Major Competitive Exams MCQ & Objective Questions
Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.
What You Will Practise Here
Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams
Exam Relevance
The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.
Common Mistakes Students Make
Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam
FAQs
Question: How can I improve my performance in Major Competitive Exams?Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.
Question: What types of questions should I focus on for these exams?Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.
Question: Are there specific strategies for tackling objective questions?Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.
Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!
Q. A 5 kg object is lifted to a height of 3 m. What is the work done against gravity?
A.
15 J
B.
30 J
C.
45 J
D.
60 J
Show solution
Solution
Work done against gravity is W = mgh = 5 * 9.8 * 3 = 147 J.
Correct Answer:
B
— 30 J
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Q. A 5 kg object is moving with a constant velocity. What is the net force acting on it? (2022)
A.
0 N
B.
5 N
C.
10 N
D.
15 N
Show solution
Solution
If the object is moving with constant velocity, the net force acting on it is 0 N according to Newton's first law.
Correct Answer:
A
— 0 N
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Q. A 5 kg object is moving with a velocity of 10 m/s. What is its kinetic energy?
A.
25 J
B.
50 J
C.
100 J
D.
250 J
Show solution
Solution
Kinetic energy (KE) = 0.5 * mass * velocity² = 0.5 * 5 * (10)² = 250 J.
Correct Answer:
C
— 100 J
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Q. A 5 kg object is moving with a velocity of 10 m/s. What is its momentum? (2021)
A.
50 kg m/s
B.
100 kg m/s
C.
150 kg m/s
D.
200 kg m/s
Show solution
Solution
Momentum p = mv = 5 kg * 10 m/s = 50 kg m/s.
Correct Answer:
B
— 100 kg m/s
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Q. A 5 kg object is moving with a velocity of 3 m/s. What is its kinetic energy?
A.
22.5 J
B.
30 J
C.
45 J
D.
60 J
Show solution
Solution
Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 5 kg × (3 m/s)² = 22.5 J.
Correct Answer:
A
— 22.5 J
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Q. A 5 kg object is moving with a velocity of 4 m/s. What is its momentum? (2023)
A.
10 kg m/s
B.
15 kg m/s
C.
20 kg m/s
D.
25 kg m/s
Show solution
Solution
Momentum = mass × velocity = 5 kg × 4 m/s = 20 kg m/s.
Correct Answer:
C
— 20 kg m/s
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Q. A 5 kg object is pulled with a force of 25 N. What is the acceleration of the object?
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
Show solution
Solution
Using F = ma, acceleration a = F/m = 25 N / 5 kg = 5 m/s².
Correct Answer:
C
— 4 m/s²
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Q. A 5 kg object is pushed with a force of 15 N. If the frictional force is 5 N, what is the acceleration of the object?
A.
1 m/s²
B.
2 m/s²
C.
3 m/s²
D.
4 m/s²
Show solution
Solution
Net force = applied force - friction = 15 N - 5 N = 10 N. Acceleration = F/m = 10 N / 5 kg = 2 m/s².
Correct Answer:
B
— 2 m/s²
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Q. A 5 kg object is subjected to a net force of 15 N. What is its acceleration?
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
Show solution
Solution
Using F = ma, a = F/m = 15 N / 5 kg = 3 m/s².
Correct Answer:
B
— 3 m/s²
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Q. A 5 kg object is subjected to a net force of 15 N. What is the object's acceleration?
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
Show solution
Solution
Using F = ma, a = F/m = 15 N / 5 kg = 3 m/s².
Correct Answer:
B
— 3 m/s²
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Q. A 5 kg object is subjected to a net force of 25 N. What is its acceleration?
A.
2 m/s²
B.
5 m/s²
C.
10 m/s²
D.
15 m/s²
Show solution
Solution
Using F = ma, a = F/m = 25 N / 5 kg = 5 m/s².
Correct Answer:
C
— 10 m/s²
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Q. A 5 kg object is thrown vertically upward with a speed of 20 m/s. What is the maximum height reached by the object? (g = 10 m/s²)
A.
20 m
B.
30 m
C.
40 m
D.
50 m
Show solution
Solution
Using the formula h = v²/(2g) = (20 m/s)² / (2 * 10 m/s²) = 20 m.
Correct Answer:
B
— 30 m
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Q. A 5 ohm resistor and a 10 ohm resistor are connected in series. What is the total resistance?
A.
15 ohms
B.
5 ohms
C.
10 ohms
D.
2 ohms
Show solution
Solution
In series, the total resistance is R_total = R1 + R2 = 5 + 10 = 15 ohms.
Correct Answer:
A
— 15 ohms
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Q. A 50 kg crate is at rest on a flat surface. What is the normal force acting on the crate?
A.
0 N
B.
50 N
C.
500 N
D.
1000 N
Show solution
Solution
The normal force equals the weight of the crate, which is N = mg = 50 kg * 10 m/s² = 500 N.
Correct Answer:
C
— 500 N
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Q. A 50 kg crate is pushed with a force of 200 N. If the frictional force is 50 N, what is the acceleration of the crate? (2022)
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
Show solution
Solution
Net force = 200 N - 50 N = 150 N. Acceleration a = F/m = 150 N / 50 kg = 3 m/s².
