JEE Main MCQ & Objective Questions
The JEE Main exam is a crucial step for students aspiring to enter prestigious engineering colleges in India. It tests not only knowledge but also the ability to apply concepts effectively. Practicing MCQs and objective questions is essential for scoring better, as it helps in familiarizing students with the exam pattern and enhances their problem-solving skills. Engaging with practice questions allows students to identify important questions and strengthen their exam preparation.
What You Will Practise Here
Fundamental concepts of Physics, Chemistry, and Mathematics
Key formulas and their applications in problem-solving
Important definitions and theories relevant to JEE Main
Diagrams and graphical representations for better understanding
Numerical problems and their step-by-step solutions
Previous years' JEE Main questions for real exam experience
Time management strategies while solving MCQs
Exam Relevance
The topics covered in JEE Main are not only significant for the JEE exam but also appear in various CBSE and State Board examinations. Many concepts are shared with the NEET syllabus, making them relevant across multiple competitive exams. Common question patterns include conceptual applications, numerical problems, and theoretical questions that assess a student's understanding of core subjects.
Common Mistakes Students Make
Misinterpreting the question stem, leading to incorrect answers
Neglecting units in numerical problems, which can change the outcome
Overlooking negative marking and not managing time effectively
Relying too heavily on rote memorization instead of understanding concepts
Failing to review and analyze mistakes from practice tests
FAQs
Question: How can I improve my speed in solving JEE Main MCQ questions?Answer: Regular practice with timed quizzes and focusing on shortcuts can significantly enhance your speed.
Question: Are the JEE Main objective questions similar to previous years' papers?Answer: Yes, many questions are based on previous years' patterns, so practicing them can be beneficial.
Question: What is the best way to approach JEE Main practice questions?Answer: Start with understanding the concepts, then attempt practice questions, and finally review your answers to learn from mistakes.
Now is the time to take charge of your preparation! Dive into solving JEE Main MCQs and practice questions to test your understanding and boost your confidence for the exam.
Q. If the mass of an object is tripled, how does its gravitational potential energy change at a constant height?
A.
It triples
B.
It doubles
C.
It remains the same
D.
It increases by a factor of nine
Show solution
Solution
Gravitational potential energy U = mgh, so if mass is tripled, U also triples.
Correct Answer:
A
— It triples
Learn More →
Q. If the mass of an object is tripled, how does the gravitational potential energy change for a constant height?
A.
It triples
B.
It doubles
C.
It halves
D.
It remains the same
Show solution
Solution
Gravitational potential energy is directly proportional to mass, so it triples.
Correct Answer:
A
— It triples
Learn More →
Q. If the mass of the Earth is 6 x 10^24 kg and the radius is 6.4 x 10^6 m, what is the gravitational force on a 1 kg mass at the surface?
A.
9.8 N
B.
6.67 N
C.
10 N
D.
8.9 N
Show solution
Solution
Using F = G * (m1 * m2) / r^2, F = (6.67 x 10^-11) * (6 x 10^24 * 1) / (6.4 x 10^6)^2 = 9.8 N.
Correct Answer:
A
— 9.8 N
Learn More →
Q. If the mass of the Earth is 6 x 10^24 kg and the radius is 6.4 x 10^6 m, what is the gravitational acceleration at the surface of the Earth?
A.
9.8 m/s²
B.
10 m/s²
C.
9.81 m/s²
D.
11 m/s²
Show solution
Solution
Using g = G * M / R², where G = 6.67 x 10^-11 N m²/kg², M = 6 x 10^24 kg, and R = 6.4 x 10^6 m, we find g ≈ 9.8 m/s².
Correct Answer:
A
— 9.8 m/s²
Learn More →
Q. If the mass of the Earth is 6 × 10^24 kg and its radius is 6.4 × 10^6 m, what is the acceleration due to gravity at its surface?
A.
9.8 m/s²
B.
10 m/s²
C.
9.81 m/s²
D.
8.9 m/s²
Show solution
Solution
g = G * M / R² = (6.67 × 10^-11) * (6 × 10^24) / (6.4 × 10^6)² = 9.81 m/s²
Correct Answer:
C
— 9.81 m/s²
Learn More →
Q. If the mass of the Earth is M and its radius is R, what is the gravitational acceleration at the surface of the Earth?
