Arithmetic Aptitude MCQ & Objective Questions
Arithmetic Aptitude is a crucial component of many school and competitive exams in India. Mastering this subject not only enhances your mathematical skills but also boosts your confidence in tackling objective questions. Regular practice with MCQs and practice questions helps you identify important questions and improves your exam preparation, ensuring you score better in your assessments.
What You Will Practise Here
Basic arithmetic operations: addition, subtraction, multiplication, and division
Fractions and decimals: conversion and operations
Percentage calculations: increase, decrease, and comparisons
Ratio and proportion: understanding and application
Averages: calculating and interpreting data
Simple and compound interest: formulas and problem-solving
Time, speed, and distance: concepts and related problems
Exam Relevance
Arithmetic Aptitude is a significant topic in various examinations, including CBSE, State Boards, NEET, and JEE. Students can expect questions that test their understanding of basic concepts, calculations, and problem-solving abilities. Common question patterns include direct application of formulas, word problems, and data interpretation, making it essential to practice thoroughly.
Common Mistakes Students Make
Misunderstanding the question requirements, leading to incorrect answers.
Overlooking the order of operations in complex calculations.
Confusing percentages with fractions, resulting in calculation errors.
Neglecting to convert units properly in time, speed, and distance problems.
Failing to apply the correct formula for interest calculations.
FAQs
Question: What are some effective strategies for solving Arithmetic Aptitude MCQs?Answer: Practice regularly, understand the underlying concepts, and familiarize yourself with different question types to enhance your speed and accuracy.
Question: How can I improve my speed in solving Arithmetic Aptitude questions?Answer: Time yourself while practicing and focus on shortcuts and tricks that can simplify calculations.
Start your journey towards mastering Arithmetic Aptitude today! Solve practice MCQs and test your understanding to ensure you are well-prepared for your exams. Your success is just a question away!
Q. A laptop is sold for $800 after a profit of 60%. What was the cost price?
A.
$500
B.
$600
C.
$700
D.
$400
Show solution
Solution
Let Cost Price = x. Selling Price = x + 60% of x = 1.6x. 1.6x = 800. x = 800/1.6 = 500.
Correct Answer:
B
— $600
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Q. A laptop is sold for $800, which is 25% more than its cost price. What is the cost price?
A.
$600
B.
$640
C.
$700
D.
$720
Show solution
Solution
Let Cost Price = x. Selling Price = x + 25% of x = 1.25x. 1.25x = 800. x = 800/1.25 = 640.
Correct Answer:
A
— $600
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Q. A laptop is sold for $900 after a profit of 25%. What was the cost price?
A.
$700
B.
$750
C.
$800
D.
$850
Show solution
Solution
Let Cost Price = x. Selling Price = x + 25% of x = 1.25x. 1.25x = 900. x = 900/1.25 = 720.
Correct Answer:
B
— $750
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Q. A loan of $2000 is taken at a compound interest rate of 6% per annum. What will be the amount after 2 years?
A.
$2240
B.
$2120
C.
$2400
D.
$2200
Show solution
Solution
Amount = Principal * (1 + Rate)^Time = 2000 * (1 + 0.06)^2 = 2000 * 1.1236 = $2247.20.
Correct Answer:
A
— $2240
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Q. A loan of $3000 is taken for 4 years at a Banker's Discount of $600. What is the rate of interest?
Show solution
Solution
Rate = (Banker's Discount / (Principal × Time)) × 100 = (600 / (3000 × 4)) × 100 = 5%.
Correct Answer:
B
— 6%
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Q. A loan of $5000 is taken at a simple interest rate of 9% per annum. How much interest will be paid after 2 years?
A.
$900
B.
$800
C.
$700
D.
$600
Show solution
Solution
Simple Interest = (5000 × 9 × 2) / 100 = $900.
Correct Answer:
A
— $900
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Q. A loan of $5000 is taken for 2 years at a simple interest rate of 8% per annum. What is the total amount to be paid back?
A.
$5400
B.
$5600
C.
$5800
D.
