Arithmetic Aptitude for Competitive Exam Success

Arithmetic Aptitude

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Q. A population of a town increased from 10,000 to 12,500. What is the percentage increase?

A. 20%
B. 25%
C. 30%
D. 15%

Solution

Percentage increase = ((12,500 - 10,000) / 10,000) * 100 = 25%.

Correct Answer: B — 25%

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Q. A population of a town increased from 20,000 to 25,000 in a year. What is the percentage increase in population?

A. 20%
B. 25%
C. 30%
D. 15%

Solution

Percentage increase = ((25000 - 20000) / 20000) * 100 = 25%.

Correct Answer: B — 25%

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Q. A population of a town increased from 20,000 to 25,000 in a year. What is the percentage increase in the population?

A. 20%
B. 25%
C. 30%
D. 35%

Solution

Percentage increase = ((25000 - 20000) / 20000) * 100 = (5000 / 20000) * 100 = 25%.

Correct Answer: B — 25%

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Q. A population of a town increased from 20,000 to 25,000 in a year. What is the percentage increase?

A. 20%
B. 25%
C. 30%
D. 35%

Solution

Percentage increase = ((25000 - 20000) / 20000) * 100 = 25%.

Correct Answer: B — 25%

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Q. A population of a town increased from 20,000 to 25,000. What is the percentage increase?

A. 20%
B. 25%
C. 30%
D. 35%

Solution

Percentage increase = ((25000 - 20000) / 20000) * 100 = 25%

Correct Answer: B — 25%

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Q. A principal amount of $2500 is invested at a compound interest rate of 7% per annum. What will be the amount after 5 years?

A. $3500
B. $3502.50
C. $3520.25
D. $3525.00

Solution

Amount = P(1 + r)^n = 2500(1 + 0.07)^5 = 2500(1.402552) = $3506.38.

Correct Answer: C — $3520.25

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Q. A principal of $2500 is invested at a compound interest rate of 3% per annum. What will be the amount after 6 years?

A. $2925.00
B. $3000.00
C. $2800.00
D. $2700.00

Solution

Total Amount = 2500(1 + 0.03)^6 = 2500(1.191016) = 2977.54

Correct Answer: A — $2925.00

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Q. A principal of $5000 is invested at a compound interest rate of 8% per annum. What will be the total amount after 1 year?

A. $5400.00
B. $5500.00
C. $5600.00
D. $5800.00

Solution

Total Amount = 5000(1 + 0.08)^1 = 5000(1.08) = 5400.00

Correct Answer: A — $5400.00

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Q. A product is bought for $150 and sold for $120. What is the loss percentage?

A. 15%
B. 20%
C. 25%
D. 30%

Solution

Loss = Cost Price - Selling Price = 150 - 120 = 30. Loss Percentage = (Loss/Cost Price) * 100 = (30/150) * 100 = 20%.

Correct Answer: B — 20%

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Q. A product is marked at $120 and is sold at a 25% discount. What is the selling price of the product?

A. $80
B. $85
C. $90
D. $95

Solution

Discount = 25% of 120 = 30. Selling price = 120 - 30 = $90.

Correct Answer: C — $90

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Q. A product is marked at $120 and is sold at a discount of 25%. What is the selling price of the product?

A. $80
B. $85
C. $90
D. $95

Solution

Discount = 25% of 120 = 0.25 * 120 = 30; Selling price = Marked price - Discount = 120 - 30 = 90.

Correct Answer: A — $80

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Q. A product is marked at $200 and is sold at a 15% discount. What is the selling price?

A. $170
B. $180
C. $190
D. $200

Solution

Selling price = 200 - (15/100 * 200) = 200 - 30 = $170.

Correct Answer: A — $170

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Q. A product is marked at $500 and is sold at a 10% discount. What is the selling price?

A. $450
B. $475
C. $500
D. $550

Solution

Discount = 10% of 500 = 50. Selling price = 500 - 50 = 450.

Correct Answer: B — $475

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Q. A product is marked at $500 and is sold at a 15% discount. What is the selling price?

A. $425
B. $450
C. $475
D. $500

Solution

Discount = 15% of 500 = 0.15 * 500 = 75. Selling price = 500 - 75 = 425.

Correct Answer: A — $425

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Q. A product is sold for $120 after a 25% profit. What was the cost price?

A. $90
B. $100
C. $80
D. $70

Solution

Let the cost price be x. Then, x + 0.25x = 120 => 1.25x = 120 => x = 120 / 1.25 = 96.

Correct Answer: A — $90

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Q. A product is sold for $120 after a discount of 20%. What was the original price?