A.
g = GM/R^2
B.
g = GMR^2
C.
g = G/MR^2
D.
g = MR/G
Show solution
Solution
The gravitational acceleration at the surface of the Earth is given by g = GM/R^2.
Correct Answer:
A
— g = GM/R^2
Learn More →
Q. If the mass of the Earth is M and the radius is R, what is the gravitational acceleration at the surface of the Earth?
A.
g = GM/R^2
B.
g = GMR^2
C.
g = G/R
D.
g = M/R^2
Show solution
Solution
The gravitational acceleration at the surface of the Earth is given by g = GM/R^2.
Correct Answer:
A
— g = GM/R^2
Learn More →
Q. If the mass of the Earth is M and the radius is R, what is the gravitational force acting on a satellite of mass m at a height h?
A.
GmM/R^2
B.
GmM/(R+h)^2
C.
GmM/(R-h)^2
D.
GmM/h^2
Show solution
Solution
The gravitational force F acting on a satellite at height h is given by F = GmM/(R+h)^2, where G is the gravitational constant.
Correct Answer:
B
— GmM/(R+h)^2
Learn More →
Q. If the mass of the Earth were to double while its radius remained the same, what would happen to the gravitational acceleration at its surface?
A.
It would double
B.
It would remain the same
C.
It would halve
D.
It would increase by a factor of four
Show solution
Solution
Gravitational acceleration is directly proportional to mass, so if the mass doubles, g also doubles.
Correct Answer:
A
— It would double
Learn More →
Q. If the mass of the Earth were to double while its radius remains the same, what would happen to the gravitational acceleration at its surface?
A.
It would double
B.
It would remain the same
C.
It would halve
D.
It would increase by a factor of four
Show solution
Solution
Gravitational acceleration is directly proportional to mass; thus, if the mass doubles, g also doubles.
Correct Answer:
A
— It would double
Learn More →
Q. If the mass of the Earth were to double while the radius remains the same, what would happen to the weight of an object on its surface?
A.
It would double
B.
It would remain the same
C.
It would increase by a factor of four
D.
It would decrease by half
Show solution
Solution
Weight is proportional to mass; thus, if the Earth's mass doubles, the weight of an object on its surface also doubles.
Correct Answer:
A
— It would double
Learn More →
Q. If the mass of the Earth were to double, what would happen to the gravitational force between the Earth and an object on its surface?
A.
It would double
B.
It would remain the same
C.
It would halve
D.
It would quadruple
Show solution
Solution
F ∝ M; if M doubles, F also doubles.
Correct Answer:
A
— It would double
Learn More →
Q. If the mass of the Earth were to double, what would happen to the gravitational force it exerts on an object at its surface?
A.
It would double
B.
It would remain the same
C.
It would increase by a factor of four
D.
It would decrease by half
Show solution
Solution
If the mass of the Earth doubles, the gravitational force on an object at its surface would also double.
Correct Answer:
A
— It would double
Learn More →
Q. If the mass of the Earth were to double, what would happen to the gravitational force between two objects on its surface?
A.
It would double
B.
It would remain the same
C.
It would be halved
D.
It would quadruple
Show solution
Solution
F = G * (m1 * m2) / r², doubling the mass of Earth doubles the force.
Correct Answer:
A
— It would double
Learn More →
Q. If the mass of the Earth were to double, what would happen to the weight of an object on its surface?
A.
It would double
B.
It would remain the same
C.
It would be halved
D.
It would be quartered
Show solution
Solution
Weight is directly proportional to mass. If the Earth's mass doubles, the weight of the object also doubles.
Correct Answer:
A
— It would double
Learn More →
Q. If the mass of the Earth were to increase while the radius remains constant, what would happen to the gravitational force experienced by an object on its surface?
A.
It would decrease
B.
It would increase
C.
It would remain the same
D.
It would become zero
Show solution
Solution
If the mass of the Earth increases, the gravitational force experienced by an object on its surface would increase.
Correct Answer:
B
— It would increase
Learn More →
Q. If the mean of a data set is 12 and there are 8 values, what is the total sum of the values?
A.
