Q. What is the gravitational potential energy of a 2 kg mass at a height of 10 m above the ground? (g = 9.8 m/s^2)
A.
196 J
B.
98 J
C.
20 J
D.
0 J
Show solution
Solution
Gravitational potential energy (U) is given by U = mgh = 2 kg * 9.8 m/s^2 * 10 m = 196 J.
Correct Answer:
A
— 196 J
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Q. What is the gravitational potential energy of a 2 kg mass at a height of 10 m above the ground? (g = 9.8 m/s²)
A.
196 J
B.
98 J
C.
20 J
D.
0 J
Show solution
Solution
Gravitational potential energy (U) is calculated as U = mgh = 2 kg * 9.8 m/s² * 10 m = 196 J.
Correct Answer:
A
— 196 J
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Q. What is the gravitational potential energy of a 2 kg mass at a height of 10 m?
A.
20 J
B.
15 J
C.
10 J
D.
5 J
Show solution
Solution
Gravitational potential energy (U) = mgh = 2 kg * 9.8 m/s^2 * 10 m = 196 J.
Correct Answer:
A
— 20 J
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Q. What is the gravitational potential energy of a 2 kg mass at a height of 10 m? (g = 9.8 m/s²)
A.
196 J
B.
98 J
C.
20 J
D.
0 J
Show solution
Solution
U = mgh = 2 * 9.8 * 10 = 196 J.
Correct Answer:
A
— 196 J
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Q. What is the gravitational potential energy of a 2 kg mass at a height of 5 m?
A.
10 J
B.
20 J
C.
30 J
D.
40 J
Show solution
Solution
Using U = mgh, U = 2 kg * 9.8 m/s^2 * 5 m = 98 J.
Correct Answer:
B
— 20 J
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Q. What is the gravitational potential energy of a 2 kg mass at a height of 5 m? (g = 9.8 m/s²)
A.
19.6 J
B.
39.2 J
C.
49 J
D.
9.8 J
Show solution
Solution
Potential Energy PE = m * g * h = 2 kg * 9.8 m/s² * 5 m = 98 J
Correct Answer:
B
— 39.2 J
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Q. What is the gravitational potential energy of a 5 kg mass at a height of 10 m above the ground?
A.
490 J
B.
500 J
C.
510 J
D.
450 J
Show solution
Solution
Gravitational potential energy U = mgh = 5 * 9.8 * 10 = 490 J.
Correct Answer:
B
— 500 J
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Q. What is the gravitational potential energy of a mass 'm' at height 'h' above the Earth's surface?
A.
mgh
B.
mg/h
C.
gh/m
D.
mgh^2
Show solution
Solution
The gravitational potential energy U at height h is given by U = mgh.
Correct Answer:
A
— mgh
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Q. What is the gravitational potential energy of a mass m at a height h above the Earth's surface?
A.
U = mgh
B.
U = mg/h
C.
U = mgh²
D.
U = gh/m
Show solution
Solution
The gravitational potential energy is given by the formula U = mgh, where g is the acceleration due to gravity.
Correct Answer:
A
— U = mgh
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Q. What is the gravitational potential energy of a mass of 10 kg at a height of 5 m in a gravitational field of strength 9.8 N/kg?
A.
490 J
B.
50 J
C.
98 J
D.
0 J
Show solution
Solution
Gravitational potential energy U = mgh = 10 * 9.8 * 5 = 490 J.
Correct Answer:
A
— 490 J
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Q. What is the gravitational potential energy of a mass of 10 kg at a height of 5 m above the ground? (g = 9.8 m/s²)
A.
490 J
B.
98 J
C.
588 J
D.
0 J
Show solution
Solution
U = mgh = 10 * 9.8 * 5 = 490 J
Correct Answer:
A
— 490 J
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Q. What is the gravitational potential energy of a mass of 10 kg at a height of 5 m above the ground? (2000)
A.
500 J
B.
1000 J
C.
1500 J
D.
2000 J
Show solution
Solution
Gravitational potential energy U = mgh = 10 kg * 9.8 m/s² * 5 m = 490 J, approximately 500 J.
Correct Answer:
B
— 1000 J
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Q. What is the gravitational potential energy of a mass of 2 kg at a height of 10 m above the ground? (g = 9.8 m/s^2)
A.
