Undergraduate MCQ & Objective Questions
The undergraduate level is a crucial phase in a student's academic journey, especially for those preparing for school and competitive exams. Mastering this stage can significantly enhance your understanding and retention of key concepts. Practicing MCQs and objective questions is essential, as it not only helps in reinforcing knowledge but also boosts your confidence in tackling important questions during exams.
What You Will Practise Here
Fundamental concepts in Mathematics and Science
Key definitions and theories across various subjects
Important formulas and their applications
Diagrams and graphical representations
Critical thinking and problem-solving techniques
Subject-specific MCQs designed for competitive exams
Revision of essential topics for better retention
Exam Relevance
Undergraduate topics are integral to various examinations such as CBSE, State Boards, NEET, and JEE. These subjects often feature a mix of conceptual and application-based questions. Common patterns include multiple-choice questions that assess both theoretical knowledge and practical application, making it vital for students to be well-versed in undergraduate concepts.
Common Mistakes Students Make
Overlooking the importance of understanding concepts rather than rote memorization
Misinterpreting questions due to lack of careful reading
Neglecting to practice numerical problems that require application of formulas
Failing to review mistakes made in previous practice tests
FAQs
Question: What are some effective strategies for solving undergraduate MCQ questions?Answer: Focus on understanding the concepts, practice regularly, and review your answers to learn from mistakes.
Question: How can I improve my speed in answering objective questions?Answer: Time yourself while practicing and gradually increase the number of questions you attempt in a set time.
Start your journey towards mastering undergraduate subjects today! Solve practice MCQs and test your understanding to ensure you are well-prepared for your exams. Your success is just a question away!
Q. What is the volume of a cylinder with radius 2 and height 5? (2023)
A.
20π
B.
10π
C.
15π
D.
25π
Show solution
Solution
Volume = πr²h = π(2²)(5) = 20π cubic units.
Correct Answer:
A
— 20π
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Q. What is the volume of a cylinder with radius 3 units and height 5 units? (2021)
A.
45π
B.
30π
C.
15π
D.
9π
Show solution
Solution
Volume = πr²h = π(3²)(5) = 45π cubic units.
Correct Answer:
A
— 45π
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Q. What is the volume of a sphere with radius 5 units? (2021)
A.
500/3π
B.
125/3π
C.
100/3π
D.
200/3π
Show solution
Solution
Volume = (4/3)πr³ = (4/3)π(5)³ = (4/3)π(125) = 500/3π cubic units.
Correct Answer:
A
— 500/3π
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Q. What is the wavelength of light emitted when an electron transitions from n=3 to n=1 in a hydrogen atom? (2020)
A.
102.6 nm
B.
656.3 nm
C.
486.1 nm
D.
434.0 nm
Show solution
Solution
Using the Rydberg formula, the wavelength for the transition from n=3 to n=1 can be calculated to be approximately 102.6 nm.
Correct Answer:
A
— 102.6 nm
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Q. What is the wavelength of light emitted when an electron transitions from n=4 to n=2 in a hydrogen atom? (2020)
A.
486 nm
B.
656 nm
C.
434 nm
D.
410 nm
Show solution
Solution
Using the Rydberg formula, the wavelength for the transition from n=4 to n=2 can be calculated to be approximately 486 nm.
Correct Answer:
A
— 486 nm
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Q. What is the wavelength of light if the first-order maximum occurs at an angle of 30° in a double-slit experiment with a slit separation of 0.1 mm and a screen distance of 1 m? (2019)
A.
0.5 mm
B.
0.3 mm
C.
0.2 mm
D.
0.1 mm
Show solution
Solution
Using the formula λ = d sin θ / m, where d = 0.1 mm, θ = 30°, and m = 1, we find λ = 0.1 mm * sin(30°) = 0.1 mm * 0.5 = 0.05 mm = 0.2 mm.
Correct Answer:
C
— 0.2 mm
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Q. What is the work done by a force of 15 N acting at an angle of 60° while moving an object 4 m? (2021)
A.