$6000
Show solution
Solution
Total Amount = Principal + Simple Interest = 5000 + (5000 × 8 × 2 / 100) = $5600.
Correct Answer:
B
— $5600
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Q. A loan of $5000 is taken for 2 years at a simple interest rate of 8% per annum. What is the total interest paid?
A.
$800
B.
$600
C.
$400
D.
$200
Show solution
Solution
Simple Interest = Principal × Rate × Time / 100 = 5000 × 8 × 2 / 100 = $800
Correct Answer:
A
— $800
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Q. A loan of $5000 is taken for 2 years at a simple interest rate of 8%. What will be the total amount to be paid back?
A.
$5400
B.
$5600
C.
$5800
D.
$6000
Show solution
Solution
Total Amount = Principal + Simple Interest = 5000 + (5000 × 8 × 2 / 100) = $5400.
Correct Answer:
B
— $5600
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Q. A loan of $5000 is taken for 3 years at a certain rate of interest. If the true discount is $600, what is the rate of interest?
Show solution
Solution
True Discount = Present Worth * Rate * Time / 100. 600 = 5000 * Rate * 3 / 100. Rate = (600 * 100) / (5000 * 3) = 4%.
Correct Answer:
C
— 6%
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Q. A loan of $5000 is taken for 3 years at a simple interest rate of 9%. What will be the total amount to be paid back?
A.
$6000
B.
$6500
C.
$7000
D.
$7200
Show solution
Solution
Simple Interest = (5000 * 9 * 3) / 100 = $1350. Total Amount = Principal + Interest = 5000 + 1350 = $6350.
Correct Answer:
B
— $6500
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Q. A loan of $5000 is taken for 4 years at a simple interest rate of 7%. What will be the total interest paid?
A.
$1400
B.
$1500
C.
$1600
D.
$1700
Show solution
Solution
Simple Interest = 5000 × 7 × 4 / 100 = $1400.
Correct Answer:
A
— $1400
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Q. A loan of $5000 is taken for 4 years at a simple interest rate of 8% per annum. What is the total interest paid?
A.
$1600
B.
$1800
C.
$2000
D.
$2200
Show solution
Solution
Simple Interest = 5000 × 8 × 4 / 100 = $1600.
Correct Answer:
A
— $1600
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Q. A loan of $6000 is taken for 3 years at a bankers discount of 15%. What is the total discount?
A.
$2700
B.
$270
C.
$600
D.
$900
Show solution
Solution
Total Discount = (6000 × 15 × 3) / 100 = $2700.
Correct Answer:
A
— $2700
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Q. A loan of $8000 is taken for 3 years at a Banker's Discount of 15%. What is the total discount?
A.
$3600
B.
$2400
C.
$1200
D.
$1800
Show solution
Solution
Banker's Discount = 8000 x 15/100 x 3 = $3600.
Correct Answer:
B
— $2400
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Q. A loan of $8000 is taken for 4 years at a Banker's Discount of $960. What is the rate of interest?
Show solution
Solution
Rate = (Banker's Discount / (Principal × Time)) × 100 = (960 / (8000 × 4)) × 100 = 3%.
Correct Answer:
C
— 4%
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Q. A machine can produce 100 units in 5 hours. How many units can it produce in 8 hours?
A.
150 units
B.
160 units
C.
180 units
D.
200 units
Show solution
Solution
Rate of production = 100 units/5 hours = 20 units/hour. In 8 hours, it produces 20 * 8 = 160 units.
Correct Answer:
B
— 160 units
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Q. A man bought a bicycle for $120 and sold it for $150. What is the profit percentage?
A.
20%
B.
25%
C.
30%
D.
15%
Show solution
Solution
Profit = Selling Price - Cost Price = 150 - 120 = 30. Profit Percentage = (Profit/Cost Price) * 100 = (30/120) * 100 = 25%.
Correct Answer:
B
— 25%
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Q. A man bought a laptop for $800 and sold it for $720. What is the loss percentage?
A.
10%
B.
15%
C.
20%
D.
