Q. What is the electric potential energy of a system of two charges, +1 µC and -1 µC, separated by 0.1 m?
A.
-0.09 J
B.
0.09 J
C.
0.18 J
D.
0.36 J
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Solution
Potential energy U = k * q1 * q2 / r = (8.99 x 10^9 N m²/C²) * (1 x 10^-6 C) * (-1 x 10^-6 C) / 0.1 m = -0.09 J.
Correct Answer:
A
— -0.09 J
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Q. What is the electric potential energy stored in a capacitor of 2 µF charged to 12 V?
A.
0.144 mJ
B.
0.288 mJ
C.
0.576 mJ
D.
0.072 mJ
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Solution
U = 1/2 * C * V² = 1/2 * 2 x 10^-6 F * (12 V)² = 0.144 mJ.
Correct Answer:
B
— 0.288 mJ
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Q. What is the electric potential energy stored in a capacitor of capacitance 2 µF charged to 12 V?
A.
0.144 mJ
B.
0.024 mJ
C.
0.288 mJ
D.
0.072 mJ
Show solution
Solution
Electric potential energy (U) is given by U = 1/2 CV^2. Here, U = 1/2 * 2 µF * (12 V)^2 = 0.144 mJ.
Correct Answer:
A
— 0.144 mJ
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Q. What is the electric potential energy stored in a capacitor with a capacitance of 2 µF charged to 12 V?
A.
0.144 mJ
B.
0.12 mJ
C.
0.24 mJ
D.
0.06 mJ
Show solution
Solution
Electric potential energy (U) is given by U = 1/2 C V^2. Here, U = 1/2 * 2 µF * (12 V)^2 = 0.144 mJ.
Correct Answer:
A
— 0.144 mJ
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Q. What is the energy of a photon related to?
A.
Its mass.
B.
Its frequency.
C.
Its speed.
D.
Its temperature.
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Solution
The energy of a photon is directly proportional to its frequency, as described by the equation E = hf, where E is energy, h is Planck's constant, and f is frequency.
Correct Answer:
B
— Its frequency.
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Q. What is the energy stored in a capacitor of 20 µF charged to 10 V?
A.
0.1 J
B.
0.2 J
C.
0.05 J
D.
0.15 J
Show solution
Solution
Energy U = 0.5 * C * V² = 0.5 * 20 x 10^-6 F * (10 V)² = 0.1 J.
Correct Answer:
B
— 0.2 J
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Q. What is the energy stored in a capacitor of 20 µF charged to 12 V?
A.
1.44 mJ
B.
0.12 mJ
C.
0.24 mJ
D.
0.48 mJ
Show solution
Solution
Energy stored, U = 0.5 * C * V^2 = 0.5 * (20 x 10^-6 F) * (12 V)^2 = 1.44 mJ.
Correct Answer:
A
— 1.44 mJ
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Q. What is the energy stored in a capacitor of 4 µF charged to a voltage of 12 V?
A.
0.288 mJ
B.
0.576 mJ
C.
0.144 mJ
D.
0.072 mJ
Show solution
Solution
Using the formula U = 1/2 * C * V^2 = 1/2 * 4 x 10^-6 F * (12 V)^2 = 0.288 mJ.
Correct Answer:
B
— 0.576 mJ
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Q. What is the energy stored in a capacitor of 5 µF charged to 12V?
A.
0.36 mJ
B.
0.72 mJ
C.
0.12 mJ
D.
0.24 mJ
Show solution
Solution
Energy U = 1/2 * C * V^2 = 1/2 * 5 x 10^-6 F * (12V)^2 = 0.36 mJ.
Correct Answer:
A
— 0.36 mJ
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Q. What is the energy stored in a capacitor of 5 µF charged to a voltage of 10 V?
A.
0.25 mJ
B.
0.5 mJ
C.
0.75 mJ
D.
1 mJ
Show solution
Solution
Energy (U) = 0.5 * C * V² = 0.5 * 5 x 10^-6 F * (10 V)² = 0.25 mJ.
