Q. A store offers a 25% discount on a jacket that is originally priced at $200. What is the final price after the discount?
A.
$150
B.
$160
C.
$170
D.
$180
Show solution
Solution
Discount = 25% of 200 = 0.25 * 200 = 50. Final Price = Original Price - Discount = 200 - 50 = 150.
Correct Answer:
A
— $150
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Q. A store offers a 30% discount on a jacket that is originally priced at $200. What is the final price after the discount?
A.
$130
B.
$140
C.
$150
D.
$160
Show solution
Solution
Discount = 30% of 200 = 0.30 * 200 = $60. Final Price = 200 - 60 = $140.
Correct Answer:
A
— $130
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Q. A store offers a 30% discount on a jacket that originally costs $200. What is the final price after the discount?
A.
$130
B.
$140
C.
$150
D.
$160
Show solution
Solution
Discount = 30% of 200 = 0.30 * 200 = $60. Final Price = 200 - 60 = $140.
Correct Answer:
A
— $130
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Q. A store offers a 30% discount on a jacket that originally costs $80. What is the sale price of the jacket?
A.
$56
B.
$60
C.
$54
D.
$50
Show solution
Solution
Discount = 30% of 80 = (30/100) * 80 = 24. Sale price = 80 - 24 = $56.
Correct Answer:
A
— $56
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Q. A store offers a discount of 15% on a jacket that costs $120. What is the final price after discount?
A.
$90
B.
$100
C.
$105
D.
$110
Show solution
Solution
Discount = 15% of 120 = 0.15 * 120 = $18. Final Price = Cost - Discount = 120 - 18 = $102.
Correct Answer:
B
— $100
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Q. A store sells a laptop for $800 after applying a discount of 20%. What was the original price?
A.
$900
B.
$1000
C.
$1100
D.
$1200
Show solution
Solution
Let the original price be x. Selling Price = x - 0.20x = 0.80x. So, 0.80x = 800. Therefore, x = 800 / 0.80 = 1000.
Correct Answer:
B
— $1000
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Q. A student has scores of 60, 70, and 80 in three tests. If he wants an average of 75 after the fourth test, what score does he need?
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Solution
Let the fourth score be x. (60 + 70 + 80 + x) / 4 = 75 => 210 + x = 300 => x = 90.
Correct Answer:
A
— 90
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Q. A student needs to score 75% to pass an exam. If the total marks are 400, what is the minimum score required to pass?
A.
300
B.
250
C.
350
D.
280
Show solution
Solution
Minimum score required = 75% of 400 = (75/100) * 400 = 300.
Correct Answer:
A
— 300
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Q. A student scored 80 marks in an exam. If the passing marks are increased by 20%, what are the new passing marks if they were originally 75?
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Solution
New Passing Marks = Original Passing Marks + (20% of Original Passing Marks) = 75 + (0.2 * 75) = 75 + 15 = 90.
Correct Answer:
A
— 90
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Q. A student scored 80% in a test. If the maximum marks are 200, how many marks did the student score?
A.
160
B.
180
C.
150
D.
170
Show solution
Solution
Marks scored = 80% of Maximum Marks = 0.8 * 200 = 160.
Correct Answer:
A
— 160
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Q. A student scored 80% in an exam. If the total marks were 200, how many marks did the student score?
A.
160
B.
180
C.
200
D.
150
Show solution
Solution
Marks scored = 80% of Total Marks = 0.8 * 200 = 160.
Correct Answer:
A
— 160
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Q. A student scored 80% in Mathematics and 70% in Science. If both subjects are equally weighted, what is the average percentage?
A.
75%
B.
76%
C.
77%
D.
78%
Show solution
Solution
Average percentage = (80 + 70) / 2 = 75%.
Correct Answer:
A
— 75%
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Q. A student scored 80, 90, and 70 in three subjects. If the fourth subject is scored 100, what will be the weighted average of the scores?