196 J
B.
98 J
C.
20 J
D.
10 J
Show solution
Solution
Gravitational potential energy (U) = mgh = 2 kg * 9.8 m/s^2 * 10 m = 196 J.
Correct Answer:
A
— 196 J
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Q. What is the gravitational potential energy of a mass of 2 kg at a height of 10 m in a gravitational field of 9.8 m/s²?
A.
19.6 J
B.
39.2 J
C.
78.4 J
D.
98 J
Show solution
Solution
Gravitational potential energy (U) = mgh = 2 kg * 9.8 m/s² * 10 m = 196 J.
Correct Answer:
B
— 39.2 J
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Q. What is the gravitational potential energy of a mass of 2 kg at a height of 10 m? (g = 9.8 m/s²)
A.
19.6 J
B.
39.2 J
C.
78.4 J
D.
98 J
Show solution
Solution
PE = mgh = 2 * 9.8 * 10 = 196 J
Correct Answer:
B
— 39.2 J
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Q. What is the gravitational potential energy of a satellite of mass m at a height h above the Earth's surface?
A.
-GMm/R
B.
-GMm/(R+h)
C.
-GMm/(R-h)
D.
-GMm/(R^2 + h^2)
Show solution
Solution
The gravitational potential energy of a satellite at height h is given by U = -GMm/(R+h), where R is the radius of the Earth.
Correct Answer:
B
— -GMm/(R+h)
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Q. What is the gravitational potential energy of an object of mass m at a height h above the Earth's surface?
A.
mgh
B.
gh/m
C.
mg/h
D.
mgh^2
Show solution
Solution
The gravitational potential energy is given by the formula U = mgh.
Correct Answer:
A
— mgh
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Q. What is the gravitational potential energy of two masses m1 and m2 separated by a distance r?
A.
-G * (m1 * m2) / r
B.
G * (m1 * m2) / r
C.
G * (m1 + m2) / r
D.
-G * (m1 + m2) / r
Show solution
Solution
The gravitational potential energy is given by U = -G * (m1 * m2) / r.
Correct Answer:
A
— -G * (m1 * m2) / r
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Q. What is the gravitational potential energy U of two masses m1 and m2 separated by a distance r?
A.
U = -G * (m1 * m2) / r
B.
U = G * (m1 * m2) / r
C.
U = (m1 + m2) * r
D.
U = G * (m1 - m2) / r
Show solution
Solution
The gravitational potential energy is given by U = -G * (m1 * m2) / r.
Correct Answer:
A
— U = -G * (m1 * m2) / r
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Q. What is the half-life of a radioactive isotope?
A.
Time taken for half of the sample to decay
B.
Time taken for the entire sample to decay
C.
Time taken for the sample to double
D.
None of the above
Show solution
Solution
The half-life is defined as the time taken for half of the radioactive sample to decay.
Correct Answer:
A
— Time taken for half of the sample to decay
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Q. What is the half-life of a radioactive substance if it takes 10 years for half of the substance to decay?
A.
5 years
B.
10 years
C.
20 years
D.
30 years
Show solution
Solution
The half-life is defined as the time required for half of the radioactive substance to decay, which is given as 10 years.
Correct Answer:
B
— 10 years
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Q. What is the half-life of a radioactive substance?
A.
The time taken for half of the substance to decay
B.
The time taken for the entire substance to decay
C.
The time taken for the substance to double
D.
The time taken for the substance to reach equilibrium
Show solution
Solution
The half-life of a radioactive substance is defined as the time taken for half of the substance to decay.
Correct Answer:
A
— The time taken for half of the substance to decay
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Q. What is the heat required to raise the temperature of 250 g of aluminum from 25°C to 75°C? (Specific heat of aluminum = 0.9 J/g°C)
A.
4500 J
B.
5000 J
C.
6000 J
D.
7000 J
Show solution
Solution
Q = m*c*ΔT = 250 g * 0.9 J/g°C * (75°C - 25°C) = 4500 J.
Correct Answer:
A
— 4500 J
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Q. What is the ideal gas equation?
A.
PV = nRT
B.
PV = nRT^2
C.
PV = nR/T
D.
PV = nRT^3
Show solution
Solution
The ideal gas equation is PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.
