JEE Main MCQ & Objective Questions
The JEE Main exam is a crucial step for students aspiring to enter prestigious engineering colleges in India. It tests not only knowledge but also the ability to apply concepts effectively. Practicing MCQs and objective questions is essential for scoring better, as it helps in familiarizing students with the exam pattern and enhances their problem-solving skills. Engaging with practice questions allows students to identify important questions and strengthen their exam preparation.
What You Will Practise Here
Fundamental concepts of Physics, Chemistry, and Mathematics
Key formulas and their applications in problem-solving
Important definitions and theories relevant to JEE Main
Diagrams and graphical representations for better understanding
Numerical problems and their step-by-step solutions
Previous years' JEE Main questions for real exam experience
Time management strategies while solving MCQs
Exam Relevance
The topics covered in JEE Main are not only significant for the JEE exam but also appear in various CBSE and State Board examinations. Many concepts are shared with the NEET syllabus, making them relevant across multiple competitive exams. Common question patterns include conceptual applications, numerical problems, and theoretical questions that assess a student's understanding of core subjects.
Common Mistakes Students Make
Misinterpreting the question stem, leading to incorrect answers
Neglecting units in numerical problems, which can change the outcome
Overlooking negative marking and not managing time effectively
Relying too heavily on rote memorization instead of understanding concepts
Failing to review and analyze mistakes from practice tests
FAQs
Question: How can I improve my speed in solving JEE Main MCQ questions?Answer: Regular practice with timed quizzes and focusing on shortcuts can significantly enhance your speed.
Question: Are the JEE Main objective questions similar to previous years' papers?Answer: Yes, many questions are based on previous years' patterns, so practicing them can be beneficial.
Question: What is the best way to approach JEE Main practice questions?Answer: Start with understanding the concepts, then attempt practice questions, and finally review your answers to learn from mistakes.
Now is the time to take charge of your preparation! Dive into solving JEE Main MCQs and practice questions to test your understanding and boost your confidence for the exam.
Q. If the refractive index of a medium is 1.33, what is the maximum angle of incidence for total internal reflection when light travels to air?
A.
41.8°
B.
48.6°
C.
53.1°
D.
60.0°
Show solution
Solution
The critical angle θc can be calculated as θc = sin^(-1)(n2/n1) = sin^(-1)(1.00/1.33) ≈ 48.6°.
Correct Answer:
A
— 41.8°
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Q. If the refractive index of a medium is 1.33, what is the speed of light in that medium if the speed of light in vacuum is 3 x 10^8 m/s?
A.
2.25 x 10^8 m/s
B.
2.5 x 10^8 m/s
C.
2.75 x 10^8 m/s
D.
3 x 10^8 m/s
Show solution
Solution
Speed of light in medium = c/n = (3 x 10^8 m/s) / 1.33 ≈ 2.25 x 10^8 m/s.
Correct Answer:
A
— 2.25 x 10^8 m/s
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Q. If the refractive index of a medium is 1.5, what is the maximum angle of incidence for total internal reflection when light travels to air?
A.
41.8°
B.
48.6°
C.
60.0°
D.
90.0°
Show solution
Solution
The critical angle θc is given by sin(θc) = n2/n1 = 1/1.5, which gives θc ≈ 41.8°.
Correct Answer:
A
— 41.8°
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Q. If the refractive index of a medium is 1.5, what is the speed of light in that medium?
A.
2 x 10^8 m/s
B.
3 x 10^8 m/s
C.
1.5 x 10^8 m/s
D.
4.5 x 10^8 m/s
Show solution
Solution
The speed of light in a medium is given by v = c/n. Here, c = 3 x 10^8 m/s and n = 1.5, so v = 3 x 10^8 / 1.5 = 2 x 10^8 m/s.
Correct Answer:
A
— 2 x 10^8 m/s
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Q. If the refractive index of a medium is 1.5, what is the speed of light in that medium? (Speed of light in vacuum = 3 x 10^8 m/s)
A.
2 x 10^8 m/s
B.
1.5 x 10^8 m/s
C.
3 x 10^8 m/s
D.
4.5 x 10^8 m/s
Show solution
Solution
Speed of light in medium = c/n = (3 x 10^8 m/s) / 1.5 = 2 x 10^8 m/s.
Correct Answer:
A
— 2 x 10^8 m/s
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Q. If the refractive index of a medium is 1.5, what is the wavelength of light in that medium if the wavelength in vacuum is 600 nm?