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Solution
The average is (80 + 90 + 70 + 100) / 4 = 85.
Correct Answer:
B
— 90
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Q. A student scores 60, 70, and 80 in three subjects. If he wants an average of 75 after scoring in a fourth subject, what should he score?
Show solution
Solution
Total score needed for average of 75 = 4 * 75 = 300. Current total = 60 + 70 + 80 = 210. Score needed in fourth subject = 300 - 210 = 90.
Correct Answer:
C
— 80
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Q. A student scores 70, 80, and 90 in three exams. What score does he need in the fourth exam to achieve an average of 85?
Show solution
Solution
Let the fourth score be x. (70 + 80 + 90 + x) / 4 = 85. Solving gives x = 95.
Correct Answer:
C
— 95
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Q. A student scores 70, 80, and 90 in three subjects. If he scores 100 in the fourth subject, what will be his average score?
Show solution
Solution
Total score = 70 + 80 + 90 + 100 = 340. Average = 340 / 4 = 85.
Correct Answer:
C
— 90
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Q. A student scores 70, 80, and 90 in three subjects. If he wants to achieve an average of 85 after the fourth subject, what score does he need in the fourth subject?
Show solution
Solution
Total score needed for average of 85 = 4 * 85 = 340. Current total = 70 + 80 + 90 = 240. Score needed in fourth subject = 340 - 240 = 100.
Correct Answer:
C
— 95
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Q. A student scores 70, 80, and 90 in three tests. If he wants an average of 85 after the fourth test, what must he score?
Show solution
Solution
Total score needed for average of 85 = 4 * 85 = 340. Current total = 70 + 80 + 90 = 240. Score needed = 340 - 240 = 100.
Correct Answer:
C
— 95
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Q. A student scores 80% in a test after increasing his score by 20 marks. If the maximum score is 100, what was his original score?
Show solution
Solution
Let the original score be x. Then, x + 20 = 80% of 100 => x + 20 = 80 => x = 80 - 20 = 60.
Correct Answer:
C
— 70
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Q. A student scores 80% in a test. If the total marks are 200, how many marks did the student score?
A.
160
B.
150
C.
170
D.
180
Show solution
Solution
Marks scored = 80% of Total Marks = 0.8 * 200 = 160.
Correct Answer:
A
— 160
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Q. A sum of $1200 is invested at a rate of 6% per annum compounded annually. What will be the amount after 3 years?
A.
$1449.22
B.
$1350.00
C.
$1500.00
D.
$1600.00
Show solution
Solution
Amount = P(1 + r)^n = 1200(1 + 0.06)^3 = 1200(1.191016) = $1430.82.
Correct Answer:
A
— $1449.22
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Q. A sum of $1500 is invested at a compound interest rate of 6% per annum. What will be the total amount after 3 years?
A.
$1785.00
B.
$1800.00
C.
$1890.00
D.
$2000.00
Show solution
Solution
Total Amount = P(1 + r/n)^(nt) = 1500(1 + 0.06/1)^(1*3) = 1500(1.191016) = 1786.52.
Correct Answer:
C
— $1890.00
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Q. A sum of $1500 is invested at a compound interest rate of 7% per annum. What will be the amount after 1 year?
A.
$1605.00
B.
$1550.00
C.
$1575.00
D.
$1650.00
Show solution
Solution
Amount = P(1 + r)^n = 1500(1 + 0.07)^1 = 1500(1.07) = $1605.00.
Correct Answer:
A
— $1605.00
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Q. A sum of $2000 is invested at a compound interest rate of 6% per annum. What will be the amount after 5 years?
A.
$2676.28
B.
$2500
C.
$2600
D.
$2700
Show solution
Solution
Amount = 2000(1 + 0.06)^5 = 2000(1.338225) = $2676.28.
Correct Answer:
A
— $2676.28
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Q. A sum of $2500 is invested at a compound interest rate of 6% per annum. What will be the amount after 2 years?
