Q. If a 5 kg object is moving with a velocity of 3 m/s, what is its momentum? (2023)
A.
5 kg·m/s
B.
10 kg·m/s
C.
15 kg·m/s
D.
20 kg·m/s
Show solution
Solution
Momentum p = mv = 5 kg * 3 m/s = 15 kg·m/s.
Correct Answer:
C
— 15 kg·m/s
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Q. If a 5 kg object is subjected to a net force of 20 N, what is its acceleration? (2023)
A.
2 m/s²
B.
4 m/s²
C.
5 m/s²
D.
10 m/s²
Show solution
Solution
Using F = ma, we find a = F/m = 20 N / 5 kg = 4 m/s².
Correct Answer:
B
— 4 m/s²
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Q. If a 5Ω resistor is connected in series with a 10Ω resistor, what is the total resistance? (2022)
A.
15Ω
B.
5Ω
C.
10Ω
D.
20Ω
Show solution
Solution
In series, R_eq = R1 + R2 = 5Ω + 10Ω = 15Ω.
Correct Answer:
A
— 15Ω
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Q. If a 5Ω resistor is connected to a 10V source, what is the power dissipated? (2023)
A.
2W
B.
5W
C.
10W
D.
20W
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Solution
Power P = V²/R = (10V)² / 5Ω = 100 / 5 = 20W.
Correct Answer:
C
— 10W
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Q. If a 6Ω and a 3Ω resistor are connected in parallel, what is the equivalent resistance? (2022)
A.
2Ω
B.
4Ω
C.
1.5Ω
D.
9Ω
Show solution
Solution
Using the formula for parallel resistors: 1/R_eq = 1/R1 + 1/R2 = 1/6 + 1/3 = 1/6 + 2/6 = 3/6. Therefore, R_eq = 2Ω.
Correct Answer:
A
— 2Ω
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Q. If a 6Ω resistor is connected in parallel with a 3Ω resistor, what is the equivalent resistance? (2023)
A.
2Ω
B.
1.5Ω
C.
4Ω
D.
9Ω
Show solution
Solution
Using the formula 1/R_eq = 1/R1 + 1/R2, we get 1/R_eq = 1/6 + 1/3 = 1/6 + 2/6 = 3/6, thus R_eq = 2Ω.
Correct Answer:
A
— 2Ω
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Q. If a 9V battery is connected to a 3Ω resistor, what is the current flowing through it? (2021)
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Solution
Using Ohm's law, I = V/R = 9V / 3Ω = 3A.
Correct Answer:
B
— 2A
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Q. If a 9V battery is connected to a 3Ω resistor, what is the energy consumed in 10 seconds? (2023)
A.
30J
B.
90J
C.
60J
D.
45J
Show solution
Solution
Power (P) = V²/R = 9²/3 = 27W. Energy (E) = P * t = 27W * 10s = 270J.
Correct Answer:
B
— 90J
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Q. If a 9V battery is connected to a 3Ω resistor, what is the power dissipated in the resistor? (2023)
Show solution
Solution
Power (P) can be calculated using P = V²/R = (9V)² / 3Ω = 81 / 3 = 27W.
Correct Answer:
A
— 3W
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Q. If a 9V battery is connected to a 3Ω resistor, what is the voltage drop across the resistor? (2023)
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Solution
The voltage drop across the resistor is equal to the battery voltage, which is 9V.
Correct Answer:
C
— 9V
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Q. If a body is moving in a circular path with a constant speed, what is its acceleration? (2023)
A.
Zero
B.
Tangential
C.
Centripetal
D.
Radial
Show solution
Solution
The body experiences centripetal acceleration directed towards the center of the circular path.
Correct Answer:
C
— Centripetal
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Q. If a body is moving in a circular path with a constant speed, what type of acceleration does it experience?
A.
Centripetal acceleration
B.
Linear acceleration
C.
Angular acceleration
D.
No acceleration
Show solution
Solution
A body moving in a circular path experiences centripetal acceleration directed towards the center of the circle.
Correct Answer:
A
— Centripetal acceleration
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Q. If a capacitor is charged to 12V and has a capacitance of 6μF, what is the stored energy? (2022)
A.