Correct Answer:
A
— 0.25 mJ
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Q. What is the energy stored in a capacitor of 5 µF charged to a voltage of 12 V?
A.
0.36 mJ
B.
0.60 mJ
C.
0.72 mJ
D.
0.84 mJ
Show solution
Solution
Energy stored U = 0.5 * C * V² = 0.5 * 5 x 10^-6 F * (12 V)² = 0.36 mJ.
Correct Answer:
C
— 0.72 mJ
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Q. What is the energy stored in a capacitor of 5µF charged to a voltage of 10V?
A.
0.25 mJ
B.
0.5 mJ
C.
1 mJ
D.
2.5 mJ
Show solution
Solution
Energy (U) = 0.5 * C * V² = 0.5 * 5 x 10^-6 F * (10V)² = 0.25 mJ.
Correct Answer:
B
— 0.5 mJ
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Q. What is the energy stored in a capacitor of capacitance 5 µF charged to 10 V?
A.
0.25 mJ
B.
0.5 mJ
C.
0.75 mJ
D.
1 mJ
Show solution
Solution
Energy (U) is given by U = 1/2 CV^2. Here, U = 1/2 * 5 µF * (10 V)^2 = 0.5 mJ.
Correct Answer:
B
— 0.5 mJ
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Q. What is the entropy change when 1 kg of water at 100°C is converted to steam at 100°C?
A.
2260 J/K
B.
100 J/K
C.
540 J/K
D.
0 J/K
Show solution
Solution
The entropy change for phase change at constant temperature is ΔS = Q/T. For 1 kg of water to steam, Q = 2260 kJ, T = 373 K, so ΔS = 2260 kJ / 373 K = 6.06 kJ/K.
Correct Answer:
A
— 2260 J/K
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Q. What is the entropy change when 1 mole of an ideal gas expands isothermally and reversibly from volume V1 to V2?
A.
R ln(V2/V1)
B.
R (V2 - V1)
C.
0
D.
R ln(V1/V2)
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Solution
The entropy change for an isothermal and reversible expansion is given by ΔS = R ln(V2/V1).
Correct Answer:
A
— R ln(V2/V1)
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Q. What is the entropy change when 1 mole of an ideal gas expands isothermally from volume V1 to V2?
A.
R ln(V2/V1)
B.
R (V2 - V1)
C.
R (V1/V2)
D.
0
Show solution
Solution
The entropy change for an isothermal expansion of an ideal gas is given by ΔS = nR ln(V2/V1). For 1 mole, it simplifies to ΔS = R ln(V2/V1).
Correct Answer:
A
— R ln(V2/V1)
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Q. What is the equivalent capacitance of two capacitors (3 µF and 6 µF) in series?
A.
2 µF
B.
1.5 µF
C.
9 µF
D.
18 µF
Show solution
Solution
1/Ceq = 1/C1 + 1/C2 = 1/3 + 1/6 = 1/2. Therefore, Ceq = 2 µF.
Correct Answer:
B
— 1.5 µF
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Q. What is the equivalent capacitance of two capacitors of 4 µF and 6 µF connected in series?
A.
2.4 µF
B.
10 µF
C.
1.5 µF
D.
3.6 µF
Show solution
Solution
1/C_total = 1/C1 + 1/C2 = 1/4 µF + 1/6 µF = 1.2 µF, so C_total = 2.4 µF.
Correct Answer:
A
— 2.4 µF
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Q. What is the equivalent capacitance of two capacitors, 2 µF and 3 µF, connected in series?
A.
1.2 µF
B.
5 µF
C.
0.6 µF
D.
6 µF
Show solution
Solution
For capacitors in series, 1/C_eq = 1/C1 + 1/C2. Thus, 1/C_eq = 1/2 + 1/3 = 5/6. Therefore, C_eq = 6/5 = 1.2 µF.
Correct Answer:
A
— 1.2 µF
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Q. What is the equivalent capacitance of two capacitors, 3 µF and 6 µF, connected in series?
A.
2 µF
B.
1 µF
C.
9 µF
D.
4 µF
Show solution
Solution
1/C_eq = 1/C1 + 1/C2 = 1/3 + 1/6 = 1/2. Therefore, C_eq = 2 µF.
