The Chemistry (School & UG) category covers the fundamental to advanced concepts of Chemistry, structured to support Class 11–12 students, competitive exam aspirants, and undergraduate learners. The content emphasizes conceptual clarity, problem-solving skills, and strong alignment with NCERT and university syllabi.
In this category, you will study:
Physical Chemistry – atomic structure, thermodynamics, chemical kinetics, equilibrium, electrochemistry, and solutions
Inorganic Chemistry – periodic trends, chemical bonding, coordination compounds, metallurgy, and s-, p-, d-, and f-block elements
Numerical problem-solving – formula-based calculations, mole concept, and graph-based questions
Reaction mechanisms and derivations with step-by-step explanations
Comparisons, trends, and exceptions important for exams
NCERT-based theory, supported by diagrams, tables, MCQs, assertion–reason questions, numericals, and PYQs
The content is designed to build strong foundations, improve analytical and quantitative skills, and prepare students for school examinations, competitive exams, and undergraduate assessments.
Develop a clear, logical, and application-oriented understanding of Chemistry to excel academically and confidently tackle problem-based and conceptual questions at both school and UG levels.
Q. In the nitration of toluene, which position is most likely to be attacked by the electrophile?
A.
Ortho position
B.
Meta position
C.
Para position
D.
All positions equally
Solution
The para position is favored in the nitration of toluene due to the electron-donating effect of the methyl group, which stabilizes the carbocation intermediate.
Q. In the presence of a strong electrophile, which position on a disubstituted benzene ring will a third substituent most likely attach?
A.
Ortho
B.
Meta
C.
Para
D.
Random
Solution
The position of the third substituent depends on the nature of the existing substituents; however, ortho and para positions are generally favored for activating groups.
Q. In the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g), what will happen if the pressure is increased?
A.
Shifts to the left
B.
Shifts to the right
C.
No effect
D.
Increases the temperature
Solution
Increasing the pressure will shift the equilibrium to the right, favoring the formation of SO3, as it has fewer moles of gas (2 moles) compared to the reactants (3 moles).
Q. In the reaction A(g) + B(g) ⇌ C(g), if the pressure is increased, which direction will the equilibrium shift if there are more moles of gas on the left?
A.
Shifts to the right
B.
Shifts to the left
C.
No effect
D.
Increases temperature
Solution
Increasing pressure will shift the equilibrium to the right, favoring the side with fewer moles of gas.
Q. In the reaction CO(g) + 2H2(g) ⇌ CH3OH(g), what is the effect of increasing the pressure?
A.
Shifts to the right
B.
Shifts to the left
C.
No effect
D.
Increases the temperature
Solution
Increasing the pressure favors the side with fewer moles of gas. In this case, the right side has fewer moles (1 mole of CH3OH) compared to the left (3 moles), so the equilibrium shifts to the right.
Q. In the reaction of an alkene with HBr, what is the major product when the alkene is asymmetric?
A.
Markovnikov product
B.
Anti-Markovnikov product
C.
No reaction
D.
Polymerization
Solution
According to Markovnikov's rule, the hydrogen from HBr adds to the less substituted carbon of the alkene, leading to the formation of the Markovnikov product.
Q. In the reaction of benzyl chloride with sodium hydroxide, which mechanism is primarily involved?
A.
SN1
B.
SN2
C.
E1
D.
E2
Solution
The reaction of benzyl chloride with sodium hydroxide primarily follows the SN1 mechanism due to the stability of the benzyl carbocation formed during the reaction.