Correct Answer:
B
— 3 m/s²
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Q. A 50 kg crate is pushed with a force of 200 N. If the frictional force is 50 N, what is the acceleration? (2022)
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
Show solution
Solution
Net force = applied force - friction = 200 N - 50 N = 150 N. Acceleration a = F/m = 150 N / 50 kg = 3 m/s².
Correct Answer:
B
— 3 m/s²
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Q. A 50 kg crate is pushed with a force of 200 N. What is the acceleration of the crate? (Assume no friction) (2021)
A.
2 m/s²
B.
4 m/s²
C.
5 m/s²
D.
10 m/s²
Show solution
Solution
Using F = ma, acceleration a = F/m = 200 N / 50 kg = 4 m/s².
Correct Answer:
B
— 4 m/s²
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Q. A 50 kg object is at rest on a surface. What is the normal force acting on it?
A.
0 N
B.
50 N
C.
100 N
D.
500 N
Show solution
Solution
The normal force equals the weight of the object, which is F = mg = 50 kg * 9.8 m/s² = 490 N.
Correct Answer:
C
— 100 N
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Q. A 50 kg object is dropped from a height of 20 m. What is the speed just before it hits the ground? (g = 10 m/s²) (2020)
A.
10 m/s
B.
20 m/s
C.
30 m/s
D.
40 m/s
Show solution
Solution
Using v² = u² + 2gh, v² = 0 + 2 * 10 m/s² * 20 m = 400, v = √400 = 20 m/s.
Correct Answer:
B
— 20 m/s
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Q. A 50 kg object is in free fall. What is the net force acting on it?
A.
50 N
B.
100 N
C.
200 N
D.
500 N
Show solution
Solution
The net force is equal to the weight of the object, F = mg = 50 kg * 9.8 m/s² = 490 N (approximately 500 N).
Correct Answer:
B
— 100 N
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Q. A 50 kg object is moving with a constant velocity. What can be said about the net force acting on it?
A.
It is zero
B.
It is equal to its weight
C.
It is equal to the applied force
D.
It is maximum
Show solution
Solution
If the object is moving with constant velocity, the net force acting on it is zero.
Correct Answer:
A
— It is zero
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Q. A 50 kg object is moving with a velocity of 10 m/s. What is its kinetic energy? (2022)
A.
2500 J
B.
500 J
C.
1000 J
D.
2000 J
Show solution
Solution
Kinetic energy KE = (1/2)mv² = (1/2)(50)(10²) = 2500 J.
Correct Answer:
A
— 2500 J
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Q. A 50 kg object is moving with a velocity of 10 m/s. What is its momentum?
A.
500 kg m/s
B.
1000 kg m/s
C.
1500 kg m/s
D.
2000 kg m/s
Show solution
Solution
Momentum = mass × velocity = 50 kg × 10 m/s = 500 kg m/s.
Correct Answer:
B
— 1000 kg m/s
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Q. A 50 kg object is moving with a velocity of 4 m/s. What is its kinetic energy?
A.
100 J
B.
200 J
C.
400 J
D.
800 J
Show solution
Solution
Kinetic Energy (KE) = 0.5 * m * v² = 0.5 * 50 kg * (4 m/s)² = 400 J.
Correct Answer:
C
— 400 J
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Q. A 50 kg object is moving with a velocity of 5 m/s. What is its momentum? (2023)
A.
100 kg·m/s
B.
150 kg·m/s
C.
200 kg·m/s
D.
250 kg·m/s
Show solution
Solution
Momentum p = mv = 50 kg * 5 m/s = 250 kg·m/s.
Correct Answer:
A
— 100 kg·m/s
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Q. A 50 kg object is pulled with a force of 200 N. What is its acceleration? (2023)
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
Show solution
Solution
Using F = ma, we find a = F/m = 200 N / 50 kg = 4 m/s².
Correct Answer:
D
— 5 m/s²
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Q. A 50 kg object is pulled with a force of 200 N. What is the acceleration of the object?
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
Show solution
Solution
Using F = ma, we have a = F/m = 200 N / 50 kg = 4 m/s².
Correct Answer:
D
— 5 m/s²
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Q. A 50 kg object is pushed with a force of 200 N over a distance of 10 m. What is the work done? (2000)
A.
2000 J
B.
1000 J
C.
500 J
D.
3000 J
Show solution
Solution
Work Done = Force * Distance = 200 N * 10 m = 2000 J
Correct Answer:
A
— 2000 J
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Q. A 50 kg object is pushed with a force of 200 N. What is the frictional force if the object moves with constant velocity? (2023)
A.
0 N
B.
50 N
C.
200 N
D.
100 N
Show solution
Solution
If the object moves with constant velocity, the frictional force equals the applied force, which is 200 N.
Correct Answer:
C
— 200 N
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Q. A 50 kg person jumps off a diving board with a speed of 5 m/s. What is the momentum of the person just before hitting the water?
A.
100 kg·m/s
B.
200 kg·m/s
C.
250 kg·m/s
D.
300 kg·m/s
Show solution
Solution
Momentum p = mv = 50 kg * 5 m/s = 250 kg·m/s.
Correct Answer:
A
— 100 kg·m/s
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