The electric field due to a point charge varies inversely with the square of the distance, so at 2r, E becomes E/4.

The electric field just outside a conductor in electrostatic equilibrium is perpendicular to the surface.

In electrostatic equilibrium, excess charge resides on the surface of the conductor, leading to zero electric field inside.

The electric field is the negative gradient of the electric potential. If the potential is constant (0 V), the electric field is zero.

Electric potential energy U is given by U = VQ. Here, U = 10 V * 2 C = 20 J.

Work done W = q(V1 - V2) = 2 C (10 V - 0 V) = 20 J.

Work done = Charge × Potential = 2 C × 10 V = 20 J.

Distance d = V / E = 100 V / 50 N/C = 2 m.

Work done W = q * V = 2 C * 100 V = 200 J.

If the electric field is directed towards the point, it indicates that the charge creating the field is negative.

Potential difference ΔV = E * d = (150 V / 3 m) * 3 m = 150 V.

Potential energy U = q * V = -1 C * 200 V = -200 J.

Work done W = q * (V1 - V2) = 0.5 C * (200 V - 100 V) = 50 J.

Work done W = q * V = 0.5 C * 200 V = 100 J.

The force on a charge in a static electric field is not determined by potential alone; it depends on the electric field, which is not given.

Work done W = q * ΔV = 3 × 10^-6 C * (600 V - 300 V) = 3 × 10^-6 * 300 = 0.9 mJ.

Distance d = V/E = 50 V / 5 N/C = 10 m.

Change in potential energy ΔU = qΔV = 3 C × (15 V - 5 V) = 30 J.

An increase in electric potential at a point generally indicates a stronger electric field, as the electric field is related to the rate of change of potential.

If the electric potential increases, the work done by the external force must increase to move the positive charge against the electric field.

The work done (W) by the electric field is given by W = q(V_A - V_B). For a unit charge, W = 10 V - 5 V = 5 J.

Potential difference (V_AB) = V_A - V_B = 15 V - 5 V = 10 V.

Work done W = Q(V_B - V_A) = 2 C * (15 V - 5 V) = 20 J.

The potential difference V_AB = V_B - V_A = 15 V - 5 V = 10 V.

If the electric potential is constant, the electric field in that region is zero, as E = -dV/dx.

The potential gradient is given as 0.6 V/m, which is the calibration value for the potentiometer.

The balancing length is calculated as L = V / (potential gradient) = 2V / 4 V/m = 0.5 m.

If the enthalpy of a system increases, the process is considered endothermic.

An increase in enthalpy indicates that the system is gaining heat.

A negative enthalpy change indicates that the reaction releases heat, making it exothermic.