30 J
B.
60 J
C.
45 J
D.
90 J
Show solution
Solution
Work = F × d × cos(θ) = 15 N × 4 m × cos(60°) = 15 × 4 × 0.5 = 30 J.
Correct Answer:
C
— 45 J
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Q. What is the work done by an ideal gas during an isobaric expansion if it expands from 2 L to 5 L at a pressure of 3 atm? (2022)
A.
9 J
B.
12 J
C.
15 J
D.
18 J
Show solution
Solution
Work done (W) = P * ΔV = 3 atm * (5 L - 2 L) = 3 atm * 3 L = 9 atm·L = 15 J (1 atm·L = 101.325 J)
Correct Answer:
C
— 15 J
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Q. What is the work done by an ideal gas during an isobaric expansion if the pressure is 5 atm and the volume changes from 2 L to 5 L? (2019)
A.
15 L·atm
B.
10 L·atm
C.
5 L·atm
D.
20 L·atm
Show solution
Solution
Work done (W) = PΔV = P(V_final - V_initial) = 5 atm * (5 L - 2 L) = 15 L·atm.
Correct Answer:
A
— 15 L·atm
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Q. What is the work done by an ideal gas during an isobaric expansion? (2019)
Show solution
Solution
The work done by an ideal gas during an isobaric (constant pressure) expansion is given by W = PΔV.
Correct Answer:
A
— PΔV
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Q. What is the work done by an ideal gas during an isothermal expansion from volume V1 to V2 at temperature T? (2021)
A.
nRT ln(V2/V1)
B.
nRT (V2 - V1)
C.
PV
D.
0
Show solution
Solution
The work done during an isothermal expansion is given by W = nRT ln(V2/V1).
Correct Answer:
A
— nRT ln(V2/V1)
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Q. What is the work done by an ideal gas during isothermal expansion? (2021)
A.
0
B.
nRT ln(Vf/Vi)
C.
nRT (Vf - Vi)
D.
nR (Tf - Ti)
Show solution
Solution
For an ideal gas undergoing isothermal expansion, the work done is given by W = nRT ln(Vf/Vi).
Correct Answer:
B
— nRT ln(Vf/Vi)
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Q. What is the work done on a gas during an isothermal compression? (2019)
A.
Positive
B.
Negative
C.
Zero
D.
Depends on the volume
Show solution
Solution
The work done on a gas during isothermal compression is positive, as work is done on the gas to compress it.
Correct Answer:
A
— Positive
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Q. What is the work done on a gas when it is compressed from 4 L to 2 L at a constant pressure of 2 atm?
A.
4 L·atm
B.
2 L·atm
C.
8 L·atm
D.
0 L·atm
Show solution
Solution
Work done (W) = P * ΔV = 2 atm * (2 L - 4 L) = 2 atm * (-2 L) = -4 L·atm (work done on the gas is positive).
Correct Answer:
A
— 4 L·atm
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Q. What is the work done on a gas when it is compressed from 5 L to 2 L at a constant pressure of 200 kPa? (2022)
A.
600 J
B.
800 J
C.
1000 J
D.
1200 J
Show solution
Solution
Work done (W) = P * ΔV = 200 kPa * (2 L - 5 L) = 200 kPa * (-3 L) = -600 J (work done on the gas).
Correct Answer:
C
— 1000 J
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Q. What is the work done when 1 mole of an ideal gas expands isothermally from 10 L to 20 L at 300 K? (R = 8.31 J/mol·K) (2023)
A.
0 J
B.
830 J
C.
1660 J
D.
2490 J
Show solution
Solution
Work done = nRT ln(Vf/Vi) = 1 mol × 8.31 J/mol·K × 300 K × ln(20/10) = 1660 J.
Correct Answer:
C
— 1660 J
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Q. What is the work done when 1 mole of an ideal gas expands isothermally from 10 L to 20 L at a temperature of 300 K? (2020)
A.