A.
$2800
B.
$2650
C.
$2820
D.
$2750
Show solution
Solution
Amount = P(1 + r)^n = 2500(1 + 0.06)^2 = 2500(1.1236) = $2809.
Correct Answer:
C
— $2820
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Q. A sum of $2500 is invested at a simple interest rate of 6% per annum. How much interest will be earned in 4 years?
A.
$300
B.
$400
C.
$500
D.
$600
Show solution
Solution
Simple Interest = P * r * t = 2500 * 0.06 * 4 = 600.
Correct Answer:
B
— $400
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Q. A sum of $5000 is invested at a compound interest rate of 6% per annum. What will be the amount after 2 years?
A.
$5630
B.
$6000
C.
$5300
D.
$5500
Show solution
Solution
Amount = P(1 + r/n)^(nt) = 5000(1 + 0.06/1)^(1*2) = 5000(1.1236) = $5630
Correct Answer:
A
— $5630
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Q. A sum of $8000 is invested at a rate of 6% per annum compounded annually. What will be the amount after 3 years?
A.
$9500
B.
$9000
C.
$9008
D.
$9006
Show solution
Solution
Amount = P(1 + r)^n = 8000(1 + 0.06)^3 = 8000(1.191016) = $9528.13.
Correct Answer:
C
— $9008
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Q. A sum of money amounts to $1200 in 2 years at compound interest. If the rate of interest is 10% per annum, what was the principal?
A.
$1000
B.
$900
C.
$1100
D.
$950
Show solution
Solution
Let P be the principal. 1200 = P(1 + 0.10)^2 => P = 1200 / 1.21 = $991.74
Correct Answer:
A
— $1000
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Q. A sum of money becomes $1200 in 3 years at simple interest. If the rate of interest is 5% per annum, what was the principal?
A.
$1000
B.
$1100
C.
$900
D.
$950
Show solution
Solution
Let the principal be P. Then, A = P + SI = P + (P × 0.05 × 3) = 1200. Solving gives P = $1000.
Correct Answer:
A
— $1000
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Showing 391 to 420 of 1468 (49 Pages)
Quantitative Aptitude (SSC) MCQ & Objective Questions
Quantitative Aptitude is a crucial component of various exams, especially for students preparing for the SSC (Staff Selection Commission) exams. Mastering this subject not only enhances problem-solving skills but also boosts confidence in tackling objective questions. Regular practice with MCQs and practice questions is essential for scoring better and understanding important concepts effectively.
What You Will Practise Here
Number Systems and their properties
Percentage, Ratio, and Proportion calculations
Time, Speed, and Distance problems
Simple and Compound Interest concepts
Algebraic expressions and equations
Data Interpretation and analysis
Mensuration and Geometry basics
Exam Relevance
Quantitative Aptitude is a significant part of the syllabus for CBSE, State Boards, and competitive exams like NEET and JEE. In these exams, students can expect questions that assess their ability to apply mathematical concepts to real-world scenarios. Common question patterns include direct problem-solving, data interpretation, and application of formulas, making it essential for students to be well-prepared.
Common Mistakes Students Make
Misunderstanding the problem statement leading to incorrect assumptions
Neglecting to apply the correct formulas in calculations
Overlooking units of measurement in word problems
Rushing through questions without double-checking calculations
FAQs
Question: What are the best ways to prepare for Quantitative Aptitude in SSC exams?Answer: Regular practice with MCQs, understanding key concepts, and solving previous years' question papers are effective strategies.
Question: How can I improve my speed in solving Quantitative Aptitude questions?Answer: Practicing timed quizzes and focusing on shortcut methods can significantly enhance your speed and accuracy.
Start your journey towards mastering Quantitative Aptitude today! Solve practice MCQs and test your understanding to achieve your exam goals. Remember, consistent practice is the key to success!
