Momentum p = mv = 5 kg * 3 m/s = 15 kg·m/s.

Using F = ma, we find a = F/m = 20 N / 5 kg = 4 m/s².

In series, R_eq = R1 + R2 = 5Ω + 10Ω = 15Ω.

Power P = V²/R = (10V)² / 5Ω = 100 / 5 = 20W.

Using the formula for parallel resistors: 1/R_eq = 1/R1 + 1/R2 = 1/6 + 1/3 = 1/6 + 2/6 = 3/6. Therefore, R_eq = 2Ω.

Using the formula 1/R_eq = 1/R1 + 1/R2, we get 1/R_eq = 1/6 + 1/3 = 1/6 + 2/6 = 3/6, thus R_eq = 2Ω.

Using Ohm's law, I = V/R = 9V / 3Ω = 3A.

Power (P) = V²/R = 9²/3 = 27W. Energy (E) = P * t = 27W * 10s = 270J.

Power (P) can be calculated using P = V²/R = (9V)² / 3Ω = 81 / 3 = 27W.

The voltage drop across the resistor is equal to the battery voltage, which is 9V.

The body experiences centripetal acceleration directed towards the center of the circular path.

A body moving in a circular path experiences centripetal acceleration directed towards the center of the circle.

Energy = 0.5 × C × V² = 0.5 × 6 × 10^-6 × 12² = 0.432 mJ.

Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 1000 kg × (20 m/s)² = 200000 J = 2000 J

Kinetic Energy (KE) = 0.5 × mass (m) × velocity² (v²). KE = 0.5 × 1000 kg × (20 m/s)² = 200,000 J.

Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 1000 kg × (20 m/s)² = 200,000 J

Distance = Speed × Time = 60 km/h × 2 h = 120 km.

Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 1200 kg × (15 m/s)² = 13500 J

The force (F) on a charge in an electric field is given by F = qE. Here, F = 2μC * 1000 N/C = 2 N.

The force (F) on a charge in an electric field is given by F = qE. Here, F = 2μC * 500 N/C = 1000 N.

The force (F) on a charge in an electric field is given by F = qE. Here, F = (2 * 10^-6 C)(1000 N/C) = 2 N.

The force (F) on a charge in an electric field is given by F = qE. Here, F = 2μC * 500 N/C = 1000 N.

The force (F) on a charge in an electric field is given by F = qE. Here, F = 5 × 10^-6 C * 2000 N/C = 10 N.

Using Ohm's Law, V = I × R = 2 A × 5 Ω = 10 V.

Using Ohm's law, V = IR = 1.5A * 12Ω = 18V.

Using Ohm's law, V = IR = 1.5A * 12Ω = 18V.

Using Ohm's law, V = IR = 3A * 12Ω = 36V.

Using Ohm's law, V = IR = 4A * 12Ω = 48V.

Using Ohm's law, V = I * R = 2A * 5Ω = 10V.

Using Ohm's law, V = IR = 4A * 8Ω = 32V.