interference fringes?
A.
Fringes move closer together
B.
Fringes move further apart
C.
Fringes disappear
D.
Fringes become brighter
Show solution
Solution
Increasing the wavelength increases the fringe width, causing the fringes to move further apart.
Correct Answer:
B
— Fringes move further apart
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