0.432 mJ
B.
0.072 mJ
C.
0.864 mJ
D.
0.216 mJ
Show solution
Solution
Energy = 0.5 × C × V² = 0.5 × 6 × 10^-6 × 12² = 0.432 mJ.
Correct Answer:
A
— 0.432 mJ
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Q. If a car accelerates from rest to a speed of 20 m/s, and its mass is 1000 kg, what is the kinetic energy gained by the car? (2021)
A.
200,000 J
B.
100,000 J
C.
50,000 J
D.
400,000 J
Show solution
Solution
Kinetic Energy (KE) = 0.5 × mass (m) × velocity² (v²). KE = 0.5 × 1000 kg × (20 m/s)² = 200,000 J.
Correct Answer:
B
— 100,000 J
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Q. If a car accelerates from rest to a speed of 20 m/s, and its mass is 1000 kg, what is the kinetic energy of the car at that speed? (2020)
A.
200 J
B.
1000 J
C.
2000 J
D.
4000 J
Show solution
Solution
Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 1000 kg × (20 m/s)² = 200000 J = 2000 J
Correct Answer:
C
— 2000 J
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Q. If a car accelerates from rest to a speed of 20 m/s, what is the kinetic energy of the car if its mass is 1000 kg?
A.
200,000 J
B.
100,000 J
C.
50,000 J
D.
400,000 J
Show solution
Solution
Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 1000 kg × (20 m/s)² = 200,000 J
Correct Answer:
B
— 100,000 J
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Q. If a car travels at a speed of 60 km/h, how far will it travel in 2 hours? (2022)
A.
120 km
B.
100 km
C.
150 km
D.
90 km
Show solution
Solution
Distance = Speed × Time = 60 km/h × 2 h = 120 km.
Correct Answer:
A
— 120 km
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Q. If a car with a mass of 1200 kg is moving at a speed of 15 m/s, what is its kinetic energy? (2021)
A.
13500 J
B.
9000 J
C.
18000 J
D.
27000 J
Show solution
Solution
Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 1200 kg × (15 m/s)² = 13500 J
Correct Answer:
A
— 13500 J
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Q. If a charge of +2μC is placed in an electric field of 1000 N/C, what is the force experienced by the charge? (2023)
A.
2 N
B.
0.002 N
C.
2000 N
D.
0.2 N
Show solution
Solution
The force (F) on a charge in an electric field is given by F = qE. Here, F = 2μC * 1000 N/C = 2 N.
Correct Answer:
A
— 2 N
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Q. If a charge of +2μC is placed in an electric field of 500 N/C, what is the force experienced by the charge? (2022)
A.
1000 N
B.
250 N
C.
500 N
D.
2000 N
Show solution
Solution
The force (F) on a charge in an electric field is given by F = qE. Here, F = 2μC * 500 N/C = 1000 N.
Correct Answer:
A
— 1000 N
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Q. If a charge of +2μC is placed in an electric field of strength 1000 N/C, what is the force acting on the charge? (2023)
A.
2 N
B.
0.002 N
C.
2000 N
D.
0.2 N
Show solution
Solution
The force (F) on a charge in an electric field is given by F = qE. Here, F = (2 * 10^-6 C)(1000 N/C) = 2 N.
Correct Answer:
A
— 2 N
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Q. If a charge of +2μC is placed in an electric field of strength 500 N/C, what is the force experienced by the charge? (2022)
A.
1000 N
B.
250 N
C.
500 N
D.
2000 N
Show solution
Solution
The force (F) on a charge in an electric field is given by F = qE. Here, F = 2μC * 500 N/C = 1000 N.
Correct Answer:
A
— 1000 N
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Q. If a charge of 5 μC is placed in an electric field of 2000 N/C, what is the force experienced by the charge? (2023)
A.
10 N
B.
1 N
C.
0.1 N
D.
100 N
Show solution
Solution
The force (F) on a charge in an electric field is given by F = qE. Here, F = 5 × 10^-6 C * 2000 N/C = 10 N.
Correct Answer:
A
— 10 N
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Q. If a circuit has a resistance of 5 ohms and a current of 2 A, what is the voltage? (2014)
A.