80
B.
90
C.
100
D.
110
Show solution
Solution
Total sum = Mean * Number of values = 12 * 8 = 96.
Correct Answer:
A
— 80
Learn More →
Q. If the mean of a data set is 20 and the standard deviation is 4, what is the coefficient of variation?
A.
20%
B.
25%
C.
15%
D.
10%
Show solution
Solution
Coefficient of Variation = (Standard Deviation / Mean) * 100 = (4 / 20) * 100 = 20%.
Correct Answer:
B
— 25%
Learn More →
Q. If the mean of a data set is 30 and there are 10 values, what is the total sum of the values?
A.
300
B.
310
C.
320
D.
330
Show solution
Solution
Total sum = Mean * Number of values = 30 * 10 = 300.
Correct Answer:
A
— 300
Learn More →
Q. If the mean of a data set is 50 and the standard deviation is 10, what is the coefficient of variation?
A.
20%
B.
10%
C.
15%
D.
25%
Show solution
Solution
Coefficient of Variation = (Standard Deviation / Mean) * 100 = (10 / 50) * 100 = 20%.
Correct Answer:
A
— 20%
Learn More →
Q. If the mean of a data set is 50 and there are 10 values, what is the total sum of the values?
A.
500
B.
600
C.
700
D.
800
Show solution
Solution
Total sum = Mean * Number of values = 50 * 10 = 500.
Correct Answer:
A
— 500
Learn More →
Q. If the measured length of a rod is 20 cm with an error of 0.5 cm, what is the relative error in the measurement?
A.
0.025
B.
0.05
C.
0.0025
D.
0.005
Show solution
Solution
Relative error = (Absolute error / Measured value) = 0.5 / 20 = 0.025 or 2.5%
Correct Answer:
B
— 0.05
Learn More →
Q. If the measured value of a quantity is 100 with a relative error of 0.02, what is the absolute error?
Show solution
Solution
Absolute error = Relative error * Measured value = 0.02 * 100 = 2.
Correct Answer:
A
— 2
Learn More →
Q. If the measured value of a quantity is 75 with a relative error of 0.04, what is the true value?
Show solution
Solution
Relative error = Absolute error / True value. Let true value be x. 0.04 = |75 - x| / x. Solving gives x = 78.
Correct Answer:
B
— 78
Learn More →
Q. If the median of the data set 3, 5, 7, 9, x is 7, what is the value of x?
Show solution
Solution
For median to be 7, x must be 7 or less, hence x = 7.
Correct Answer:
D
— 8
Learn More →
Q. If the median of the data set {1, 2, 3, 4, 5, 6, 7, 8} is x, what is the value of x?
Show solution
Solution
Median = (4 + 5) / 2 = 9 / 2 = 4.5.
Correct Answer:
B
— 4.5
Learn More →
Q. If the median of the data set {3, 1, 4, 2, 5} is x, what is the value of x?
Show solution
Solution
Sorted data set: {1, 2, 3, 4, 5}. Median = 3.
Correct Answer:
B
— 3
Learn More →
Q. If the medians of a triangle are 6 cm, 8 cm, and 10 cm, what is the area of the triangle?
A.
48 cm²
B.
60 cm²
C.
72 cm²
D.
80 cm²
Show solution
Solution
Area = (4/3) * √[m1 * m2 * m3] = (4/3) * √[6 * 8 * 10] = 48 cm².
Correct Answer:
B
— 60 cm²
Learn More →
Q. If the medians of a triangle are 6, 8, and 10, what is the area of the triangle?
Show solution
Solution
Area = (4/3) * √(s(s - m1)(s - m2)(s - m3)), where s = (6 + 8 + 10)/2 = 12. Area = (4/3) * √(12 * 6 * 4 * 2) = 48.
Correct Answer:
C
— 48
Learn More →
Q. If the mode of a data set is 5, which of the following statements is true?
A.
5 occurs most frequently
B.
5 is the average
C.
5 is the middle value
D.
5 is the least value
Show solution
Solution
Mode is the value that appears most frequently in a data set.
Correct Answer:
A
— 5 occurs most frequently
Learn More →
Showing 3811 to 3840 of 10700 (357 Pages)