A. $100
B. $120
C. $150
D. $140

Solution

Let the original price be x. Then, x - 0.2x = 120, 0.8x = 120, x = 120 / 0.8 = $150.

Correct Answer: A — $100

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Q. A product is sold for $150 after a discount of 10%. What was the original price?

A. $165
B. $160
C. $170
D. $150

Solution

Let the original price be x. Then, selling price = x - 10% of x = 0.9x. Given selling price = $150, we have 0.9x = 150. Therefore, x = 150 / 0.9 = $166.67.

Correct Answer: A — $165

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Q. A product is sold for $240 after a discount of 20%. What was the marked price?

A. $300
B. $280
C. $250
D. $320

Solution

Let the marked price be x. Then, selling price = x - 20% of x = 0.8x. Given selling price = $240, we have 0.8x = 240. Therefore, x = 240 / 0.8 = $300.

Correct Answer: A — $300

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Q. A product's price increased from $150 to $180. What is the percentage increase in price?

A. 15%
B. 20%
C. 25%
D. 30%

Solution

Percentage increase = ((180 - 150) / 150) * 100 = (30 / 150) * 100 = 20%.

Correct Answer: B — 20%

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Q. A product's price increased from $200 to $250. What is the percentage increase in price?

A. 20%
B. 25%
C. 30%
D. 35%

Solution

Percentage increase = ((250 - 200) / 200) * 100 = (50 / 200) * 100 = 25%.

Correct Answer: B — 25%

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Q. A product's price increased from $200 to $250. What is the percentage increase in the price?

A. 20%
B. 25%
C. 30%
D. 35%

Solution

Percentage increase = ((250 - 200)/200)*100 = (50/200)*100 = 25%.

Correct Answer: B — 25%

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Q. A product's price increased from $50 to $65. What is the percentage increase in the price?

A. 25%
B. 30%
C. 35%
D. 40%

Solution

Increase = 65 - 50 = 15; Percentage increase = (15/50) * 100 = 30%.

Correct Answer: B — 30%

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Q. A product's price increased from $80 to $100. What is the percentage increase?

A. 20%
B. 25%
C. 30%
D. 35%

Solution

Percentage increase = ((100 - 80) / 80) * 100 = (20 / 80) * 100 = 25%.

Correct Answer: B — 25%

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Q. A recipe requires sugar and flour in the ratio of 2:3. If there are 10 cups of flour, how many cups of sugar are needed?

A. 4
B. 6
C. 8
D. 5

Solution

Let sugar be 2x and flour be 3x. Given 3x = 10, x = 10/3. Therefore, sugar = 2x = 2*(10/3) = 20/3 ≈ 6.67.

Correct Answer: A — 4

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Q. A recipe requires sugar and flour in the ratio of 2:3. If there are 15 cups of flour, how many cups of sugar are needed?

A. 10
B. 8
C. 12
D. 6

Solution

Let sugar be 2x and flour be 3x. Given 3x = 15, x = 5. Therefore, sugar = 2x = 2*5 = 10.

Correct Answer: A — 10

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Q. A rectangle has an area of 72 cm² and a length of 12 cm. What is its width?

A. 6 cm
B. 8 cm
C. 4 cm
D. 10 cm

Solution

Area = length × width. Therefore, width = Area/length = 72 cm²/12 cm = 6 cm.

Correct Answer: B — 8 cm

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Q. A rectangle has an area of 72 m² and a length of 12 m. What is its width?

A. 6 m
B. 8 m
C. 4 m
D. 10 m

Solution

Area = length × width; width = Area / length = 72 m² / 12 m = 6 m.

Correct Answer: B — 8 m

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Q. A rectangular box has a length of 10 cm, a width of 5 cm, and a height of 2 cm. What is the total surface area of the box?

A. 70 cm²
B. 60 cm²
C. 100 cm²
D. 80 cm²

Solution

Surface Area = 2(lw + lh + wh) = 2(10*5 + 10*2 + 5*2) = 2(50 + 20 + 10) = 2 * 80 = 160 cm².

Correct Answer: A — 70 cm²

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Q. A rectangular field has a length of 50 meters and a width of 30 meters. What is the area of the field in square meters?

A. 1500
B. 1800
C. 2000
D. 2500

Solution

Area = length × width = 50 × 30 = 1500 square meters.

Correct Answer: A — 1500

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Q. A rectangular garden has a length of 20 meters and a width of 15 meters. What is the area of the garden in square meters?

A. 300
B. 250
C. 400
D. 350

Solution

Area = length × width = 20 × 15 = 300 square meters.

Correct Answer: A — 300

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Arithmetic Aptitude

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