Correct Answer:
A
— 2 µF
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Q. What is the equivalent capacitance of two capacitors, 4 µF and 6 µF, connected in series?
A.
2.4 µF
B.
10 µF
C.
1.5 µF
D.
3.6 µF
Show solution
Solution
1/C_eq = 1/C1 + 1/C2 = 1/4 + 1/6 => C_eq = 2.4 µF.
Correct Answer:
A
— 2.4 µF
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Q. What is the equivalent capacitance of two capacitors, 4 µF and 6 µF, in series?
A.
2.4 µF
B.
10 µF
C.
1.5 µF
D.
3.6 µF
Show solution
Solution
1/C_total = 1/C1 + 1/C2 = 1/4 + 1/6 = 5/12, thus C_total = 12/5 = 2.4 µF.
Correct Answer:
A
— 2.4 µF
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Q. What is the equivalent capacitance of two capacitors, C1 = 4μF and C2 = 6μF, connected in series?
A.
2.4μF
B.
3.6μF
C.
10μF
D.
24μF
Show solution
Solution
For capacitors in series, 1/C_eq = 1/C1 + 1/C2 => C_eq = 2.4μF.
Correct Answer:
A
— 2.4μF
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Q. What is the equivalent resistance (R_eq) of two resistors (R1 and R2) in series?
A.
R_eq = R1 + R2
B.
R_eq = R1 * R2
C.
R_eq = R1 / R2
D.
R_eq = R1 - R2
Show solution
Solution
The equivalent resistance of two resistors in series is R_eq = R1 + R2.
Correct Answer:
A
— R_eq = R1 + R2
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Q. What is the equivalent resistance (R_eq) of two resistors R1 and R2 in parallel?
A.
1/R_eq = 1/R1 + 1/R2
B.
R_eq = R1 + R2
C.
R_eq = R1 * R2
D.
R_eq = R1 - R2
Show solution
Solution
For resistors in parallel, the equivalent resistance is given by 1/R_eq = 1/R1 + 1/R2.
Correct Answer:
A
— 1/R_eq = 1/R1 + 1/R2
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Q. What is the equivalent resistance of three 4 Ω resistors in series?
A.
12 Ω
B.
8 Ω
C.
16 Ω
D.
4 Ω
Show solution
Solution
R_eq = R1 + R2 + R3 = 4 Ω + 4 Ω + 4 Ω = 12 Ω.
Correct Answer:
A
— 12 Ω
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Q. What is the equivalent resistance of three resistors of 2 Ω, 3 Ω, and 5 Ω connected in series?
A.
10 Ω
B.
5 Ω
C.
8 Ω
D.
12 Ω
Show solution
Solution
R_total = R1 + R2 + R3 = 2 Ω + 3 Ω + 5 Ω = 10 Ω.
Correct Answer:
A
— 10 Ω
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Q. What is the equivalent resistance of three resistors of 2 Ω, 3 Ω, and 5 Ω in series?
A.
10 Ω
B.
8 Ω
C.
5 Ω
D.
3 Ω
Show solution
Solution
R_eq = R1 + R2 + R3 = 2 Ω + 3 Ω + 5 Ω = 10 Ω.
Correct Answer:
A
— 10 Ω
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Q. What is the equivalent resistance of three resistors of 2 Ω, 3 Ω, and 6 Ω in series?
A.
11 Ω
B.
10 Ω
C.
9 Ω
D.
8 Ω
Show solution
Solution
R_eq = R1 + R2 + R3 = 2 Ω + 3 Ω + 6 Ω = 11 Ω.
Correct Answer:
A
— 11 Ω
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Q. What is the equivalent resistance of three resistors of 4 ohms, 6 ohms, and 12 ohms connected in series?
A.
22 ohms
B.
12 ohms
C.
10 ohms
D.
8 ohms
Show solution
Solution
In series, R_eq = R1 + R2 + R3 = 4Ω + 6Ω + 12Ω = 22Ω.
Correct Answer:
A
— 22 ohms
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