The water surface inside the capillary tube is concave due to the adhesive forces between water and the tube material being stronger than the cohesive forces among water molecules.

Using the capillary rise formula, h = (2γcosθ)/(ρgr), where γ is surface tension, θ is contact angle, ρ is density, g is acceleration due to gravity, and r is radius.

The height of the liquid column in a capillary tube is determined by both surface tension and the density of the liquid, as described by the capillary rise formula.

The rise of water in a capillary tube is due to both surface tension (which pulls the liquid up) and adhesion (the attraction between water molecules and the tube's surface).

The water will rise in the capillary tube due to capillary action, which is a result of surface tension.

Using the formula h = 2γ/(ρgr), h = 2 × 0.072 N/m / (1000 kg/m³ × 9.81 m/s² × 0.0005 m) = 0.2 m.

Using F = ma, F = 1000 kg * 2 m/s² = 2000 N.

Using the formula d = ut + 0.5at², where u = 0, a = (20 m/s) / 10 s = 2 m/s², we get d = 0 + 0.5 * 2 * (10)² = 100 m.

Work Done = Change in Kinetic Energy = 1/2 * m * (v^2) = 1/2 * 1000 * (20^2) = 200,000 J

Work Done = Change in Kinetic Energy = 1/2 * m * (v^2) = 1/2 * 1000 * (20^2) = 200,000 J

Using the formula d = ut + 0.5at², where u = 0, a = (30 m/s) / 10 s = 3 m/s², we get d = 0 + 0.5 * 3 * (10)² = 150 m.

Work done = Change in Kinetic Energy = 0.5 × mass × (final speed² - initial speed²) = 0.5 × 800 kg × (30 m/s)² = 360,000 J.

Using the formula: distance = initial velocity * time + 0.5 * acceleration * time^2. Here, initial velocity = 0, final velocity = 20 m/s, time = 10 s. Acceleration = (final velocity - initial velocity) / time = 2 m/s². Distance = 0 + 0.5 * 2 * 10² = 100 m.

Distance (s) = ut + (1/2)at^2. Here, a = (v-u)/t = (25-0)/10 = 2.5 m/s². So, s = 0 + (1/2)*2.5*10^2 = 125 m.

Using the formula P = W/t, we find P = 3000 J / 5 s = 600 W.

Using the formula P = W/t, we have P = 3000 J / 5 s = 600 W.

Relative speed = Speed of motorcycle - Speed of car = 60 km/h - 80 km/h = -20 km/h (20 km/h behind).

Relative speed = Speed of motorcycle - Speed of car = 100 km/h - 80 km/h = 20 km/h.

Relative speed = Speed of motorcycle - Speed of car = 100 km/h - 80 km/h = 20 km/h.

Relative speed = Speed of motorcycle - Speed of car = 60 km/h - 80 km/h = -20 km/h (20 km/h behind the car).

Relative speed = Speed of motorcycle - Speed of car = 60 km/h - 80 km/h = -20 km/h (20 km/h behind).

Centripetal acceleration (a_c) = v²/r = (20 m/s)² / (50 m) = 8 m/s².

Angular displacement θ = (v/r)t = (15/50)(10) = 3 rad.

Circumference = 2πr = 2π(100) = 200π m. Time period (T) = Circumference / Speed = 200π / 20 = 10π s.

Circumference = 2πr = 2π(100) = 200π m. Time period (T) = Circumference / Speed = 200π / 20 = 10π s.

Centripetal force = mv²/r = 1000(15²)/50 = 4500 N.

Angular momentum L = mvr = 1000 * 15 * 50 = 750000 kg m²/s.

The centripetal force required is provided by friction: F = mv^2/r. The frictional force is μmg. Setting them equal gives μ = v^2/(rg). Here, μ = (20^2)/(100*9.8) ≈ 0.4.

Frictional force = m * a_c; μmg = mv²/r; μ = v²/(rg) = (15 m/s)² / (100 m * 9.8 m/s²) ≈ 0.23.

Centripetal acceleration (a_c) = v²/r = (20²)/50 = 8 m/s².