Total internal reflection cannot occur when light travels from a rarer medium (air) to a denser medium (glass).

Total internal reflection occurs when light travels from a denser medium (glass) to a less dense medium (air) at an angle greater than the critical angle.

Total internal reflection cannot occur when light travels from a rarer medium (air) to a denser medium (glass).

Light is most likely to be polarized when it reflects off a surface, such as a lake.

Total internal reflection cannot occur when light travels from a rarer medium (air) to a denser medium (water) at any angle, as it will always refract.

Distance between fringes (y) = (λD)/d. Assuming λ = 500 nm, y = (500 x 10^-9 * 1)/(0.2 x 10^-3) = 0.0025 m = 0.25 mm. Distance between first and second bright fringes = 0.4 mm.

Fringe width (β) = λD/d. Here, D = 1 m, d = 0.2 mm = 0.0002 m, λ = 500 nm = 500 x 10^-9 m. β = (500 x 10^-9 * 1) / 0.0002 = 0.0025 m = 0.25 mm.

Fringe width (β) is given by β = λD/d, where D is the distance to the screen and d is the distance between the slits. If d is doubled, β halves.

Fringe width is given by β = λD/d. If d (distance between slits) is doubled, the fringe width β will halve.

Constructive interference occurs when the path difference is an integer multiple of λ.

A phase difference of π radians corresponds to a path difference of λ/2, leading to destructive interference.

Constructive interference occurs when the path difference is an integer multiple of λ, and 0.5λ corresponds to a half wavelength, leading to constructive interference.

Phase difference (φ) = (2π/λ) * path difference. Given λ = 1 m, φ = (2π/1) * 0.5 = π rad.

Phase difference (Δφ) = (2π/λ) * path difference. For sound in air, λ = v/f. Assuming f = 1000 Hz and v = 340 m/s, λ = 0.34 m. Δφ = (2π/0.34) * 0.5 = π/2 rad.

Replacing monochromatic light with white light results in a colored diffraction pattern due to the different wavelengths.

Increasing the distance between the slits decreases the fringe width, as fringe width is inversely proportional to the slit separation.

Increasing the distance to the screen results in an increase in fringe width in the diffraction pattern.

Decreasing the slit width increases the diffraction angle, causing the diffraction pattern to become wider.

When a lens is immersed in a medium with a higher refractive index, its effective focal length decreases due to the reduced refractive power.

The focal length of a lens decreases when immersed in a medium with a higher refractive index than air.

Fringe width (β) is inversely proportional to the distance to the screen (D). If D is halved, the fringe width decreases.

As the object moves closer, the image distance increases.

When an object is placed at infinity, a concave lens forms a virtual image at its focal point, which is upright.

When the object is at the center of curvature, the image formed is real, inverted, and of the same size.

When the object is placed between the focal point and the mirror, the image formed is virtual and upright.

When the object is within the focal length of a convex lens, the image formed is virtual and upright.

When the object is within the focal length of a convex lens, the image formed is virtual.

When light passes through two polarizers at 90 degrees to each other, the intensity becomes zero because no light can pass through.

The intensity of light passing through two polarizers at an angle of 45 degrees is quartered.

Covering one slit eliminates the condition for interference, resulting in a single-slit diffraction pattern instead of an interference pattern.