Arithmetic Aptitude for Competitive Exam Success

Arithmetic Aptitude

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Q. A rectangular garden is 15 m long and 10 m wide. If a path of 1 m width is built around it, what is the area of the path?

A. 80 m²
B. 100 m²
C. 60 m²
D. 120 m²

Solution

Total area with path = (15+2) × (10+2) = 17 × 12 = 204 m². Area of garden = 15 × 10 = 150 m². Area of path = 204 - 150 = 54 m².

Correct Answer: A — 80 m²

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Q. A rectangular garden is 15 meters long and 10 meters wide. What is the area of the garden in square meters?

A. 100
B. 120
C. 150
D. 200

Solution

Area = length × width = 15 × 10 = 150 square meters.

Correct Answer: B — 120

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Q. A rectangular plot has an area of 180 square meters and a length of 15 meters. What is the width of the plot?

A. 12
B. 10
C. 15
D. 14

Solution

Width = Area / length = 180 / 15 = 12 meters.

Correct Answer: A — 12

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Q. A rectangular plot has an area of 240 square meters and a length of 20 meters. What is the width of the plot in meters?

A. 10
B. 12
C. 14
D. 16

Solution

Area = length × width; 240 = 20 × width; width = 240 / 20 = 12 meters.

Correct Answer: B — 12

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Q. A rectangular prism has dimensions 3 cm, 4 cm, and 5 cm. What is the volume of the prism?

A. 60 cm³
B. 12 cm³
C. 15 cm³
D. 20 cm³

Solution

Volume = length * width * height = 3 * 4 * 5 = 60 cm³.

Correct Answer: A — 60 cm³

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Q. A rectangular room is 8 meters long and 6 meters wide. What is the area of the room in square meters?

A. 40
B. 48
C. 50
D. 60

Solution

Area = length × width = 8 × 6 = 48 square meters.

Correct Answer: B — 48

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Q. A rectangular swimming pool is 20 meters long and 10 meters wide. What is the area of the pool in square meters?

A. 150
B. 200
C. 250
D. 300

Solution

Area = length × width = 20 × 10 = 200 square meters.

Correct Answer: B — 200

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Q. A rectangular swimming pool is 25 meters long and 10 meters wide. What is the area of the pool?

A. 250
B. 200
C. 300
D. 150

Solution

Area = length × width = 25 × 10 = 250 square meters.

Correct Answer: A — 250

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Q. A rhombus has diagonals of lengths 10 cm and 24 cm. What is its area?

A. 120 cm²
B. 140 cm²
C. 160 cm²
D. 180 cm²

Solution

Area = (d1 × d2)/2 = (10 cm × 24 cm)/2 = 120 cm².

Correct Answer: A — 120 cm²

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Q. A seller bought a watch for $150 and sold it for $120. What is the loss in dollars?

A. $20
B. $30
C. $25
D. $15

Solution

Loss = Cost Price - Selling Price = 150 - 120 = 30.

Correct Answer: A — $20

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Q. A shirt is sold for $240 after a discount of 20%. What was the original price of the shirt?

A. $200
B. $220
C. $240
D. $300

Solution

Let the original price be x. After a 20% discount, the selling price is x - 0.2x = 0.8x. Given 0.8x = 240, we find x = 240 / 0.8 = 300.

Correct Answer: A — $200

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Q. A shirt is sold for $30 after a discount of 25%. What was the original price of the shirt?

A. $35
B. $40
C. $45
D. $50

Solution

Let the original price be x. Then, 0.75x = 30. Therefore, x = 30 / 0.75 = 40.

Correct Answer: B — $40

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Q. A shopkeeper bought a shirt for $40 and sold it for $50. What is the percentage profit?

A. 20%
B. 25%
C. 30%
D. 15%

Solution

Profit = Selling Price - Cost Price = 50 - 40 = 10. Percentage Profit = (Profit/Cost Price) * 100 = (10/40) * 100 = 25%.

Correct Answer: B — 25%

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Q. A shopkeeper bought a shirt for $40 and sold it for $50. What is the profit percentage?

A. 20%
B. 25%
C. 30%
D. 15%

Solution

Profit = Selling Price - Cost Price = 50 - 40 = 10. Profit Percentage = (Profit/Cost Price) * 100 = (10/40) * 100 = 25%.

Correct Answer: B — 25%

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Q. A shopkeeper bought a watch for $200 and sold it for $250. What is the profit percentage?

A. 20%
B. 25%
C. 30%
D. 35%

Solution

Profit = Selling Price - Cost Price = $250 - $200 = $50. Profit Percentage = (Profit / Cost Price) * 100 = ($50 / $200) * 100 = 25%.

Correct Answer: B — 25%

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Q. A shopkeeper bought an article for $200 and sold it for $240. What is the profit percentage?