A.
400 nm
B.
600 nm
C.
800 nm
D.
900 nm
Show solution
Solution
Wavelength in medium = λ/v = λ0/n = 600 nm / 1.5 = 400 nm.
Correct Answer:
A
— 400 nm
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Q. If the refractive index of a medium is 2.0, what is the critical angle for total internal reflection when light travels from this medium to air?
A.
30°
B.
45°
C.
60°
D.
90°
Show solution
Solution
Using the formula sin(θc) = n2/n1, where n1 = 2.0 (medium) and n2 = 1.0 (air), we find sin(θc) = 1.0/2.0 = 0.5, leading to θc = 60°.
Correct Answer:
C
— 60°
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Q. If the refractive index of a medium is 2.0, what is the critical angle for total internal reflection?
A.
30°
B.
45°
C.
60°
D.
90°
Show solution
Solution
Using the formula θc = sin^(-1)(1/n), where n = 2.0, we find θc = sin^(-1)(1/2) = 30°.
Correct Answer:
C
— 60°
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Q. If the refractive index of a medium is 2.0, what is the critical angle for total internal reflection at the interface with air?
A.
30°
B.
45°
C.
60°
D.
90°
Show solution
Solution
Using the formula sin(θc) = n2/n1, we have sin(θc) = 1.00/2.00, leading to θc ≈ 30°.
Correct Answer:
C
— 60°
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Q. If the refractive index of a medium is 2.0, what is the maximum angle of incidence for total internal reflection when light travels to air?
A.
30°
B.
45°
C.
60°
D.
90°
Show solution
Solution
Critical angle θc = sin⁻¹(n2/n1) = sin⁻¹(1.00/2.00) ≈ 30°; thus, maximum angle of incidence for total internal reflection is 60°.
Correct Answer:
C
— 60°
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Q. If the refractive index of a medium is greater than 1, how does it affect the speed of light in that medium?
A.
Increases speed
B.
Decreases speed
C.
No effect
D.
Depends on wavelength
Show solution
Solution
The speed of light in a medium is given by v = c/n, where n is the refractive index. If n > 1, the speed decreases.
Correct Answer:
B
— Decreases speed
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Q. If the refractive index of a medium is greater than 1, what happens to the speed of light in that medium?
A.
It increases
B.
It decreases
C.
It remains the same
D.
It becomes infinite
Show solution
Solution
The speed of light in a medium is given by v = c/n, where n is the refractive index. If n > 1, then v < c, meaning the speed decreases.
Correct Answer:
B
— It decreases
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Q. If the refractive index of a medium is greater than 1, what happens to the speed of light in that medium compared to vacuum?
A.
It increases
B.
It decreases
C.
It remains the same
D.
It becomes infinite
Show solution
Solution
The speed of light in a medium is less than that in vacuum, given by v = c/n, where n > 1.
Correct Answer:
B
— It decreases
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Q. If the refractive index of a medium is greater than 1, what happens to the wavelength of light in that medium compared to its wavelength in vacuum?
A.
It increases
B.
It decreases
C.
It remains the same
D.
It becomes zero
Show solution
Solution
The wavelength of light decreases in a medium with a refractive index greater than 1, as it is given by λ' = λ/n.
Correct Answer:
B
— It decreases
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Q. If the refractive index of a medium is greater than 1, what happens to the wavelength of light in that medium?
A.
It increases
B.
It decreases
C.
It remains the same
D.
It becomes zero
Show solution
Solution
The wavelength of light decreases in a medium with a refractive index greater than 1, as λ' = λ/n.
Correct Answer:
B
— It decreases
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Q. If the refractive index of a thin film is greater than that of the surrounding medium, what happens to the phase of the reflected wave?
A.
No phase change
B.
Phase change of π
C.
Phase change of 2π
D.
Phase change of λ/2
Show solution
Solution
When light reflects off a medium with a higher refractive index, it undergoes a phase change of π (180 degrees).
Correct Answer:
B
— Phase change of π
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Q. If the refractive index of diamond is 2.42, what is the critical angle for total internal reflection when light travels from diamond to air?
A.
24.4°
B.
30.0°
C.
36.9°
D.
41.8°
Show solution
Solution
Using the formula sin(θc) = n2/n1, where n1 = 2.42 (diamond) and n2 = 1.00 (air), we find θc ≈ 24.4°.
Correct Answer:
A
— 24.4°
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Q. If the relation R on set A = {1, 2, 3} is defined as R = {(1, 1), (2, 2), (3, 3)}, is R reflexive?