1.5 kJ
B.
2.5 kJ
C.
3.5 kJ
D.
4.5 kJ
Show solution
Solution
Work done (W) = nRT ln(Vf/Vi) = 1 mol * 8.314 J/(mol K) * 300 K * ln(20/10) = 2.5 kJ.
Correct Answer:
B
— 2.5 kJ
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Q. What is the work done when 1 mole of an ideal gas expands isothermally from 10 L to 20 L at 300 K? (2022)
A.
300 J
B.
600 J
C.
150 J
D.
0 J
Show solution
Solution
Work done W = nRT ln(Vf/Vi) = 1 * 8.314 * 300 * ln(20/10) = 600 J.
Correct Answer:
B
— 600 J
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Q. What is the work done when a 50 N force moves an object 3 m in the direction of the force?
A.
150 J
B.
100 J
C.
50 J
D.
200 J
Show solution
Solution
Work done (W) = F × d = 50 N × 3 m = 150 J.
Correct Answer:
A
— 150 J
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Q. What is the work done when a force of 10 N moves an object 5 m in the direction of the force? (2016)
A.
50 J
B.
25 J
C.
10 J
D.
5 J
Show solution
Solution
Work done (W) = Force × Distance = 10 N × 5 m = 50 J.
Correct Answer:
A
— 50 J
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Q. What is the work done when a force of 15 N moves an object 3 m at an angle of 0 degrees to the direction of motion?
A.
45 J
B.
30 J
C.
60 J
D.
75 J
Show solution
Solution
Work = Force * Distance * cos(θ) = 15 N * 3 m * cos(0°) = 45 J.
Correct Answer:
A
— 45 J
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Q. What is the work done when a force of 15 N moves an object 3 m at an angle of 60° to the direction of the force?
A.
22.5 J
B.
30 J
C.
36.5 J
D.
45 J
Show solution
Solution
W = F × d × cos(θ) = 15 N × 3 m × cos(60°) = 15 × 3 × 0.5 = 22.5 J.
Correct Answer:
A
— 22.5 J
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Q. What is the work done when a force of 15 N moves an object 3 m in the direction of the force? (2021)
A.
45 J
B.
30 J
C.
15 J
D.
60 J
Show solution
Solution
Work Done (W) = Force * Distance = 15 N * 3 m = 45 J.
Correct Answer:
A
— 45 J
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Q. What is the work done when a force of 15 N moves an object 4 m in the direction of the force?
A.
60 J
B.
30 J
C.
45 J
D.
75 J
Show solution
Solution
Work done = Force × Distance = 15 N × 4 m = 60 J
Correct Answer:
A
— 60 J
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Q. What is the x-intercept of the line 5x + 2y = 10?
Show solution
Solution
Setting y = 0 in the equation gives 5x = 10, thus x = 2. The x-intercept is 2.
Correct Answer:
B
— 5
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Q. What is the x-intercept of the line 5x - 2y + 10 = 0?
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Solution
Setting y = 0 in the equation gives 5x + 10 = 0, thus x = -2.
Correct Answer:
B
— 2
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Q. What is the x-intercept of the line 6x - 2y = 12?
Show solution
Solution
Setting y = 0 in the equation gives 6x = 12, thus x = 2. The x-intercept is 2.
Correct Answer:
B
— 3
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Q. What is the y-intercept of the line 2x - 3y + 6 = 0? (2023)
Show solution
Solution
Rearranging gives y = (2/3)x + 2; y-intercept = 2
Correct Answer:
A
— 2
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Q. What is the y-intercept of the line 2x - 3y = 6? (2022)
Show solution
Solution
To find y-intercept, set x = 0: 2(0) - 3y = 6 => -3y = 6 => y = -2
Correct Answer:
B
— 3
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Q. What is the y-intercept of the line 3x - 2y = 6? (2020) 2020
Show solution
Solution
Setting x = 0, we get -2y = 6, so y = -3.
Correct Answer:
A
— 3
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