10 V
B.
5 V
C.
2 V
D.
1 V
Show solution
Solution
Using Ohm's Law, V = I × R = 2 A × 5 Ω = 10 V.
Correct Answer:
A
— 10 V
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Q. If a circuit has a total resistance of 12Ω and a current of 1.5A flows through it, what is the voltage across the circuit? (2022)
A.
18V
B.
12V
C.
15V
D.
10V
Show solution
Solution
Using Ohm's law, V = IR = 1.5A * 12Ω = 18V.
Correct Answer:
A
— 18V
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Q. If a circuit has a total resistance of 12Ω and a current of 1.5A, what is the voltage across the circuit? (2021)
A.
18V
B.
12V
C.
15V
D.
10V
Show solution
Solution
Using Ohm's law, V = IR = 1.5A * 12Ω = 18V.
Correct Answer:
A
— 18V
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Q. If a circuit has a total resistance of 12Ω and a current of 3A flows through it, what is the voltage across the circuit? (2020)
A.
36V
B.
12V
C.
4V
D.
24V
Show solution
Solution
Using Ohm's law, V = IR = 3A * 12Ω = 36V.
Correct Answer:
A
— 36V
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Q. If a circuit has a total resistance of 12Ω and a current of 4A, what is the voltage across the circuit? (2023)
A.
48V
B.
36V
C.
24V
D.
12V
Show solution
Solution
Using Ohm's law, V = IR = 4A * 12Ω = 48V.
Correct Answer:
A
— 48V
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Q. If a circuit has a total resistance of 5Ω and a current of 2A, what is the voltage across the circuit? (2022)
Show solution
Solution
Using Ohm's law, V = I * R = 2A * 5Ω = 10V.
Correct Answer:
A
— 10V
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Q. If a circuit has a total resistance of 8Ω and a current of 4A, what is the voltage across the circuit? (2023)
A.
32V
B.
24V
C.
16V
D.
12V
Show solution
Solution
Using Ohm's law, V = IR = 4A * 8Ω = 32V.
Correct Answer:
A
— 32V
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Showing 361 to 390 of 846 (29 Pages)
Physics (MHT-CET) MCQ & Objective Questions
Physics is a crucial subject for students preparing for the MHT-CET exam, as it forms the foundation for many scientific concepts. Mastering Physics through MCQs and objective questions not only enhances your understanding but also significantly boosts your exam scores. Regular practice with these questions helps you identify important topics and improves your problem-solving skills, making it an essential part of your exam preparation.
What You Will Practise Here
Mechanics: Laws of Motion, Work, Energy, and Power
Thermodynamics: Laws, Heat Transfer, and Applications
Waves and Oscillations: Types of Waves, Sound Waves, and Properties
Optics: Reflection, Refraction, and Optical Instruments
Electromagnetism: Electric Fields, Magnetic Fields, and Circuits
Modern Physics: Quantum Theory, Atomic Structure, and Nuclear Physics
Key Formulas and Definitions: Essential for quick revisions
Exam Relevance
Physics is a significant component of various examinations including CBSE, State Boards, NEET, and JEE. In these exams, questions often focus on conceptual understanding and application of theories. Common patterns include numerical problems, conceptual MCQs, and application-based questions that test your grasp of fundamental principles. Familiarity with these patterns through practice will enhance your confidence and performance on exam day.
Common Mistakes Students Make
Misunderstanding the application of formulas in different contexts.
Overlooking units and dimensions, leading to incorrect answers.
Confusing similar concepts, such as velocity and acceleration.
Neglecting to read questions carefully, resulting in misinterpretation.
Rushing through calculations without checking for errors.
FAQs
Question: What are the best ways to prepare for Physics (MHT-CET) MCQs?Answer: Regular practice with previous years' question papers and mock tests, along with a focus on understanding concepts, is key to success.
Question: How can I improve my speed in solving Physics MCQs?Answer: Time yourself while practicing and focus on solving simpler questions first to build confidence and speed.
Start your journey towards mastering Physics today! Solve practice MCQs and test your understanding to ensure you are well-prepared for the MHT-CET exam. Your success in Physics is just a question away!