Major Competitive Exams

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Major Competitive Exams

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Major Competitive Exams MCQ & Objective Questions

Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.

What You Will Practise Here

Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams

Exam Relevance

The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.

Common Mistakes Students Make

Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam

FAQs

Question: How can I improve my performance in Major Competitive Exams?
Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.

Question: What types of questions should I focus on for these exams?
Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.

Question: Are there specific strategies for tackling objective questions?
Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.

Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!

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Q. An object is placed at a distance of 30 cm from a convex lens of focal length 15 cm. What is the distance of the image from the lens?

A. 10 cm
B. 15 cm
C. 20 cm
D. 30 cm

Solution

Using the lens formula, 1/f = 1/v - 1/u. Here, f = 15 cm, u = -30 cm. Solving gives v = 10 cm.

Correct Answer: C — 20 cm

Q. An object is placed at a distance of 40 cm from a convex lens of focal length 20 cm. Where will the image be formed?

A. 10 cm
B. 20 cm
C. 30 cm
D. 40 cm

Solution

Using the lens formula 1/f = 1/v - 1/u, we find v = 10 cm.

Correct Answer: A — 10 cm

Q. An object is placed at the focus of a concave lens. What type of image is formed?

A. Real and inverted
B. Virtual and erect
C. Real and erect
D. Virtual and inverted

Solution

A concave lens always forms a virtual and erect image regardless of the object position.

Correct Answer: B — Virtual and erect

Q. An object is placed at the focus of a concave mirror. What type of image is formed?

A. Real and inverted
B. Virtual and upright
C. No image
D. Real and upright

Solution

When the object is at the focus of a concave mirror, the rays are parallel after reflection, resulting in no image being formed.

Correct Answer: C — No image

Q. An object is projected at an angle of 60 degrees with an initial speed of 30 m/s. What is the horizontal component of its velocity?

A. 15 m/s
B. 25 m/s
C. 30 m/s
D. 20 m/s

Solution

Horizontal component (v_x) = u * cos(θ) = 30 * (1/2) = 15 m/s.

Correct Answer: B — 25 m/s

Q. An object is projected at an angle of 60 degrees with an initial speed of 30 m/s. What is the vertical component of its velocity?

A. 15 m/s
B. 25 m/s
C. 30 m/s
D. 20 m/s

Solution

Vertical component (v_y) = u * sin(θ) = 30 * (√3/2) = 25.98 m/s.

Correct Answer: B — 25 m/s

Q. An object is projected at an angle of 60 degrees with an initial velocity of 30 m/s. What is the horizontal component of its velocity?

A. 15 m/s
B. 25 m/s
C. 30 m/s
D. 20 m/s

Solution

Horizontal component Vx = u * cos(θ) = 30 * (1/2) = 15 m/s.

Correct Answer: B — 25 m/s

Q. An object is projected at an angle of 60 degrees with an initial velocity of 30 m/s. What is the time of flight?

A. 3 s
B. 5 s
C. 6 s
D. 10 s

Solution

Time of flight (T) = (2u * sin(θ)) / g = (2 * 30 * √3/2) / 9.8 = 5.18 s.

Correct Answer: C — 6 s

Q. An object is thrown at an angle of 30 degrees with a speed of 40 m/s. What is the time of flight until it returns to the same vertical level?

A. 4 s
B. 5 s
C. 6 s
D. 8 s

Solution

Time of flight (T) = (2 * u * sin(θ)) / g = (2 * 40 * 0.5) / 9.8 ≈ 4.08 s.

Correct Answer: C — 6 s

Q. An object is thrown horizontally from a height of 45 m. How long will it take to hit the ground? (Take g = 10 m/s²) (2022)

A. 3 s
B. 4 s
C. 5 s
D. 6 s

Solution

Using h = (1/2)gt², 45 = (1/2)(10)t². Solving gives t² = 9, so t = 3 s.

Correct Answer: B — 4 s

Q. An object is thrown horizontally from the top of a 45 m high cliff. How far from the base of the cliff will it land if the initial speed is 10 m/s?

A. 10 m
B. 20 m
C. 30 m
D. 40 m

Solution

Time of flight (t) = √(2h/g) = √(2*45/9.8) = 3.03 s. Horizontal distance = speed * time = 10 * 3.03 = 30.3 m.

Correct Answer: B — 20 m

Q. An object is thrown horizontally from the top of a 45 m high cliff. How far from the base of the cliff will it land if it is thrown with a speed of 10 m/s?

A. 20 m
B. 30 m
C. 40 m
D. 50 m

Solution

Time of flight (t) = √(2h/g) = √(2*45/9.8) = 3.03 s. Horizontal distance = speed * time = 10 * 3.03 = 30.3 m.

Correct Answer: B — 30 m

Q. An object is thrown horizontally from the top of a cliff 80 m high. How long does it take to hit the ground?

A. 2 s
B. 4 s
C. 5 s
D. 8 s

Solution

Using h = (1/2)gt^2, we have 80 = (1/2)(9.8)t^2, solving gives t ≈ 4 s.

Correct Answer: B — 4 s

Q. An object is thrown horizontally from the top of a cliff of height 80 m. How long does it take to hit the ground?

A. 2 s
B. 4 s
C. 5 s
D. 8 s

Solution

Using h = (1/2)gt^2, we have 80 = (1/2)(9.8)t^2, solving gives t ≈ 4 s.

Correct Answer: B — 4 s

Q. An object is thrown horizontally from the top of a tower 80 m high. How long will it take to hit the ground?

A. 4 s
B. 5 s
C. 3 s
D. 2 s

Solution

Using the equation h = (1/2)gt², where h = 80 m and g = 9.8 m/s², we have 80 = (1/2)*9.8*t². Solving gives t² = 16.33, so t ≈ 4 s.