Correct Answer:
A
— PV = nRT
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Q. What is the image distance for a concave lens with a focal length of -12 cm when the object is placed at 24 cm?
A.
-8 cm
B.
8 cm
C.
-12 cm
D.
12 cm
Show solution
Solution
Using the lens formula, 1/f = 1/v - 1/u, we find v = -8 cm.
Correct Answer:
A
— -8 cm
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Q. What is the image distance for a convex lens if the object is placed at 10 cm and the focal length is 5 cm?
A.
-15 cm
B.
15 cm
C.
5 cm
D.
10 cm
Show solution
Solution
Using the lens formula 1/f = 1/v - 1/u, we find v = 15 cm.
Correct Answer:
A
— -15 cm
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Q. What is the image distance for a convex lens if the object is placed at 30 cm and the focal length is 10 cm?
A.
15 cm
B.
20 cm
C.
25 cm
D.
30 cm
Show solution
Solution
Using the lens formula 1/f = 1/v - 1/u, we find v = 15 cm.
Correct Answer:
B
— 20 cm
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Q. What is the image distance for a convex lens with a focal length of 10 cm when the object is placed 30 cm from the lens?
A.
5 cm
B.
10 cm
C.
15 cm
D.
20 cm
Show solution
Solution
Using the lens formula 1/f = 1/v - 1/u, we find v = 20 cm.
Correct Answer:
D
— 20 cm
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Q. What is the impedance of a series circuit containing a resistor (R) and an inductor (L)?
A.
R
B.
√(R^2 + (ωL)^2)
C.
R + ωL
D.
R - ωL
Show solution
Solution
The impedance Z = √(R^2 + (ωL)^2) in a series R-L circuit.
Correct Answer:
B
— √(R^2 + (ωL)^2)
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Q. What is the impedance of a series circuit containing a resistor and an inductor?
A.
R
B.
√(R^2 + (ωL)^2)
C.
R + jωL
D.
R - jωL
Show solution
Solution
The impedance Z in a series R-L circuit is given by Z = √(R^2 + (ωL)^2).
Correct Answer:
B
— √(R^2 + (ωL)^2)
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Showing 3811 to 3840 of 5000 (167 Pages)
Physics Syllabus (JEE Main) MCQ & Objective Questions
The Physics Syllabus for JEE Main is crucial for students aiming to excel in their exams. Understanding this syllabus not only helps in grasping fundamental concepts but also enhances problem-solving skills through practice. Engaging with MCQs and objective questions is essential for effective exam preparation, as it allows students to identify important questions and strengthen their knowledge base.
What You Will Practise Here
Mechanics: Laws of Motion, Work, Energy, and Power
Thermodynamics: Laws of Thermodynamics, Heat Transfer
Waves and Oscillations: Simple Harmonic Motion, Wave Properties
Electromagnetism: Electric Fields, Magnetic Fields, and Circuits
Optics: Reflection, Refraction, and Optical Instruments
Modern Physics: Quantum Theory, Atomic Models, and Nuclear Physics
Fluid Mechanics: Properties of Fluids, Bernoulli's Principle
Exam Relevance
The Physics Syllabus (JEE Main) is integral to various examinations, including CBSE, State Boards, and competitive exams like NEET and JEE. Questions often focus on conceptual understanding and application of theories. Common patterns include numerical problems, conceptual MCQs, and assertion-reason type questions, which test both knowledge and analytical skills.
Common Mistakes Students Make
Misinterpreting the question stem, leading to incorrect answers.
Neglecting units and dimensions in calculations.
Overlooking the significance of diagrams in understanding concepts.
Confusing similar concepts, such as velocity and acceleration.
Failing to apply formulas correctly in different contexts.
FAQs
Question: What are the key topics in the Physics Syllabus for JEE Main?Answer: Key topics include Mechanics, Thermodynamics, Waves, Electromagnetism, Optics, Modern Physics, and Fluid Mechanics.
Question: How can I improve my performance in Physics MCQs?Answer: Regular practice of MCQs, understanding concepts deeply, and revising important formulas can significantly enhance your performance.
Start solving practice MCQs today to test your understanding of the Physics Syllabus (JEE Main). This will not only boost your confidence but also prepare you effectively for your upcoming exams. Remember, consistent practice is the key to success!