A. 15%
B. 20%
C. 25%
D. 30%

Solution

Profit = Selling Price - Cost Price = 240 - 200 = $40. Profit percentage = (40 / 200) * 100 = 20%.

Correct Answer: B — 20%

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Q. A shopkeeper sells a mixture of two types of tea at a profit of 20%. If the cost price of the mixture is $50, what is the selling price?

A. $55
B. $60
C. $65
D. $70

Solution

Selling Price = Cost Price + Profit = 50 + (20% of 50) = 50 + 10 = $60.

Correct Answer: A — $55

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Q. A shopkeeper sells a shirt for $300 after giving a discount of 25% on the marked price. What was the marked price?

A. $350
B. $400
C. $450
D. $500

Solution

Let Marked Price = x. Selling Price = x - 25% of x = 0.75x. 0.75x = 300. x = 300/0.75 = 400.

Correct Answer: B — $400

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Q. A shopkeeper sells an article for $120, making a profit of 20%. What was the cost price of the article?

A. $100
B. $110
C. $90
D. $80

Solution

Let the cost price be x. Then, selling price = x + 20% of x = 1.2x. Given selling price = $120, we have 1.2x = 120. Therefore, x = 120 / 1.2 = $100.

Correct Answer: A — $100

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Q. A solution contains 40% salt. If you have 60 liters of this solution, how much salt is present?

A. 20 liters
B. 24 liters
C. 30 liters
D. 36 liters

Solution

Salt = 40% of 60 liters = 0.4 * 60 = 24 liters.

Correct Answer: B — 24 liters

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Q. A solution is made by mixing 60 liters of a 20% salt solution with 40 liters of a 30% salt solution. What is the percentage of salt in the new mixture?

A. 24%
B. 26%
C. 28%
D. 30%

Solution

Salt in 60 liters of 20% solution = 0.2 * 60 = 12 liters. Salt in 40 liters of 30% solution = 0.3 * 40 = 12 liters. Total salt = 12 + 12 = 24 liters. Total mixture = 60 + 40 = 100 liters. Percentage of salt = (24/100) * 100 = 24%.

Correct Answer: B — 26%

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Q. A sphere has a radius of 7 cm. What is the surface area of the sphere?

A. 154 cm²
B. 308 cm²
C. 616 cm²
D. 44 cm²

Solution

Surface Area = 4πr² = 4 * π * 7² = 4 * 3.14 * 49 = 615.44 cm².

Correct Answer: B — 308 cm²

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Q. A square has a perimeter of 40 cm. What is its area?

A. 100 cm²
B. 200 cm²
C. 160 cm²
D. 80 cm²

Solution

Perimeter = 4 × side; side = 40 cm / 4 = 10 cm. Area = side² = 10 cm × 10 cm = 100 cm².

Correct Answer: A — 100 cm²

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Q. A square has a perimeter of 40 m. What is its area?

A. 100 m²
B. 200 m²
C. 160 m²
D. 80 m²

Solution

Side = perimeter/4 = 40 m/4 = 10 m. Area = side² = (10 m)² = 100 m².

Correct Answer: A — 100 m²

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Q. A square has a perimeter of 40 meters. What is the area of the square in square meters?

A. 100
B. 160
C. 200
D. 250

Solution

Perimeter = 4 × side; side = 40/4 = 10 meters. Area = side² = 10² = 100 square meters.

Correct Answer: A — 100

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Q. A square plot has a side length of 12 meters. What is the area of the plot in square meters?

A. 120
B. 144
C. 150
D. 160

Solution

Area = side² = 12² = 144 square meters.

Correct Answer: B — 144

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Q. A stock is bought for $500 and sold for $450. What is the loss percentage?

A. 10%
B. 15%
C. 20%
D. 25%

Solution

Loss = Cost Price - Selling Price = 500 - 450 = 50. Loss Percentage = (Loss / Cost Price) * 100 = (50 / 500) * 100 = 10%

Correct Answer: C — 20%

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Q. A stock is sold at a loss of 10%. If the cost price is $300, what is the selling price?

A. $270
B. $300
C. $330
D. $150

Solution

Selling Price = Cost Price - (Loss% of Cost Price) = 300 - (10/100 * 300) = 300 - 30 = $270

Correct Answer: A — $270

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Q. A stock worth $150 is sold at a loss of 10%. What is the selling price?

A. $135
B. $140
C. $145
D. $150

Solution

Selling Price = Cost Price - (Loss% of Cost Price) = 150 - (10/100 * 150) = 150 - 15 = $135

Correct Answer: A — $135

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Q. A stock's price decreased from $120 to $90. What is the percentage decrease?

A. 25%
B. 30%
C. 20%
D. 15%

Solution

Percentage Decrease = ((Old Price - New Price) / Old Price) * 100 = ((120 - 90) / 120) * 100 = 25%

Correct Answer: B — 30%

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Arithmetic Aptitude

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