Correct Answer: B — 5 s

Q. An object is thrown upwards with a speed of 20 m/s. How long will it take to reach the maximum height? (Assume g = 10 m/s²)

A. 1 s
B. 2 s
C. 3 s
D. 4 s

Solution

Time to reach maximum height = initial velocity / g = 20 m/s / 10 m/s² = 2 s.

Correct Answer: B — 2 s

Q. An object is thrown upwards with a velocity of 20 m/s. How high will it go before coming to rest? (g = 10 m/s²)

A. 20 m
B. 40 m
C. 50 m
D. 80 m

Solution

Using the formula h = v²/(2g) = (20 m/s)² / (2 * 10 m/s²) = 20 m.

Correct Answer: B — 40 m

Q. An object is thrown upwards with a velocity of 20 m/s. How high will it go before it starts to fall back down? (g = 10 m/s²)

A. 20 m
B. 30 m
C. 40 m
D. 50 m

Solution

Using the formula h = v²/(2g) = (20 m/s)² / (2 * 10 m/s²) = 20 m.

Correct Answer: B — 30 m

Q. An object is thrown vertically upward with a speed of 20 m/s. How high will it rise before coming to rest?

A. 10 m
B. 20 m
C. 30 m
D. 40 m

Solution

Maximum height (H) = (u²)/(2g) = (20²)/(2*9.8) ≈ 20.4 m.

Correct Answer: C — 30 m

Q. An object is thrown vertically upward with a speed of 30 m/s. How high will it rise before coming to rest?

A. 45 m
B. 90 m
C. 135 m
D. 180 m

Solution

Using the formula: h = (v² - u²) / (2g), where v = 0 m/s, u = 30 m/s, g = 9.8 m/s². h = (0 - 30²) / (2 * -9.8) = 45.92 m, approximately 45 m.

Correct Answer: B — 90 m

Q. An object is thrown vertically upward with a speed of 30 m/s. How high will it rise before coming to a momentary stop?

A. 45 m
B. 60 m
C. 90 m
D. 135 m

Solution

Using the formula: h = (v² - u²) / (2g), where v = 0 m/s (at the highest point), u = 30 m/s, g = 9.8 m/s². h = (0 - 30²) / (2 * -9.8) = 45.92 m, approximately 45 m.

Correct Answer: B — 60 m

Q. An object is thrown vertically upwards with a speed of 15 m/s. What is the maximum height it reaches? (g = 10 m/s²)

A. 11.25 m
B. 22.5 m
C. 15 m
D. 20 m

Solution

Maximum Height (h) = v^2 / (2g) = (15^2) / (2 * 10) = 11.25 m

Correct Answer: B — 22.5 m

Q. An object is thrown vertically upwards with a speed of 20 m/s. How high will it rise before coming to rest? (Take g = 10 m/s²) (2020)

A. 20 m
B. 40 m
C. 50 m
D. 80 m

Solution

Using the formula h = (u²)/(2g) = (20²)/(2 × 10) = 20 m.

Correct Answer: B — 40 m

Q. An object is thrown vertically upwards with a speed of 20 m/s. How high will it go before coming to rest?

A. 20 m
B. 40 m
C. 50 m
D. 80 m

Solution

Using the formula h = v²/(2g), where g = 10 m/s², h = (20 m/s)²/(2 * 10 m/s²) = 20 m.

Correct Answer: B — 40 m

Q. An object is thrown vertically upwards with a speed of 20 m/s. How long will it take to reach the maximum height?

A. 1 s
B. 2 s
C. 3 s
D. 4 s

Solution

Time to reach maximum height (t) = u/g = 20/9.8 = 2.04 s.

Correct Answer: B — 2 s

Q. An object is thrown vertically upwards with a speed of 30 m/s. How high will it rise before coming to rest?

A. 45 m
B. 60 m
C. 90 m
D. 120 m

Solution

Using the formula: h = (v² - u²) / (2g), where v = 0 m/s, u = 30 m/s, g = 9.8 m/s². h = (0 - 30²) / (2 * -9.8) = 45.92 m, approximately 45 m.

Correct Answer: B — 60 m

Q. An object is thrown vertically upwards with a speed of 30 m/s. How high will it rise before coming to rest momentarily?

A. 45 m
B. 60 m
C. 90 m
D. 135 m

Solution

Using the formula: h = (v² - u²) / (2g), where v = 0 m/s (at the highest point), u = 30 m/s, g = 9.8 m/s². h = (0 - 30²) / (2 * -9.8) = 45.92 m, approximately 45 m.

Correct Answer: B — 60 m

Q. An object is thrown vertically upwards with a velocity of 20 m/s. How high will it rise? (Assume g = 10 m/s²) (2020)

A. 20 m
B. 30 m
C. 40 m
D. 50 m

Solution

Using h = v²/(2g) = (20 m/s)² / (2 × 10 m/s²) = 20 m.

Correct Answer: A — 20 m

Q. An object moves in a circular path with a radius of 10 m at a speed of 5 m/s. What is the period of the motion?

A. 2π s
B. 4π s
C. 10 s
D. 20 s

Solution

Period (T) = (2πr)/v = (2π * 10)/5 = 4π s.

Correct Answer: A — 2π s

Q. An object moves in a straight line with a uniform speed of 10 m/s. How far will it travel in 15 seconds? (2023)

A. 100 m
B. 120 m
C. 150 m
D. 200 m

Solution

Distance = Speed × Time = 10 m/s × 15 s = 150 m.

Correct Answer: C — 150 m

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