25%
Show solution
Solution
Loss = Cost Price - Selling Price = 800 - 720 = 80. Loss Percentage = (Loss/Cost Price) * 100 = (80/800) * 100 = 10%.
Correct Answer:
A
— 10%
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Q. A man bought a watch for $200 and sold it for $250. What is the gain in percentage?
A.
20%
B.
25%
C.
30%
D.
15%
Show solution
Solution
Gain = Selling Price - Cost Price = 250 - 200 = 50. Gain Percentage = (Gain/Cost Price) * 100 = (50/200) * 100 = 25%.
Correct Answer:
B
— 25%
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Q. A man bought a watch for $200 and sold it for $250. What is the percentage profit?
A.
20%
B.
25%
C.
30%
D.
15%
Show solution
Solution
Profit = Selling Price - Cost Price = 250 - 200 = 50. Percentage Profit = (Profit / Cost Price) * 100 = (50 / 200) * 100 = 25%.
Correct Answer:
B
— 25%
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Q. A man bought a watch for $200 and sold it for $250. What is the profit percentage?
A.
25%
B.
20%
C.
30%
D.
15%
Show solution
Solution
Profit = Selling Price - Cost Price = 250 - 200 = $50. Profit Percentage = (Profit / Cost Price) × 100 = (50 / 200) × 100 = 25%.
Correct Answer:
A
— 25%
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Q. A man buys a bicycle for $300 and sells it for $360. What is his profit percentage?
A.
15%
B.
20%
C.
25%
D.
30%
Show solution
Solution
Profit = Selling Price - Cost Price = 360 - 300 = $60. Profit Percentage = (Profit / Cost Price) * 100 = (60 / 300) * 100 = 20%.
Correct Answer:
B
— 20%
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Q. A man buys a watch for $80 and sells it for $100. What is his profit percentage?
A.
20%
B.
25%
C.
30%
D.
15%
Show solution
Solution
Profit = Selling Price - Cost Price = 100 - 80 = $20. Profit Percentage = (Profit / Cost Price) × 100 = (20 / 80) × 100 = 25%.
Correct Answer:
B
— 25%
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Q. A man can complete a work in 10 days. If he works for 6 days, what fraction of the work is left?
A.
1/5
B.
1/3
C.
2/5
D.
1/2
Show solution
Solution
Work done in 6 days = 6/10 = 3/5. Work left = 1 - 3/5 = 2/5.
Correct Answer:
C
— 2/5
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Q. A man can complete a work in 15 days. If he works for 3 days, how much work is left?
A.
1/5
B.
1/4
C.
1/3
D.
1/2
Show solution
Solution
Work done in 3 days = 3/15 = 1/5. Work left = 1 - 1/5 = 4/5.
Correct Answer:
C
— 1/3
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Q. A man can complete a work in 20 days. If he works for 5 days, what fraction of the work is left?
A.
1/4
B.
3/4
C.
1/5
D.
2/5
Show solution
Solution
In 5 days, he completes 5/20 = 1/4 of the work. Therefore, the remaining work is 1 - 1/4 = 3/4.
Correct Answer:
B
— 3/4
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Q. A man can do a piece of work in 12 days. If he works for 4 days, what fraction of the work is left?
A.
1/3
B.
1/4
C.
1/2
D.
2/3
Show solution
Solution
Work done in 4 days = 4/12 = 1/3. Work left = 1 - 1/3 = 2/3.
Correct Answer:
D
— 2/3
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Q. A man can do a piece of work in 12 days. If he works for 4 days, what part of the work is completed?
A.
1/3
B.
1/4
C.
1/2
D.
1/6
Show solution
Solution
Work done in 4 days = 4/12 = 1/3 of the work.
Correct Answer:
A
— 1/3
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Q. A man can do a piece of work in 12 days. If he works for 4 days, what part of the work is left?
A.
1/3
B.
1/4
C.
2/3
D.
1/2
Show solution
Solution
In 4 days, he completes 4/12 = 1/3 of the work. Therefore, work left = 1 - 1/3 = 2/3.
Correct Answer:
C
— 2/3
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