A.
Yes
B.
No
C.
Only for 1
D.
Only for 2
Show solution
Solution
A relation is reflexive if every element in the set is related to itself. Here, R includes (1, 1), (2, 2), and (3, 3), so R is reflexive.
Correct Answer:
A
— Yes
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Q. If the relation R on set A = {1, 2, 3} is defined as R = {(1, 2), (2, 3)}, is R reflexive?
A.
Yes
B.
No
C.
Depends on A
D.
None of the above
Show solution
Solution
A relation is reflexive if every element is related to itself. Here, (1,1), (2,2), and (3,3) are not in R, so R is not reflexive.
Correct Answer:
B
— No
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Q. If the resistance in a circuit is doubled while keeping the voltage constant, what happens to the current?
A.
It doubles.
B.
It halves.
C.
It remains the same.
D.
It quadruples.
Show solution
Solution
According to Ohm's Law (I = V/R), if resistance (R) is doubled and voltage (V) remains constant, the current (I) will be halved.
Correct Answer:
B
— It halves.
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Q. If the resistance in a circuit is doubled while the voltage remains constant, what happens to the current?
A.
Doubles
B.
Halves
C.
Remains the same
D.
Increases exponentially
Show solution
Solution
According to Ohm's law (V = IR), if resistance (R) is doubled and voltage (V) remains constant, the current (I) will be halved.
Correct Answer:
B
— Halves
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Q. If the resistance in one arm of a Wheatstone bridge is increased, what effect does it have on the balance condition?
A.
The bridge will always remain balanced.
B.
The bridge will become unbalanced.
C.
The balance condition will improve.
D.
It has no effect.
Show solution
Solution
Increasing the resistance in one arm will disturb the balance condition, making the bridge unbalanced.
Correct Answer:
B
— The bridge will become unbalanced.
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Q. If the resistance in one arm of a Wheatstone bridge is increased, what happens to the balance condition?
A.
It remains balanced
B.
It becomes unbalanced
C.
It depends on other resistances
D.
It becomes short-circuited
Show solution
Solution
Increasing the resistance in one arm will disturb the balance condition, making it unbalanced.
Correct Answer:
B
— It becomes unbalanced
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Q. If the resistance of a circuit is 10 ohms and the induced EMF is 20 V, what is the induced current?
A.
2 A
B.
0.5 A
C.
10 A
D.
5 A
Show solution
Solution
Using Ohm's law, I = V/R. Here, I = 20 V / 10 Ω = 2 A.
Correct Answer:
A
— 2 A
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Q. If the resistance of a circuit is doubled while keeping the induced EMF constant, what happens to the induced current?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It becomes zero
Show solution
Solution
According to Ohm's law (I = V/R), if the resistance is doubled while the voltage (induced EMF) remains constant, the current will be halved.
Correct Answer:
B
— It halves
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Q. If the resistance of a circuit is doubled while the voltage remains constant, what happens to the current?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
Show solution
Solution
According to Ohm's Law, I = V/R. If R is doubled, the current I will be halved.
Correct Answer:
B
— It halves
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Q. If the resistance of a wire is doubled, how does it affect the current flowing through it when connected to a constant voltage source?
A.
Current doubles
B.
Current halves
C.
Current remains the same
D.
Current quadruples
Show solution
Solution
According to Ohm's law, if resistance is doubled and voltage remains constant, current will be halved.
Correct Answer:
B
— Current halves
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Q. If the resistance of a wire is doubled, what happens to the current flowing through it when the voltage remains constant?
A.
Doubles
B.
Halves
C.
Remains the same
D.
Increases by 50%
Show solution
Solution
According to Ohm's law, if resistance increases while voltage remains constant, current decreases.
Correct Answer:
B
— Halves
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Q. If the resistance of a wire is doubled, what happens to the current flowing through it if the voltage remains constant?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It quadruples
Show solution
Solution
According to Ohm's law, if resistance increases while voltage remains constant, current decreases.
Correct Answer:
B
— It halves
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Q. If the resistance of one arm of a Wheatstone bridge is increased, what effect does it have on the balance condition?
A.
It remains balanced
B.
It becomes unbalanced
C.
It depends on the other resistances
D.
It increases the current
Show solution
Solution
Increasing the resistance in one arm will disturb the balance condition, making the bridge unbalanced.
Correct Answer:
B
— It becomes unbalanced
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