Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.
What You Will Practise Here
Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams
Exam Relevance
The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.
Common Mistakes Students Make
Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam
FAQs
Question: How can I improve my performance in Major Competitive Exams? Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.
Question: What types of questions should I focus on for these exams? Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.
Question: Are there specific strategies for tackling objective questions? Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.
Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!
Q. A trophy costs $150 and is awarded to the top three students in a competition. If the total cost of the trophies is $450, how many trophies were purchased? (2020)
A.
1
B.
2
C.
3
D.
4
Solution
Total cost of trophies = $450. Cost per trophy = $150. Number of trophies = 450 / 150 = 3.
Q. A tuning fork produces a sound wave of frequency 440 Hz. What is the wavelength of the sound wave in air (speed of sound = 340 m/s)?
A.
0.77 m
B.
0.85 m
C.
0.90 m
D.
1.00 m
Solution
The wavelength λ can be calculated using the formula λ = v/f, where v is the speed of sound and f is the frequency. Thus, λ = 340 m/s / 440 Hz = 0.77 m.
Q. A tuning fork produces a sound wave with a frequency of 440 Hz. What is the wavelength of the sound wave in air, given that the speed of sound in air is approximately 340 m/s?
A.
0.77 m
B.
0.85 m
C.
0.90 m
D.
1.00 m
Solution
Wavelength λ is given by the formula λ = v/f. Here, v = 340 m/s and f = 440 Hz. Thus, λ = 340/440 = 0.7727 m, approximately 0.77 m.
Q. A uniform rod of length L and mass M is pivoted at one end and allowed to fall under gravity. What is the angular acceleration of the rod just after it is released? (2019)
A.
g/L
B.
2g/L
C.
3g/L
D.
g/2L
Solution
The torque τ = Mg(L/2) and moment of inertia I = (1/3)ML². Using τ = Iα, we find α = 3g/2L.
Q. A uniform rod of length L and mass M is pivoted at one end and released from rest. What is the angular velocity just before it hits the ground?
A.
√(3g/L)
B.
√(2g/L)
C.
√(g/L)
D.
√(4g/L)
Solution
Using conservation of energy, potential energy at the top = rotational kinetic energy at the bottom. mgh = (1/2)Iω^2. For a rod, I = (1/3)ML^2, h = L/2. Solving gives ω = √(3g/L).
Q. A uniform rod of length L and mass M is pivoted at one end and released from rest. What is the angular velocity of the rod when it makes an angle θ with the vertical?
A.
√(g/L)(1-cosθ)
B.
√(2g/L)(1-cosθ)
C.
√(g/L)(1+cosθ)
D.
√(2g/L)(1+cosθ)
Solution
Using conservation of energy, the potential energy lost equals the rotational kinetic energy gained. The angular velocity ω can be derived as ω = √(2g/L)(1-cosθ).
Q. A uniform rod of length L and mass M is pivoted at one end and released from rest. What is the angular speed of the rod just before it hits the ground? (2019)
A.
√(3g/L)
B.
√(2g/L)
C.
√(g/L)
D.
√(4g/L)
Solution
Using conservation of energy, potential energy at the top converts to rotational kinetic energy at the bottom. The angular speed ω = √(3g/L).
Q. A uniform rod of length L and mass M is pivoted at one end and released from rest. What is the angular velocity of the rod just before it hits the ground? (2019)
A.
√(3g/L)
B.
√(2g/L)
C.
√(g/L)
D.
√(4g/L)
Solution
Using conservation of energy, potential energy at the top is converted to rotational kinetic energy at the bottom. The angular velocity ω can be found using the relation ω = √(3g/L).
